How to change layout by pressing the button? - android

I am trying to bring a new layout by pressing a button in my android app. Here is the code piece:
Button button = (Button)findViewById(R.id.btnAccept);
button.setOnClickListener(new View.OnClickListener() {
LayoutInflater layoutInflater = LayoutInflater.from(getBaseContext());
View promptView = layoutInflater.inflate(R.layout.empty_layout, null);
public void onClick(View v) {
// What should I write here to prompt empty_layout?
}
}
I dont know how to use "promptView". Can you give me some insight please?
Thank you guys!

If its the whole view of your screen then use
setContentView(prompView);
If its only a portion of a view then use
yourPortionViewContainer.addView(prompView);
Or may be you could use Fragment.

you should create Intent to open new Activity or create Fragment and let FragmentManager show it.

I don't know if i understand your question correctly but what I would do to add a layout when a button is pressed is to do it programmatically like this:
LinearLayout mainLayout;
mainLayout = (LinearLayout)findViewById(R.id.mainLayout)//assuming u gave the main layout an id of mainLayout in your XML file
public void onClick(View v) {
LinearLayout layout = new LinearLayout(this);
LayoutParams params = new LinearLayout.LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT);//create variable to store layout parameters
layout.setOrientation(LinearLayout.VERTICAL);//set orientation of layout
layout.setLayoutParams(params);//set layout parameters
mainLayout.addView(layout);//add the newly created layout to the already existing layout
}

Related

How to create another button in android dynamically

As the title states, I am looking to find out how to create a button dynamically when another button in another activity is pressed. This is being done with the Android SDK.
Basically, I have two activities, MainActivity and SecondaryActivity, within the SecondaryActivity you enter some information, title, text, id, so on and so forth. When you click the "Save" button it sends some, information to MainActivity(not the issue). As well as sending the information, I need to create an entirely new button within the MainActivity.
Any suggestions on how this should be accomplished?
Thanks.
Edit 1
public void CreateNewButton(View view)
{
LinearLayout lineLayout = (LinearLayout)findViewById(R.id.linear_layout);
TextView newTextView = new TextView(this);
int id = rand.nextInt(100);
int newId;
newTextView.setVisibility(View.VISIBLE);
newTextView.setId( R.id.new_button + id );
newTextView.setText("New Item");
newTextView.setTextSize(35);
newTextView.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View view) {
intent = new Intent(getBaseContext(), SecondActivity.class);
startActivity(intent);
}
});
lineLayout.addView(newTextView);
}
This code generates the new TextView( Decided to change it up ) but now the issue I have, is newTextView.setText(); needs to get the text from the other activity
newTextView.setText(i.getData().toString());
putting this in the CreateNewButton(View view) methods causes an error since technically there is no data in the field that it is trying to grab from.
The problem at hand is I need to create the new TextView field WITH the name of the new account that has yet to be created. If that makes any sense.
I'm going to assume you want to add this button to a LinearLayout:
LinearLayout linearLayout = (LinearLayout) findViewById(R.id.linearLayout1);
Button button = new Button(this);
button.setText("I'm a button!");
// add whatever other attributes you want to the button
linearLayout.addView(button);

How can I remove / delete a dynamically generated button in Android?

