I am using the intent with ACTION_CALL to make call in my app:
str="tel:0123456789";
Intent intent = new Intent(Intent.ACTION_CALL);
intent.setData(Uri.parse(str));
startActivity(intent);
But it pops up the system dialing screen. I understand this is built into ROM and can not be customized. But Can I hide this screen and keep the user staying on my activity?
Did some googling and research here. But no clear answer so far.
It looks like you can't customize the dialing screen, but you can use a PhoneStateListener to get certain information about the phone call. See this link.
Related
i am amateur in android
i want to take a screenshot from dial activity of user`s phone,
i use this for going to dial page
Intent call = new Intent(Intent.ACTION_DIAL);
startActivity(call);
what is the best way for get screenshot without root? and we should write the code inside onPause() method? because our app is paused when we go to an intent
You can use this library for getting screen shot
Link
hope it help
I am trying to launch an SMS app (Messenger/Hangouts) from my app. But the UI transition is not as expected. On launch, my app moves to the background and SMS app is launched from below the screen and this transition is slow and very much visible to the user.
I want the transition to be as fast as possible without showing any animation. I tried overridePendingTransition(0,0) and setting the Intent flag (FLAG_ACTIVITY_NO_ANIMATION), still does not help.
What should I be doing to acheive this?
This snippet of code works fine for me:
Intent sendIntent = new Intent(Intent.ACTION_VIEW);
sendIntent.setData(Uri.parse("sms:"));
overridePendingTransition(0,0);
startActivity(sendIntent);
Please paste the relevant code you have used for the same if the above does not work and I can look into it. Hope this helps!
I cant find any refrence to call the Intent screen "Choose screen lock".
Cant find anything?
Any idea?
You can call action DevicePolicyManager.SET_NEW_PASSWORD to send user to lock screen settings fragment (firstly he will have to type current password/pattern for secure lock types):
Intent intent = new Intent(DevicePolicyManager.ACTION_SET_NEW_PASSWORD);
startActivity(intent);
There is none. You can view all possible Intents in android's source code: https://github.com/android/platform_packages_apps_settings/blob/master/AndroidManifest.xml
EDIT:
It turns out that this had been added in Version 2.2 of Android.
Please ee pleczko's answer below.
Before Android 2.2 there is no intent to do this.
On many Android devices you can get into a secret settings menu from Phone app by typing in
*#*#4636#*#*
http://technology-headlines.com/2010/09/17/4636-android-secret-codes/
There are also some other codes.
Is it also possible to open this stuff programmatically?
I've tried this:
Intent intent = new Intent(Intent.ACTION_CALL);
intent.setData(Uri.parse("tel:*#*#4636#*#*"));
startActivity(intent);
But it just tries to initiate a phone call and of course fails, hangs up and closes the Phone app.
EDIT: The phone *#*#4636#*#* gets saved to my Contact list as "Unknown" but the call just fails. In fact, the secret code only works when you type manually on buttons in Phone app without pressing Call in the end. Is it probably just a hidden feature of Phone app which has nothing to do with calling?
If so, one could open the Phone app programmatically and simulate typing on the buttons.
According to this post
Programmatically press a button in another appplication's activity
this should NOT be possible because if any app on non-rooted phone could just start other apps and press something there, it could take over control of the whole device and do bad things.
Here are some more details but I guess the post is a bit old and even if it worked it may have been changed in current Android versions:
http://mylifewithandroid.blogspot.de/2009/01/generating-keypresses-programmatically.html
So, no easier way to enter secret code?
Is it also possible to open this stuff programmatically?
