I need to send a byte arrray file using WCF rest services. I have to send the data using HttpPost method in android. The code which i am using give the status as HTTP/1.1 400 Bad Request error.
private final static String URI = "http://192.168.1.15/QueryService/Import/Test";
final HttpPost request = new HttpPost(URI);
final HttpClient httpClient = new DefaultHttpClient();
final ByteArrayEntity entity = new ByteArrayEntity(fileToBytes(pathToOurFile));
entity.setContentType("application/octet-stream");
entity.setChunked(true);
request.setEntity(entity);
final HttpResponse hr = httpClient.execute(request);
final StatusLine status = hr.getStatusLine();
httpClient.getConnectionManager().shutdown();
It is difficult to tell what is wrong with your request. The standard way of resolving this kind of errors is:
Create a WCF client for your service. Verify that it works as expected.
Use Fiddler or another suitable tool to intercept the HTTP request your client is generating. Both the headers and the body are important.
Modify your Android request to generate the exact same request as the WCF client.
I was also facing same problem with WCF service. 400 Bad request means request parameter value which you are passing to method doesn't match with method's parameter. I have used Base64 string encoding to pass file as method parameter. May it'll help you.
Related
I am trying to fire an API in which I need to add two headers i.e token and deviceid. Below is my code to add header:
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(nameValuePairs[0].get(0).getValue().toString());
nameValuePairs[0].remove(0);
ResponseHandler<String> res = new BasicResponseHandler();
// set header
httpPost.setHeader("Content-Type", "application/x-www-form-urlencoded");
httpPost.setHeader("deviceid", "358978060711939");
httpPost.setHeader("token", "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJHVUlEIjoiYjdlNjZiOWQtMjBjNy00MGI2LTliMzgtOTc3OGQ2OWIwM2E1IiwiRU5USVRZIjoiRUFCTSIsIlVOSVQiOiJVQk0yIiwiUk9MRU5BTUUiOiJTRUxGIiwiSUQiOiIwMDAyMzciLCJBTFRJRCI6IjMzMyIsIlVTRVJfTkFNRSI6IkFuaWwiLCJMT0dJTl9HVUlEX0tFWSI6ImU2NWM2YWEzLTZlNDItNDUyYS1hOGEwLWRlYzRhMGRiNTIxNyIsImlhdCI6MTQ1OTI0ODkyM30.m742d9xd6XlBBjZ3_ODWuoCEdWvSkhPAuNrDee1vi74");
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs[0]));
response = httpClient.execute(httpPost, res);
In Response I am getting: org.apache.http.client.HttpResponseException: Not Found
When I replace token with any alpha numeric value then I am getting response with error message. But when I passed actual token value which is mentioned above I am getting exception. Even I tried with addHeader function also but getting same issue. I am unable to understand how to resolve this error.
it's the handler which is causing the error. Don't use.
You should either write your own handler or call execute without a handler.
httpClient.execute(httpPost);//remove the handler
I hope this is helpful. ThankYou
Your token seems to be incorrect. Header set in HTTP protocols has their own restrictions. To check it, just try to send your trim token (ex 30 chars).
If it don't helped, you have incorrect another parameters. Anyway, i would give you advice, to use Retrofit.
Im coding a RESTful API & Android client at the same time as I go and im currently working on pulling the users profile from the server. I feel like this should definitely be a get request being that im only pulling existing data and im not adding/editing anything to my database, but I do need a user_id param to be able to query for the appropriate profile. Can I send just one tiny little variable along with my HttpGet some how or am i supposed to use a HttpPost in this situation regardless?
Android uses Apache's HTTPClient. So, copying their tutorial code:
public void sendStringTo(String remoteUrl, String myString) {
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(remoteUrl+"?string1="+myString);
HttpResponse response1 = httpclient.execute(httpGet);
// The underlying HTTP connection is still held by the response object
// to allow the response content to be streamed directly from the network socket.
// In order to ensure correct deallocation of system resources
// the user MUST either fully consume the response content or abort request
// execution by calling HttpGet#releaseConnection().
try {
System.out.println(response1.getStatusLine());
HttpEntity entity1 = response1.getEntity();
// do something useful with the response body
// and ensure it is fully consumed
EntityUtils.consume(entity1);
} finally {
httpGet.releaseConnection();
}
return;
}
GET can support adding variables/parameters. For example you could make a Url that looks like this:
http://yourwebsite.com/script.php?user_id=19898424
I am using the HttpPut to communicate with server in Android, the response code I am getting is 500.After talking with the server guy he said prepare the string like below and send.
