Showing result in tabhost on android eclipse - android

The above image is just adding two values and displaying the result on the below textview.
But i need to show that answer on the first tab(ie.Tab_1) of tabhost on next screen.
How to do this?
.java class
public class Demo_webserviceActivity extends Activity
{
/** Called when the activity is first created. */
private static String NAMESPACE = "http://tempuri.org/";
private static String METHOD_NAME = "FahrenheitToCelsius";
private static String SOAP_ACTION = "http://tempuri.org/FahrenheitToCelsius";
private static String URL = "http://www.w3schools.com/webservices/tempconvert.asmx?WSDL";
Button btnFar;
EditText txtFar;
#Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
btnFar = (Button)findViewById(R.id.btnFar);
txtFar = (EditText)findViewById(R.id.txtFar);
btnFar.setOnClickListener(new View.OnClickListener()
{
public void onClick(View v)
{
String b;
//Initialize soap request + add parameters
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
//Use this to add parameters
request.addProperty("Fahrenheit",txtFar.getText().toString());
//Declare the version of the SOAP request
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
envelope.dotNet = true;
try
{
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
//this is the actual part that will call the webservice
androidHttpTransport.call(SOAP_ACTION, envelope);
// Get the SoapResult from the envelope body.
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
if(result != null)
{
//Get the first property and change the label text
b = result.toString();
Intent i = new Intent(getApplicationContext(),Activity2.class);
i.putExtra("gotonextpage", b.toString());
startActivity(i);
}
else
{
Toast.makeText(getApplicationContext(), "No Response",Toast.LENGTH_SHORT).show();
}
}
catch (Exception e)
{
e.printStackTrace();
}
}
});
}
}
NOTE : This source is actually consuming a webservice from android and showing the result by SOAP method
Thanks a lot.

You can use Shared preferences to store values, then you can access it in any activity of your project:
follow this link

Related

Android Web Service connenction Error

I created Java web services and trying to connect with android code.I am getting the service running but android app is showing error in soap object creating for namespace and method name.I did all the changes and everything is correct namespace,method name,URL all is correct.But I don't know what is wrong can anyone help me out...!
My android code is----->
showing error in
-"SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);"
public class RetailerActivity extends Activity {
private static final String SOAP_ACTION = "urn:training/searchCompanyInfo";
private static final String METHOD_NAME = "searchCompanyInfo";
private static final String NAMESPACE = "urn:training/";
private static final String URL = "http://localhost/attest/CompanyInfoService?wsdl";
/** Called when the activity is first created. */
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
System.out.println(NAMESPACE);
System.out.println(METHOD_NAME);
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
HttpTransportSE ht = new HttpTransportSE(URL);
try {
ht.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
SoapPrimitive s = response;
String str = s.toString();
String resultArr[] = str.split("&");//Result string will split & store in an array
TextView tv = new TextView(this);
for(int i = 0; i<resultArr.length;i++){
tv.append(resultArr[i]+"\n\n");
}
setContentView(tv);
} catch (Exception e) {
e.printStackTrace();
}
}
}
In Android, You cannot perform network operation on the main thread, You need to execute your soap request in a background thread. Please read up on AsyncTask.

cant parse xml using a KSOAP2

I have connected to the asp.net Service using Ksoap2 and it connects fine, but one thing is that i get the response back in XML. Is there anyway i can get it to display in normal text.
This is the code i have used
public class AndroidWebService extends Activity {
/** Called when the activity is first created. */
private static String SOAP_ACTION = "http://tempuri.org/GetHelpDeskCalls";
private static String NAMESPACE = "http://tempuri.org/";
private static String METHOD_NAME = "GetHelpDeskCalls";
static final String URL = "https://198.125.364:8080/AndroidServices/Service1.asmx";
Button getData;
EditText userID;
TextView data;
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.helpdesk);
getData = (Button) findViewById(R.id.button1);
userID = (EditText) findViewById(R.id.txtFar);
data = (TextView) findViewById(R.id.textView1);
Thread nT = new Thread() {
#Override
public void run() {
getData.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
SoapObject request = new SoapObject(NAMESPACE,
METHOD_NAME);
request.addProperty("userID", userID.getText()
.toString());
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
try {
HttpTransportSE androidHttpTransport = new HttpTransportSE(
URL);
// androidHttpTransport.call(SOAP_ACTION, envelope);
androidHttpTransport.debug = true;
androidHttpTransport.call(SOAP_ACTION, envelope);
final String ss = androidHttpTransport.responseDump;
// final SoapObject response = (SoapObject) envelope
// .getResponse();
runOnUiThread(new Runnable() {
public void run() {
data.setText(ss.toString());
}
});
} catch (Exception e) {
data.setText("Error");
}
}
});
}
};
nT.start();
}
}
There is a neat website called google, it does wonders.
since you seem to be lazy there are 3 basic xml parsing methods you can use
SAX parser,
DOM parser,
XML pull parser
read about xml parsing here

