Develop Reference

How to make a file object of a file in the drawable or raw folder?

I want to bundle an image with my application. I am planing to keep the image in the drawable or the raw folder. I wanted to know how to make a File object of this image?
Something like this:
File file = new File("fileurl");
Thank you.

Can you please try this one ?
try {
File mFile=new File("my file name");
InputStream inputStream = getResources().openRawResource(R.drawable.ic_launcher);
OutputStream out=new FileOutputStream(mFile);
byte buf[]=new byte[1024];
int len;
while((len=inputStream.read(buf))>0)
out.write(buf,0,len);
out.close();
inputStream.close();
}catch (Exception e){
e.printStackTrace();
}
Hope this will help you.

If you put your image resource inside your Raw folder within your workspace, you can access it inside your class by using :
getResources.openRawResources(R.raw.resource_id)
EDIT :
the above code will return an inputStream, to convert it to file, try this one :
inputStream = getResources.openRawResources(R.raw.resource_id)`
// write the inputStream to a FileOutputStream
File file = new File("fileurl");
outputStream = new FileOutputStream(file);
int read = 0;
byte[] bytes = new byte[1024];
while ((read = inputStream.read(bytes)) != -1) {
outputStream.write(bytes, 0, read);
}
outputStream.close();
inputStream.close();

Error while creating a new file in Android: FileNotFoundException: /test.png: open failed: EROFS (Read-only file system)

I have a png file in the raw folder. I get the inputStream using :
inputStream = getResources().openRawResource(R.raw.test);
I am trying to write this inputStream in a new file in an Android application. This is my code:
inputStream = getResources().openRawResource(R.raw.test);
File file = new File("/test.png");
outputStream = new FileOutputStream(file);
int read = 0;
byte[] bytes = new byte[1024*1024];
while ((read = inputStream.read(bytes)) != -1) {
outputStream.write(bytes, 0, read);
}
outputStream.close();
inputStream.close();
When I run the application, I get the following error in the logcat:
java.io.FileNotFoundException: /test.png: open failed: EROFS (Read-only file system)
Basically I want to create a File object so that I can send this to my server.
Thank you.

You will not have access to the file-system root, which is what you're attempting to access. For your purposes, you can write to internal files new File("test.png"), which places the file in the application-internal storage -- better yet, access it explicitly using getFilesDir().
For truly temporary files, you might want to look into getCacheDir() -- should you forget to delete those temporary files, the system will reclaim the space when it runs out of room.

Here's my solution:
inputStream = getResources().openRawResource(R.raw.earth);
file = new File(Environment.getExternalStorageDirectory() + File.separator + "test.png");
file.createNewFile();
outputStream = new FileOutputStream(file);
int read = 0;
byte[] bytes = new byte[1024*1024];
while ((read = inputStream.read(bytes)) != -1) {
outputStream.write(bytes, 0, read);
}
outputStream.close();
inputStream.close();

Android: Faster way to read/write a ZipInputStream?

I am currently writing an application that reads a zip file in my assets folder which contains a bunch of images. I am using the ZipInputStream API to read the contents and then writing each file to my: Environment.getExternalStorageDirectory() directory. I have everything working but the first time the application is run writing the images to the storage directory is INCREDIBLY slow. It takes about about 5 minutes to write my images to disc. My code looks like this:
ZipEntry ze = null;
ZipInputStream zin = new ZipInputStream(getAssets().open("myFile.zip"));
String location = getExternalStorageDirectory().getAbsolutePath() + "/test/images/";
//Loop through the zip file
while ((ze = zin.getNextEntry()) != null) {
File f = new File(location + ze.getName());
//Doesn't exist? Create to avoid FileNotFoundException
if(f.exists()) {
f.createNewFile();
}
FileOutputStream fout = new FileOutputStream(f);
//Read contents and then write to file
for (c = zin.read(); c != -1; c = zin.read()) {
fout.write(c);
}
}
fout.close();
zin.close();
The process of reading the contents of the particular entry and then writing to it is VERY slow. I am assuming it is more to do with reading than writing. I've read that you can use a byte[] array buffer to speed up the process but this does not seem to work! I tried this but it only read part of the file...
FileOutputStream fout = new FileOutputStream(f);
byte[] buffer = new byte[(int)ze.getSize()];
//Read contents and then write to file
for (c = zin.read(buffer); c != -1; c = zin.read(buffer)) {
fout.write(c);
}
}
When I do that I only get about 600-800 bytes written. Is there a way to speed this up?? Have I implemented the buffer array incorrectly??

I found a much better solution which implements the BuffererdOutputStream API. My solution looks like this:
byte[] buffer = new byte[2048];
FileOutputStream fout = new FileOutputStream(f);
BufferedOutputStream bos = new BufferedOutputStream(fout, buffer.length);
int size;
while ((size = zin.read(buffer, 0, buffer.length)) != -1) {
bos.write(buffer, 0, size);
}
//Close up shop..
bos.flush();
bos.close();
fout.flush();
fout.close();
zin.closeEntry();
I managed to increase my load time from anywhere from an average of about 5 minutes to about 5 (depending on how many images are in the package). Hope this helps!

Try use http://commons.apache.org/io/
like:
InputStream in = new URL( "http://jakarta.apache.org" ).openStream();
try {
System.out.println( IOUtils.toString( in ) );
} finally {
IOUtils.closeQuietly(in);
}

Playing video from app cache dir

Can anyone explain why downloading/playing a video from my applications cache directory does not work, but downloading/playing the same video from my sdcard does work?
Note: this video is being downloaded. I am saving to memory before calling VideoView.setVideoPath(...).
// Works
File file = new File(Environment.getExternalStorageDirectory(), "vid-test.3gp");
// Does not work
File file = new File(getCacheDir(), "vid-test.3gp");
In each case the file in question does exist.
If I attempt to call VideoView.setVideoURI(...) and "stream" the video to my VideoView, it is hit and miss whether or not it will work.
Can anyone explain this behavior?

It's probably a permission issue. Here is a working snipped:
InputStream in = connection.getInputStream();
File file = new File(getApplicationContext().getCacheDir() ,fileName);
if(!file.exists()){
file.setReadable(true);
file.createNewFile();
if (file.canWrite()){
FileOutputStream out = new FileOutputStream(file);
byte[] buffer = new byte[1024];
int len1 = 0;
while ( (len1 = in.read(buffer)) > 0 ) {
out.write(buffer,0, len1);
}
out.close();
}
in.close();
Runtime.getRuntime().exec("chmod 755 "+getCacheDir() +"/"+ fileName);
}

How to download dropbox files into my android application programmatically

i am trying to download files using getFileStream() in dropbox api but it returns file
information only,please help me to download file data.
here is code..
FileDownload fd = api.getFileStream("dropbox","/public/myfilename.rtf", null);
BufferedReader br = new BufferedReader(new InputStreamReader(fd.is));
BufferedWriter bw = new BufferedWriter(new FileWriter(newfile));
char[] buffer = new char[4096];
int read;
while (true) {
read = br.read(buffer);
if (read <= 0) {
break
}
bw.write(buffer, 0, read);
}

FileDownload fd = api.getFileStream("dropbox",path, null);
File f=new File("/sdcard/test.pdf");
OutputStream out=new FileOutputStream(f);
byte buf[]=new byte[1024];
int len;
while((len=fd.is.read(buf))>0)
out.write(buf,0,len);
out.close();
fd.is.close();
and mention your path like "/public/myfilename"
Here in my code i want to save it as a PDF so
i am creating one pdf and writing data to that.