Is there any way to get device Id using MIT App inventor?
I am using Activity starter from other stuff and setting properties like this:
Action: android.intent.action.ACTION_MAIN
Activity Class: TelephonyManager
Activity Package: android.telephony
Is this the correct process for getting the device id?
as Gary already mentioned, this is currently not possible with AI
EDIT: However, you can identify a user with OAuth, see an example here http://puravidaapps.com/taifunOA.php. The user can authorize the app to get his email address for identification.
UPDATE: now with the new Extension feature, you can use an extension to get this information, see also my answer here.
Related
The documentation link: https://developer.squareup.com/docs/pos-api/build-mobile-web#step-5-test-your-code suggest straight forward code like this:
<a href="intent:#Intent;
action=com.squareup.pos.action.CHARGE;
package=com.squareup;
S.browser_fallback_url=https://my.website.com/index.html;
S.com.squareup.pos.WEB_CALLBACK_URI=https://my.website.com/index.html;
S.com.squareup.pos.CLIENT_ID=sq0ids-yourClientId;
S.com.squareup.pos.API_VERSION=v2.0;
i.com.squareup.pos.TOTAL_AMOUNT=100;
S.com.squareup.pos.CURRENCY_CODE=USD;
S.com.squareup.pos.TENDER_TYPES=com.squareup.pos.TENDER_CARD,com.squareup.pos.TENDER_CASH;
end">Start Transaction</a>
I tested it and it does not open any link, my devide already have app installed.
When I try this code:
Take a QR code 2
It open play store app with squareup pos app information, I need to directly open the app and not play store screen of the app, is there any way?
*UPDATE:
I got transactions to work after adding S.com.squareup.pos.LOCATION_ID={{ my_location_id }}. The location ID can be found in Square Developer Portal > Locations. Also if the POS app is passcode protected, you have to open and login with passcode before sending transaction.
*END UPDATE
I've been working through this same issue. I still haven't gotten a transaction to work, but have at least gotten the app to open.
Make sure the CLIENT ID is your production application ID. NOT sandbox.
The WEB_CALLBACK_URI needs to match the Web Callback URL defined in your Square Developer Portal > Point Of Sale API.
I hope this helps. If you do figure this out and get transactions to work, please post your solution for me and others who are sure to run into this issue since the documentation is lacking.
I'm making a pair of website-based apps for both Android and iOS interfaces, and I'm struggling with a part of it. Perhaps you guys could help me out!
I'm using Android Studio and Xcode, and launching the website through WebKit and WK WebView respectively. It's super simple, just an app which calls a website into it directly. No external navigation, nothing but a full-page website. And this part is working great!
But I do have one problem! I don't want my users to get consistently logged out if they close the app, or after a few hours of not using it. I'd like it to stay logged in for them, or to automatically log-in when they use it.
The maker of the website has given me a way to do this through the URL.
Basically, my URL currently is set up like "https://URL.com/x/y/z" and it goes to the website, and that is great, but I need to set it up to be "https://url.com/x/y/z/[insert user's IMEI or UDID here]". That unique ID from their Android device will keep them logged in. I've tested it using my own device with my own IMEI and it works great, but obviously using one specific identifier for everyone will not work. I just need it to call the specific user's IMEI or UDID into the URL, to complete it.
How should I go about this?
I am assuming that you are talking about an Android app that visualizes a website in an activity. On Android, you can retrieve the device's IMEI OR MEID string by calling:
android.telephony.TelephonyManager.getDeviceId().
But be warned, this requires that you add a permission to your manifest:
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
You should inform your users why you are requesting this permission.
For iOS/Xcode, you can get the device UUID via UIDevice:
// Swift 4
let uuid = UIDevice.current.identifierForVendor!.uuidString
If you are targeting iOS 11 or newer, Apple introduced Device Check to get a device specific token. I personally haven't used it, but it sounds like it's use case is similar to what you're looking for.
Update:
From your comment, here is how'd you include it in the url string.
let urlString = "url.com/x/y/z/" + uuid
I want to make an app which will pay users money on downloading another apps from within my app, so how can i track that user had downloaded that app or not, and i want to make sure that after user registered in the downloaded app then only he/she is going to get money, so how can i do this.
Some examples of these types of apps are : Ladooo app, TaskBucks App, Pokkt App,
I found following links which helped me somehow but it is not clear :
http://android-developers.blogspot.in/2010/12/analytics-for-android-apps.html
https://developers.google.com/analytics/devguides/collection/android/v4/
you can retrieve the list of installed applications in the following manner
// retrieve the list of installed applications
List<ApplicationInfo> apps = mPm.getInstalledApplications(0);
can get the package name of the app through
String pkg = apps.get(i).packageName;
I know this is not the full answer but i hope this helps
Not Sure About your requirement or not have idea about playstore api but can give simple logic for this, hope it will help.
When any user share or refer the application for download to other user, create one unique id from the serverside(combination with user who refer) in simple word redirect url to playstore with uniqueid and share that link with intent.
When user register you can check or if redirect url for playstore is via your server than you can send money or points when redirect link callback on server.
check this
or you can refer some codes on github:
here or here
I need to verify the spam score of mobile numbers using Truecaller API .I found documentation here . In the API URL , I need to send a APPKEY , But how to get that ? there is no registration page for Truecaller API .
https://api.truecaller.com/v1.0/search.json?userKey=APPKEY&phone=NUMBER
Any help will be appreciated...
You should Read this Document for Name Search API
it Says that....
The one thing to keep in mind is that all requests to our API require
authentication. For that, you will need to use a User Key (userKey)
along with your requests. These access details basically associate,
your server, script or program with a specific application. All
requests to the API must be made over SSL (https:// not http://).
It means you have registered Truecaller developer account then Do Login and get your Access Key(USER KEY) and pass it everytime you request to access API..
But I Think Truecaller API is not accessible for public users...
Read This Article for More Details : http://www.3scale.net/2013/05/truecaller-api-search-among-over-600-million-phone-numbers-worldwide/
Why don't you try this?
callerpy
Here is the explanation from the developer:
Truecaller Name Retriever.
Since my request for the API was rejected, I commenced using python parsing libraries.
Callerpy emulates the process one would encounter if using a web-browser.
I tried it, and it works like a charm from the command line.
I am developing a android application for a exploratory project using client server architecture. I thought of using UDID but now its replaced by new "Advertising ID", but in my application, i need to store data about user on server with some unique ID per device.
so what should i use as alternative to UDID?
i checked open UDID but that is also outdated now.
Using "advertising ID" imposes problem of consistency when user clears/resets his advertising ID.
Request the community to help me out.
There is also identifierForVendor see more in apple docs
I don't have much idea about Android :
But Check these :
GeneratingDeviceSpecificSerialNo && HEre
In IOS :
-identifierForVendor
ID that is identical between apps from the same developer.
Erased with removal of the last app for that Team ID.
Backed up.
For more Info Here
You can register the device with the Google Cloud Messaging platform.
When you register the device correctly this gives you back a register id that´s unique for every device.
http://developer.android.com/google/gcm/client.html
UPDATE
You can also, if you haven't tried it out yet, to user the telephony manager to get the device identifier.
TelephonyManager tManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
String uuid = tManager.getDeviceId();
On iOS you can try this
NSString *UUID = [[NSUUID UUID] UUIDString];
This will give you a unique id per app.