Develop Reference

how to implement search contacts using number in ContactsContract query. Like "display_name LIKE ?" for name

I want to implement search the contacts on basis of number provided.
I have used ContactsContract to read all the contacts. I have implemented search criteria on basis of name by proving a searchView and the matching name will be displayed but I want to do the same by number also
private List<ContactItem> getContacts(String s) {
String whereString = "display_name LIKE ?";
String[] whereParams = new String[]{ "%" + s + "%"};
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, whereString, whereParams, null);
List<ContactItem> contacts = new ArrayList<>();
assert cur != null;
while (cur.moveToNext()) {
String name = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
String phoneNumber = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
contacts.add(new ContactItem(name,phoneNumber));
}
cur.close();
return contacts;
}
I want to use phone number instead of display_name here. How to do that

Try the following code, should filter based on both name and number:
private List<ContactItem> getContacts(String numberOrName) {
Uri searchUri = Uri.withAppendedPath(Phone.CONTENT_FILTER_URI, Uri.encode(numberOrName));
String[] projection = new String[] { Phone.DISPLAY_NAME, Phone.NUMBER };
Cursor cur = getContentResolver().query(searchUri, projection, null, null, null);
List<ContactItem> contacts = new ArrayList<>();
assert cur != null;
while (cur.moveToNext()) {
String name = cur.getString(0);
String phoneNumber = cur.getString(1);
contacts.add(new ContactItem(name, phoneNumber));
}
cur.close();
return contacts;
}

how to fetch local phone contacts effeciently

I am using the below code to fetch the local phone contacts. It is working fine and also fetching the contacts very fast.
But the problem comes here, in my contact list there are few contacts that are having multiple Emails and multiple phone numbers.
In case of multiple phone or emails address it repeats the name of the same person multiple times.
And if i change
ContactsContract.CommonDataKinds.Email.CONTENT_URI
to ContactsContract.CommonDataKinds.Phone.CONTENT_URI then it will repeat name according to the number of phone number exists for a contact. Please help
private static final String[] PROJECTION = new String[]{
ContactsContract.CommonDataKinds.Email.CONTACT_ID,
ContactsContract.CommonDataKinds.Nickname.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Email.DATA,
ContactsContract.CommonDataKinds.Phone.NUMBER,
};
ContentResolver cr = mContext.getContentResolver();
Cursor cursor = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, PROJECTION, null, null, null);
if (cursor != null) {
try {
final int contactIdIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.CONTACT_ID);
final int displayNameIndex = cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME);
final int emailIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA);
final int phoneIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
long contactId;
String displayName, email, phone, photo;
while (cursor.moveToNext()) {
mNK_UserModel = new NK_Contact();
contactId = cursor.getLong(contactIdIndex);
displayName = cursor.getString(displayNameIndex);
//Adding display name
mNK_UserModel.setFirstName(displayName);
Util.DEBUG_LOG(1, "contact", "contact id :" + contactId);
al_PhoneContacts.add(mNK_UserModel);
}
} finally {
cursor.close();
}
}

If i had to guess i would say you are missing a "break" in your while-loop. Since the cursor tries to fetch the next available column entry. But have a look at my solution which worked for me in the past.
It uses a seperate cursor for each row which gives you more control over the data.
Map<String, String> contactDataMap = new HashMap<String, String>();
Uri contactData = data.getData();
Cursor cursor = getContentResolver().query(contactData, null, null, null, null);
cursor.moveToFirst();
String name = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
String id = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts._ID));
contactDataMap.put(NAME, (name != null)?name:"");
if (Integer.parseInt(cursor.getString(
cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor pCur = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id},
null);
while (pCur.moveToNext()) {
String number = pCur.getString(pCur.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER));
contactDataMap.put(PHONE, (number != null)?number:"");
break;
}
pCur.close();
}
Cursor emailCur = getContentResolver().query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
new String[]{id}, null);
while (emailCur.moveToNext()) {
String email = emailCur.getString(
emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
contactDataMap.put(MAIL, (email != null)?email:"");
break;
}
emailCur.close();
cursor.close();

