I am creating an AlertDialog using an AlertDialog.Builder and showing it. After showing it, I need to pause application until the user comfirms the Dialog.
I exactly need to pause in a method showing Dialog thread, because its calling method throws a fatal error after return.
Is there any way to do that?
In Android, you can't pause the UI-Thread, as it will result in the OS showing the Application is not responding dialog after about 5 seconds of being paused.
Also, as mentioned by CommonsWare in the comments, Dialogs don't operate in a separate thread.
Without seeing your code it's a bit difficult to answer, but what I could suggest right now is place all the code you need to "pause" in an AsyncTask.
You can place all the code before the pause in the onPreExecute() method, than show your dialog, and in the doInBackground() method, maybe in a while loop or something with volatile variables or something (this code runs on a background thread so it won't stuck the UI-Thread) and then the code after the pause in the onPostExecute() method.
both onPreExecute() and onPostExecute() operates on the UI-Thread. the onPost is called after the doInBackground has finished.
But again, if you'd show some code of the pause it would be easier to help you.
Further reading: AsyncTask
Another way to handle this is to use threads. In a non-UI thread, call your AlertDialog's show() method using the runOnUiThread() method of your Activity. Call Object.wait() in your non-UI thread, and call Object.notifyAll() in your AlertDialog's OnClickListener. The non-UI thread will then wait until the user clicks on your AlertDialog.
Related
I am new in Kotlin, I have a first activity with login, and second activity with recycle view. The data of recicle view is taken from http3 method.
Sorry for my bad english.
How I can show a dialogPopUp when I have code 404, and return in previous one login activity?
OkHttp callbacks are executed on a background thread if you use enqueue and showing a dialog is a UI task therefor it needs to be run on the UI thread.
In your case you can easily do this by running your dialog code using runOnUiThread.
runOnUiThread {
dialogPopUp("Error parameters", mContext ).showDialog()
}
Just as you have done in your else block.
You can also achieve this by using a Handler which has been created on the UI thread.
Update: Taking a closer look at your code I realized you're running fetchJson in a background thread by using the doAsync function. When you use enqueue on a OkHttp.Call you're basically sending it to be executed on a background thread so no need to use doAsync.
If you remove the doAsync you don't need to use runOnUiThread anymore as the callback will be executed on the UI thread.
Can't create handler inside thread that has not called Looper.prepare()
This basically means that you need to use the UI thread when calling this code. The UI thread will need to be used for showing your dialog.
You can do:
runOnUiThread {
dialogPopUp("Error parameters", mContext ).showDialog()
}
my AsyncTask should wait till event in the UI-thread happen.
so, I started to have simple while loop. However, in some of the devices that caused the UI thread to freeze. so after reading the following answer:
Fatal Spin-On-Suspend/Stuck on ThreadID
[However, it is not quite the same - i put the while in the async-task not in main-activity]
I added Thread.sleep - and it seem to indeed solve the problem.
However, I feel like I'm doing something wrong here...I wonder what is the right way to do it.
Do not ever sleep or block the UI thread. Wait in the background thread of the AsyncTask.
One way is as suitianshi is pointing out with wait()/notifyAll(). Another one is to use a CountDownLatch:
In the UI thread create a latch: CountDownLatch latch = new CountDownLatch(1);
Subclass AsyncTask so that it takes a latch in the constructor and save it to a reference mLatch
in doInBackground(), when you need to wait call mLatch.await(). This will block the AsyncTask
in the UI, when the event you're waiting happens, call latch.countDown()
You should be good to go from here.
My opinion is going to be different...
my AsyncTask should wait till event in the UI-thread happen.
AsyncTask's are great for long running operations like http downloads, long i/o operations, image resizing, or any cpu intensive operation that would freeze the UI thread.
However, Android runs AsyncTasks sequentially and not in a pool by default. More details here.
So if you have an AsyncTask that runs indefinitely, such as waiting for a UI action, you could likely block other AsyncTasks from running. Leading to more deadlock and threading problems.
I would suggest any of the following:
Use a different Executor for your AsyncTask so it runs similarly as it does today, but not to conflict with other AsyncTask items. This is the easiest approach.
Split your AsyncTask up into multiple tasks. The first one does whatever your current AsyncTask does up until the wait. The second one does whatever your current one does after the UI event. The latter task gets queued by the UI that generated the event.
Use a dedicated Thread. Use the Handler class to marshall events back from the thread to the UI thread as appropriate.
AsyncTask is introduced for running things which takes long time. In earlier android OS, it can be done in main thread or UI thread. But now android forces us to do long running things in AsyncTask to make UI thread responsive. If you want during AsyncTask your android UI do nothing then you can simply add progress Dialog during it. Start progress Dialog in onPreExecute() & end it in onPostExecute(String[] result).
