I need to parse XML data from a web service. But, when I am getting the data from the web service the data comes in the format of JSON (In the browser I am seeing the data as XML). So, please guide me how to get xml data into my application.
I am using the following.
In my main activity:
static final String URL = "http://nclex.testshell.net/api/resources";
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL); // getting XML
Log.e("Response is...",xml);
My xmlParser class
public class XMLParser {
// constructor
public XMLParser() {
}
/**
* Getting XML from URL making HTTP request
* #param url string
* */
public String getXmlFromUrl(String url) {
String xml = null;
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
// return XML
return xml;
}
}
output response is
[{"ResourceId":1,"Title":"GRE revised General Test","Description":"The
Verbal Reasoning section of the GRE revised General
Test","Link":"http://www.ets.org/gre/revised_general/about/content/verbal_reasoning"},{"ResourceId":2,"Title":"GRE Power Pre","Description":"GRE Power
Pre","Link":"http://www.number2.com/exams/gre/companion/index.cfm?s=0"},{"ResourceId":3,"Title":"GRE Analytical Writing","Description":"GRE Analytical
Writing","Link":"http://www.mygretutor.com/tests.aspx"},{"ResourceId":4,"Title":"GATE
Architecture & Planning","Description":"GATE Architecture &
Planning","Link":"http://www.onestopgate.com/gate-sample-papers/architecture-planning/"},{"ResourceId":5,"Title":"TarGATE","Description":"GATE
to acheive your
target","Link":"http://gateforum.com/Testseries-Venue.php"},{"ResourceId":6,"Title":"TOEFL
iBT","Description":"TOEFL iBT Test Sample
Questions","Link":"https://www.ets.org/toefl/ibt/prepare/sample_questions"}]
The type or format of data you retrieved from the server using web service is totally depends on the language in which web service is implemented and the response code that web service choose to format the data..
Older web services or platforms mainly supports XML format.And the new web services uses the Json format for its light-weight.
In your case,Your web service supports both type of format(XML,Json) and it chooses the format as per the platform from which it receives the request(Mobile,Desktop).(May be it acts as a Generic Webservice).
One way to test the webservice response is to requesting it from platform browser i.e use your platform browser(Desktop or mobile) to see the response for your platform.
Finally,Answer to your question,
Change the code at your server side and make sure that it returns XML data as a response for Mobile platform(you don't have to worry about the code at your application side;all changes to be done at server side).
However,you can also convert Json to xml as,
JSONObject Jobj = new JSONObject(jsonString);
Then you can get it in XML format using the XML class, like so:
String xml = org.json.XML.toString(Jobj);
but it's not recommended as it need extra cpu time to convert Json to xml and it can be a problem if your response data is huge.
Related
I am developing an android app where user logs on to his/her account. After logging in I will receive XSRF token and Laravel Session Id to recognise the specific user. I have to send these tokens for every request I send to the API's to get the appropriate information. But when I am sending the required details as shown in the image, I am getting HTMl file as response instead of getting JSON Object. I was seriously stuck at this problem. Correct Solution may take forward the whole app.
class RegisterConnection extends AsyncTask<String,String,JSONObject> {
protected JSONObject doInBackground(String... arg0) {
JSONObject output = new JSONObject();
DefaultHttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 5000); //Timeout Limit
HttpResponse response = null;
try {
HttpGet get = new HttpGet(statsURL);
get.setHeader("Accept", "application/json");
CookieStore store = new BasicCookieStore();
BasicClientCookie cookie1 = new BasicClientCookie("XSRF-TOKEN", XSRF);
BasicClientCookie cookie2 = new BasicClientCookie("laravel_session", laravel);
store.addCookie(cookie1);
store.addCookie(cookie2);
client.setCookieStore(store);
response = client.execute(get);
if(response!=null){
InputStream in = response.getEntity().getContent();
String resultstring = Utilities.convertStreamToString(in);
Log.i("Result1", resultstring);
output = new JSONObject(resultstring);
Log.i("Result2", output.toString());
}
} catch(Exception e) {
e.printStackTrace();
try {
output.put("sai","error");
Log.i("MainActivity", output.toString());
} catch (JSONException e1) {
e1.printStackTrace();
}
return output;
}
return output;
}
These are the server requirements
http://imgur.com/OY9Q673
This is the Output received
http://imgur.com/IB5AEcT
As far as I can tell, there is nothing wrong with your Android client code.
You are getting HTML from the server so the main reason could be that your Laravel server is rendering the views and sending you back html instead of JSON. Instead of rendering the views on the server, you should send JSON response on your Laravel server side.