How to display music name by playlist name Android programming

There are some similar questions have been posted here, I have used those suggestions and tried it in different ways, but still no results for getting out, my codes is like this:
private Cursor getPlaylists(String playlistName) {
Cursor cursor = null;
String[] projection1 = { MediaStore.Audio.Playlists._ID,
MediaStore.Audio.Playlists.NAME };
cursor = this.managedQuery(
MediaStore.Audio.Playlists.EXTERNAL_CONTENT_URI, projection1,
MediaStore.Audio.Playlists.NAME + "=\"" + playlistName + "\"", null,
null); // I need to put "" for the string, otherwise sqlite errors for no such table
startManagingCursor(cursor);
cursor.moveToFirst();
String playlist_id = cursor.getString(0);
Long playlist_id2 = cursor.getLong(0);
if (playlist_id2 > 0) {
String[] projection = {
MediaStore.Audio.Playlists.Members.AUDIO_ID,
MediaStore.Audio.Playlists.Members.ARTIST,
MediaStore.Audio.Playlists.Members.TITLE,
MediaStore.Audio.Playlists.Members._ID
};
cursor = getContentResolver().query(MediaStore.Audio.Playlists.Members.getContentUri("external",playlist_id2),
projection,
null,
null,
null);
}
return cursor;
But after these codes, how can I exactly get music list names?　does then store in projection, but my projection variable are always no music list information inside. If I need to iterate this cursor again to get music list names, how can I do it, I have tried this way.. but it won't work.
// startManagingCursor(cursor);
for (boolean hasItem = cursor.moveToFirst(); hasItem; hasItem = cursor
.moveToNext()) {
String musicName = cursor.getString(cursor
.getColumnIndex(MediaStore.Audio.Playlists.Members.TITLE));
Log.i(LOGGING_TAG, musicName);
}
it looks like hasItem is null as always. I am stuck on this for couple of hours, maybe that is a stupid question but any suggestions would be graceful.

If I understand you correctly, you want to list the tracks on a given playlist.
This is how I do it. Once you have your cursor, you just loop around it by getting the values you need.
see examples below :
public Cursor getPlaylistTracks(Context context, Long playlist_id) {
Uri newuri = MediaStore.Audio.Playlists.Members.getContentUri("external",playlist_id);
ContentResolver resolver = context.getContentResolver();
String _id = MediaStore.Audio.Playlists.Members._ID;
String audio_id = MediaStore.Audio.Playlists.Members.AUDIO_ID;
String artist = MediaStore.Audio.Playlists.Members.ARTIST;
String album = MediaStore.Audio.Playlists.Members.ALBUM;
String title = MediaStore.Audio.Playlists.Members.TITLE;
String duration = MediaStore.Audio.Playlists.Members.DURATION;
String location = MediaStore.Audio.Playlists.Members.DATA;
String composer = MediaStore.Audio.Playlists.Members.COMPOSER;
String playorder = MediaStore.Audio.Playlists.Members.PLAY_ORDER;
String date_modified = MediaStore.Audio.Playlists.Members.DATE_MODIFIED;
String[] columns = { _id, audio_id, artist, album, title, duration,
location, date_modified, playorder, composer };
Cursor cursor = resolver.query(newuri, columns, null, null, null);
return cursor;
}
if (cursor!= null){
cursor.moveToFirst();
int artistColumn = cursor.getColumnIndex(MediaStore.Audio.Playlists.Members.ARTIST);
int durationColumn = cursor.getColumnIndex(MediaStore.Audio.Playlists.Members.DURATION);
for (cursor.moveToFirst(); !cursor.isAfterLast(); cursor.moveToNext())
{
artist = cursor.getString(artistColumn);
duration = duration + cursor.getLong(durationColumn);
// do something else
}
cursor.close();
}

Android query phonenumber to obtain rawcontactID

I would like to query on phonenumber to obtain the rawcontactID.
The only thing I know of the contact is the given phonenumber, but for my function I need to have the rawcontactID. I got a working code but now I did use 2 seperate queries. What I would like to have is 1 query that can do both just to save some query time.
my code:
Uri uri = Uri.withAppendedPath(Phone.CONTENT_FILTER_URI, Uri.encode(phoneNumber));
String[] columns = new String[]{Phone.CONTACT_ID, Phone.DISPLAY_NAME, Phone.NUMBER, Phone._ID };
Cursor cursor = contentResolver.query(uri, columns, null, null, null);
if(cursor!=null) {
int clenght = cursor.getCount();
while(cursor.moveToNext()){
//contactName = cursor.getString(cursor.getColumnIndexOrThrow(PhoneLookup.DISPLAY_NAME));
id = cursor.getString(cursor.getColumnIndex(Phone.CONTACT_ID));
}
cursor.close();
}
Cursor pCur = contentResolver.query(ContactsContract.Data.CONTENT_URI, new String[]{ContactsContract.Data.RAW_CONTACT_ID}, ContactsContract.Data.CONTACT_ID+" = "+ id, null, null);
if(pCur!=null) {
int clenght = pCur.getCount();
while(pCur.moveToNext()){
//contactName = cursor.getString(cursor.getColumnIndexOrThrow(PhoneLookup.DISPLAY_NAME));
id = pCur.getString(pCur.getColumnIndex(ContactsContract.Data.RAW_CONTACT_ID));
}
pCur.close();
}
thanks in advance
Edit:
My code above works fine, but I am still looking for increasing speed for large number of contacts. Therefore I will give a bounty if someone comes with a solution to combine my queries.

