Develop Reference

Spliting a Text on multiple conditions

I am writing an app with Android Studio and I want to split a text into different values.
I have following text in result
*"Name: Peter;Age: 25; City: Chicago"*
I want to get:
*Name = Peter;
Age = 25;
City = Chicago;*
I used the search function and found these solutions: Android Split string but for my problem it seems to be too complicated.

The easiest way is to use split() method.
String s1="Name: Peter;Age: 25; City: Chicago";
String[] words=s1.split(";");
//using java foreach loop to print elements of string array
for(String w:words)
{
Log.i("Words: ", w);
}

what is the characters behind the characters down the line?

I am converting between "\n" to ":" in file .txt. And here, this is my paragraph before convert:
You can see that, between string "Hoa" and string "Đàm", it have one character " " and two character "\n". And this is my convert function:
private String convertData(){
String different = "~`!##$%^&*()-_=+*/\\\"'|]}{[:;?/.><,\n ";
StringBuilder data = new StringBuilder(tvData.getText().toString().trim());
for (int j = 0; j < data.length(); j++){
if(different.contains("" + data.charAt(j))) data.setCharAt(j, ':');
}
String convertData = data.toString().trim();
return convertData;
}
And this is result:
You can see behind character "\n" have a character, and it is not in string different.
Can anyone tell me what to do?

1 - Proceed like you're currently doing, but the \n (and the other escaped sequences).
So, use
String different = "~`!##$%^&*()-_=+*/'|]}{[:;?/.><, ";
2 - After the loop, use string.replace() to replace only the substring "\n" and the other sequences, i.e.: "\\" and "\"".
You could use a loop to replace the sequences, but you must replace 2 characters instead of one.
Basically, in the first loop you replace all the single characters.
Then, you replace the character sequences.

Notepad only supports Windows line endings (\r\n), so that must be what your file contains. Convert the file to Unix line endings (\n) using literally any program that is not Notepad, or add \r to your search pattern.

How to replace character at particular index in android?

I am working on android. I have a string containing huge data. In that string I want to replace a particular character to another character. I got the index of the character which I want to replace. But I am unable to replace that character.
How can I do that?
String str = "data1data2mdata2test1test2test3dd"
int ind = str.indexOf("m");
System.out.println("the index of m" + ind);
Now in the above string I want to replace the character "m"(after data2) to "#".
Now how can I replace the m to #. Please help me in this reagard.

You can use substring:
String newStr = str.substring(0, ind) + '#' + str.substring(ind + 1);

Try this:
str = str.replaceFirst("m", "#");
It will replace the first m to #

String str1 = "data1data2mdata2test1test2test3dd"
String str = str1.replace("m", "#");
System.out.println(str);

So you are getting 10 as system out,
so this way you can replace it like,
Str.replace('m', '#')--->when you want all occurrences of it to replace it,
Or if you want only first occurrence to be replaced by # then you can do following trick,
StringBuffer buff=new StringBuffer();
buff.append(Str.substring(0,ind)).append("#").append(Str.substring(ind+1));
i hope it would help

Parse a string and get certain values

I have a string like this:
_id:2 thread_id:189 address:0292 m_size:null person:0 date:1372494272447 date_sent:0 protocol:0 read:1 status:-1 type:1 reply_path_present:0 subject:null body:Ok. Reply message. service_center:051108 locked:0 sim_id:0 error_code:0 seen:1 _id:1 thread_id:189 address:292 m_size:null person:0 date:1372493695831 date_sent:0 protocol:null read:1 status:-1 type:2 reply_path_present:null subject:null body:Test message service_center:null locked:0 sim_id:0 error_code:0 seen:0
I want to retrieve only parts of this string, for example the address:0292 and the body:xyz from the entire string. I want all instances of these two from a very large String (above is just a sample). Let's assume its more than 20000 characters.
How can I achieve this?

Looks like every address is followed by m_size, so use the string.split() function, to split over the keyword address then select the string.substring() (from each string in the resulting array) until reaching the keyword m_size. And repeat the entire thing for the keywords body and service_center. I can't think of any other way.

You are right, it doesn't seem pretty. But it works :)
String[] splitString = string.split(" ");
for (int i = 0; i < splitString.length; i++) {
if (splitString[i].startsWith("body") || splitString[i].startsWith("address"))
Log.i(TAG, "Found: " + splitString[i]);
// Do whatever you need to do
}

Removing newline from string

Here's my issue:
I have a database and it is full of episodes of a tv show. One column denotes the episode number. I want to display the episodes in a list like this:
Episode 1
Episode 2
Episode 3
etc.
I'm using my own adapter class that extends SimpleCursorAdapter to do this...
Since I had formatting errors I am using Android.R.layout.simple_list_item_1 and Android.R.id.text1
Basically the only reason I have a custom adapter is so I can do something like this:
textView.setText("Episode " + cursor.getString("column_for_episode_number");
The problem is, I get a list that looks like this:
Episode
1
Episode
2
Episode
3
When I try something like this(which worked in a different portion of my code):
String text = "Episode " + cursor.getString("blah");
text = text.replaceAll("\\n","");
I get the exact same list output :(
Why don't I use create a custom view with two textboxes next to each other? It is hard for me to get that to look pretty :/

text.replaceAll(System.getProperty("line.separator"), "");

There is a mistake in your code. Use "\n" instead of "\\n"
String myString = "a string\n with new line"
myString = myString.replaceAll("\n","");
Log.d("myString",myString);

Check if there is new line at the beginning before you replace and do the same test again:
for(int i=0; cursor.getString("blah").length()-1; i++)
{
if(cursor.getString("blah").charAt(i)=='\\n') <-- use the constant for the line separator
{
Log.i("NEW LINE?", "YES, WE HAVE");
}
}
Or use the .contains("\n"); method:
Check the xml for the width of the textview as well.
Why are you using getString() when you are fetching an integer? Use getInt() and then use Integer.toString(theint) when you are setting the values in a textview.

This could help you:
response = response.replaceAll("\\s+","");

It sounds like you are hitting wrapping issues rather than newline issues. Change this:
String text = "Episode " + cursor.getString("blah");
To this:
String text = "Episode" + cursor.getString("blah");
And see if that changes the output. Post your layout xml please?

this worked for my (on android 4.4):
(where body is a string with a newline entered from an EditText view on handset)
for (int i=0; i<body.length(); i++) {
if (body.charAt(i) == '\n' || body.charAt(i) == '\t') {
body = body.substring(0, i) + " " + body.substring(i+1, body.length());
}
}

have you tried
cursor.getString("blah").trim()