Add Jsoup dependency in your gradle file
implementation 'org.jsoup:jsoup:1.11.2'
Document document = Jsoup.parse("http://imgur.com/IB5AEcT");
Elements el = doc.select("button");
Log.i("..........",""+el.attr("data-invite-details"));
Jsoup tutorial
http://jsoup.org/apidocs/org/jsoup/Jsoup.html
Can anyone tell me which is the best, ease and flexible method to consume web service from android? I'm using eclipse.
Since you only care about consuming a webservice, I assume you already know how to send data from the web server. Do you use JSON or XML, or any other kind of data format?
I myself prefer JSON, especially for Android.
Your question still lacks some vital information.
I personally use apache-mime4j and httpmime-4.0.1 libraries for web services.
With these libraries I use the following code
public void get(String url) {
HttpResponse httpResponse = null;
InputStream _inStream = null;
HttpClient _client = null;
try {
_client = new DefaultHttpClient(_clientConnectionManager, _httpParams);
HttpGet get = new HttpGet(url);
httpResponse = _client.execute(get, _httpContext);
this.setResponseCode(httpResponse.getStatusLine().getStatusCode());
HttpEntity entity = httpResponse.getEntity();
if(entity != null) {
_inStream = entity.getContent();
this.setStringResponse(IOUtility.convertStreamToString(_inStream));
_inStream.close();
Log.i(TAG, getStringResponse());
}
} catch(ClientProtocolException e) {
e.printStackTrace();
} catch(IOException e) {
e.printStackTrace();
} finally {
try {
_inStream.close();
} catch (Exception ignore) {}
}
}
I make a request via _client.execute([method], [extra optional params])
The result from the request is put in a HttpResponse object.
From this object you can get the status code and the entity containing the result.
From the entity I take the content. The content would in my case be the actualy JSON string. You retrieve this as an InputStream, convert the stream to a string and do whatever you want with it.
For example
JSONArray result = new JSONArray(_webService.getStringResponse()); //getStringResponse is a custom getter/setter to retrieve the string converted from an inputstream in my WebService class.
Depending on how you build your JSON. mine is nested deeply with objects in the array etc.
But handling this is basic looping.
JSONObject objectInResult = result.getJSONObject(count);//count would be decided by a while or for loop for example.
You can extract data from the current JSON object in this case like:
objectInResult.getString("name"); //assume the json object has a key-value pair that has name as a key.
to parse "JSON" I recommend the following library is the faster and better.
Jackson Java JSON-processor
I've been looking online for how to pass parameters to RESTlet webservice but it seem there are not much tutorial concerning RESTlet.
I would like to send some parameters gathered from a form on my android application (it would be great if i could do this using JSON).
well i solved this
as for the server side
#Post
public JSONArray serverSideFunction(Representation entity)
throws JSONException {
try {
JSONObject req = (new JsonRepresentation(entity)).getJsonObject();
System.out.println(req.getString(/* filed name */));
System.out.println(req.getString(/* filed name */));
/*
* you can retrieve all the fields here
* and make all necessary actions
*/
} catch (IOException e) {
e.printStackTrace();
}
}
as for the Android Side
HttpClient client = new DefaultHttpClient();
String responseBody;
JSONObject jsonObject = new JSONObject();
try{
HttpPost post = new HttpPost(WebService_URL);
jsonObject.put("field1", ".........");
jsonObject.put("field2", ".........");
StringEntity se = new StringEntity(jsonObject.toString());
post.setEntity(se);
post.setHeader(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
post.setHeader("Content-type", "application/json");
Log.e("webservice request","executing");
ResponseHandler responseHandler = new BasicResponseHandler();
responseBody = client.execute(post, responseHandler);
/*
* You can work here on your responseBody
* if it's a simple String or XML/JSON response
*/
}
catch (Exception e) {
e.printStackTrace();
}
I hope this may be of help
In fact, it depends on what you want to do. With REST (see http://en.wikipedia.org/wiki/Representational_state_transfer), there are two ways to pass parameters or data. Before you need to understand some concepts:
Resource: the REST entity by itself.
Representation: corresponds to its state and can be gotten or updated using different HTTP methods. The kind of content is identified using the content type header (media type in Restlet).
Methods: the GET method is used to get the resource state, PUT to update it, POST to create a new resource and specify its state the same time, DELETE to delete a resource.
Restlet provides Java entities for REST elements.
