Develop Reference

android upload file on shared folder inside htdocs

I need to upload file on shared folder inside lampp ht-docs directory.
The file is inside internal storage. I have also path of that file with me.
I have tried some of the solutions but it is not moving file to that shared folder inside lampp ht-docs.
I have the URL like this http://192.168.1...../OrderFiles/. OrderFiles is the shared folder inside lampp htdocs directory. I want to upload file here from file path of internal storage.
Here is what i have tried.
public void uploadLocal() {
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
File fileName = new File(DBController.lastXmlPathLocal);
Log.w("getAbsolutePath", fileName.getAbsolutePath());
Log.w("getPath", fileName.getPath());
String existingFileName = fileName.getAbsolutePath();
Log.w("existingFileName", existingFileName);
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
String responseFromServer = "";
String urlString = "http://192.168.1......./OrderFiles/";
Log.w("urlString", urlString);
try {
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(fileName.getPath()));
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
//while (bytesRead > 0)
Log.v("info", ".size." + bytesRead);
for (int n1 = 0; n1 < bytesRead; n1++) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.v("info", "File is written");
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
Log.v("info", "error: " + ex.getMessage(), ex);
} catch (IOException ioe) {
Log.v("info", "error: " + ioe.getMessage(), ioe);
}
/*//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream(conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null) {
Log.v("info", "Server Response " + str);
}
inStream.close();
} catch (IOException ioex) {
Log.v("info", "error: " + ioex.getMessage(), ioex);
}*/
}
The above code showing File is written in logcat but inside that folder not showing any of the file.
Is their any other solution to integrate this ?
Any help would be greatly appreciated.

First you need a php script to upload a file to begin with. And after that the php script should contain code to move the uploaded file to your wanted folder. And that is how it goes. And that is how you should do it.

how to send file from sd card to http post?

i want to send file from our app to sever through http post method.
My code is looking like as fallows
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName = Environment.getExternalStorageDirectory().getAbsolutePath()
+ "/TamTrack/TamTrackDetails.xml";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://192.158.1.7/Geo/myfilename";
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(existingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
//while (bytesRead > 0)
Log.v("info",".size."+bytesRead);
for(int n1=0;n1<bytesRead;n1++)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.v("info","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.v("info", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.v("info", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.v("info","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex)
{
Log.v("info", "error: " + ioex.getMessage(), ioex);
}
return null;
It is working fine.but empty file is created in server.
If any one know the solution ,please help me .
Thanks in advance.

Try this code. It is using a class "SimpleMultipartEntity" using which you can easily send the file.

I'd prefer using Apache Http commons, it is part of android. I think this is a much simpler and cleaner approach. You need to do something like this:
AndroidHttpClient client = AndroidHttpClient.newInstance("useragent string");
URI uri = "something";
File file = new File("/tmp/data");
HttpPost post = new HttpPost(uri);
post.setEntity(new FileEntity(file, "text/html"));
HttpResponse httpResponse = client.execute(post);
int statusCode = httpResponse.getStatusLine().getStatusCode();

Upload and download 2 or more files to/from server

I am trying to make an app that can connect android app to the server, and I need to upload and download 2 or more files
I found this code
private void doFileUpload() {
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName = Environment.getExternalStorageDirectory()
.getAbsolutePath() + "/android/data/[package]/files/productHistory";
**String existingFileName2 = Environment.getExternalStorageDirectory()
.getAbsolutePath() + "/android/data/[package]/files/productStock";**
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
String responseFromServer = "";
String urlString = "http://192.168.1.112/johnson/learn/android/";
try {
// ------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(
existingFileName));
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\""
+ existingFileName + "\"" + lineEnd);
**dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\""
+ existingFileName2 + "\"" + lineEnd);**
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug", "File is written");
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
Log.e("Debug", "error: " + ex.getMessage(), ex);
} catch (IOException ioe) {
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
// ------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream(conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null) {
Log.e("Debug", "Server Response " + str);
}
inStream.close();
} catch (IOException ioex) {
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
The bold text is edited by me,
but it is fail, it only upload the first one
my question is 1. how to upload 2/more files with the code?
2. and how to download them?
thanks in advance

Not sure if you have to use a specific server, yet Parse offers a sweet SDK with intuitive API to send/receive data (images in you case) to and from the server. I'd suggest you try that out if you don't want to spend to much time writing code that sends and receives data to and from a server. (and no, I don't work at Parse, just a big fan of their tools :P).

How to upload image and video on server using HttpUrl connection?

I want to to upload the video along with the thumbnails of that video to the server using url connection only. I am able to upload the video, but I do not know how to upload the image at the same time.
Here's my code for reference:
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName = selectedPath;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://xxx/yyy/zzz/hh.php; //path of the php file on server
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(existingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
bmThumbnail = ThumbnailUtils.createVideoThumbnail(existingFileName,
Thumbnails.MICRO_KIND);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data;name=\"uploadedfile\";filename=\"" + existingFileName +"\"" + lineEnd);
// dos.writeBytes(bmThumbnail);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
//check server response
int serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("file sent to:" +existingFileName,"Code:" + serverResponseCode +"Message: "+ serverResponseMessage);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
Any suggestions? Thanks in advance.

Use multipart http post. You can use libraries to do it, or, you can compose http request manually.

Android video upload error?

I use this to upload the video to php server, when i try to upload the image ,it was working fine, but when i tried to upload the Video the following error occur,
"02-22 18:22:35.588: ERROR/dalvikvm-heap(780): Out of memory on a 14680278-byte allocation."
***
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String exsistingFileName = "/sdcard/Video/dance.wmv";
// Is this the place are you doing something wrong.
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://172.17.0.146/viddygo/upload.php";
try
{
//------------------ CLIENT REQUEST
Log.e("MediaPlayer","Inside second Method");
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e("MediaPlayer","Headers are written");
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
BufferedReader in = new BufferedReader(
new InputStreamReader(
conn.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
tv.append(inputLine);
// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("MediaPlayer","Server Response"+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}
can anyone suggest some idea to solve this.

I think error happened in follow line because DataOutputStream size is exceeds VM budget when you write
dos.write(buffer, 0, bufferSize);