I want to print from my android application to the printer I registered with Google cloud print. But every time I tried printing the web page, I always got the document missing error. This is my code but I don't know which line is causing the error.
public void print() {
Uri docUri = Uri.parse("http://myserver.com/view/myusername");
String docMimeType = "text/html";
String docTitle = "myTestPage";
Intent printIntent = new Intent(myContext, PrintDialogActivity.class);
printIntent.setDataAndType(docUri, docMimeType);
printIntent.putExtra("title", docTitle);
startActivity(printIntent);
}
So basically, http://myserver.com/demo/view/myusername is the web page I want to print and text/html is the mime type I provide. Can someone tells me which part of it that causes the error because I tried the URL from my laptop browser and the web page is loaded. Thank you very much. :D
Well, I'm not sure what's wrong with my code, and I still haven't got the slightest idea what should the mime type be. So I came up with a solution:
Generate the html file programatically
Print it with "text/html" type
That should get it done. :)
Related
i have a url link am trying to send to my user, but the link breaks up cause. it sends the full link but about half of it is not underlined as a link. this is what am trying to send
String locateUrl="http://maps.google.com?q="+latitude()+","+longitude();
first it does not recognize this ?q= as a link and it just breaks up from there, have checked other answers and tried them but seems not to be working
Just solved this by putting "/" before ?q= thereby making sure the link doesn't break
full link will then be
String locateUrl="http://maps.google.com/?q="+latitude()+","+longitude();
Your link may be breaking because of space at the beginning or in between trim it and then use it.
String locateUrl="http://maps.google.com?q="+latitude()+","+longitude();
locateUrl = locateUrl.trim();
I am having a curious problem that perhaps someone has insight into. I encode a query string into a URL on Android using the following code:
request = REQUEST_BASE + "?action=loadauthor&author=" + URLEncoder.encode(author, "UTF-8");
I then add a few other parameters to the string and create a URI like this:
uri = new URI(request);
At a certain point, I pull out the query string to make a checksum:
uri.getRawQuery().getBytes();
Then I send it on its way with:
HttpGet get = new HttpGet(uri);
On the Appengine server, I then retrieve the string and try to match the checksum:
String query = req.getQueryString();
Normally, this works fine. However, there are a few characters that seem to get unencoded on the way to the server. For example,
action=loadauthor&author=Charles+Alexander+%28Ohiyesa%29+Eastman×tamp=1343261225838&user=1479845600
shows up in the server logs (and in the GAE app) as:
action=loadauthor&author=Charles+Alexander+(Ohiyesa)+Eastman×tamp=1343261226837&user=1479845600
This only happens to a few characters (like parentheses). Other characters remain encoded all the way through. Does anyone have a thought about what I might be doing wrong? Any feedback is appreciated.
I never did find a solution for this problem. I worked around it by unencoding certain characters on the client before sending things to the server:
request = request.replace("%28", "(");
request = request.replace("%29", ")");
request = request.replace("%27", "'");
If anyone has a better solution, I am sure that I (and others) would be interested!
URLEncoder does not encode parentheses and certain other characters, as they are supposed to be "safe" for most servers. See URLEncoder. You will have to replace these yourself if necessary.
Example:
URI uri = new URI(request.replace("(","%28"));
If a lot of replacements are needed, you can try request.replaceAll(String regularExpression, String replacement). This, of course, requires knowledge of regular expressions.
I'm having a slight problem opening a certain URL in the browser. First of all I use the following code to launch the browser:
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(Globals.currentChatURL));
startActivity(Intent.createChooser(browserIntent, "Select browser:"));
Now if I set Globals.currentChatURL to something like http://www.google.com then it opens that site just fine. But my URL is a little more complicated as it contains multiple parameters which are all base64 encoded. Here is an example of how my URL looks:
http://webportal.mysite.com/ChatProgram/chat.php? intgroup=UFYyMA==&intid=UFYyMEZN&hg=Pw__&pref=user&en=U0NPVFQgTUlMTEFS&ee=cGF1bGdAbWFnbmF0ZWNoLmNvbQ==&eq=UFRWRkVI&ec=TUFHTkFURUNI
Now if I use my above code to try and launch this URL it brings me to the Google search page with the following message:
"Your search - http://URLabove ... did not match any documents"
Yet if I copy the URL and paste it into the address box it brings me to the right place. How can I fix this?? The whole point of this is to have the user click the button and the site to launch, not for the user to have to copy and paste the URL manually.
