I want to get the CreateDate value from xml file
the xml file is like this way.
<d:CreateDate m:type="Edm.DateTime">2012-03-18T15:11:30.403</d:CreateDate>
I created JSONObject as
JSONObject json=new WCFServices().getWhatsNew();//i get the json object WCFServices class.
JSONArray whatsnew= json.getJSONArray("d");
String CreateDate= c.getString("CreateDate");
if i try to print the value it gives me output as:
/Date(1330041600000)/
I want to get the value as like 2012-03-18T15:11:30.403
how to get it ?
I think your output is in epoch date format. So you need to convert it to normal date time. Try this for it..
public String normal_date_time(String epoch_date)
{
try
{
long epoch = Long.parseLong( epoch_date );
String dateFormat = "dd/MM/yyyy HH:mm:ss.SSS";
SimpleDateFormat formatter = new SimpleDateFormat(dateFormat);
Calendar calendar = Calendar.getInstance();
calendar.setTimeInMillis(epoch);
String formated_date = formatter.format(calendar.getTime());
Log.d("Date", formated_date);
return formated_date;
}
catch (Exception e)
{
// TODO: handle exception
return null;
}
You can find more about DateFormat by following links, It will help you to retrieve output in different formats.
http://developer.android.com/reference/java/text/SimpleDateFormat.html
http://developer.android.com/reference/android/text/format/DateFormat.html
Hope this will help you..And don't forget to accept this if it help you.
Thanks...
Related
I am getting Time from an api in this format
"2018-03-07T11:19:54.686Z" ..... How to convert this String data to mm-dd-yyyy date format in android.
SimpleDateFormat format = new SimpleDateFormat(" MM,dd,yy");
String date = format.format(Date.parse(data));
I have tried using the above two but there is a parse error.
First you have to parse the given date "2018-03-07T11:19:54.686Z" in the same format and then you can apply formatting with the desired format.
SimpleDateFormat parseDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
String date = format.format(parseDateFormat.parse(data));
you used below code and show your format according to date.
String date="2018-03-07T11:19:54.686Z";
SimpleDateFormat parseDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
DateFormat formatdate = new SimpleDateFormat("MM,dd,yy");//if show mm-dd-yy
try {
Date date1=parseDateFormat.parse(date);
Log.d("New Date",formatdate.format(date1));
} catch (ParseException e) {
e.printStackTrace();
}
I am accessing Dot net web services and using Ksoap library as my web services are Soap based.
Basically i want to save the dates and show them in list at it is. I do not want the date conversion to any specific region or time zone.
my dates which are coming from services has following pattern please have an example of threee different fields.
patient DOB = 1974-05-18T00:00:00
Collection Date = 2016-07-27T11:00:00
attachment Date uploaded = 2016-09-28T10:19:23.48
and I am using following method to convert them
public static Date convertStringToDate(String date,String dateFormat)throws Exception {
Date output = null;
SimpleDateFormat simpleDateFormat = new SimpleDateFormat(dateFormat);
try {
simpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
output = simpleDateFormat.parse(date);
} catch (ParseException e) {
throw e;
}
return output;
}
where dateFormat is "yyyy-MM-dd" and whereas date could be any string shown above in above example.
Problems:
1> When I convert date using that method I sometimes get accurate time and date
2> Some times I observed slightly changed in time , like 2 to 7 hours shift in time. this is due to time zone conversion
3> Some times I observe a whol day shift. Let suppose if the date that was coming from server was 2016-09-28T10:19:23.48 after conversion it becomes 2016-09-27 to me .
Whats wrong ? How can I simple show date as it is from web services How can i get that except saving dates directly in strings and showing those strings by splitting.
Please help me.
