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Sending and Parsing JSON in Android
I have a JSON result in the following format which JSON Lint shows this as a Valid Response.
My question is: how do I accesss the content of "reportId0" value "164", "reportId1" value 157,reportId2 value 165, etc are all dynamic values?
My sample code for accessing value of properties.How to get Value reportid And add allvalue in Arraylist?
"properties": {
"link": "",
"approvalsReportCount": 3,
"reportName0": "srcapprovals",
"reportId0": 164,
"reportName1": "Approvals",
"reportId1": 157,
"requests_report_id": "163",
"requests_report_name": "EG approvals",
"reportName2": "fulfillment",
"reportId2": 165
}
This is the best way i found it to get ReportId value.
Below is My code
JSONObject jObj = new JSONObject(result);
JSONObject jsonResultArray = jObj.getJSONObject("results");
JSONObject pro_object = jsonResultArray.getJSONObject("properties");
Iterator keys = pro_object.keys();
while(keys.hasNext()) {
String currentDynamicKey = (String)keys.next();
String value = pro_object.getString(currentDynamicKey);
String upToEightCharacters = currentDynamicKey.substring(0, Math.min(currentDynamicKey.length(), 8));
if(upToEightCharacters.startsWith("reportId"))
{
Log.v("key"," new report ID key " + currentDynamicKey);
Log.v("key"," new report ID key " + pro_object.getString(currentDynamicKey) );
}
}
you can use this
public ArrayList<String> getReportIds() {
boolean isContinue = true;
JSONObject json;
String tag = "reportId";
int i = 0;
ArrayList<String> repIdList = new ArrayList<String>();
JSONObject prop = null;
try {
json = new JSONObject("<your json string>");
prop = json.getJSONObject("properties");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
while (isContinue) {
String repId = "";
try {
repId = prop.getString(tag + i);
repIdList.add(repId);
i++;
} catch (JSONException e) {
isContinue = false;
e.printStackTrace();
}
}
return repIdList;
}
You can Try This!!
try {
JSONObject jObj = new JSONObject(result);
JSONObject jsonResultArray = jObj.getJSONObject("results");
Log.v("log_tag","json result Array : "+ jsonResultArray);
JSONObject pro_object = jsonResultArray.getJSONObject("properties");
Iterator keys = pro_object.keys();
while(keys.hasNext()) {
// loop to get the dynamic key
String currentDynamicKey = (String)keys.next();
String value = pro_object.getString(currentDynamicKey);
approvaldto_Key = new All_Approval_Key_dto();
String upToEightCharacters = currentDynamicKey.substring(0, Math.min(currentDynamicKey.length(), 8));
if(upToEightCharacters.startsWith("reportId"))
{
approvaldto_Key.requestId = pro_object.getString(currentDynamicKey);
fetchrecursUserData.add(approvaldto_Key);
}
}
}
catch (JSONException e) {
e.printStackTrace();
}
return fetchrecursUserData;
}
You can try below code
String serial= jsonObject.getJSONObject("response").getString("serialNumber");
or
JSONObject json;
try {
json = new JSONObject(buffer.toString());
String accessToken = json.getString("access_token");
return accessToken;
} catch (JSONException e) {
Log.e("Podcast", "There was an error", e);
}
Related
I have a dynamic JSON string that looks like this:
{"_id":"7","food_name":"Fiber Balance"},{"_id":"8","food_name":"Sport +"}
I am able to get the first name, but not the second one. This is my code for getting the first (Fiber Balance):
// Dynamic text
TextView textViewDynamicText = (TextView)getActivity().findViewById(R.id.textViewDynamicText);
String stringJSON = textViewDynamicText.getText().toString();
String stringFoodname = "";
try {
JSONObject jsonObject = new JSONObject(stringJSON);
Iterator<String> iter = jsonObject.keys();
while (iter.hasNext()) {
String key = iter.next();
try {
stringFoodname = jsonObject.getString("food_name");
Toast.makeText(getContext(), stringFoodname, Toast.LENGTH_LONG).show();
} catch (JSONException e) {
// Something went wrong!