Yes:
Intent in = new Intent(Intent.ACTION_MAIN);
in.setClassName("com.android.settings", "com.android.settings.TestingSettings");
startActivity(in);
You just need to watch logcat output to learn what this magic combination actually opens:
I/ActivityManager(31362): START {act=android.intent.action.MAIN
flg=0x10000000 cmp=com.android.settings/.TestingSettings} from pid
4257
Secret codes exist and work independent of the dialer application. The dialer application just provides a handy interface for these codes. It recognizes the special string and then calls a special intent to invoke the action. You shouldn't use the dialer to call these dialogs. Instead you can call the secret codes directly yourself like the dialer does internally:
Invoking built in secret codes:
What the dialer really does when you enter the code is extracting the number between *#*# and #*#* and then broadcasting the following intent:
sendBroadcast(new Intent("android.provider.Telephony.SECRET_CODE", Uri.parse("android_secret_code://4636")));
Register your own secret codes (if you like):
You can even register your own secret code actions using:
<action android:name="android.provider.Telephony.SECRET_CODE" />
<data android:scheme="android_secret_code" android:host="4636" />
Source: http://android.amberfog.com/?p=422
Edit: Fixed a bug in the original code (see comment)
try this
String ussdCode = "*" +Uri.encode ("#")+"*"+Uri.encode ("#")+ "4636" + Uri.encode ("#")+"*"+Uri.encode ("#")+"*";
startActivity (new Intent ("android.intent.action.CALL", Uri.parse ("tel:" + ussdCode)));
finally you must encode '#' using Uri.encode()
ACTION_DIAL sends the user to the dialer with the given code (it does not call). So that would be :
Intent intent = new Intent(Intent.ACTION_DIAL);
intent.setData(Uri.parse("tel:*#*#4636#*#*"));
startActivity(intent);
It would appear that codes are to be dialed, rather than to be called
looking for this
Intent intent = new Intent("android.intent.action.MAIN");
intent.setClassName("com.android.settings", "com.android.settings.Settings$TestingSettingsActivity");
startActivity(intent);
There are different activities for different phone, we can jump to the activity through typing in ##4636##.
And use
adb shell dumsys activity activities
to find the realActivity package and name.
e.g: Xiaomi 8
Intent intent = new Intent("android.intent.action.MAIN");
intent.setClassName("com.android.settings", "com.android.settings.Settings$TestingSettingsActivity");
startActivity(intent);
Im having trouble getting this to work, here´s a quick overview of the idea.
First, I cant change the logic behind this, it was a specific requirement from the customer, I realize that with any tool such as AnyCut it could be bypassed but that doesnt matter really.
My customer offers a suite of apps, the idea is that all applications bellonging to the suite would be launched from a "Dashboard app", so that I only show the Dashboard app in the main launcher and not all app icons.
Lets take two Apps to get the idea solved. The Dashboard App (A) and the Recieving App (B).
I want to establish an intent filter (I think) on app B so that whenever I go into app A, and click the app B icon the app will be either launched or started from where it let of (brought to front).
Is this even possible? If so, how can I do it? I managed to get it to launch by specifically launching one activity in the app using:
Intent i = new Intent();
i.setClassName("PACKAGE_NAME","SPECIFIC_CLASS");
startActivity(i);
But that isnt the behaviour that I want, as it always starts app B in the same spot.
Thanx in advance,
Stefano
Edit: Added some new information. I was taking a look at the DDMS.
If I launch the application from scratch through the main Android launcher the intent is exactly the same as when I leave the home button pressed and then only bring the app to front, what ever activity im in. So I was trying to reproduce, unsucsesfully until now, this intent.
INFO/ActivityManager(1292): Starting activity: Intent { act=android.intent.action.MAIN cat=[android.intent.category.LAUNCHER] flg=0x10200000 cmp=com.example.package/.uiPackage.Activity}
This is how AnyCut does it
Intent { act=android.intent.action.VIEW flg=0x10000000 cmp=com.example.package/.uiPackage.Activity bnds=[125,242][235,360]}
Any idea how I could go about creating that exact same intent? I cant even find that flag in the Intent API.
Figured it out, this is how I did it.
Intent i = new Intent();
i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
i.setAction("android.intent.action.VIEW");
i.setComponent(ComponentName.unflattenFromString("com.example.package/com.example.package.activityName"));
startActivity(i);
I'm not quite sure I'm following the expected results you want to see, but the following would launch the app from the dashboard and remove the dashboard from the activity stack leaving the selected app running:
Intent i = new Intent();
i.setClassName("PACKAGE_NAME","SPECIFIC_CLASS");
i.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(i);
I believe this should start the app as if you were starting any other app.
Please add more information on your logic if this is not what you are looking for.
I think that when you switch activities android's default action is to sort of pause or hold the activity in its state the user left it in last. I know there is a way to make it so that the state is not saved when switching activities but I cant remember it off the top of my head.