Update
i am converting back my date object back to string to show on UI in following manner
public static String convertDateToString(Date date,String dateFormat)throws Exception {
String output = "";
try {
SimpleDateFormat simpleDateFormat = new SimpleDateFormat(dateFormat);
simpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
output = simpleDateFormat.format(date);
} catch (Exception e) {
throw e;
}
return output;
}
To achieve that, you need to know the actual timezone and dateformat of the server. If you knew it already, the following snippet would be useful
public static String parseDateFormat(String incomingDate, String inputFormat, String outputFormat) {
String finalDate = null;
SimpleDateFormat input = new SimpleDateFormat(inputFormat); // server date format
input.setTimeZone(TimeZone.getTimeZone(SERVER_TIMEZONE)); // timezone set in the server
SimpleDateFormat output = new SimpleDateFormat(outputFormat); // format to which you want to convert
output.setTimeZone(Constants.UTC_TIMEZONE); // timezone to which you want to convert
try {
Date realDate = input.parse(incomingDate);
finalDate = output.format(realDate);
} catch (ParseException e) {
Log.e("Error", e.getMessage(),e);
}
return finalDate;
}
Setting the time zone on the date format adds an offset to the time stamp. And your server's time format doesn't include any time zone.
Remove the line simpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
You generally need to set the time zone only when you intend to account for the difference between locales.
I was found many solution but its not working for me.
I am trying to parse date to user selected date format.
I was getting date from server in this format 2016-06-30T00:00:00Z UTC Timezone
Now I want to Parse it in User selected format for e.g MM/dd/yyyy
How Can i do that.? I was found many solution but its not working for me.
To get date into a particular format, first you have to parse the date string into it's given format and there you will get Date object. Second, you can convert the date object into a desired format.
private String getFormattedDate(String strDate) {
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
Date d= (Date)formatter.parse(strDate);
SimpleDateFormat fmtOut = new SimpleDateFormat("MM/dd/yyyy");
return fmtOut.format(date);
}
This function help to convert any type of string date in any formate
public String getFormatedDate(String dateString, String format, String currentFormat) {
SimpleDateFormat sdf = new SimpleDateFormat(currentFormat, Locale.ENGLISH);
try {
Date date = sdf.parse(dateString);
String formated = new SimpleDateFormat(format).format(date);
return formated;
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
I have a string which returns the date and time as 2012-11-08 12:45:30 . I need to get the date and time in separate strings and then the date has to be shown in the format which is there in the Phone's Date and Time settings.
Here is the code which I have tried so far:
date value from db is 2012-11-08
I am getting the date format in phone's settings as
String datefrmt = Settings.System.getString(
context.getContentResolver(), Settings.System.DATE_FORMAT);
the code to apply this format to the obtained date from db is:
SimpleDateFormat sdf = new SimpleDateFormat(datefrmt);
java.util.Date date_1 = sdf.parse("2012-11-08");
String s = sdf.format(date_1);
I am getting the month and day properly but the year its returning something randomly and thats not a correct value. Can anyone please guide me where am I going wrong. Thanks
If you have 2012-11-08 12:45:30 string and you want to parse it to Date object and change its format to another (system format for example or 2012-11-08 format):
try {
String yourString="2012-11-08 12:45:30";
//first we parse input date string and create Date object
String inputDateString ="yyyy-dd-MM hh:mm:ss";
SimpleDateFormat inputDateFormat = new SimpleDateFormat(inputDateString);
java.util.Date date = inputDateFormat.parse(yourString);
//log
Log.e(getClass().getName(), inputDateFormat.format(date));
//create system date format
String dateformt = Settings.System.getString( this.getContentResolver(), Settings.System.DATE_FORMAT);
//if its for some reason==null let it be "yyyy-dd-MM"
if(dateformt==null){
dateformt="yyyy-dd-MM";
}
SimpleDateFormat systemDateFormat = new SimpleDateFormat(dateformt);
String outputString = systemDateFormat.format(date);
//log
Log.e(getClass().getName(), outputString);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
you can use the simpleDateFormat as:
SimpleDateFormat simpDate = new SimpleDateFormat(datefrmt,
Locale.ENGLISH);
String s = simpDate.format(new Date());
