I want to convert the selected text from Edit Text to Hyperlink. Basically i know how to convert text in hyperlink, but not able to do in Edit Text.
I have tried Linkify, but not working.
Any Help would be appreciated..
Here is the way how i solved the problem.
text = EditText
int start = text.getSelectionStart();
int end = text.getSelectionEnd();
SpannableStringBuilder spb = new SpannableStringBuilder(text
.getText().toString());
String hyper = text.getText().toString().substring(start, end);
text.setText(hyper);
text.setAutoLinkMask(Linkify.ALL); // Linkify.WEB_URLS
text.setText(spb);
Related
I want to change text color before displaying it to TextView.
For example,I am getting a text from server like
<b>Pratik<b/> has shared photo with <b>you</b>.
Now the requirements are to display Pratik and you with Bold style and Blue text color. I tried several ways using <span> tag, but I am not getting clear way to display it.
String htmlBody = "<b>Pratik<b/> has shared photo with <b>you</b>.";
String formattedBody = "<span>" + htmlBody + "</span><style>b { color: #309ce8 ; } span {font-family: 'Avenir', 'Heavy'; font-size: 17; }</style>";
SpannableString text = new SpannableString(formattedBody);
tvMessage.setText(text, TextView.BufferType.SPANNABLE); // This is not working as expected.
tvMessage.setText(Html.fromHtml(htmlBody)); // This is not working as expected.
Help me achieve that.
String htmlBody = "<b style='color:blue !important;'>Pratik</b> has shared photo with <b style='color:blue !important;'>you</b>.";
Your Solution is:
String styledText = "<b><font color='red'>Pratik</font><b/> has shared photo with <b><font color='red'>you</font></b>";
You have to use like this
public void methodName() {
String html = "Some text <b>here</b>, and some <b>there</b>";
String result = html.replace("<b>","<font color=\"#ff0000\"><b>").replace("</b>", "</b></font>");
textView.setText(Html.fromHtml(result));
}
I am selecting a part of the TextView and on click of a "highlight" button, I am sending the start and the end index of selection to the database. Then I am loading all the start and end indexes from db and changing the color of text between them.
The problem is after once or twice, the app is changing the color of text that is not in selection.. and the selected part remains unchanged.
MY CODE:
When user selects and presses the highlight button
int i=contentText.getSelectionStart();
int j=contentText.getSelectionEnd();
db.insertHiglightIndex(String.valueOf(i),String.valueOf(j));
setHighlightedText();
The setHighlightedText() method..
String fullText=contentText.getText().toString();
for(int i=0; i<db.getAllStartIndex().size();i++){
String a=fullText.substring(Integer.parseInt(db.getAllStartIndex().get(i)),Integer.parseInt(db.getAllEndIndex().get(i)));
fullText = fullText.replace(a, "<font color='red'>"+a+"</font>");
}
contentText.setText(Html.fromHtml(fullText), TextView.BufferType.SPANNABLE);
MY SCREENSHOTS.
The selection:
The Result:
Clearly the selected area is from "Garrick" to "Bart", and the result is from "entity" to "2012"
I am not able to understand why is this happening. I think there is some problem with this <font color='red'>"+a+"</font> line.
Thank you
It got wrong indexed because There is already added <font color='red'> in the beginning, So that in second time This tag is also counted as a part of string, So I suggest creating a new temporary String, assign same text to the String but after replacing the previous font tag it held. Use this syntax to remove previous font tag from originalString
String tempString = originalString.replaceAll("[<](/)?font[^>]*[>]", "");
After that work with only tempString. That means again add every previous font tag you have to tempString and set that text.
In next time again do the same first remove all font tag and again add all of them back in tempString as well as current selection using same loop you are using currently.
You have wrong indexes because you are modifying the fullText content within the loop.
Taking a look at this example you can figure it:
final TextView tv = (TextView) findViewById(R.id.textView);
tv.setText( "abcdefghijklmnopqrstuvwxyz0123456789");
String fullText= tv.getText().toString();
// your first iteration
String a = fullText.substring(1,3);
// a contains "ab"
fullText = fullText.replace(a, "<font color='red'>"+a+"</font>");
After the first iteration full text contains now
a<font color='red'>bc</font>defghijklmnopqrstuvwxyz0123456789"
Then the substring() in the second iteration won't returns the substring base on your initial content.
