i have problem with two parameters passing with URL link. Can anyone help me?
private void FillDetails(String _userid,int _sporttype) {
al_TeamName=new ArrayList<String>();
try{
spf=SAXParserFactory.newInstance();
sp=spf.newSAXParser();
xr=sp.getXMLReader();
URL sourceUrl = new URL(
"http://10.0.2.2:2291/acd.asmx/Get_Teams?_userid ="+_userid & "_sporttype="+ _sporttype);
MyHandler mh=new MyHandler();
xr.setContentHandler(mh);
xr.parse(new InputSource(sourceUrl.openStream()));
setListAdapter(new MyAdapter());
}
catch(Exception ex)
{
}
}
when i using this code, i am getting null.If i send single parameter then it works fine.
Is this correct procedure for URL passing two parameters?
Thanks in advance..........
UPDATED ANSWER:
Now you have multiple errors in your URL:
URL sourceUrl = new URL("http://10.0.2.2:2291/acd.asmx/Get_Teams?_userid =" +
_userid & "_sporttype="+ _sporttype);
You still have a space before the first = sign
There's no + between the _userid variable and the rest of the string.
The & sign is outside the second string
It should be something like this:
URL sourceUrl = new URL("http://10.0.2.2:2291/acd.asmx/Get_Teams?_userid="
+ _userid + "&_sporttype=" + _sporttype);
ORIGINAL ANSWER:
You currently have a space instead of a = sign after your first parameter:
?_userid "+_userid
should be
?_userid="+_userid
Solved.
URL sourceUrl = new URL("http://0.0.0.0/acd.asmx/GetList?Value1="+Value1+"&ID="+ID);
"http://10.0.2.2:2291/acd.asmx/Get_Teams?_userid ="+_userid & "_sporttype="+ _sporttype);
You have an & after _userid, which probably does who knows what on _userid. Usually a single & does binary manipulation, so you might be transforming what comes out of _userid. Also, I would recommend URLEncoding your REST tags if you aren't doing that already
I would recommend logging the REST parameters while in development as well to double-check that it's being formed correctly
Update: The & was outside the quote and you needed to use a +
"http://10.0.2.2:2291/acd.asmx/Get_Teams?_userid ="+_userid + "&_sporttype="+ _sporttype);
If you came here because you searched for a version working in Kotlin (like me), you can use this function to build your URL:
import java.net.URL
// Your URL you want to append the query on
val url: String = "http://10.0.2.2:2291/acd.asmx/Get_Teams"
// The parameters you want to pass
val params: Map<String, String> = mapOf(
"_userid" to _user_id
, "_sporttype" to _sporttype
)
// The final build url. Standard encoding for URL is already utf-8
val final_url: URL = URL(
"$url?" // Don't forget the question-mark!
+ params.map {
"${it.key}=${it.value}"
}.joinToString("&")
)
Related
I have a retrofit request
#GET("{link}")
suspend fun getFilePart(#Path(value = "link") link: String): Deferred<NetworkResponse<ResponseBody, NetworkError>>
and when i call it i pass a 'link'
val base = if (BuildConfig.DEBUG) BuildConfig.TRANSFER_URL_DEBUG else BuildConfig.TRANSFER_URL
apiManager.appApiService(base).getFilePart(it.link)
Lets say the link is something like "https://storage_dev.example.com/10002/6d197e1e57e37070760c4ae28bf1..." but in the Logcat i see that some characters get urlEncoded.
For example
the following Url
https://storage_dev.example.com/10002/6d197e1e57e37070760c4ae28bf18d813abd35a372b6a1f462e4cef21e505860.1&Somethingelse
turns to
https://storage_dev.example.com/10002/6d197e1e57e37070760c4ae28bf18d813abd35a372b6a1f462e4cef21e505860.1%3FSomethingelse
As i can see the link is a String that has many characters inside that get encoded like "&" has turned to "%3F"
How can i prevent this?
You can add encoded = true to your request param to tell retrofit to not encode it again:
/**
* Specifies whether the parameter {#linkplain #value() name} and value are already URL encoded.
*/
boolean encoded() default false;
Example:
#Path(value = "link", encoded = true)
If your link includes the baseurl part you should use #Url to avoid that problem
#GET
suspend fun getFilePart(#Url link: String): Deferred<NetworkResponse<ResponseBody, NetworkError>>
I think I'm late but however this is how I solved it ..
my issue was the url to containes " so on request url it gets encoded then looks like this domain.com/api/%22SOME_URL_%22
simply just add interceptor to catch the request and decode it.
if(it.request().url().toString().contains("api/MY_SUB_DOMAIN")){
val newUrl = java.net.URLDecoder.decode( it.request().url().toString(),
StandardCharsets.UTF_8.name()) // <--- This is your main solution (decode)
.replace("\"", "") // <---- I had to do this to remove parenthasis "
requestBuilder.url(newUrl) // <--- DONT FORGET TO ASSAIGN THE NEW URL
}
I have a strange behaviour when I click on a link in a webview that is a PDF file link.
