I have a zip file which I'm listing and sorting each file inside by iterating through the stream using zis.getNextEntry().
Works fine for getting String objects from the ZipEntry, what I need is to save a copy to a directory in my application.
The directory part I'm fine with I just need to know how to save each bitmap straight away, without necessarily decoding it and creating a Bitmap object in memory.
This is my code to get each of the text file's contents.
if (decodeFile) { // WE ARE LOOKING AT A FILE WE CAN DECODE
while ((read = zis.read(buffer, 0, 1024)) >= 0) {
String string = new String(buffer, 0, read);
s.append(string);
}
stringArray.add(s.toString());
} else { // WE ARE LOOKING AT AN IMAGE/DIRECTORY
}
Thanks in advance.
if (decodeFile) { // WE ARE LOOKING AT A FILE WE CAN DECODE
FileWriter fw = new FileWriter("path/name.ext");
while ((read = zis.read(buffer, 0, 1024)) >= 0) {
String string = new String(buffer, 0, read);
fw.write(string);
}
fw.close();
} else { // WE ARE LOOKING AT AN IMAGE/DIRECTORY
}
Maybe like so?
You should simply create an OutputStream and instead of reading values to String write them directly to the OutputStream.
It should be something like this:
ZipFile zipFile = new ZipFile("foo.zip");
InputStream in = null;
OutputStream out = new FileOutputStream("...");
in = zipFile.getInputStream(zipFile.getEntry("yourbitmap.jpg"));
byte data[] = new byte[1024];
while ((count = in.read(data, 0, 1024)) != -1) {
out.write(data, 0, count);
}
Related
I use this code but it fails at the file outputstream.
When i make a static void then getResources will fail.
public void copy (Context context) {
InputStream in = getResources().openRawResource(R.raw.high1);
FileOutputStream out = new FileOutputStream("/sdcard/pic1.jpg");
byte[] buff = new byte[1024];
int read = 0;
try {
while ((read = in.read(buff)) > 0) {
out.write(buff, 0, read);
}
} finally {
in.close();
out.close();
}
}
To getResources() do not fail when changing it to static, modify the line:
InputStream in = getResources().openRawResource(R.raw.high1);
To:
InputStream in = context.getResources().openRawResource(R.raw.high1);
Additionally, quoting CommonsWare:
NEVER HARDCODE PATHS. Use getExternalFilesDir(), or Environment.getExternalStoragePublicDirectory(), or something like that to get a directory on external storage to use.
I've a functionality in my application in which I save a doc/img file path in my database. This file is lying in a folder (E.g. "/mnt/sdcard/MyApp/MyItem/test.png"). Now what i want to do is to copy this file to other folder (E.g. /mnt/sdcard/MyApp/MyItem/Today/test.png).
Right now I am using the code below but it's not working :
private void copyDirectory(File from, File to) throws IOException {
try {
int bytesum = 0;
int byteread = 0;
InputStream inStream = new FileInputStream(from);
FileOutputStream fs = new FileOutputStream(to);
byte[] buffer = new byte[1444];
while ((byteread = inStream.read(buffer)) != -1) {
bytesum += byteread;
fs.write(buffer, 0, byteread);
}
inStream.close();
fs.close();
} catch (Exception e) {
}
}
and on button click am using the following code :
File sourceFile = new File(fileList.get(0).getAbsolutePath); //comes from dbs
File targetFile = new File(Environment.getExternalStorageDirectory(),"MyApp/MyItem/Today/");
copyDirectory(sourceFile,targetFile, currDateStr);
Any idea why it's not working?
This code is working fine for me.
public void copy(File src, File dst) throws IOException {
InputStream in = new FileInputStream(src);
OutputStream out = new FileOutputStream(dst);
// Transfer bytes from in to out
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
in.close();
out.close();
}
And one more thing have you added in Manifest file *permission to write to external storage.*
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
Yup got it working, I was not giving file name while copying the files, and didnt really look at error log, got it working now thanks. And yea the above code works just fine.
I need to get image from the web and store it in the phone for later use.
I tryed this:
public Drawable grabImageFromUrl(String url) throws Exception
{
return Drawable.createFromStream((InputStream)new URL(url).getContent(), "src");
}
So this my function to grab image from Url, i just need a proccess to get the returned drawable and save.
How can i do that ?
see this complete example give here
http://android-example-code.blogspot.in/p/download-store-and-read-images-from.html
Based off here, you can actually download the image using a different method. Is it absolutely necessary that you store it as a drawable before saving it? Because I think you could save it first, and THEN open it, if need be.