Any suggestions would be greatly appreciated.
Thanks a lot
There is unwanted equal signs in the query part of your http URI. Such signs have a specific meaning as delimiters in the form ¶meter=value.
This equal signs represents padding values (0, 1 or 2) from your base64 encoding.
You can either
remove them because your base64 server decoder won't bother reconstructing them, or
percent encode them (with all other reserved characters).
In android you can use percent encode this way:
String value = URLEncoder.encode("annoying values with reserved chars &=#", "utf-8");
String url = "http://stackoverflow.com/search?q=" + value;
The RFC 2396 is now deprecated but that is what URI.parse() is based on as stated by the documentation:
uriString an RFC 2396-compliant, encoded URI
In my app I receive a URL such as
http://www.wassersportlotse.de/php/lib/smart_image_resizer/image.php/Mühlendammschleuse.jpg?image=/media/images/uploads/Mühlendammschleuse.jpg
When there are no German characters in the fullurl I can just use it without encoding and it works fine. However if I receive a URL such as the one above it doesn't work (the ü is causing the problem). Below I have tried to encode the seperate parts of the URI to no avail. As alway advice is very much appreciated.
public ImageDownloader(String fullurl) throws URISyntaxException{
URI uri = new URI(fullurl);
path = uri.getPath();
path = URLEncoder.encode(path);
query = uri.getQuery();
query = URLEncoder.encode(query);
auth = uri.getAuthority();
url = "http://" + auth + path + query;
}
Maybe the encoder das encode the Umlaut as UTF-8 characters (so ü would be encoded with two characters) and they are not put back together properly at the server (for us it didn't work with Tomcat). To solve this situation we used URLEncoder.encode(param, "ISO-8859-1") to encode the parameters.
There's no simple answer, because it depends on the server serving that URI which encoding is expected.
Usually it's UTF-8.
In that case: use String.getBytes, specifying the UTF-8 encoding, and obtain a byte array from that. Re-encode that byte array as string by taking all bytes <= 127 as-is, and substituting all others by the %hh form. (percent sign, then two hex digits). See http://greenbytes.de/tech/webdav/rfc3986.html#rfc.section.2.1.
You can use Android's Uri class to help you out. That class has an encode() method which will use UTF-8 to encode your string.
I recently had a problem with URLs for images whose names included umlauts and German special characters, and I lost a day looking for the solution. The images simply did not appear if there was an ä or and ü in the file name or the directory name. I thought it might be spring, or some other Java technology I am working with, or in the browser. And strangely enough, even with the url encoded, it failed to find the image. But in the end, the solution was in my tomcat server.xml configuration. In your server.xml file, find your connector and add these two lines:
URIEncoding="UTF-8"
useBodyEncodingForURI="true"
At the end, it should look something like this:
<Connector connectionTimeout="20000"
port="8080"
protocol="HTTP/1.1"
redirectPort="8443"
URIEncoding="UTF-8"
useBodyEncodingForURI="true"/>
Now I do not need to url-encode the url. This is a help to my clients, because they can see the German words in the urls spelled correctly.
Here is another tip: if you are coding in eclipse and starting and stopping your server from inside eclipse, then the configuration file (server.xml) could be in your eclipse workspace in the Servers folder. It must be changed here for it to work with eclipse. This can be maddening, when you have made the change in your principal tomcat configuration, and the urls work there, but they are still broken when running the server in eclipse.
That did it for me. I hope it helps someone out there! :-)
Have your tried unsing:
android.net.Uri.encode(urlString, ":/");
It encodes the string but skips ":" and "/".
Android Sharing Intent takes a string for the body.
How do you introduce a line break? Gmail appears to do plain text by default, and so I can't get any line breaks in my sharing message.
\n, , <br />, and 0x0A all don't work.
Okay \n does indeed work. And if you change the sharing intent setType to text\html, then < br />.
My problem was caused by issues inside HTML templating and then sent through a phonegap sharing plugin.