Movie_search is a text field got from the user and ive referenced it by using
movie_search= (EditText)findViewById(r.id.editText);
and same goes for the button too
btn.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
Log.i(NEWS,"IMDB LINK->:"+movie_search);
URL="http://www.omdbapi.com/?t="+movie_search+"";
Log.i(NEWS,"IMDB LINK->:"+URL);
new DownloadConfigurationTask().execute(URL);
}
});
the problem is the string doesnt seem to append to the url,
the log i get is
IMDB LINK->:movie_search
IMDB LINK->:http://www.omdbapi.com/?t=
instead of
IMDB LINK->:movie_search
IMDB LINK->:http://www.omdbapi.com/?t=movie_search
any ideas what might be the problem ?
use EditText.getText() for getting text entered by user and append it with URL instead of EditText instance. change it as:
URL="http://www.omdbapi.com/?t="+movie_search.getText()+"";
Related
please predecessors, Am creating a web browser homepage in android studio and want to be able to input URL from the same editText as that of my search.
have been able to take search and load google results, but URL still end up in searched instade of loading the URL website.
this is my codes.
EditText searchEditText = rootView.findViewById (R.id.searchEditText);
ImageButton searchBt = rootView.findViewById (R.id.searchBt);
searchBt.setOnClickListener (new View.OnClickListener ( ) {
#Override
public void onClick(View v) {
String searchQuery = searchBar.getText ().toString ();
if(URLUtil.isValidUrl (searchQuery)){
webView.loadUrl (searchQuery);
}else {
String searchURL = "https://www.google.com/search?q="+searchQuery;
webView.loadUrl (searchURL);
}
}
});
The problem is probably because your URL doesn't have https at the beginning.
Try using some other mechanism to determine if the URL is valid.
For example, use WEB_URL pattern in Patterns Class
Patterns.WEB_URL.matcher(potentialUrl).matches()
I am creating an android application wherein I have mentioned the phone number, email, website of the business similar to the screenshot of google maps as attached.
Just like in the g maps where
Single click makes an intent to the respective app (opens dialer with phone number copied) etc.
Long Click/Press & hold will copy the number to clipboard displaying a toast that "Phone number is copied to clicpboard".
Now I have set up the intents properly and they are working fine --> step-1 achieved.
When I try to display the toast using "OnLongClickListener" method it is taking quite some time to display the toast message. Is there any way we can speed this up or am I missing something or should I use some other alternative like onTouch() method?
(Stuck with this, yet to learn and try out copying to clipboard thing. Inputs in this regards are also welcome!)
In the g maps app, the toast message appears almost instantly on press & hold. So the same is to be achieved.
The code extract from MainActivity.java (The website, phone number, email id are text views with drawableLeft. And I found out that we cannot use setOnItemLongClick on TextView as it is only for ListView)
// This method is called when the website text view is clicked and opens the compnay website
public void openWebsite(View v) {
TextView textView = (TextView) findViewById(R.id.webURL_text_view);
textView.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View view) {
Intent openWebsiteIntent = new Intent(Intent.ACTION_VIEW);
openWebsiteIntent.setData(Uri.parse("https://www.company.com"));
if (openWebsiteIntent.resolveActivity(getPackageManager()) != null) {
startActivity(openWebsiteIntent);
}
}
});
textView.setOnLongClickListener(new View.OnLongClickListener() {
#Override
public boolean onLongClick(View view) {
showMessage();
return true;
}
});
}
public void showMessage(){
Toast.makeText(this,"Information copied to Clipboard", Toast.LENGTH_LONG).show();
}
I am new to android development and just trying out something, so please be as elaborative as possible. Thank You.