So I generated some button. The numbers it depends on the user (when clicked a button, create a new one).
This is how I made it:
RelativeLayout layout = (RelativeLayout) findViewById(R.id.layoutcprompt);
RelativeLayout.LayoutParams OBJ = new RelativeLayout.LayoutParams (140,80);
if ((commandsi%6)==0) {adjust=adjust+86; commandsi=1;}
OBJ.leftMargin =(140*(commandsi-1))+10;
OBJ.topMargin =250+adjust;
Button command = new Button(this);
command.setLayoutParams(OBJ);
command.setId(ID);
command.setText(edittxt.getText().toString());
edittxt.setText("");
command.setBackgroundResource(R.drawable.costum_button);
command.setTextColor(Color.WHITE);
command.setTextSize(14);
layout.addView(command);
command.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Button b = (Button)view;
scommand=b.getText().toString();
}
});
command.setVisibility(View.VISIBLE);
I want to remove/delete them, but I don't know how.... I gave them a unique id, but I still dunno how can I remove them :/
I cannot comment another post, but using
command = new Button(this)
might involve an implicit memory Leak on this! (which can be the Activity). Rather use Context object. Or remove the button at least.
Then because you have the parent of your Button. Just remove it:
ViewGroup layout = (ViewGroup) findViewById(R.id.layoutcprompt);
View command = layout.findViewById(ID);
layout.removeView(command);
Make command a global variable. Then you can access it later, and call command.setVisibility(View.GONE);
So at the top, of your class file, you would declare the global variable:
Button command;
Then remove the redefinition later on and instead assign to the global variable:
command = new Button(this);
Then when you want to hide it, call:
command.setVisibility(View.GONE);
Try using the documentation, 5 seconds of research can lead you to the RemoveView method.
layout.removeView(command);
Update
If you have a null pointer exception on this line, means your layout is null, not your command. Make your layout variable global for that class.
Also be sure to keep different variables for each of your created buttons. If you have a global variable, and create 10 buttons using the same variable you will only have a reference to the last one created. If you explain exactly when you want to remove the button we might be able to help you further.
As an example, if you want to remove the button when the user clicks on it you can change your clickListener:
command.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Button b = (Button)view;
scommand=b.getText().toString();
layout.removeView(view);
}
});
One other implementation that may help others who view this thread is that you can consider removing all the child elements in the parent layout. Once you get the view's parent (which I assume is a layout container),you can remove all the child elements.
command.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
ViewGroup vg = (ViewGroup)view.getParent();
vg.removeAllViews();
}
});
You can also do it like this for security purpose:
ViewGroup layout = (ViewGroup) command.getParent();
if(null!=layout) //for safety only as you are doing onClick
layout.removeView(command);
You can also use this snipper
For Adding the Button
LinearLayout dynamicview = (LinearLayout)findViewById(R.id.buttonlayout);
LinearLayout.LayoutParams lprams = new LinearLayout.LayoutParams( LinearLayout.LayoutParams.WRAP_CONTENT,
LinearLayout.LayoutParams.WRAP_CONTENT);
Button btn = new Button(this);
btn.setId(count);
final int id_ = btn.getId();
btn.setText("Capture Image" + id_);
btn.setTextColor(Color.WHITE);
btn.setBackgroundColor(Color.rgb(70, 80, 90));
dynamicview.addView(btn, lprams);
btn = ((Button) findViewById(id_));
btn.setOnClickListener(this);
For removing the button
ViewGroup layout = (ViewGroup) findViewById(R.id.buttonlayout);
View command = layout.findViewById(count);
layout.removeView(command);

Clear previous View and show new View on button click in the same Activity

I have created an activity with two buttons at the top. One button to show "SMS Logs" and second to show "Call Logs".
On clicking "SMS Logs" button, i am dynamically creating textviews and linear layout to show sms logs.
On Clicking "Call Logs", i am dynamically creating another textviews and linear layout to show call logs.
But the problem is that, once if we click "sms log" button and then we click "call log" button, the previously created linear layouts are not removed and the both(previous layouts and the current layouts) are shown simultaneously.
But i want that the previous layouts should be removed on clicking the second button.
Which function, should i use to remove the previous viewgroups or the layouts. Tell me if you need to read my class file.
Edit:
This is my Activity's code,
public class General extends Activity
{
String phone, message;
TextView Logs;
View layout, callLayout;
TextView data, callData, line, callLine;
Button smsLog, callLog;
LinearLayout ll, callll;
#Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.general_main);
Logs = (TextView)findViewById(R.id.Logs);
layout = findViewById(R.id.layout);
callLayout = findViewById(R.id.layout);
smsLog = (Button)findViewById(R.id.smsLogs);
callLog = (Button)findViewById(R.id.callLogs);
smsLog.setOnClickListener(new View.OnClickListener() {
public void onClick(View v)
{
callLayout.setVisibility(View.GONE);
ll = new LinearLayout(getApplicationContext());
ll.setOrientation(LinearLayout.VERTICAL);
data = new TextView(getApplicationContext());
data.setText("First Line");
data.setTextColor(Color.YELLOW);
line = new TextView(getApplicationContext());
line.setText("Second Line");
((ViewGroup) ll).addView(data);
((ViewGroup) layout).addView(line);
((ViewGroup) layout).addView(ll);
}
});
callLog.setOnClickListener(new View.OnClickListener()
{
public void onClick(View v)
{
layout.setVisibility(View.GONE);
callll = new LinearLayout(getApplicationContext());
callll.setOrientation(LinearLayout.VERTICAL);
callData = new TextView(getApplicationContext());
callLine = new TextView(getApplicationContext());
callData.setText("Third Line");
callLine.setText("Fourth Line");
((ViewGroup) callll).addView(callData);
((ViewGroup) callLayout).addView(callLine);
((ViewGroup) callLayout).addView(callll);
}
});
}
}
I have removed the extra code and made it simple to understand.
You can use FrameLayout to solve your problem. But I recommend you to use tabview.Here is the link that demonstrates how to develop tabbed applications.Good Luck
You could implement a TabView.
But having your current setup just change the visibility of one view group to GONE and the other to VISIBLE.
GONE will make the view invisible and it won't take up any space anymore.
EDIT based on the code added to the question
Both your layout and callLayout are using the same XML view. Implement 2 identical views in your xml and keep one visible and one gone. This way when you set layout or callLayout visibility to GONE they are 2 different ones not the same. So your onClick() will have something like this:
for smsLog:
layout.setVisibility(View.GONE);
callLayout.setVisibility(View.VISIBLE);
for callLog:
callLayout.setVisibility(View.GONE);
callLayout.setVisibility(View.VISIBLE);