}
}
} catch (org.json.JSONException e) {
// Something went wrong!
}
How can I go to the next item in the json string?
If you have multiple data than you need to use Array,if you want to get all data from your json use below trick,
String json = "{\"_id\":\"7\",\"food_name\":\"Fiber Balance\"},{\"_id\":\"8\",\"food_name\":\"Sport +\"}";
json = "[" + json + "]";
try {
JSONArray array = new JSONArray(json);
for (int i = 0; i < array.length(); i++) {
JSONObject object = array.getJSONObject(i);
String foodName = object.getString("food_name");
Log.e("FoodName:", foodName);
}
} catch (JSONException e) {
e.printStackTrace();
Log.e("error", "json", e);
}
I want to get the id ^& content value in http://rest-service.guides.spring.io/greeting
What i tried is,
try {
JSONObject jsonObj = new JSONObject(parsingUrl);
// If you have array
JSONArray resultArray = jsonObj.getJSONArray("id"); // Here you will get the Array
// Iterate the loop
for (int i = 0; i < resultArray.length(); i++) {
// get value with the NODE key
JSONObject obj = resultArray.getJSONObject(i);
String name = obj.getString("content");
}
// If you have object
//String result1 = jsonObj.getString("result");
} catch (Exception e) {
e.printStackTrace();
}
Thanks
The url that your mentioned dont have json arrays, parsing will be like
try {
JSONObject jsonObj = new JSONObject(resultfromUrl);
int id = jsonObj.getInt("id");
String name = jsonObj.getString("content");
} catch (JSONException e) {
e.printStackTrace();
}
I am trying to get the user details using people.get in which I have emails which I need to get that value.
This is what I mean:
This is how I'm trying to do but unable to get the value
try {
String resp =profile.getEmails().toString();
JSONObject mainObject = new JSONObject(resp);
JSONObject uniObject = mainObject.getJSONObject("emails");
String email = uniObject.getString("value");
((TextView) findViewById(R.id.txtemail)).setText(email);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Any help is appreciated.
In your JSON response, emails is a JSONArray, not a JSONObject. You would need to get it like this:
JSONObject json= new JSONObject(responseString); //your response
try {
JSONArray responseArray = jsonObj.getJSONArray("email");
for (int i = 0; i < responseArray.length(); i++) {
// get value with the NODE key
JSONObject obj = responseArray.getJSONObject(i);
String lastName = obj.getString("value");
String firstName = obj.getString("type");
EmailResponse myResp = new EmailResponse();
myResp.setValue(value);
myResp.setType(type);
//set all other Strings
//lastly add this object to ArrayList<MyResponse> So you can access all data after saving
}
}
catch (JSONException e) {
e.printStackTrace();
}
POJO Class:
public class EmailResponse{
public String value = "";
public String type = "";
//getter setters
}
Hope this helps.
I am working on an Android application. In my app I have to convert a string to JSON Object, then parse the values. I checked for a solution in Stackoverflow and found similar issue here link
The solution is like this
`{"phonetype":"N95","cat":"WP"}`
JSONObject jsonObj = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");
I use the same way in my code . My string is
{"ApiInfo":{"description":"userDetails","status":"success"},"userDetails":{"Name":"somename","userName":"value"},"pendingPushDetails":[]}
string mystring= mystring.replace("\"", "\\\"");
And after replace I got the result as this
{\"ApiInfo\":{\"description\":\"userDetails\",\"status\":\"success\"},\"userDetails\":{\"Name\":\"Sarath Babu\",\"userName\":\"sarath.babu.sarath babu\",\"Token\":\"ZIhvXsZlKCNL6Xj9OPIOOz3FlGta9g\",\"userId\":\"118\"},\"pendingPushDetails\":[]}
when I execute JSONObject jsonObj = new JSONObject(mybizData);
I am getting the below JSON exception
org.json.JSONException: Expected literal value at character 1 of
Please help me to solve my issue.