Sample code : in AsyncTask
#Override
protected void onPreExecute() {
dialog = new ProgressDialog(MainActivity.this);
dialog.setMessage("Loading, please wait...");
dialog.setIndeterminate(true);
dialog.show();
}
#Override
protected void onPostExecute(String[] result) {
if (dialog.isShowing()) {
dialog.dismiss();
}
// do something with result
}
Thanks
I use a code that access HTTP service to receive login data, and before it, I tried to show a processing dialog, but it did not showed up. Then I tried to simply change the button label to tell the user to wait until data returns, but it also did not work. That's my code:
tryingToLoginDialog = ProgressDialog.show(this, "Por Favor Aguarde", "Efetuando Login...", true);
btn_Entrar.setText("Wait while logins...");
btn_Entrar.invalidate();
App.webService.Login(txtLogin.getText().toString(), txtSenha.getText().toString());
String LoginUserData = App.webService.getUserData(); /* this method freezes the app but do not crash it cause ThreadPolicy permit all*/
/* here some if's */
tryingToLoginDialog.dismiss();
btn_Entrar.setText("Login");
btn_Entrar.invalidate();
You should use AsynTask. This has 4 different method doInBackground() This method run in background(not in UI Thread) In your case you can do your networking stuff here and other three methods are onProgressUpdate(), onPostExecute() and onPreExecute() run in UI Thread So you can use these function to update GUI.
You were saying you want to show dialog so setup progressdialog in onPreExecute() and do your freezing stuff in doInBackground() and use other method according to your need.
See detail here
I have an Android App that uses an RPC mechanism to set/get information to/from a server. I call the RPCs from whithin the main thread (blocking) and I want them to be blocking. However, sometimes a call can last for some seconds and I'd like to display an indeterminate progress dialog after some specified time (e.g. 1 second).
I tried to spawn a new thread that makes the call and the main thread waits in a loop (with sleeps) until the call has been finished. Inside this loope I show the progress dialog but this is not working.
Is it possible to show and update the progress dialog inside another Thread or does anybody know a better solution that allows me to use blocking calls?
You cannot do both, make the main thread wait in a loop and show a progress dialog, at the same time. Either the main thread waits or shows the dialog.
Why do you want to block the main thread? Communication over the internet should always be done in a background thread because you never know how long it will take to complete. Do that stuff in AsyncTask and show the progress dialog in main.
Try using AsyncTask. It is an android mechanism which is used to make such network calls. Get the brief detailing of AsyncTask here:
Using AsynTask to show progress bar while attempting to SSH to Server
Using a AsyncTask you can block the user from proceeding ahead. You have to show a progress dialog in the onPreExecute() method of the AsyncTask. All your network related activities will take place in doInBackground(). After the background action is completed there will be a call to onPostExecute() where the progress dialog will be dismissed.
AsyncTask is a asynchronous call because you have 2 threads working simultaneously, one is the UI thread on which you are showing your progress dialog and the other is the non-ui background thread which is fetching your data from the server.
Hope this explanation helps.
I have found a solution that seems to work (at least I havent noticed any problems yet). I know the proper way would be to use somethn like AsyncTask but in my case I have no benefit from it and it complicates the program logic.
To update the UI within a new thread:
new Thread()
{
public void run()
{
Looper.prepare();
... do UI stuff here
Looper.loop();
}
}.start();
I am developing my first Androïd application and I'm facing a problem when I want to display a ProgressDialog to indicate that a process is being run.
In my application, the user triggers a time consuming task by pressing a Button. The "OnClick" function of my "OnClickListener" is called when the user presses the Button. In this function, here is what I'm currently doing :
- creation and configuration of an instance of the ProgressDialog class,
- creation of a thread dedicated to the time consuming task,
- attempt to display the ProgressDialog using the "show" method,
- start of the thread,
- main Activity suspended (call of the "wait" function)
- wake up of the main Activity by the thread when it is finished
- removal of the ProgressDialog by calling the "dismiss" function.
Everything works fine (the result of the long task is correct) but the ProgressDialog nevers appears. What am I doing wrong?
Thanks in advance for the time you will spend trying to help me.
You should not call wait() to the Main Activity/UI thread, because this is actually freezing the UI including your ProgressDialog, so it has no time to fade in and will never be shown.
Try to use multithreading correctly: http://developer.android.com/resources/articles/painless-threading.html
final Handler transThreadHandler = new Handler();
public void onClick(View v) {
// show ProgressDialog...
new Thread(){
public void run(){
// your second thread
doLargeStuffHere();
transThreadHandler.post(new Runnable(){public void run(){
// back in UI thread
// close ProgressDialog...
}});
}
}.start();
}
I would suggest using AsyncTask, as it's purpose is exactly to handle this kind of problem. See here for instructions how to use it. Note that the linked page in Floern's answer also recommends the use of AsyncTask.
You would need to do the following:
subclass AsyncTask
override it's onPreExecute() method to create and show a ProgressDialog. (You could hold a reference to it in a member of your subclass)
override it's doInBackground() method to execute your time consuming action.
override it's onPostExecute() method to hide your dialog.
in your activity, create an instance of your subclass and call execute() on it.
If you make your subclass an inner class of your activity, you can even use all of your activity's members.