Develop Reference

How to parse the String with custom tags?

Can anyone please tell me how to parse the below string?
"Testing the parser - <tag><name>ANKIT</name><id>7</id></tag> <tag><name>VIKRAM</name><id>8</id></tag>. Some random text here"
How can I get the name "ANKIT" which is inside the <tag><name> ?
I tried SAX parser.
I think the XML parsers works only when the starting line is <?xml version="1.0"?>.
Is my understanding correct?

Since your text isn't valid XML but reminds more structure like HTML which isn't as strict, consider using HTML parser like https://jsoup.org/. With this library your code can look like
String myXML = "Testing the parser - <tag><name>ANKIT</name><id>7</id></tag> <tag><name>VIKRAM</name><id>8</id></tag>. Some random text here";
Document doc = Jsoup.parse(myXML, "", Parser.xmlParser());
String tag_name_text = doc.select("tag name")//CSS query to find <name> elements inside <tag> elements
.first()//take first result
.text();//get text it would generate in browser
System.out.println(tag_name_text);
Output: ANKIT

If I understand you right, try
STRINGNAME.substring(STRINGNAME.lastIndexOf(""), STRINGNAME.indexOf(""));

Need to get the value of the element tag when parsing XML with SAX Parser

Grabbing an XML file off of the internet and feeding it's data into a database. Most of it works just fine. But I have a problem with xml tags having the same name but different values attached.
So, we have an xml file like this:
<Overtag>
<Tag> Name </Tag>
<SubTag> TextSubTag </SubTag>
<TagWithValue value="SomeValue"> TextTagWithValue </TagWithValue>
</Overtag>
<Overtag>...
I can set up a NodeList by Overtag. I can get a nodeist of Overtag's Children which I call Children.
So, I run this over a for loop - for(int nN=0; nN
I grab the Text of the Tags themselves:
String sTag = Children.item(nN).getNodeName();
I can even grab the text between the Tags:
Children.item(nN).getTextContent()
BUT I need to organize this text based on the value.
What command can I use to get "SomeValue" if nN = the childlist number for (in this case 2)?
As in: Children.item(nN).?

Found it...
if using NodeList to list out your xml tags, you need to return it to an element, then use getAttribute; so if the tag is (assuming your list with TagWithValue in it is a NodeList called Children):
Element eChild = (Element) Children.item(nN);
String sAtt = eChild.getAttribute("value");`
This will give you sAtt = "SomeValue". Sorry to waste space by posting then finding the answer two hours later; hopefully someone else finds this useful.

Getting Iframe src from a XML using Xpath

I am trying to get an iframe src from a XML for showing it in a WebView. For this i am using XPath for getting the value. Currently i am trying to parse this iframe. But i am not getting any value at all.
I have tried this XPath:
"//GoodreadsResponse/book/reviews_widget/iframe[#id=\"the_iframe\"]/#src/text()"
Is my XPath wrong for getting this iframe src? Full xml is here.

Perhaps another answer will correct me, but I don't think XPath will parse data within the CDATA section.
You can do this in two steps, however.
Grab the text section of //GoodreadsResponse/book/reviews_widget
This is the CDATA section before. It's not XML as it is (multiple root elements), but we can add a parent element and then parse it.
I will include a .NET snippet which hopefully you can convert.
XmlNode node = document.SelectSingleNode("//GoodreadsResponse/book/reviews_widget");
String cdataText = node.InnerText;
// The cdataText here isn't quite XML, as it has multiple roots.
// let's surround it by a single root element
String xml = "<root>" + cdataText + "</root>";
XmlDocument innerDoc = new XmlDocument();
innerDoc.LoadXml(xml);
XmlNode srcAttr = innerDoc.SelectSingleNode("/root/div/iframe[#id=\"the_iframe\"]/#src");
// This prints out https://www.goodreads.com/api/reviews_widget_iframe?did=DEVELOPER_ID&format=html&isbn=0307277674&links=660&min_rating=&review_back=fff&stars=000&text=000
Console.WriteLine(srcAttr.Value);

how to get the values from soap response in android?

the following xml tag for webservice response ,i dont know how to parse it..help me..
<NewDataSet>
<JOBLIST>
<CSIDNO>CS13224</CSIDNO>
<PName>Selva</PName>
<HouseID>G 34</HouseID>
<NAME>Dilipan</NAME>
<Address>Coimbatore</Address>
</JOBLIST>
<JOBLIST>
<CSIDNO>CS13224</CSIDNO>
<PName>Selva</PName>
<HouseID>G 35</HouseID>
<NAME>Kanrupannan</NAME>
<Address>Coimbatore</Address>
</JOBLIST>
</NewDataSet>
i am using the following java code .....
for(int i=0;i<result.getPropertyCount();i++)
{
SoapObject ob=(SoapObject)result.getProperty(i);
homeid[i]=String.valueOf(ob.getProperty("HouseID"));
namearr[i]=String.valueOf(ob.getProperty("NAME"));
address[i]=String.valueOf(ob.getProperty("Address"));
csidno[i]=String.valueOf(ob.getProperty("CSIDNO"));
}
how to get the values form xml tag..

Why using Soap there are different kinds of parsing methods you can use one of them. Parsing methods are SAXParser, Json parser, DOM parser, XML pull parser. In yourt situation SAX parser will be good to parse. see this and this tutorial. It will help you in parsing the xml you are receiving. Let me know if they helps you

Its pretty simple you have to get the respose as a string and use pattern matches to extract the detail you needed>Please see this post hope it helps you and you understand it.
String r = NameArray.columncount("userid", limitstart, loadNumber,loggername);
String temp = r.replaceAll(";\\s", ",").replaceAll("string=", " ")
.replace("anyType{", "").replace(",}", "");
enter code here
check this link for step by step instruction
http://amalan008.blog.com/2013/02/07/how-to-process-an-array-returned-by-a-wsdl-android/

JSON parsing in android

I am new to android development,
I want to parse xml i have tried using sax xml parser but as it consist of "&" in it so that URL part is not getting completed parsed.SAX parser parsing upto "&' the rest of the part it is neglacting so i have to use json parser.
But for json parser i need to parse xml into json then from json to string which can be used by the JSON parser.
if any one is having idea wheather it will solve my problem of "&" in xml?
thnx for any help.......

As I see, you want to parse non standard xml. If you can change xml structure, use CDATA for links. If not, you can do some hack, like replace '&' before parsing onto some unique string. And after successful parsing you can replace it back.
DEMO:
String xmlString = "<link>linkwith&</link>"; //some xml with &
xmlString = xmlString.replaceAll("[&]", ".!.!.!.");
XMLHandler xml = new XMLHandler(); //your sax parse handler
xml.parseXML(output); //your parse function
After that, you get your parsed link somehow and make replace back:
String parsedLink = "linkwith.!.!.!.";
parsedLink = parsedLink.replaceAll(".!.!.!.", "&");