for reference, you can refer to developer site:
for more information refer this link
Since your DB date is in yyyy-MM-dd, don't use the dynamic format to get the date, otherwise it will crash(throw parse exception), instead use the static format as below to get the date. You may use the dynamic format to convert the string as below:
//use static format to convert into date from static formatted data in db
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd");
java.util.Date date_1 = sdf1.parse("2012-11-08");//got the date
//use the dynamic format to convert into string
SimpleDateFormat sdf2 = new SimpleDateFormat(datefrmt);
String s = sdf2.format(date_1);
Since final String format = Settings.System.getString(getActivity().getContentResolver(), Settings.System.DATE_FORMAT);//may be NULL
So I customized my function as below for general purposes
#SuppressLint("SimpleDateFormat")
public String getCurrentShortDateFormat() {
final String[] SFs = new String [] {
"MM/dd/yyyy",
"dd/MM/yyyy",
"yyyy/MM/dd"
};
final Date date = new Date(24638400000L);//24638400000=Oct/13/1970; 0==Jan/1/1970
java.text.DateFormat shortDateFormat = android.text.format.DateFormat.getDateFormat(getActivity().getApplicationContext());
String current = shortDateFormat.format(date);
SimpleDateFormat which = new SimpleDateFormat();
for (int i = 0; i < SFs.length; i++) {
which.applyPattern(SFs[i]);
if (which.format(date).compareTo(current)==0)
return SFs[i];
}
return null;
}
#Override
public void onResume() {
super.onResume();
Log.d(LOG_TAG, "----- onResume.CurrentShortDateFormat-----" + getCurrentShortDateFormat());
}
I want to convert date time object in java to json string in format as below:
{"date":"/Date(18000000+0000)/"}
I did like this but it didn't give me the format i desired:
JSONObject object = new JSONObject();
object.put("date",new Date());
and the result of object.toString()
{"date":"Fri May 04 11:22:32 GMT+07:00 2012"}
i want the string "Fri May 04 11:22:32 GMT+07:00 2012" transform to "/Date(18000000+0000)/" (18000000+0000 here is just a example).
Thanks for your help.
Here is my solution, although it is not a good way, but I finally find a workable solution.
SimpleDateFormat format = new SimpleDateFormat("Z");
Date date = new Date();
JSONObject object = new JSONObject();
object.put("date", "/Date(" + String.valueOf(date.getTime()) + format.format(date) + ")/");
public static String convertToJsonDateTime(String javaDate)
{
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-mm-dd HH:mm:ss");
Date currentDate = null;
try {
currentDate = dateFormat.parse(javaDate);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
long time =currentDate.getTime();
return "\\/Date("+time+"+0000)\\/";
}
My solution : I think this is the simplest Way
DateFormat dateFormat=new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
yourJsonObject.accumulate("yourDateVarible",dateFormat.format(new Date()));
The date format that you want is /Date(<epoch time><Time Zone>)/.
You can get the epoch time in java using long epoch = System.currentTimeMillis()/1000;(found at this link) and the time zone you can get by using the date and time patteren as Z. Then combine all the strings into one and store it to the Json Object.
Other possibility is that the time you are getting from iOS device may be of the pattern yyMMddHHmmssZ as got from here. Check the output on the iOS device at different times and identify the correct pattern.
From json.org's description of JSONObject:
The values can be any of these types: Boolean, JSONArray, JSONObject, Number, and String, or the JSONObject.NULL object.
This library doesn't support the "complex" mapping of a Date to a JSON representation. You'll have to do it yourself. You may find something like SimpleDateFormat helpful.
If your format like this -> "DDmmYYYY+HHMM"
DD -> Day (2 Digit)
mm -> Month (2 Digit)
YYYY -> Year (4 Digit)
HH -> Hour
MM -> Minute
Than you can do like this:
SimpleDateFormat format = new SimpleDateFormat("DDmmYYYY+HHMM");
JSONObject object = new JSONObject();
object.put("date", "/Date(" + format.format(new Date()) + ")/");
I suppose that's a representation of ISO international date-time format.
YYYYMMDD+HHMM
I think now you will be able to create that string
may be like,
Date d=new Date();
String tmp="";
tmp="/Date("d.getYear()+""+d.getMonth()+""+d.getDate()+"+"+d.getHours()+""+d.getMinutes()+")/";
Upgrade one of the previous answer:
public static String convertToJsonDateTime(Date dateToConvert) {
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-mm-dd HH:mm:ss");
long time = dateToConvert.getTime();
return "/Date(" + time + "+0000)/";
}