Remove the slashes:
String json = {"phonetype":"N95","cat":"WP"};
try {
JSONObject obj = new JSONObject(json);
Log.d("My App", obj.toString());
} catch (Throwable t) {
Log.e("My App", "Could not parse malformed JSON: \"" + json + "\"");
}
This method works
String json = "{\"phonetype\":\"N95\",\"cat\":\"WP\"}";
try {
JSONObject obj = new JSONObject(json);
Log.d("My App", obj.toString());
Log.d("phonetype value ", obj.getString("phonetype"));
} catch (Throwable tx) {
Log.e("My App", "Could not parse malformed JSON: \"" + json + "\"");
}
try this:
String json = "{'phonetype':'N95','cat':'WP'}";
You just need the lines of code as below:
try {
String myjsonString = "{\"phonetype\":\"N95\",\"cat\":\"WP\"}";
JSONObject jsonObject = new JSONObject(myjsonString );
//displaying the JSONObject as a String
Log.d("JSONObject = ", jsonObject.toString());
//getting specific key values
Log.d("phonetype = ", jsonObject.getString("phonetype"));
Log.d("cat = ", jsonObject.getString("cat");
}catch (Exception ex) {
StringWriter stringWriter = new StringWriter();
ex.printStackTrace(new PrintWriter(stringWriter));
Log.e("exception ::: ", stringwriter.toString());
}
just try this ,
finally this works for me :
//delete backslashes ( \ ) :
data = data.replaceAll("[\\\\]{1}[\"]{1}","\"");
//delete first and last double quotation ( " ) :
data = data.substring(data.indexOf("{"),data.lastIndexOf("}")+1);
JSONObject json = new JSONObject(data);
To get a JSONObject or JSONArray from a String I've created this class:
public static class JSON {
public Object obj = null;
public boolean isJsonArray = false;
JSON(Object obj, boolean isJsonArray){
this.obj = obj;
this.isJsonArray = isJsonArray;
}
}
Here to get the JSON:
public static JSON fromStringToJSON(String jsonString){
boolean isJsonArray = false;
Object obj = null;
try {
JSONArray jsonArray = new JSONArray(jsonString);
Log.d("JSON", jsonArray.toString());
obj = jsonArray;
isJsonArray = true;
}
catch (Throwable t) {
Log.e("JSON", "Malformed JSON: \"" + jsonString + "\"");
}
if (object == null) {
try {
JSONObject jsonObject = new JSONObject(jsonString);
Log.d("JSON", jsonObject.toString());
obj = jsonObject;
isJsonArray = false;
} catch (Throwable t) {
Log.e("JSON", "Malformed JSON: \"" + jsonString + "\"");
}
}
return new JSON(obj, isJsonArray);
}
Example:
JSON json = fromStringToJSON("{\"message\":\"ciao\"}");
if (json.obj != null) {
// If the String is a JSON array
if (json.isJsonArray) {
JSONArray jsonArray = (JSONArray) json.obj;
}
// If it's a JSON object
else {
JSONObject jsonObject = (JSONObject) json.obj;
}
}
Using Kotlin
val data = "{\"ApiInfo\":{\"description\":\"userDetails\",\"status\":\"success\"},\"userDetails\":{\"Name\":\"somename\",\"userName\":\"value\"},\"pendingPushDetails\":[]}\n"
try {
val jsonObject = JSONObject(data)
val infoObj = jsonObject.getJSONObject("ApiInfo")
} catch (e: Exception) {
}
Here is the code, and you can decide which
(synchronized)StringBuffer or
faster StringBuilder to use.