Ksoap2 .NET web service connection

http://i.stack.imgur.com/pK9rm.png
http://i.stack.imgur.com/27Qj0.png
I want to connection web service using ksoap2,I have a working example but how can I integrate my application?
public class WebServiceDemoActivity extends Activity
{
private static String SOAP_ACTION = "http://tempuri.org/UrunleriListele";
private static String NAMESPACE = "http://tempuri.org/";
private static String METHOD_NAME = "UrunleriListele";
private static String URL = "http://services.annebebekavm.com/Service1.asmx?WSDL";
Button btnFar,btnCel,btnClear;
EditText txtFar,txtCel;
#Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
btnFar = (Button)findViewById(R.id.btnFar);
txtFar = (EditText)findViewById(R.id.txtFar);
btnFar.setOnClickListener(new View.OnClickListener()
{
#Override
public void onClick(View v)
{
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("Fahrenheit",txtFar.getText().toString());
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
envelope.dotNet = true;
try {
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapObject result = (SoapObject)envelope.bodyIn;
if(result != null)
{
txtFar.setText(result.getProperty(0).toString());
}
else
{
Toast.makeText(getApplicationContext(), "No Response",Toast.LENGTH_LONG).show();
}
} catch (Exception e) {
e.printStackTrace();
}
}
});
}
}
Please reconsider to use another client
http://code.google.com/p/android-ws-client/
you can create all classe what you need to.
by one application copy libs to your project
with your generate classes
Here is example it look really simple to
Service servis = new Service();
ServiceSoap soap12 = servis.getServiceSoap12();
LoginParams inParams = new LoginParams();
inParams.setLogin("user");
inParams.setPassword("pass");
inParams.setStrategy(LoginStrategy.NOHASHPASS); // even enums are supported
LoginState result = soap.authorize(inParams);
result.isLogin(); // boolean if is succesfull

SOAP web service call from android

Could anyone please help in processing the SOAP request and response from an android application.
I have followed the tutorial at
http://www.c-sharpcorner.com/UploadFile/88b6e5/how-to-call-web-service-in-android-using-soap/
But when I run the application, it exits prematurely with the error
Unfortunately, has stopped.
I am running it in an emulator.
Can anyone please explain what I might be missing. Any example source code will be very useful.
I have one simple code for you. Where we have a button and we will be calling helloworld method.
Button Worldmethod;
private static final String SOAP_ACTION1 = "http://tempuri.org/HelloWorld";
private static final String HelloWorldmethod = "HelloWorld";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://192.168.1.5/MobileDemo/Demo.asmx";
#Override
protected void onCreate(Bundle savedInstanceState) {
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
super.onCreate(savedInstanceState);
setContentView(R.layout.webservices_layout);
Worldmethod= (Button)findViewById(R.id.Worldmethod);
Worldmethod.setOnClickListener(this);
#Override
public void onClick(View v) {
switch (v.getId()){
case R.id.Worldmethod:
try
{
methodbody= (TextView)findViewById(R.id.methodbody);
SoapObject request1 = new SoapObject(NAMESPACE, HelloWorldmethod);
// add paramaters and values
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request1);
//Web method call
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.debug = true;
androidHttpTransport.call(SOAP_ACTION1, envelope);
//get the response
SoapPrimitive result= (SoapPrimitive)envelope.getResponse();
String results = result.toString();
methodbody.setText( ""+results);
}
catch (Exception e)
{
methodbody.setText(e.getMessage());
e.printStackTrace();
}
break;
}
}

Web Service Issue

I am using Soap WEb service but I am facing one problem like this soap:Server' faultstring: 'Server was unable to process request. ---> There is no row at position 0.' faultactor: 'null
My Code is
public class GetData extends Activity {
private static final String SOAP_ACTION="http://xxx.mobi/GetMobileContentMetaData";
private static final String METHOD_NAME="GetMobileContentMetaData";
private static final String NAMESPACE ="http://xxx.mobi/";
private static final String URL = "http://webservices.xxx.mobi/MobileLMSServices.asmx";
SoapObject request;
Button submit;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.getdata);
submit=(Button)findViewById(R.id.submit);
submit.setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("SiteURL","http://heaklthcare.xxx.mobi/");
request.addProperty("ContentID","62b90739-57b9-47cc-884a-8be2ef265304");
request.addProperty("UserID",809);
request.addProperty("DelivoryMode",2);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
SoapObject result = null;
envelope.setOutputSoapObject(request);
AndroidHttpTransport sab = new AndroidHttpTransport(URL);
sab.debug = true;
try {
sab.call(SOAP_ACTION, envelope);
if (envelope.getResponse() != null)
{
result = (SoapObject) envelope.bodyIn;
for (int i1 = 0; i1 < 1; i1++) {
Object property = result.getProperty(i1);
if (property instanceof SoapObject) {
SoapObject countryObj = (SoapObject) property;
Log.d("country" ,"object"+countryObj);
}
}
}
}catch (Exception e) {
e.printStackTrace();
}
}
});
}
}
Should be an error returned by the server. If you can, call the web method from .net (or if you have a localhost copy of the webservice, input parameters in the browser) .
I struggled with this error this morning, then I did a small (5 lines) .net app to call the web method. then i got a clearer error message. Also turned out my java code had no problems the whole time.

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