I need to apply click/touch events for only visible part of the View. Say for example a image of size 200X200. Apart from center 50X50, remaining part is transparent. I want to get touch events only for that 50X50 visible part Not on remaining transparent part.
In above image (its single image), only inner Diamond has got visible part. Apart from that Diamond is transparent area. So, if I touch Diamond then only I want to do something else ignore.
Edit :
Rachita's link helped me. I gone through that link and got idea how can I implement. But I could not understand some constants like 320, 240 etc while creating Points. In my case, I know the Diamond (in above image) x and y Ponits (hard coded values asctually). So, using those how can I determine, whether I touched inside Diamond or outside?
my Diamond points are as below
pointA = new Point(0, 183);
pointB = new Point(183, 0);
pointC = new Point(366, 183);
pointD = new Point(183, 366);
Edit :
Finally got solution from Luksprog. Its based on checking touched point pixel color. If color is 0 means, you touched transparent layer else you touched some colored part of the image. Simple, but very effective. Have a look at it here.
AFAIK you can not implement this with onclick listener or my any other direct way .You will have to use onTouchListener .
Firstly set your view dynamically at a specific (x,y) position using this How can I dynamically set the position of view in Android?
Calculate the region your diamond will occupy (you should khow the size of image inorder to calculate area of diamond)
3.Trigger a action in onTouchListener only when x, y fall in the required region. Use How to get the Touch position in android?
check this link to calculate if a given point lies in the required square
EDIT
To understand the coordinate system of android refer to this link How do android screen coordinates work?
Display mdisp = getWindowManager().getDefaultDisplay();
int maxX= mdisp.getWidth();
int maxY= mdisp.getHeight();
(x,y) :-
1) (0,0) is top left corner.
2) (maxX,0) is top right corner
3) (0,maxY) is bottom left corner
4) (maxX,maxY) is bottom right corner
here maxX and maxY are screen maximum height and width in pixels, which we have retrieved in above given code.
Remember if you want to support multiple devices with different screen sizes,make sure you use a relative value for x,y ie some ratio of screen height or width ,as different devices have different ppi
Check if touched point lies in the required polygon
I thinks these link might help you determining if the point touched (you can get x,y from onTouch event eg.event.getX()) lies in the required polygon whose points you have mentioned in the question . determine if a given point is inside the polygon and How can I determine whether a 2D Point is within a Polygon?
Related
I am using CCTMXTiledMap on cocos2dx-2.2, I created and added the tiled map like this:
// TileMap
CCTMXTiledMap *m_pTileMap = CCTMXTiledMap::create("tilesets/my-isometric-small.tmx");
float fPosX = m_pTileMap->getPositionX();
float fPosY = m_pTileMap->getPositionY();
CCLOG( "TileMapPos: %f, %f", fPosX, fPosY );
this->addChild(m_pTileMap);
The tiled map are created and rendered successfully, but out of position. I use CCTMXTiledMap::getPosition, CCTMXLayer::positionAt, and also examine the CCSprite that I get from CCTMXLayer::tileAt... all of them are returning the correct value based on cocos2d screen coordinate { (0, 0) from bottom left and increasing upward and rightward } However, when viewed on the screen, there is always a slight offset and I can't get where it come from. All the m_obOffsetPosition are confirmed to be zero...
By correct value, I mean the tiles are positioned in the pink area (I getPosition from each of the tile, create CCSprite for each, setPosition of each tile and add it to the screen... They show up in the pink area)
Image supposed to be positioned at shady pink boxes, but instead positioned in the blue area (the entire blue sea is the whole map)
Any ideas are highly appreciated... Thanks!!
After wasting days trying to dissect tilemap_parallax_nodes in cocos2d-x, finally I figured out the culprit... it is the Layer Property cc_vertexz that cause it to be rendered off position. I haven't got the time to figure out how and why it works that way and since I'm not going to use it anyway (I just need flat, single layer, thus no need z order etc), so I just remove that property from all of my Layers and the problem is gone..
Hope it helps someone... Thanks!
Ohh.. damm Math !! once again stuck. It seems to be easy but i think its not that easy,
Problem Statement: I want to rotate the 3 fixed points which lies on a fixed circle.
1.when 1 point is selected remaining 2 points should be static mode and only selected point should move/rotate on circumference of circle.
2.And all 3 points are connected via 3 lines as shown in images..when we select a point and rotate it,connected lines also increase and decrease..
I already tried to solve this problem finding angle at each instant after touch.but its not quite working as per my need..
something like this
I hope the following explanation enable you to put the steps into your coding language.
Presumption is that the vertex to be moved has already selected and so the calculation of (xcnd,ycnd) as defined below is used to set the selected vertex of the triangle.
Let the constraining circle have centre at (cx,cy) and radius r.
Let the coordinates of where the screen is touched be (xtch,ytch)
Let the coordinates of where the screen is touched relative to the centre be (xrel,yrel)
then xrel = xtch - cx and yrel = ytch - cy
Let the coordinates of the point on the constraining circle when the screen is touched at (xtch,ytch) be (xcnd,ycnd).
xcndrel = xcnd - cx, and ycndrel = ycnd - cy give the coordinates on the constraining circle relative to its centre,
Note that
xrel and xcndrel will have the same signs (ie both positive or both negative)
and yrel and ycndrel will also have the same signs.
the function abs(x) = x if x>=0 and -x if x<0 should be available in whatever language you are using
the function sign(x) may or may not be available, sign(x) =1 if x>0 and -1 if x<0 and undefined for x=0
If not available then sign(x)=x/abs(x)
Check if xrel=0
if xrel=0 xcndrel=0, ycndrel=r*sign(yrel)
Otherwise work in first quadrant ie where x>0 and y>0 using abs(xrel) and abs(yrel)
find angle where screen is touched relative to centre of circle using
theta=arctan(abs(yrel)/abs(xrel))
find the coordinates (xcndrel, ycndrel) by using theta in the first quadrant and then placing in the correct quadrant using the signs of xrel and yrel
xcndrel = sign(xrel)*r*COS(theta)
ycndrel = sign(yrel)*r*SIN(theta)
Screen coordinates can now be found
xcnd = xcndrel +cx
ycnd = ycndrel + cy
I want to create a semi doughnut shaped button which is only clickable in the region where it is visible and not in the the whole rectangular region.
http://i.stack.imgur.com/MKD45.png
I want clicking to affect only this blue region.
