Since AVD tools 16 I'm getting this warning:
Replace "..." with ellipsis character (..., …) ?
in my strings.xml
at this line
<string name="searching">Searching...</string>
How do I replace ...? Is it just literally …?
Could someone explain this encoding?
… is the unicode for "…" so just replace it. It's better to have it as one char/symbol than three dots.
To make thing short just put … in place ...
Link to XML character Entities List
Look at Unicode column of HTML for row named hellip
If you're using Eclipse then you can always do the following:
Right click on the warning
Select "Quick Fix" (shortcut is Ctrl + 1 by default)
Select "Replace with suggested characters"
This should replace your three dots with the proper Unicode character for ellipsis.
Just a note: The latest version of ADT (21.1) sometimes won't do the replace operation properly, but earlier versions had no problem doing this.
This is the character: …
The solution to your problem is:
Go to Window -> Preferences -> Android -> Lint Error Checking
And search for "ellipsis". Change the warning level to "Info" or "Ignore".
This answer is indirectly related to this question:
In my case textView1.setTextView("done…"); was showing some box/chinese character. Later, I checked into fileformat.info for what the value represents and I found this is a Han character.
So, what to do? I searched for "fileformat.info ellipse character" and then everything became clear to me once I saw its values are;
UTF-16 (hex) 0x2026 (2026)
UTF-16 (decimal) 8,230
So, you have several encoding available to represent a character (e.g. 10 in Decimal is represented as A in hexa) so it is very important to know when you are writing an unicode character, how receiving function decodes it. If it decodes as decimal value then you have to provide decimal value, if it accept hexadecimal then you have to provide hexadecimal.
In my case, setTextView() function accepts decimal encoded value but I was providing hexadecimal values so I was getting wrong character.
The quick fix shortcut in Android Studio is Alt + Enter by default.
Best not to ignore it as suggested by some, it seems to me. Use Android Studio to correct it (rather than actually typing in the character code), and the tool will replace the three dots with the three-dot unicode character. Won't be confusing to translators etc.
Related
I need help with creating a regex that removes all special characters, including commas, but not periods. What I have tried to do is escape all the characters, symbols and punctuation I do not want. It is not working as intended.
replace("[-\\[\\]^/,'*:.!><~##\$%+=?|\"\\\\()]+".toRegex(), "")
I removed the period and tested that too. It did not work.
replace("[-\\[\\]^/,'*:!><~##\$%+=?|\"\\\\()]+".toRegex(), "")
For example, lets take the String "if {cat.is} in a hat, then I eat green eggs and ham!".
I want the result
if {cat.is} in a hat then I eat green eggs and ham (comma and exclamation symbol removed)
Note: I want to keep brackets, although braces are OK to omit.
Anyone have a solution for this?
You can use
"""[\p{P}\p{S}&&[^.]]+""".toRegex()
The [\p{P}\p{S}&&[^.]]+ pattern matches one or more (+) punctuation proper (\p{P}) or symbol (\p{S}) chars other than dots (&&[^.], using character class subtraction).
See a Kotlin demo:
println("a-b)h.".replace("""[\p{P}\p{S}&&[^.]]+""".toRegex(), ""))
// => abh.
I've been trying to find a good way to be able to keep only emojis and letters in a given text, but every article I found, I didn't have success with .
I've tried to use regex, but seems that I can not make it work.
I've tried to use emoji4j but it seems that this library is working with emojis in this form ":)", which don't help me, because my emojis are groups of unicode characters.
The result I want is the following :
"This is. a text 👨👩👧👦,,1234" => "This is a text 👨👩👧👦"
"👨👩👧👦" => "👨👩👧👦"
"👨👩👧👦😃123abc👨👩👧👦" => "👨👩👧👦😃abc👨👩👧👦"
Here's the emoji regex : ?:[\u2700-\u27bf]|(?:[\ud83c\udde6-\ud83c\uddff]){2}|[\ud800\udc00-\uDBFF\uDFFF]|[\u2600-\u26FF])[\ufe0e\ufe0f]?(?:[\u0300-\u036f\ufe20-\ufe23\u20d0-\u20f0]|[\ud83c\udffb-\ud83c\udfff])?(?:\u200d(?:[^\ud800-\udfff]|(?:[\ud83c\udde6-\ud83c\uddff]){2}|[\ud800\udc00-\uDBFF\uDFFF]|[\u2600-\u26FF])[\ufe0e\ufe0f]?(?:[\u0300-\u036f\ufe20-\ufe23\u20d0-\u20f0]|[\ud83c\udffb-\ud83c\udfff])?)*|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|[\ud83c\udd70-\ud83c\udd71]|[\ud83c\udd7e-\ud83c\udd7f]|\ud83c\udd8e|[\ud83c\udd91-\ud83c\udd9a]|[\ud83c\udde6-\ud83c\uddff]|[\ud83c\ude01-\ud83c\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c\ude32-\ud83c\ude3a]|[\ud83c\ude50-\ud83c\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff] .
