i am preparing one small game like jigsaw , for that i am using 9 imageview's with 9 different images in the layout. set the images to imageview at the time of starting those are actual images, after shuffle user will do sliding the images to complete puzzle, i want to check the modified image with actual image's, weather it's equal or not if those are equal popup a message, like gameover.
i tried like this
1.by using AND operator between the images(Drawables) but unlucky.
2.Using setLevel() for the images, compare those setLevel values with getLevel values for images after sliding still Unlucky.. here the problem is if i click on imageview one time getLevel() gives correct value, if i click more than once it gives zero value. Why it happens like this..
Please help me if you find any mistake in my code, otherwise guide me with good technique..
Xml code like this
<RelativeLayout
//9 imageview's
in jave code like this
if user will click on imageview it will swap the image's
img_View11.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
if(img_View21.getDrawable() == default_img ||
img_View12.getDrawable() == default_img) {
System.out.println("yes");
++click;
Noof_moves.setText("Moves: " +click);
ImageView iv = (ImageView)v;
d11 = iv.getDrawable();
prev_img = prev_imgView.getDrawable();
la11 = d11.getLevel();
System.out.println("d11 value is " +la11);
prev_imgView.setImageDrawable(d11);
img_View11.setImageDrawable(prev_img);
prev_imgView = img_View11;
check();
}
else { System.out.println("no"); }
}
});
void check(){
System.out.println("in checking condition");
if((lb11==la11) && (lb12==la12) && (lb13==la13) && (lb21==la21) && (lb22==la22)
&& (lb23==la23) && (lb31==la31) && (lb32==la32) && (lb33==la33)) {
Context c = getBaseContext();
System.out.println("gameover");
Toast.makeText(c, " GameOver ", Toast.LENGTH_SHORT).show();
}else{ System.out.println(" codition not checked "); }
}
//here lb=level before sliding
// la=level after sliding..
Ok, here is what you do for the solution.
maintain a new set of drawables marking them as original drawables that you had initially.
may be like
drawable og11 = imageView11.getDrawable();
do this part before shuffling. now you have original drawables, stored in the form of drawables.
After every click , check if og11 == imageView11.getDrawable(),... and so on for all the images in the jigsaw, if they match , it matches, else, they don't.
HTH.
I have a simple solution. Set serial number Integer tags to ImageViews using View.setTag(index) before jumbling(before preparing the puzzle.) Then everytime the user makes a move, loop through all the imageviews and check if they are in order. If out of order then puzzle is not completed yet.
class PuzzleItem {
Drawable puzzlepartImage;
int correctPosition;
public PuzzleItem(Drawable d, int index) {
puzzlepartImage = d;
correctPosition = index;
}
}
ArrayList<PuzzleItem> list = new ArrayList<PuzzleItem>();
for (int i = 0; i < 9; i++) {
list.add(new PuzzleItem(drawables[i], i));
}
Collections.shuffle(list);
//Create the views from this list and add to the layout serially.
// set the last view as emptyview.
On every move:
void onClick(View v) {
/* swap drawables */
Drawable clickedDrawable = v.getDrawable();
v.setDrawable(null);
mEmptyView.setDrawable(clickedDrawable);
mEmptyView = v;
/* swap tag integers */
Integer temp = (Integer)mEmptyView.getTag();
mEmptyView.setTag(v.getTag());
v.setTag(temp);
}
After every move check for completion:
for (int i = 0; i < 9; i++) {
if (imgView[i].getTag() != i) break;
}
if (i == 9)// puzzle completed.
why don't you use a gridView? and after each change, just check the items to see that images are in desired order
When you use == operator they are checking if both the objects are referencing the same object. But in your case they are 2 different objects.
You should set a tag to both the actual image and the other image. And check if they are both the same. That should work in your if condition.
For the drawable class i did notice a method setLevel and getLevel. You might be able to use this for your requirement.
Related
Is there a way to use a counter in a java file to set a resource/drawable/image to a variable?
For instance:
Layout file
<ImageView
android:id="#+id/imageHolder"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:padding="10dp"/>
Java file
int index = 0;
ImageView imgHolder =(ImageView) findViewById(R.id.imgHolder);
Drawable drawable = getResources().getDrawable(R.drawable.img<index>);
imgHolder.setImageDrawable(drawable);
I'm sure this isn't possible like this, but I just wanted to give an example of what I'm trying to accomplish.
I would just want to get around what I feel is inevitable, ie:
if(index == 1)
{
drawable = getResources().getDrawable(R.drawable.img1);
imgHolder.setImageDrawable(drawable);
}
else if(index == 2)
{
drawable = getResources().getDrawable(R.drawable.img2);
imgHolder.setImageDrawable(drawable);
}
else if(index == 3)
etc...
Similar to my answer here How to add ImageView's that are depending on the text of the TextView in a ListView
image.setImageResource(getImageId(this, "img" + index);
So basically you're getting the number from your counter and manipulating it to be in the format you're storing your images and calling the below helper to get the correct image id.
public static int getImageId(Context context, String imageName) {
return context.getResources().getIdentifier("drawable/" + imageName, null, context.getPackageName());
}
One view in application has to show some pictures in a row. But they are shown in the wrong order. In this method I get images' names. After I had renamed the images nothing has changed. Any ideas, please?
void childParseAttributes(final Properties attributes) {
// ...
String image = attributes.getProperty("icon");
if (image.indexOf("png") != -1)
image = image.substring(0, image.length() - 4);
int i = Utils.getImageId(image);
if (i > 0) {
ImageView icon = (ImageView) findViewById(R.id.footer_icon);
icon.setBackgroundResource(i);
// ...
}
Logcat
07-17 14:18:35.553: D/some_app.image(504): card_lock id=2130837532
07-17 14:18:35.562: D/some_app.image(504): card_unlock id=2130837537
I've renamed "card_lock" as "card_unlock" and vice versa. New card_lock's id was 2130837532 and new card_unlock's id was 2130837537, i.e. nothing has changed.
I have a couple of EditTexts arranged on rows and columns.Those EditTexts contain product name,quantity and price and a TextView that shows the total in real time(calculates it each time you write on one of the EditTexts)
I've setup a a button on each row that when clicked sets visibility of the row(3EditTexts for product name,price and quantity) to GONE.
My problem is that after i set the visibility to GONE,though there are no more EditTexts it still calculates their values from before being GONE.
My question now is,what happens when the EditTexts are set to visibility.GONE ?
My app calculates in real time,so when something happens to an EditText,he calculates again..but it's like the values are still there...Isn't this supposed to be the difference between invisible and gone ?
I'll show you the way i calculate(it is called even after you press the X button to erase the EditTexts,not only when you change values inside EditTexts)
public void calculeaza() {
totaltest = 0;
prod = new String[allprod.size()];
pret = new String[allpret.size()];
cant = new String[allcant.size()];
for (int m = 0; m < allprod.size(); m++) {
prod[m] = allprod.get(m).getText().toString();
if (prod[m].matches("")) {
prod[m] = " - ";
}
}
for (int j = 0; j < allcant.size(); j++) {
cant[j] = allcant.get(j).getText().toString();
if (cant[j].matches("")) {
cant[j] = Float.toString(0);
}
}
for (int k = 0; k < allpret.size(); k++) {
pret[k] = allpret.get(k).getText().toString();
if (pret[k].matches("")) {
pret[k] = Float.toString(0);
}
}
for (int l = 0; l < allpret.size(); l++) {
Float temp = Float.parseFloat(cant[l]) * Float.parseFloat(pret[l]);
totaltest = totaltest + temp;
TextView totalf = (TextView) findViewById(R.id.total);
totalf.setText(String.format("Total: %.2f", totaltest));
}
}
Lines Straight from Android dev site..
View.GONE This view is invisible, and it doesn't take any space for layout purposes.
View.INVISIBLE This view is invisible, but it still takes up space for layout purposes.
i.e it retains EditText object even after Gone..
You can reinitialise edittext if you dont want it to retain its value...or setText = ""
Above quoted is the only difference...
Hope this helps...
I'm not really seeing in the code you posted anything I can use to answer this question, but there does appear to be some confusion as to what setVisibility does:
INVISIBLE elements are not seen on the page, but they still take up space (there's a hole where they would be)
GONE elements have no visible effect on the screen, from the user's perspective they aren't there. However they are still part of the view.
If you want to remove the object from the view, then you need to call removeView() on its parent.
It may still take up memory after it has been removed from the view, in case your code has kept references to it in any variables.
It may still take up memory after there are no further references to it, at least until the garbage collector gets around to it.
I'm hoping the rather generalized statements above help clarify the situation.
I am trying to compare items out of my DB to the value of an EditText (user input). The answer can have multiple answers, seperated by a ','. I first put them into a stringarray and then compare them to the answer. The LevenshteinDistance checks if the answer is more or les good (http://en.wikipedia.org/wiki/Levenshtein_distance#Computing_Levenshtein_distance).
userAnswer = etUserAnswer.getText().toString().toLowerCase();
String[] answers = qAnswer.split(",");
for (String answer : answers) {
if (answer.equals(userAnswer)) {
Toast.makeText(getApplicationContext(), ("Answer Correct"),
Toast.LENGTH_SHORT).show();
tvMessage.setText("You smartass!");
} else {
Toast.makeText(getApplicationContext(), ("Wrong"),
Toast.LENGTH_SHORT).show();
points = points - 4;
String answerGood = answer.toLowerCase();
LevenshteinDistance lDistance = new LevenshteinDistance();
int comparisonCheck = lDistance.computeLevenshteinDistance(
userAnswer, answerGood);
if (comparisonCheck == 1) {
tvMessage.setText("Almost there, but not quite yet!");
} else if (comparisonCheck > 1) {
tvMessage.setText("Are you serious, totally wrong?!");
}
}
}
Suppose I am having the answers for a question in the DB as follows: tree,test,radio
I am having two problems:
1. When I type "radi" it gives me 'Almost there...' which is good. It should also give me this if I enter "tes", but instead it gives me the 'Are you serious,...' line. I guess it keeps comparing to the last one.