I have a problem that I want to use jsoup to grab news but always fail.
this is news website.
https://www3.nhk.or.jp/news/
this is my picture . which I circle is I wanted data.
https://drive.google.com/open?id=1KJAyOSdHO8APPD6_A9MjxkoFjekcQLXt
but no matter what I do. it always get wrong data or empty.
this is my program.
public class News extends AppCompatActivity {
Button ok;
private static final String url ="https://www3.nhk.or.jp/news/";
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.news);
ok=(Button)findViewById(R.id.ok);
ok.setOnClickListener(okbtn);
}
private Button.OnClickListener okbtn=new Button.OnClickListener(){
public void onClick(View v){
try{
Connection.Response response = Jsoup.connect(url).execute();
String body = response.body();
Document data = Jsoup.parse(body);//visible-phone print_hide
Elements country=data.select("main");
Elements main=data.select("div[id=module module--news-main index-main]");
for(Element e1: country)
{
mytoast(e1+"");
}
}
catch(Exception ex){ex.printStackTrace() ;}
}
};
private void mytoast(String str)
{
Toast toast=Toast.makeText(this, str, Toast.LENGTH_LONG);
toast.setGravity(Gravity.CENTER, 0, 0);
toast.show();
}
}
please help me
thanks
You can try to see it's HTML first.
If you can't see it, you don't use jsoup.
There's a small hint in its comment:
このページではJavaScriptを使用しています
=>This is generated by JavaScript
If it's generated, you can't find it from Jsoup.
In this case, I'll use Chrome's tool to monitor the XHR tab
Look into each XHR request, and find the most possible one,
for example, I see this
https://www3.nhk.or.jp/news/json16/syuyo.json?_=1559183885640
A part of the response:
"id":"193411",
"title":"三菱UFJ銀行 新規口座は原則デジタル通帳に",
"pubDate":"Thu, 30 May 2019 04:03:11 +0900",
"cate":"5",
...
"id":"193437",
"title":"エアレース世界選手権 今季限りで終了",
"pubDate":"Thu, 30 May 2019 09:40:37 +0900",
So this is exactly what you want. It comes from another link!
You don't need Jsoup, just HttpGet the link
https://www3.nhk.or.jp/news/json16/syuyo.json?_=1559183885640
And I think the numbers looks like UnixTime,
So I check the current time is : 1559184830782, that's it.
Just use that link as API and time as parameter.
I am working on an android app. I am having an EditText on which I have applied OnCllickListener().
EditText _input = new EditText(context);
_input.setSingleLine(true);
_input.setFocusable(false);
I am setting OnClickListener() on this EditText:
_input.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View view) {
// OnClick work here
}
});
I have applied some validations on this field and calling setError() method on this EditText. It shows that red icon of error in the EditTextwhen the validation fails. But when I click on that error icon it executes the OnClickListener() on this EditTextand I am not able to see the error occurred.
Is there any other way to do so, so that I can handle both functions.
Thanks a lot in advanced !!!
You would check if currently the edit text is in an error state, within the onclick handler:
_input.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View view) {
if (view.getError() == null) {
// do not handle the click
return;
}
}
});
You can check for an error like like this:
if(view.getError() == null) return;
See the doc here
getError()
Returns the error message that was set to be displayed with
setError(CharSequence), or null if no error was set or if it the error
was cleared by the widget after user input.
Source
I have solved this with a simple solution. Just set text of editText to empty string before setting error and error message will show again like without onClickListener.
I have a simple app that I'm putting together for my company. I have 4 buttons that I've created but can't seem to get them to link correctly. One button should open our mobile site, another button to call us, another button to map to us, and the final button linked to our "News" site. Any help would be greatly appreciated!
On your buttons, you should set OnClickListener, and to do some required actions you could see the example below:
To Open a Map with Certain Location
mapButton.setOnClickListener(new OnClickListener(){
#Override
public void onClick(View v) {
Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse("geo:0,0?q=" + your-location-geo-address));
startActivity(i);
}
});
To call certain number
callButton.setOnClickListener(new OnClickListener(){
#Override
public void onClick(View v) {
Intent i = new Intent(Intent.ACTION_DIAL, Uri.parse("tel:" + telephone-number));
startActivity(i);
}
});
To open a website
linkButton.setOnClickListener(new OnClickListener(){
#Override
public void onClick(View v) {
Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse(website-address));
startActivity(i);
}
});
Change "location-address", "telephone-number", and "website-address" with your own String value.
I hope this helps.
anmustangs answer is very good, but one thing I would like to add for the button you are making for a link to your site, where anmustangs wrote (website-address) instead of just typing in a site, it needs to put formatted correctly. For example, you can use "http://www.google.com" and yes you do need to use the quotation marks I put in there. I know I am years late to this thread but who knows who my post may help.