android2.1 ListView reference - android

Hi i'm making a project and used a ListView in it. I've given it's code as
<ListView android:id="#android:id/android:list"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
</ListView>
I would need to work with the above list and i'm unable to refer it with
findViewById(#android:id/android/list);
even "R.id" isn't working.
I should use a OnClickListener().
Thank you in advance...

the correct way is :
getViewById(android.R.id.list);

try this it is useful
<ListView
android:id="#+id/list"
android:layout_width="fill_parent"
android:layout_height="wrap_content" >
</ListView>
and
findViewById(R.id.list);

Related

Activity having a list and other UI

I have an activity which has an independent ImageView and a List. Earlier, I have worked with activities which were simple list activities and the code worked fine. But now I am having an error which says
your content must have a ListView whose attribute is 'android.R.id.list'
The original code:
setArrayAdapter(ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, getResources().getStringArray(partsId[position])));
XML:
<ListView
android:id="#+android:id/list"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true" >
</ListView>
After some research, I came to the conclusion that may be I have to use a ListView and attach that attibute to my list. I did some change in the XML too. So revised code:
new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, getResources().getStringArray(partsId[position]));
lvParts.setAdapter(adapter);
XML:
<ListView
android:id="#+id/listView1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true" >
</ListView>
I think the reason this is happening is my Activity now has an ImageView also along with the List. Can anyone help?
android:id="#+android:id/list"
Change your listview id to above...
<ListView
android:id="#+android:id/list"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true" >
</ListView>
You have to extends your class to ListActivity instead of Activity

Android error: Error: No resource found that matches the given name

I am new to android, so maybe this question is naive.
I am trying to build a layout with two lists side by side. It works fine when I have one list, but when I add a second one, I get this error.
My view extends Activity and not ListActivity.
But I just can't figure out why my build fails with this error:
\main.xml:13: error: Error: No resource found that matches the given name (at 'id' with value '#android:id/selected_list').
\Android\android-sdk\tools\ant\build.xml:598: The following error occurred while executing this line:
\Android\android-sdk\tools\ant\build.xml:627: null returned: 1
This is what my main.xml looks like:
<ListView
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:id="#android:id/list"
android:layout_weight=".5"/>
<ListView
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:id="#android:id/selected_list"
android:layout_weight=".5"/>
Use "#+id/list" and "#+id/selected_list" instead of the "#android:id/...".
To find these id's in the code use:
findViewById(R.id.list);
or
findViewById(R.id.selected_list);
and make sure you import the R file: .R; and not com.android.R;
change your id's of list view
code:
<ListView
android:id="#+id/list"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_weight="1" >
</ListView>
<ListView
android:id="#+id/selected_list"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_weight="1" >
</ListView>

Android: id list view

I have a list view declared in my xml:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:orientation="vertical"
android:background="#F7EFE8">
<ListView android:id="#+id/android:list"
android:layout_width="fill_parent"
android:layout_height="fill_parent"/>
<TextView android:id="#+id/android:empty"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="#string/no_message"/>
</LinearLayout>
But when I try to declare/use it to java, the id is not found. But when i rename the list view to something else and try to use it i can see it "R.id._" but when R.id.list I can't find it. And If I didn't use the android:list there's an error that there should be a list view whose id is android:list. Any help here?
Your ListView object id should be specified either as android:id="#android:id/list"
ListView lv = (ListView) findViewById(android.R.id.list);
or it should have some other id like android:id="#+id/sampleList"
ListView lv = (ListView) findViewById(R.id.sampleList);
Check this : ListActivity
and list
Hope this would help.
In xml layout use,
<ListView
android:id="#+id/list"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
/>
In Java Code:
ListView listview=(ListView)findViewById(R.id.list);// it takes id of listview from xml
if you need to use android id for listview then replace your code as
<ListView
android:id="#+android:id/list"
android:layout_width="wrap_content"
android:layout_height="wrap_content" >
It may help you..
Try this: android:id="#+id/list"
Then clean project and rebuild.
In java, just call findViewById like this:
ListView lv = (ListView)findViewById(R.id.list);
Ref: http://developer.android.com/reference/android/view/View.html

Referencing a View in another XML file

I have a ListView in a file called a.xml.
<ListView
android:id="#+id/mylistview"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:layout_weight="1"
android:scrollbars="none"
android:layout_above="XYZ"
/>
In a.xml, I also include another file called b.xml.
<include android:id="#+id/bottombar" layout="#layout/b" />
For one of the settings of the ListView, I want to reference an id (XYZ) that exists in b.xml.
Is there a way I can do this?
I've tried the following:
<RelativeLayout
android:layout_width="fill_parent"
android:layout_height="fill_parent">
<include android:id="#+id/bottombar" layout="#layout/b" />
<ListView
android:id="#+id/mylistview"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:layout_weight="1"
android:scrollbars="none"
android:layout_above="#id/bottombar_background"
/>
</RelativeLayout>
Where #id/bottombar_background exists in #layout/b, but Eclipse throws "no resource" errors at me.
After you have used setContentView(R.layout.a) you should be able to use findViewById(R.id.my_id_in_b).
Use this syntax: android:layout_toLeftOf="#+id/my_id_from_b". It prevents any reference issues.
The plus in this instance tells the compiler to do a second pass on the layout, looking for that id on the second time through. Try it out - I know it works, as I use this syntax all the time.

List id not found: android:list

Iam trying to find the id for the listview, but it dosen't work just typing like this:
this.view = (ListView) findViewById(R.id.list);
R.id.list -> dosen't work, cause it can't find the id
Iam using my own custom made list.
<ListView
android:id="#+id/android:list"
android:layout_width="fill_parent"
android:layout_height="fill_parent" />
<ListView
android:id="#android:id/list"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
</ListView>
To obtain it:
findViewById(android.R.id.list);

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