private String[] getRawContactIdFromNumber(String givenNumber){
List<String> rawIds = new ArrayList<String>();
Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, new String[]{ContactsContract.CommonDataKinds.Phone.RAW_CONTACT_ID},ContactsContract.CommonDataKinds.Phone.NUMBER + "='"+ givenNumber +"'",null, ContactsContract.CommonDataKinds.Phone.NUMBER);
while (phones.moveToNext())
{
rawIds.add( phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.RAW_CONTACT_ID)));
Log.v("contacts","Given Number: " + givenNumber + "Raw ID: " +rawIds.get(rawIds.size() - 1));
}
phones.close();
String[] ret = new String[0];
return rawIds.toArray(ret);
}
Edited to only include the raw id in the cursor for efficiency. Also changed return type to array in case multiple contacts have the same number.

Please try
String phonenumber = "input your phone number";
Cursor pCur = getContentResolver().query(
ContactsContract.Data.CONTENT_URI,
new String[] { ContactsContract.Data.RAW_CONTACT_ID,
Phone.CONTACT_ID }, Phone.NUMBER + " = " + phonenumber,
null, null);
if (pCur != null) {
while (pCur.moveToNext()) {
String contactID = pCur.getString(pCur
.getColumnIndex(Phone.CONTACT_ID));
String Rowid = pCur.getString(pCur
.getColumnIndex(ContactsContract.Data.RAW_CONTACT_ID));
Log.e("RAW_CONTACT_ID", Rowid);
Log.e("CONTACT_ID", contactID);
}
pCur.close();
}
Now you can get Both CONTACT_ID & RAW_CONTACT_ID in single query.

Delete all contacts in a group

I'm trying to delete all contacts from a defined group but I don't know how to do a join from the contact table and group table (if it's possible).
ContentResolver cr = getContentResolver();
String where = ContactsContract.Groups.TITLE + " =='LolGroup'";
Cursor cursor = cr.query(
ContactsContract.Contacts.CONTENT_URI, null, where, null, null);
while (cursor.moveToNext()) {
String lookupKey = cursor.getString(
cursor.getColumnIndex(ContactsContract.Contacts.LOOKUP_KEY));
Uri uri = Uri.withAppendedPath(
ContactsContract.Contacts.CONTENT_LOOKUP_URI, lookupKey);
cr.delete(uri, null, null);
}
Of course it gives me an error because there is no "title" in the contacts group, but if I do a join with the ID I should get what i want.
Any idea how to do that join?

It looks strange because ContactsContract.Contacts does not have ContactsContract.Groups.TITLE column. So I think that you can get group id with the group title you want and then search contacts with the group id. The idea might go like following:
public String getGroupIdByTitle(String groupTitle){
try {
cursor = mContentResolver.query(
ContactsContract.Groups.CONTENT_URI,
new String[] {Groups._ID},
Groups.TITLE + "=?",
new String[]{groupTitle},
null);
while (cursor.moveToNext()){
return cursor.getString(cursor.getColumnIndex(0);
}
} finally {
if (cursor!=null) cursor.close();
}
return "";
}
public String getGroupIdOfContact(String lookupKey) {
String where = String.format("%s=? AND %s=?", Data.LOOKUP_KEY, Data.MIMETYPE);
String[] whereArgs = {lookupKey, GroupMembership.CONTENT_ITEM_TYPE};
String groupRowId = "";
Cursor cursor = mContentResolver.query(
Data.CONTENT_URI,
new String[]{GroupMembership.GROUP_ROW_ID},
where, whereArgs, null);
try {
if (cursor.moveToNext()) {
return cursor.getString(cursor.getColumnIndex(GroupMembership.GROUP_ROW_ID));
}
} finally {
if (cursor!=null) cursor.close();
}
return "";
}
public void deleteContactByGroupTitle(String groupTitle) {
String targetGroupId = getGroupIdByTitle(groupTitle);
Cursor cursor = null;
try {
cursor = mContentResolver.query(Contacts.CONTENT_URI, null, null, null, null);
while (cursor.moveToNext()){
String lookupKey = cursor.getString(cursor.getColumnIndex(Contacts.LOOKUP_KEY));
String groupId = getGroupIdOfContact(lookupKey);
if (targetGroupId.equals(groupId)){
//TODO. delete this contact
}
}
} finally {
if (cursor!=null) cursor.close();
}
}
The above code has not tested but I think that basic idea would be same.