For example: https://my.server.com/foobar.pdf
So I have made some research and this link will start a dowload in my webview.
I have a DownloadListener and a onDownloadStart method.
In it I send the URL to Android so that PDF apps on phone can open it.
My strange behaviour is here. If the link in the webview does not have parameters I am not able to add parameters in the URL but if the URL have one parameter -> my parameters are added.
Example will be more meaningful.
Here url in link is "https://my.server.com/foobar.pdf"
val uriTest = Uri.parse(url).buildUpon()
.appendQueryParameter("key1", val1)
.appendQueryParameter("key2", val2)
.build()
val intent = Intent(Intent.ACTION_VIEW, uriTest)
startActivity(intent)
So when the PDF app called by startActivity(intent) call the URL on my server I have no parameters in URL and on my server I see a call to "https://my.server.com/foobar.pdf" not to "https://my.server.com/foobar.pdf?key1=val1&key2=val2".
BUT
If the url in link is "https://my.server.com/foobar.pdf?t=t" when my Android code is executed on my server side I can see a call to ""https://my.server.com/foobar.pdf?t=t&key1=val1&key2=val2". My parameters are added in this case.
Is it normal? Am I missing something?
Thanks for your help!
---EDIT---
I also tried to add my parameters in the string directly and it is the same -> my parameters are ignored until the URL I get has one parameter.
Example: I get "https://my.server.com/foobar.pdf" and I do:
val url1 = url + "?key1=" + val1
or
val url1 = "$url?key1=$val1"
val yourUrl = StringBuilder("https://my.server.com/foobar.pdf")
val parameters = hashMapOf<String, String>()
parameters["key1"] = "val1"
parameters["key2"] = "val2"
var count = 0
for (i in parameters.entries) {
if (count == 0)
yourUrl.append("?${i.key}=${i.value}&")
else
yourUrl.append("${i.key}=${i.value}&")
count++
}
val yourNewUrl = yourUrl.substring(0, yourUrl.length - 1)
Timber.e("URL: $yourNewUrl")
val intent = Intent(Intent.ACTION_VIEW, Uri.parse(yourNewUrl))
startActivity(intent)
Happy coding :)
I need to post data to Webview.
I found from some of the links the below code:
WebView webview = new WebView(this);
setContentView(webview);
String url = "http://www.example.com";
String postData = username=my_username&password=my_password";
webview.postUrl(url",EncodingUtils.getBytes(postData, "BASE64"));
But in my android studio I see EncodingUtils as deprecated
Can anyone help me what is the alternative for EncodingUtils to post data to Android WebView?
Try like below...
Java:
WebView webview = new WebView(this);
setContentView(webview);
String url = "http://www.example.com";
String postData = "username=" + URLEncoder.encode(my_username, "UTF-8") + "&password=" + URLEncoder.encode(my_password, "UTF-8");
webview.postUrl(url,postData.getBytes());
Kotlin:
val webview = WebView(this)
setContentView(webview)
val url = "http://www.example.com"
val postData = "username=${URLEncoder.encode(my_username, "UTF-8")}" +
"&password=${URLEncoder.encode(my_password, "UTF-8")}"
webview.postUrl(url, postData.toByteArray())
This is a simple workaround.
String html = "<!DOCTYPE html>" +
"<html>" +
"<body onload='document.frm1.submit()'>" +
"<form action='http://www.yoursite.com/postreceiver' method='post' name='frm1'>" +
" <input type='hidden' name='foo' value='12345'><br>" +
" <input type='hidden' name='bar' value='23456'><br>" +
"</form>" +
"</body>" +
"</html>";
webview.loadData(html, "text/html", "UTF-8");
I know this is not the best method but this works.
I would like to add a few things to the answer as I had to work on same and found some info could help complete the answer to this question.
First thing is the need for such a scenario. My need was that I am
creating a payment gateway client for native applications in android.
Second thing is that the URL you are opening needs to perform some
operations right. Hence you must enable your webView to enable
such operations or else things might not work. For example if your
URL is executing some java script, than you must enable java script
for your webview. This can be done as shown below :
val set = webview.settings
set.javaScriptEnabled = true
Normally this will enable trivial things such as timers, returning results etc on your webview.
Third thing is a case when your webView needs to call methods of your android app. This can be done by adding some JavaScript Interface as shown below :
webview.addJavascriptInterface(WebAppInterface(), "Android")
Where WebAppInterface() is a simple class which atleast one method annotated with #JavascriptInterface as shown below :
class WebAppInterface() {
#JavascriptInterface
fun showToast(status: String) {
//show toast here or handle status
}
}
The name Android will be the one which will be injected into your URL as a variable and you can call the methods of your android WebAppInterace from that URL as shown below:
Android.showToast("From WebPage")
Last thing is your postURL method which is somewhat like :
webview.postUrl(actionUrl, params.toByteArray(Charsets.UTF_8))
This method has couple of things that it takes as default. First is that request type is taken as default POST as the name suggest.