So, after described that, you can see that passing data or parameters depends of your use case:
1°) Do you want to update the resource state? In this case, you will use the content of the request with methods like POST or PUT. The data structure is free from text, JSON, XML or binary... Restlet provides the ClientResource class to execute requests on RESTful applications. It also provides support to build the representation to send and extract data from the one received. In this case, your data gathered from a form will be used to build the representation. Here are some samples:
//Samples for POST / PUT
ClientResource cr = new ClientResource("http://...");
cr.post(new StringRepresentation("test"));
MyBean bean = new MyBean();
(...)
//Jackson is a tool for JSON format
JacksonRepresentation<MyBean> repr
= new JacksonRepresentation<MyBean>(bean);
cr.put(repr);
//Samples for GET
Representation repr1 = cr.get();
bean = (new JacksonRepresentation<MyBean>(repr1, MyBean.class)).getObject();
2°) Do you want to specify parameters on your GET requests (for example to configure data to retreive and so on)? In this case, you can simply add it on the ClientResource, as described below:
ClientResource cr = new ClientResource("http://...");
cr.getReference().addQueryParameter("q", "restlet");
Representation repr = cr.get();
In this case, your data gathered from a form will be used to build the parameters.
Hope it helps you.
Thierry
If you want request with json structure and your response as JSONObject maybe you can do like this in server side:
public class RequestJSON extends ServerRecource{
#Post("json")
public JSONObject testRequest(String entity){
JSONObject request = new JSONObject(entity);
String value1 = request.getString("key1");
int value2 = request.getInt("key2");
return /* your JSONObject response */;
}
}
And your request can be :
{"key1":"value1", "key2":value2}
I hope this can help you
I am creating a networking website's Application in android.I want to know how can I perform syncing ie I want to store all user contacts on websites to my android phone.
user's details will come in XML format.
Please Guide me ..
For that you have to make a web service call either by using HttpClient or by using other third-party libraries like kSoap2. But i would prefer native class instead of third-party library.
Here is a best example: http://lukencode.com/2010/04/27/calling-web-services-in-android-using-httpclient/
After making a call, you will receive a XML, after that you can parse the received XML response either by using SAX parser, Pull Parser or DOM Parser.
This is the scenario to fetch data from web to your local database.
For your info: To get response from Web:
public static InputStream getInputStreamFromWeb(String url) {
InputStream content = null;
try {
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = httpclient.execute(new HttpGet(url));
content = response.getEntity().getContent();
} catch (Exception e) {
Log.("GET", "Network exception", e);
}
return content;
}
I'm invoking a rest WS that returns XML. Some elements have strings include special characters like áãç etc...
When I get the information via browser all of it is shown properly but when invoking it from Android I don't get the proper special characters.
Notice the 'decoded' and 'encoded' variables:
when I use
URLDecoder.decode(result, "UTF-8")
The result stays the same
when I use
URLEncoder.encode(result, "UTF-8") The result changes to what it would be expected (full of %'s symbols and numeric representing symbols and special characters).
Here's the method to call the webservice:
public void updateDatabaseFromWebservice(){
// get data from webservice
Log.i(TAG, "Obtaining categories from webservice");
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(ConnectionProperties.CATEGORIES_URI);
ResponseHandler<String> handler = new BasicResponseHandler();
String result = "";
String decoded;
String encoded;
try {
result = client.execute(request, handler);
decoded = URLDecoder.decode(result, "UTF-8");
encoded = URLEncoder.encode(result, "UTF-8");
String c = "AS";
} catch (Exception e) {
Log.e(TAG, "An error occurred while obtaining categories", e);
}
client.getConnectionManager().shutdown();
}
Any help would be appreciated
Use this to get xml string, assuming the server encodes data in UTF-8:
HttpResponse response = client.execute(request);
... // probably some other code to check for HTTP response status code
HttpEntity responseEntity = response.getEntity();
String xml = EntityUtils.toString(responseEntity, HTTP.UTF_8);
Uh. URLDecoder and encoder are for encoding and decoding URLs, not XML content. It is used for URL you use when making requests. So code is just... wrong.
But even bigger issue is that you are taking a String, whereas content is really XML which needs to be parsed. And for parser to do proper decoding of UTF-8 (and handling of entities etc), you would be better of getting a byte[] from request, passing that to parser; although asking http client to do decoding may work ok (assuming service correctly indicates encoding used; not all do -- but even if not, XML parsers can figure it out from xml declaration).
So: remove URLDecoder/URLEncoder stuff, parser XML, and extract data you want from XML.