If I try something like :
val regex = "the_whole_regex_above | [^a-zA-Z]".toRegex()
myText.replace(regex,""), it won't replace anything, basically every character will pass
Basically I want to achieve pretty much the same thing as in this question, but using Kotlin.
You want to remove all punctuation, symbols (other than those used to form emojis) and digits.
To do that, you may use
myText = myText.replace("""[\p{N}\p{P}\p{S}&&[^\p{So}]]+""".toRegex(), "")
See the online Kotlin demo.
Details
[ - start of a character class that matches:
\p{N} - any Unicode digit
\p{P} - any Unicode punctuation proper
\p{S} - any Unicode symbol
&&[^\p{So}] - BUT the Unicode symbols belonging to Symbol, other Unicode category that are mostly used to form emojis
]+ - 1 or more occurrences.
I have declared a regex for password validation purposes in strings.xml file.
The criteria is
-should be atleast 8 characters
-should contain atleast one upper case letter
-should contain atleast one lower case letter
-should contain atleast one special character within these "##$%^+&="
So my whole regex looks like this now
^(?=.[0-9])(?=.[a-z])(?=.[A-Z])(?=.[##$%^+&=])(?=\S+$).{8,}$
But when I enter this, I get an error saying that & is
"Unescaped or non terminated character entity/reference"
So instead I used the escape sequence as & but the validation fails for &
I would b glad if anyone could help me out on this!!
Use * quantifers in the look-aheads. Right now, you check if 2nd character in the string meets your conditions. We need to test them all in the string.
^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*[##$%^+&=])(?=\S+$).{8,}$
Here is a demo.
EDIT
Since the regex is located inside the XML code, it should be properly encoded. Or, use it inside CDATA block.
Are you missing a parameter in your curly braces? The last bit "{8,}" seems off.
I am currently working on an app, and I have noticed that if I assign any element (e.g. Textview) a numeric id value (such as android:id="#+id/1") - I get an error and it will not compile until I add a letter to the id.
My questions are:
1) Why are we not able to use numeric values?
2) Are there any other requirements of R id's?
Just trying to better understand the logic behind this..
I have tried searching with not much luck...
Thanks
taken from http://docs.oracle.com/javase/tutorial/java/nutsandbolts/variables.html
Variable names are case-sensitive. A variable's name can be any legal identifier — an unlimited-length sequence of Unicode letters and digits, beginning with a letter, the dollar sign "$", or the underscore character "_"
i believe this goes the same for R.id's. meaning they have to start with a letter, "$" or "-".
for your second question , the convention for R.id is that it should be all lower case and no spaces between words just underscore "_".
To my understanding it is just Java convention. For example, you wouldn't call a variable "1" you would call it "one". It is so the compiler can differentiate between numbers and strings. I recommend just labeling the ids based on what it is going to do, makes it easier on you.
Variables can only start with letters or underscores. Other than that, there are no requirements.
I've just imported a chunk of text into a string element for a book app and I'm getting this error : An invalid XML character (Unicode:0x1f) was found in the element content of this document.
I looked it up here http://lwp.interglacial.com/appf_01.htm and the description says US (removing underlining doesnt seem to work).
What is this character so I can remove it if possible.
I'm very new to android so simple answers please :)
0x1f is a Unit Separator, an archaic way to separate fields in a text (Like , or Tab in CSV).
It is indeed not a valid text character in XML 1.0 (but allowed in XML 1.1). In a UTF-8 input string, you can also safely replace the byte 0x1f with 0x09(Tab) to work around the problem. Alternatively, declare the document as XML 1.1 and use an XML 1.1 parser.
US means "Unit separator". This is an invisible character, so you should open your text file with some text editor that can show the invisible characters and remove them. I think that probably Notepad++ will give you this functionality:
http://notepad-plus-plus.org/
Use Nodepad++ you will find the "Unit separator".
Like the picture: