In my android application I want to redirect the users to my twitter profile page and I use this code :
Inrent i : new Intent(Intent.ACTION_VIEW,Uri.parse(''https://www.twitter.com/MYUSER));
startActivity(i);
If I choose the browser it work fine but if I choose twitter application it show a Toast "Impossible to.complete the action". How can I resolve this problem ? Thanks
I believe you are missing the setData() method:
String url = "http://twitter.com";
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);
Please read more here: How can I open a URL in Android's web browser from my application?
Let me know if this helps!
Related
I am working on my app which will show my website and i am getting intent error in my Android Webview app whenever I try to open Instagram profile. I want it to be open in my Instagram app can someone help me out by code please
Please help me out Click here to see the error I got
Seems that url you created could be invalid, try to create your intent with urls like these:
Uri uri = Uri.parse("http://instagram.com/_u/xxx");
Intent likeIng = new Intent(Intent.ACTION_VIEW, uri);
likeIng.setPackage("com.instagram.android");
try {
//instagram app exists on device
startActivity(likeIng);
} catch (ActivityNotFoundException e) {
//instagram app does not exist on device, using browser
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("http://instagram.com/xxx")));
}
Can anyone help me in Code for opening links in external browsers or other Android app?
Now the case is the link is opening in the app itself. But if the link belongs to an android app its not opening. It's showing install the Android app.
So I want that if the link can be opened in browsers, then it will ask from a list of browsers. Or if the links belongs to an app it must show the app in the list too.
Something like this could work
Intent browserIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse("http://www.google.com"));
startActivity(browserIntent);
As #zain posted ago you can use.
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("http://www.stackoverflow.com"));
startActivity(intent);
But if you have more then one browser installed in device and want to choose from one of them. Use intent chooser like this
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("http://www.stackoverflow.com"));
// Always use string resources for UI text. This says something like "Share this photo with"
String title = getResources().getText(R.string.chooser_title);
// Create and start the chooser
Intent chooser = Intent.createChooser(intent, title);
startActivity(chooser);
refer from here
Show browser list when opening a link in android
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.google.co.in/"));
String title = "Complete Action Using";
Intent chooser = Intent.createChooser(intent, title);
startActivity(chooser);
If you are in a WebView in your App, and on clivking a link there, if the app opens the link in the App Itself, Then possibly u should have overridden this method.
myWebView.setWebViewClient(new WebViewClient()
{
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url)
{
//view.loadUrl(url);
return false;
}
});
The return of false should ask the user, where to Open the link. With the browsers installed in the mobile
How can I open Facebook page using insalled Facebook app? Exactly page, not profile, because fb://profile works fine.
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("fb://page/page_id")));
Seems like fb://page isn't working, because it's just opens feed.
fb://page/{id} is the way to go:
final String url = "fb://page/" + facebookID
Intent facebookAppIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
facebookAppIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET);
startActivity(facebookAppIntent);
Are you sure you are using the ID number of your Facebook page and NOT the username?
What I mean is that if, for example, you want to open the Facebook page of Facebook itself (i.e. https://www.facebook.com/facebook) you have to use:
fb://page/20531316728
Since 20531316728 is the ID of the Facebook page (while facebook is the username).
If you don't know the ID of your Facebook page, you can retrieve it opening:
https://graph.facebook.com/{username}
Make Sure That You are Using the page id of your page correctly
Intent intent = new Intent(Intent.ACTION_VIEW, Uri
.parse("fb://page/YOUR PAGE ID"));
startActivity(intent);
i think u should use
https://www.facebook.com/
instead of fb://page/ or fb://profile or something.
I hope it's helpful!
I'm working on an application where I need to integrate the social functionality of the different social networks: Facebook, Twitter, Google+.
For now, in Facebook and Twitter i'm recognized if the user has a native application and if he does, I'm opening it and show him my fan page.
For Twitter I use the next code:
try {
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("twitter://user?screen_name=[user_name]"));
startActivity(intent);
}catch (Exception e) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse("https://twitter.com/#!/[user_name]")));
}
And for Facebook the next code:
try{
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://profile/" + PROFILE_FACEBOOK_APP_ID));
startActivity(intent);
}catch(Exception e){
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.facebook.com/UserNamePage")));
}
Now I want to do the same thing for Google+. I saw that I can browse to my fan page with the next Url https://plus.google.com/MY_PAGE_ID/, but it keep asking me if I want to open it with Google+ application or with the browser, and I want that he will open it with the application automatically, without asking the user.
Is there a simple way to do this?
Thanks.
Found a solution:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.google.android.apps.plus",
"com.google.android.apps.plus.phone.UrlGatewayActivity");
intent.putExtra("customAppUri", "FAN_PAGE_ID");
startActivity(intent);
I think this is quite safe, because we do not need to specify the component, just the google+ app package name:
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse("https://plus.google.com/[Google+ID]/"));
intent.setPackage("com.google.android.apps.plus"); // don't open the browser, make sure it opens in Google+ app
startActivity(intent);
Unknown if google plus needs some other information in the Intent but as general Android solution you can explicitly set the target. You will need the package name of google+.
More info here: http://developer.android.com/reference/android/content/Intent.html#setPackage%28java.lang.String%29
For example:
Intent.setPackage("com.google.android.apps.plus"); //Don't know the exact package name
Hi
I want to write an app to call default browser and redirect to a designated url.
Any suggestion to 1)call the default browser, 2)redirect to a designated url.
Thanks
you just want to launch an ACTION_VIEW intent with the Uri of the webpage as your data element :
Intent httpIntent = new Intent(Intent.ACTION_VIEW);
httpIntent.setData(Uri.parse("http://www.bbc.co.uk"));
startActivity(httpIntent);
To open the default browser use an Intent with the action VIEW. To tell the browser which page to load us the data-part of the Intent.
Example:
Intent browse = new Intent(Intent.ACTION_VIEW, Uri.parse("http://stackoverflow.com"));
startActivity(browse);
Since this is a basic task in Android you might want to read some basics about Intents in Android.