URL url = new URL ("file://some/path/anImage.png");
InputStream input = url.openStream();
try {
//The sdcard directory e.g. '/sdcard' can be used directly, or
//more safely abstracted with getExternalStorageDirectory()
String storagePath = Environment.getExternalStorageDirectory();
OutputStream output = new FileOutputStream (storagePath + "/myImage.png");
try {
byte[] buffer = new byte[aReasonableSize];
int bytesRead = 0;
while ((bytesRead = input.read(buffer, 0, buffer.length)) >= 0) {
output.write(buffer, 0, bytesRead);
}
} finally {
output.close();
}
} finally {
input.close();
}
I'm trying to copy an xml file from the res/xml folder to the device storage but I'm really struggling on how to do this.
I know that the starting point is to get an InputStream to read the xml file. This is achieved by using this:
InputStream is = getResources().openRawResource(R.xml.xmlfile);
Eventually the output stream will be:
file = new File("xmlfile.xml");
FileOutputStream fileOutputStream = new FileOutputStream(file);
But I'm really struggling on how to read and copy all the information from the initial xml file correctly and accurately.
So far, I've tried using various InputStream and OutputStream to read and write (DataInputStream, DataOutputStream, OutputStreamWriter, etc.) but I still didn't managed to get it correctly. There are some unknown characters (encoding issue?) in the produced xml file. Can anyone help me on this? Thanks!
From res/xml you can't you have to put all files in your assets folder then use below code
Resources r = getResources();
AssetManager assetManager = r.getAssets();
File f = new File(Environment.getExternalStorageDirectory(), "dummy.xml");
InputStream is = = assetManager.open("fileinAssestFolder.xml");
OutputStream os = new FileOutputStream(f, true);
final int buffer_size = 1024 * 1024;
try
{
byte[] bytes = new byte[buffer_size];
for (;;)
{
int count = is.read(bytes, 0, buffer_size);
if (count == -1)
break;
os.write(bytes, 0, count);
}
is.close();
os.close();
}
catch (Exception ex)
{
ex.printStackTrace();
}
I think you should use the raw folder instead. Have a look at http://developer.android.com/guide/topics/resources/providing-resources.html.
You can also use this code:
try {
InputStream input = getResources().openRawResource(R.raw.XZY);
OutputStream output = getApplicationContext().openFileOutput("xyz.mp3", Context.MODE_PRIVATE);
byte data[] = new byte[1024];
long total = 0;
int count;
while ((count = input.read(data)) != -1) {
total += count;
output.write(data, 0, count);
}
output.flush();
output.close();
input.close();
} catch (Exception e) {
}
And when you need file use this code:
File k =getApplicationContext().getFileStreamPath("xyz.mp3");
I am currently writing an application that reads a zip file in my assets folder which contains a bunch of images. I am using the ZipInputStream API to read the contents and then writing each file to my: Environment.getExternalStorageDirectory() directory. I have everything working but the first time the application is run writing the images to the storage directory is INCREDIBLY slow. It takes about about 5 minutes to write my images to disc. My code looks like this:
ZipEntry ze = null;
ZipInputStream zin = new ZipInputStream(getAssets().open("myFile.zip"));
String location = getExternalStorageDirectory().getAbsolutePath() + "/test/images/";
//Loop through the zip file
while ((ze = zin.getNextEntry()) != null) {
File f = new File(location + ze.getName());
//Doesn't exist? Create to avoid FileNotFoundException
if(f.exists()) {
f.createNewFile();
}
FileOutputStream fout = new FileOutputStream(f);
//Read contents and then write to file
for (c = zin.read(); c != -1; c = zin.read()) {
fout.write(c);
}
}
fout.close();
zin.close();
The process of reading the contents of the particular entry and then writing to it is VERY slow. I am assuming it is more to do with reading than writing. I've read that you can use a byte[] array buffer to speed up the process but this does not seem to work! I tried this but it only read part of the file...
FileOutputStream fout = new FileOutputStream(f);
byte[] buffer = new byte[(int)ze.getSize()];
//Read contents and then write to file
for (c = zin.read(buffer); c != -1; c = zin.read(buffer)) {
fout.write(c);
}
}
When I do that I only get about 600-800 bytes written. Is there a way to speed this up?? Have I implemented the buffer array incorrectly??
I found a much better solution which implements the BuffererdOutputStream API. My solution looks like this:
byte[] buffer = new byte[2048];
FileOutputStream fout = new FileOutputStream(f);
BufferedOutputStream bos = new BufferedOutputStream(fout, buffer.length);
int size;
while ((size = zin.read(buffer, 0, buffer.length)) != -1) {
bos.write(buffer, 0, size);
}
//Close up shop..
bos.flush();
bos.close();
fout.flush();
fout.close();
zin.closeEntry();
I managed to increase my load time from anywhere from an average of about 5 minutes to about 5 (depending on how many images are in the package). Hope this helps!
Try use http://commons.apache.org/io/
like:
InputStream in = new URL( "http://jakarta.apache.org" ).openStream();
try {
System.out.println( IOUtils.toString( in ) );
} finally {
IOUtils.closeQuietly(in);
}