Benchmark shows StringBuilder is Faster.
public class Main {
int times = 777;
long t;
{
StringBuffer sb = new StringBuffer();
t = System.currentTimeMillis();
for (int i = times; i --> 0 ;) {
sb.append("");
getJSONFromStringBuffer(String stringJSON);
}
System.out.println(System.currentTimeMillis() - t);
}
{
StringBuilder sb = new StringBuilder();
t = System.currentTimeMillis();
for (int i = times; i --> 0 ;) {
getJSONFromStringBUilder(String stringJSON);
sb.append("");
}
System.out.println(System.currentTimeMillis() - t);
}
private String getJSONFromStringBUilder(String stringJSONArray) throws JSONException {
return new StringBuffer(
new JSONArray(stringJSONArray).getJSONObject(0).getString("phonetype"))
.append(" ")
.append(
new JSONArray(employeeID).getJSONObject(0).getString("cat"))
.toString();
}
private String getJSONFromStringBuffer(String stringJSONArray) throws JSONException {
return new StringBuffer(
new JSONArray(stringJSONArray).getJSONObject(0).getString("phonetype"))
.append(" ")
.append(
new JSONArray(employeeID).getJSONObject(0).getString("cat"))
.toString();
}
}
May be below is better.
JSONObject jsonObject=null;
try {
jsonObject=new JSONObject();
jsonObject.put("phonetype","N95");
jsonObject.put("cat","wp");
String jsonStr=jsonObject.toString();
} catch (JSONException e) {
e.printStackTrace();
}
Following is My Json File:-
"Restaurants":{
"8":{
"Res_name":"Purple Cafe and Wine Bar",
"foodtype":"American, Wine",
"city":"Seattle",
"state":"WA",
"latitude":"0",
"longitude":"0"
},
"9":{
"Res_name":"Quinn's",
"foodtype":"American, Pubs",
"city":"Seattle",
"state":"WA",
"latitude":"0",
"longitude":"0"
},
"19":{
"Res_name":"Dahlia Lounge",
"foodtype":"American",
"city":"Seattle",
"state":"WA",
"latitude":"0",
"longitude":"0"
},
},
I am Using below code for json parsing:-
try {
JSONObject jsonObj = new JSONObject(res);
JSONObject mRestaurant = jsonObj.getJSONObject("Restaurants");
String mResult = jsonObj.getString("Result");
System.out.println("mRestaurant is:- " + mRestaurant);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
The mRestaurant Value is below:-
{"487":{"state":"WA","Res_name":"SAM Taste","longitude":"0","latitude":"0","foodtype":"American","city":"Seattle"},"332":{"state":"WA","Res_name":"Luna Park Cafe","longitude":"0","latitude":"0","foodtype":"American","city":"Seattle"},"35":{"state":"WA","Res_name":"Restaurant Zoe","longitude":"0","latitude":"0","foodtype":"American, Bar","city":"Seattle"},"
but what is the next step for getting Res_Name, foodtype from above response.
Any Help would be appreciated.
The below code is next step for json parsing.
public void getdata() {
String res = mWebRequest.performGet(Constants.url+ "restaurants.php? action=searchRestaurant&lat=0&lon=0&foodtype="+ mEdttxtSearch.getText().toString() + "&state="+ mEdttxtSearch.getText().toString() + "&city="+ mEdttxtSearch.getText().toString()+ "&devType=Android");
System.out.println("res is:- " + res);
if (res != null) {
try {
JSONObject jsonObj = new JSONObject(res);
JSONObject mRestaurants = jsonObj.getJSONObject("Restaurants");
String mResult = jsonObj.getString("Result");
if (jsonObj.has("Restaurants")) {
Iterator<Object> keys = mRestaurants.keys();
while (keys.hasNext()) {
String key = (String) keys.next();
JSONObject obj = new JSONObject();
obj = mRestaurants.getJSONObject(key);
mRes_Name.add(obj.getString("Res_name"));
mLatitude.add(obj.getString("latitude"));
mLongitude.add(obj.getString("longitude"));
mState.add(obj.getString("state"));
mCity.add(obj.getString("city"));
mFood_Type.add(obj.getString("foodtype"));
}
}
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
Use the get() method:
String mRestaurant = jsonObj.get("487").get("Res_name");
use gson for the same, as it supports direct conversion from json to java and java to json, please see following link:
Converting JSON to Java