You can do this by grabbing the Bitmap representation of the Button, then testing the x/y pixel's alpha value.
To get the bitmap for a button:
Bitmap buttonBmp;
button.setDrawingCacheEnabled(true);
buttonBmp = Bitmap.createBitmap(button.getDrawingCache());
button.setDrawingCacheEnabled(false);
I'd recommend only doing this once, and saving the results, that way you're not creating a new bitmap every time you touch the button.
Then you override the Button's onTouchEvent so you have the local x/y where the user tapped. If the alpha in that spot is 0, you have a non-clickable area. It's not as simple as an onClickListener, but it should do the job.
This way you can use any arbitrary shape, not just a doughnut. Colors, textures, whatever.
I'm not entirely sure on this but I think this scheme would work. Create an image view in your layout to display the picture and make it clickable via an onTouchEvent. This way you can get the coordinates of the click. Check to make sure that the click is within the inner and outer radii and if it is, do the given response.
Here are a few calculations that will need:
Center of circle
-Assuming the center is the very bottom of the image, this will look something like this(not necessarily exact methods)
centerX = img.getX() + img.getWidth()/2;
centerY = img.getY() + img.getHeight()/2;
Remember that screen coordinates go from top to bottom and from left to right.
Find the distance away from the center where the click occurred
Dx = click.getX() - centerX;
Dy = click.getY() - centerY;
D = Math.sqrt(Dx^2 + Dy^2);
Then all you need is to check if the distance is within the radii(not sure how to get the exact radii here, may just need to guess and check. An alternative may be that the top of the semicircle is the top of the picture and then the max height with be the outer radius.)
if(D<=outerR && D>=innerR)
respond();
I find that the unit of the coordinate system of Canvas is different from that of screen.
For example in my case as below:
For one particular point, its on-screen coordinate obtained from ImageView.getX() and ImageView.getY() is (336, 578).
Then by trial and error, I draw a dot on the Canvas so that this dot falls EXACTLY the same position as the ImageView. I called canvas.drawCircle(330, 440, radius, paint); to achieve this.
Here comes the question:
Why would the 2 coordinates, (336, 578) and (330, 440), different?
Is it because the screen and the canvas use different units?
Is it an issue regarding pixel, dp and all that?
You could try converting to and from window coordinates using View.getLocationInWindow this way you'll always be sure you are using the same coordinates system.
Coordinates of ImageView.getX an Y are relative to the parent. Canvas coordinates are relative to the view. This could cause the differences
Edit:
I assume in one place you get the coordinates of the view (using getX and getY). Convert these to window coordinates. Call these viewXY[].
When you need to use them, to draw in your canvas, also convert the top and left coordinates to window coordinates. We call these canvasXY[].
Now, the X position to draw at would be viewXY[0] - canvasXY[0], and the Y position would be viewXY[1] - canvasXY[1].
A view's position co-ordinates are always relative to it's parent. It's like saying, where with respect to it's parent is this view placed.
There in another thing, screen Co-ordinate. This says where with respect to the window top/left (think actual physical screen) is this object placed. This can be obtained through View.getLocationOnScreen.
If you want to compare two locations, they will only be equivalent if the parent view of both these locations is same or you're using absolute screen co-ordinates. Otherwise, you'll only get results that "seem" different.
If you want to unify the two either take them to a common parent or use absolute co-ordinates.
I want to achieve a tilt effect when a button is clicked, on Android OS.
Tilt Effect: Not the whole button will be seen as pressed. Only the part that touch event occured should seem to be pressed.
Is this easily possible on Android?
A simple way would be to use canvas draws to draw 4 sided shapes.
Consider each 4 corners. The "untouched" rectangle would be full size the touched rectangle would be smaller.
You just need to draw your four sided shape using a point you calculate for each part of the rectangle. You can get the touch position, then figure out how much "weight" to give each point.
to calculate each corner, you need to figure out how much "weight" to give the touched coordinate, and how much "weight" to give the untouched coordinate. If you touch the top left corner, that corner would use 100% of the touched coordinate, and the other three corners would all use the untouched coordinate.
If you touched the top middle, you would get a shape like this:
We can calculate the corners for any touch spot, by calculating how far from the corner your touch is
float untouchedXWeight1 = Math.abs(xt - x1)/width;
//maximum of 1, minimum of 0
float untouchedYWeight1 = Math.abs(yt - y1)/height;
float untouchedWeight1 = (untouchedXWeight1 + untouchedYWeight1)/2;
//also maximum of 1, minimum of 0
float touchedWeight1 = 1 - untouchedWeight1;
so with those weights, you can calculate your x and y positions for that corner:
x1 = xUntouched1 * untouchedWeight + xTouched1 * touchedWeight1;
y1 = yUntouched1 * untouchedWeight + yTouched1 * touchedWeight1;
Then do similarly for the other 3 corners.
I've created a first draft here : https://github.com/flavienlaurent/TiltEffect
In a second step, I will make it usable with Button etc.
Unfortunatly, I didn't use the very good (but too mathematical for me) answer of HalR