Header content-type can be default taken as application/x-www-form-urlencoded and
most important params it takes as & separated key value pairs as shown :
val params = "MERCHANT_ADDR=" + addr + "&CHANNEL=android"
We must pass byteArray of this string which is shown in post URL callback.
Now after your API is hit and it in some cases loads a callback url, from that call back URL using the JavaScript Interface, you can return result to your application and close the webview.
I hope it helps people.
try this:
You need to URL-encode the parameter value before sending it.
String postData = "fileContents=" + URLEncoder.encode(fileCon, "UTF-8");
For those who came here by trying to put a html body as a postData and not working,
try to put your string body as something below:
val htmlCode = "https://ramdom.user.me"
val postData = "{\n" +
"\t\"token\": \"963966f649\"\n" + "}"
webview.postUrl(htmlCode, postData.toByteArray())
I hope to save someone`s life. :-)
I am working on an app that gets a URL link from the user via edit text widget. How can I check if a given URL has a protocol? And if it doesn't, how can I add the correct protocol for the specific URL?
For example if the user entered: google.com
how can I make it become: https://google.com
The main problem is knowing the correct URL protocol for a given address (is it http/https/ftp? and so on).
You can use String.startsWith() to check if the url String starts with http:// or not
public String valid_url(final String url)
{
if (!url.startsWith("http://") && !url.startsWith("https://"))
{
return "http://" + url;
}
return url;
}
first check if url has protocol using .contains() method
and get protocol using .indexof() and .substring() method
string url = editText.getText().toString();
string protocol;
if(url.contains("://")){
//url has a protocol
int index = url.indexof("://");
//get protocol
protocol = url.substring(0,index-1);
}else{
//url does not have a protocal
// add your protocol to begining of the url
}
You can use android web kit URLUTIL class
package android.webkit;
URLUtil.guessUrl("your web address/String")
example scenarios:
www.testurl.com
testurl.com
testurl
result:
http://www.testurl.com/
Just compare the your output string with .contains() property
String value = editText.getText().toString();
if(!value.contains("https://")) {
// add https:// to ur string
}else {
// No need to add
}
This solution worked for me:
if(!url.startsWith("www.")&& !url.startsWith("http://") && !url.startsWith("https://")){
url = "www."+url;
}
if(!url.startsWith("http://") && !url.startsWith("https://")){
url = "http://"+url;
}
Hope this will help you.
As already adviced use the URL class of the SDK.
Here an example:
var urlWithScheme = new URL("https://www.google.com");
var urlWithoutScheme = new URL("www.google.com");
if (urlWithScheme.getProtocol() != null && urlWithScheme.getProtocol().length() > 0) {
System.out.println("Given URL includes scheme: " + urlWithScheme.getProtocol());
}
if (urlWithoutScheme.getProtocol() != null && urlWithoutScheme.getProtocol().length() > 0) {
System.out.println("Given URL includes scheme: " + urlWithoutScheme.getProtocol());
} else {
System.out.println("Url has no Protocol and you can't guess it by the domain name, because under this name all possible services can exist!");
}
If the given URL has not protocoll you can't guess it. Because under a domain name there can exist any protocol specific service in parrallel.
I would narrow it down to only support http and https. For this you could write a test like connect to https url, if success use it, because https is prefered. If you get redirect or not connection try http ;)
I'm trying to get the http response headers every time I visit some site. I thought that using an observer like the following is enough to do it:
const OBS = Cc['#mozilla.org/observer-service;1'].getService(Ci.nsIObserverService);
let httpRequestObserver ={
observe: function(subject, topic, data){
var httpChannel = subject.QueryInterface(Ci.nsIHttpChannel);
if (topic == "http-on-examine-response") {
headers=httpChannel.getAllResponseHeaders();
}
}
};
And in the startup method I add it then in the shutdown I remove it:
OBS.addObserver(httpRequestObserver, "http-on-examine-response", false);//startup methode
OBS.addObserver(httpRequestObserver, "http-on-examine-response", false);//shutdown
But I'm getting this in the log:
JavaScript Error: "httpChannel.getAllResponseHeaders is not a function"
Am I taking the wrong way and the operation is more complicated than it seem? this is for an extension for firefox for android and i'm not using sdk. Thanks for your help.
nsIHttpChannel is not XMLHttpRequest. Instead XMLhttpRequest is a nice wrapper class around channels - not just http ones -, which also adds convenience functions such as getAllResponseHeaders().
You may use nsIHttpChannel.visitResponseHeaders to simulate getAllResponseHeaders.
if (subject instanceof Ci.nsIHttpChannel) {
var headers = "";
subject.visitResponseHeaders(function(header, value) {
headers += header + ": " + value + "\r\n";
});
}