{"key":"value","key":"value"}
now I am completely confused that where should i add this string in my request.
Please help me out .
I recently had to figure out a way to get my android app to communicate with a WCF service and update a particular record. At first this was really giving me a hard time figuring it out, mainly due to me not knowing enough about HTTP protocols, but I was able to create a PUT by using the following:
URL url = new URL("http://(...your service...).svc/(...your table name...)(...ID of record trying to update...)");
//--This code works for updating a record from the feed--
HttpPut httpPut = new HttpPut(url.toString());
JSONStringer json = new JSONStringer()
.object()
.key("your tables column name...").value("...updated value...")
.endObject();
StringEntity entity = new StringEntity(json.toString());
entity.setContentType("application/json;charset=UTF-8");//text/plain;charset=UTF-8
entity.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json;charset=UTF-8"));
httpPut.setEntity(entity);
// Send request to WCF service
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(httpPut);
HttpEntity entity1 = response.getEntity();
if(entity1 != null&&(response.getStatusLine().getStatusCode()==201||response.getStatusLine().getStatusCode()==200))
{
//--just so that you can view the response, this is optional--
int sc = response.getStatusLine().getStatusCode();
String sl = response.getStatusLine().getReasonPhrase();
}
else
{
int sc = response.getStatusLine().getStatusCode();
String sl = response.getStatusLine().getReasonPhrase();
}
With this being said there is an easier option by using a library that will generate the update methods for you to allow for you to update a record without having to manually write the code like I did above. The 2 libraries that seem to be common are odata4j and restlet. Although I haven't been able to find a clear easy tutorial for odata4j there is one for restlet that is really nice: http://weblogs.asp.net/uruit/archive/2011/09/13/accessing-odata-from-android-using-restlet.aspx?CommentPosted=true#commentmessage
Error 500 is Internal Server error. Not sure if this answers your question but I personally encountered it when trying to send a data URI for an animated gif in a PUT request formatted in JSON but the data URI was too long. You may be sending too much information at once.
I am trying to retrieve a JSON file from a web service using the following URL. That works fine when I use a browser to send the HTTP request.
For the Android application I came up with the following code.
// Android request
String url = "http://data.wien.gv.at/daten/geoserver/ows?service=WFS" +
"&request=GetFeature&version=1.1.0&typeName=ogdwien:BAUMOGD" +
"&srsName=EPSG:4326&outputFormat=json" +
"&bbox=16.377681,48.211448,16.379829,48.21341,EPSG:4326" +
"&maxfeatures=10"
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
String result = EntityUtils.toString(entity);
Though, EntityUtils does not output a JSON file but this XML exception.
// Value of result
<?xml version="1.0" encoding="UTF-8"?>
<ows:ExceptionReport version="1.0.0"
xsi:schemaLocation="http://www.opengis.net/ows http://data.wien.gv.at/daten/geoserver/schemas/ows/1.0.0/owsExceptionReport.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ows="http://www.opengis.net/ows">
<ows:Exception exceptionCode="NoApplicableCode">
<ows:ExceptionText>java.io.EOFException: input contained no data
input contained no data</ows:ExceptionText>
</ows:Exception>
</ows:ExceptionReport>
I hope you can see what wents wrong ...
The HTML specifications technically define the difference between "GET" and "POST" so that former means that form data is to be encoded (by a browser) into a URL while the latter means that the form data is to appear within a message body. > [source]
Since you do encode the full request into the URL (request=GetFeature etc.) => use HttpGet instead.
Might even work imo with post since the url should still be transmitted to the server but the server would need to detect that the post request is actually a get request and behave accordingly.
I want to make an Htttp Connection Here is my code
try
{
HttpClient client = new DefaultHttpClient();
HttpPost httpMethod = new HttpPost("http://www.google.co.in/");
String requestBody = "some text";
HttpMethod.setEntity(new StringEntity(requestBody));
HttpResponse response = client.execute(httpMethod);
textView.setText(response.getStatusLine().toString());
}
But i m unable to and get the "HTTP/1.0 405 Method not Allowed" error
I will be thankfull your help
It means that the requested URL does not accept the POST method. Try again with GET.
Perhaps you should try with a server that accepts POST requests. There's probably nothing wrong with your code, Google's front page just doesn't do POST.
One quick example of a server you could use I can think of is JSFiddle's echo feature. I'm sure they won't mind.