If you want to be able to have multiple substrings colored in red you can try this:
String fullText = contentText.getText().toString();
StringBuilder result = new StringBuilder();
for(int i=0; i < db.getAllStartIndex().size(); i++){
fullText = applyFont(result, fullText, Integer.parseInt(db.getAllStartIndex().get(i)), Integer.parseInt(db.getAllEndIndex().get(i)));
}
// Add here the remaining content
result.append(fullText);
contentText.setText(Html.fromHtml(result.toString()), TextView.BufferType.SPANNABLE);
private String applyFont(StringBuilder result, String source, int from, int to){
result.append(source.substring(0, from));
result.append("<font color='red'>");
result.append(source.substring(from, to));
result.append("</font>");
return source.substring(to, source.length());
}
i have one EditText and entered some text.
view.editText.setTextColor(Color.RED);
Html.toHtml(editText.getText())
convert it to html text.
o/p
text color change
i have getting only paragragh but not the selected color.
Because,
editText.getText() just returns Editable character sequence not a Html rich string.
String sample=editText.getText();
TextView str = new TextView(null);
str.setText(sample);
str.setTextColor(Color.RED);
editText.setText(str.getText().tostring());
or use this
Html.fromHtml("<font color = #ffffff>"
+ getResources().getString(editText.getText().tostring()) + "</font>")
thank you.
In my android app, I am getting the String from an Edit Text and using it as a parameter to call a web service and fetch JSON data.
Now, the method I use for getting the String value from Edit Text is like this :
final EditText edittext = (EditText) findViewById(R.id.search);
String k = edittext.getText().toString();
Now normally it works fine, but if we the text in Edit Text contains space then my app crashes.
for eg. - if someone types "food" in the Edit Text Box, then it's OK
but if somebody types "Indian food" it crashes.
How to remove spaces and get just the String ?
Isn't that just Java?
String k = edittext.getText().toString().replace(" ", "");
try this...
final EditText edittext = (EditText) findViewById(R.id.search);
String k = edittext.getText().toString();
String newData = k.replaceAll(" ", "%20");
and use "newData"
String email=recEmail.getText().toString().trim();
String password=recPassword.getText().toString().trim();
In the future, I highly recommend checking the Java String methods in the API. It's a lifeline to getting the most out of your Java environment.
You can easily remove all white spaces using something like this. But you'll face another serious problem if you just do that. For example if you have input
String input1 = "aa bb cc"; // output aabbcc
String input2 = "a abbcc"; // output aabbcc
String input3 = "aabb cc"; // output aabbcc
One solution will be to fix your application to accept white spaces in input string or use some other literal to replace the white spaces. If you are using only alphanumeric values you do something like this
String input1 = "aa bb cc"; // aa_bb_cc
String input2 = "a abbcc"; //a_abbcc
String input3 = "aabb cc"; //aabb_cc
And after all if you are don' caring about the loose of information you can use any approach you want.
I want to insert a constant string into an EditText by the press of a button. The string should be inserted at the current position in the EditText.
If I use EditText.append the text gets inserted at the end of the EditText.
How can I do that? I couldn't find a suitable method.
Cpt.Ohlund gave me the right hint. I solved it, now, partly with using EditText.getSelectionStart(), but I realized that you can also replace the selected text with the same expression and you don't need String.subString() for that.
int start = Math.max(myEditText.getSelectionStart(), 0);
int end = Math.max(myEditText.getSelectionEnd(), 0);
myEditText.getText().replace(Math.min(start, end), Math.max(start, end),
textToInsert, 0, textToInsert.length());
This works for both, inserting a text at the current position and replacing whatever text is selected by the user. The Math.max() is necessary in the first and second line because, if there is no selection or cursor in the EditText, getSelectionStart() and getSelectionEnd() will both return -1. The Math.min() and Math.max() in the third line is necessary because the user could have selected the text backwards and thus start would have a higher value than end which is not allowed for Editable.replace().
This seems simpler:
yourEditText.getText().insert(yourEditText.getSelectionStart(), "fizzbuzz");
However, Manuel's answer might be better if you want to replace any selected text with the inserted text.
Try using EditText.getSelectionStart() to get the current position of the cursor. Then you can use String.subString to get the text before and after the cursor and insert your text in the middle.
I think this function will help for you :
public void insertConstantStr(String insertStr) {
String oriContent = editText.getText().toString();
int index = editText.getSelectionStart() >= 0 ? editText.getSelectionStart() : 0;
StringBuilder sBuilder = new StringBuilder(oriContent);
sBuilder.insert(index, insertStr);
editText.setText(sBuilder.toString());
editText.setSelection(index + insertStr.length());
}
For Kotlin simply do that:
editText.text.insert(editText.selectionStart, "Your Text Here")
Editable editable = new SpannableStringBuilder("Pass a string here");
yourEditText.text = editable;