2. Every time I type in something which is not correct, I get -12 instead of -4. I suppose this is due to the fact I am having three answers and it loops three times.. but I don't know how I can make it count only once..
Anyone can help me on the way? Thanks!
Assuming you don't need to know the word which gives the least Levenshtein distance, you could modify your loop to find smallest distance only;
userAnswer = etUserAnswer.getText().toString().toLowerCase();
String[] answers = qAnswer.split(",");
LevenshteinDistance lDistance = new LevenshteinDistance();
int minDistance = lDistance.computeLevenshteinDistance(
userAnswer, answers[0].toLowerCase());
for (int i = 1; i < answers.length; ++i) {
minDistance = Math.min(minDistance, lDistance.computeLevenshteinDistance(
userAnswer, answers[i].toLowerCase()));
}
if (minDistance == 0) {
// Correct answer...
} else {
// Wrong answer...
points -= 4;
// etc etc...
}
I have a a set of 10 imageviews in my layout. I have given them sequential id's also as
android:id="#+id/pb1"
android:id="#+id/pb2"
Now I want to change background dynamically.
int totalPoi = listOfPOI.size();
int currentPoi = (j/totalPoi)*10;
for (i=1;i<=currentPoi;i++) {
imageview.setBackgroundResource(R.drawable.progressgreen);
}
Now inside the for loop I want to set the image view background dynamically. i,e if the currentpoi value is 3, background of 3 image views should be changed. What ever the times the for loop iterates that many image view's background should be changed. Hope the question is clear now.
Note : I have only 1 image progressgreen that need to be set to 10 image views
Finally I did this in the following way,
I placed all the id's in the array as
int[] imageViews = {R.id.pb1, R.id.pb2,R.id.pb3,R.id.pb4,R.id.pb5,R.id.pb6,R.id.pb7,R.id.pb8,R.id.pb9,R.id.pb10};
Now:
int pindex = 0;
for (pindex; pindex <currentPoi; pindex++) {
ImageView img = (ImageView) findViewById(imageViews[pindex]) ;
img.setImageResource(R.drawable.progressgreen);
}
Now, I am able to change the images dynamically.
#goto10. Thanks for your help. I will debug your point to see what went wrong in my side
Create an ImageView array:
ImageView views[] = new ImageView[10];
views[0] = (ImageView)findViewById(R.id.pb1);
...
views[9] = (ImageView)findViewById(R.id.pb10);
Now iterate the loop to set the background of images like this:
for (i=1;i<=currentPoi;i++)
{
views[i-1].setBackgroundResource(R.drawable.progressgreen);
}
you can do this by setting the name of drawables something like:
img_1, img_2, img_3...
for (i=1;i<=currentPoi;i++)
{
ImageView imageview=(ImageView) findViewById(getResources().getIdentifier("imgView_"+i, "id", getPackageName()));
imageview.setImageResource(getResources().getIdentifier("img_"+i, "drawable", getPackageName()));
}
Try this code.....
Create image Array..
private Integer[] mThumbIds = { R.drawable.bg_img_1, R.drawable.bg_img_2,
R.drawable.bg_img_3, R.drawable.bg_img_4, R.drawable.bg_img_5 };
And than modify your code
int totalPoi = listOfPOI.size();
int currentPoi = (j/totalPoi)*10;
for (i=1;i<=currentPoi;i++) {
imageview.setBackgroundResource(mThumbIds[i]);}
You could make an array of your ImageViews and then change them in your for loop.
ImageView views[] = new ImageView[10];
views[0] = (ImageView)findViewById(R.id.imageView0);
...
views[9] = (ImageView)findViewById(R.id.imageView9);
and then change your for loop to:
for (i=1;i<=currentPoi;i++) {
views[currentPoi].setBackgroundResource(R.drawable.progressgreen);
}
Arrays start at index 0, so make sure there's not an off-by-one error in here.
You'll need to give your ImageViews sequential ids, such as "#+id/pb1" and "#+id/pb2", etc.. Then you can get each of them in the loop like this:
for (i=1;i<=currentPoi;i++) {
// Find the image view based on it's name. We know it's pbx where 'x' is a number
// so we concatenate "pb" with the value of i in our loop to get the name
// of the identifier we're looking for. getResources.getIdentifier() is able to use
// this string value to find the ID of the imageView
int imageViewId = getResources().getIdentifier("pb" + i, "id", "com.your.package.name");
// Use the ID retrieved in the previous line to look up the ImageView object
ImageView imageView = (ImageView) findViewById(imageViewId);
// Set the background for the ImageView
imageView.setBackgroundResource(R.drawable.progressgreen);
}
Replace com.your.package.name with your application's package.