How make a layout available to a dialog

In my activity there are 3 buttons. By clicking on the first button, I want a dialog to appear with a graph (in the layout itself it works fine).
btn1 = (Button)findViewById(R.id.btn1);
btn1.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
dialog = new Dialog(ChartsDuration.this);
dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
dialog.setContentView(R.layout.dialog_charts1);
// code to show a graph. Here I have a function that calls drawChartAll(),
// but since the layout is declared outside the dialog it cannot render it to the
// linearlayout, and my graph1 linearlayout will be empty.
dialog.show();
}
});
Tha graph uses data that are queried in functions outside like
public void drawChartAll()
{
//blablabla and this is how I define the layout and render the graph to it:
LinearLayout layout = (LinearLayout) findViewById(R.id.graph1);
mChartView = ChartFactory.getBarChartView(ChartsDuration.this, buildBarDataset(titles, values),renderer,Type.DEFAULT);
mChartView.setBackgroundColor(renderer.getBackgroundColor());
layout.addView(mChartView);
}
So without the dialog, I can easily show the graph in the graph1 LinearLayout e.g below the buttons, because they are "on the same levels", but I want to show the graph in a dialog opened by clicking on a button. Because if I were in a dialog I would do this: LinearLayout layout = (LinearLayout)dialog.findViewById(R.id.graph1); But now I cannot do this, since I am outside the dialog.
How do I reach this layout?
Edit:
user113215 I did this:
in the activity:
LayoutInflater inflater = LayoutInflater.from(ChartsDuration.this);
customDialog = (ViewGroup) inflater.inflate(R.layout.dialog_charts1, null);
btn1 = (Button)findViewById(R.id.btn1);
btn1.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
dialog.setContentView(customDialog);
//queries
dialog.show();
}
});
and in drawChartAll:
public void drawChartAll()
{
//code
LinearLayout layout = (LinearLayout) customDialog.findViewById(R.id.graph1);
}
Is this what you mean? This throws me a nullpointer exception to dialog.setContentView(customDialog); line.
If I understand the problem correctly, you're having trouble manipulating things on the layout that's going into the dialog. Instead of calling setContentView(int), inflate the layout yourself and then use setContentView(View).
LayoutInflater inflater = LayoutInflater.from(this);
ViewGroup customDialog = (ViewGroup) inflater.inflate(R.layout.dialog_charts1, null);
// Do chart things here
// Prefix all calls to findViewById with "customDialog."
LinearLayout layout = (LinearLayout) customDialog.findViewById(R.id.graph1);
mChartView = ChartFactory.getBarChartView(ChartsDuration.this, buildBarDataset(titles, values),renderer,Type.DEFAULT);
mChartView.setBackgroundColor(renderer.getBackgroundColor());
layout.addView(mChartView);
// Put the manipulated layout into the dialog
dialog.setContentView(customDialog);
You can use this same trick to take advantage of the AlertDialog.Builder class while still filling the dialog with a custom layout.
Make the dialogvariable a field in your Activity class. You can reach it from anywhere. You can still use dialog.findviewbyid throughout you Activity. Just make sure setcontentView has been called before you call findviewbyid
Edit: I hope when you wrote since I am outside the dialog. you meant you could not access the variable

I need to add onClickListener to a bunch of ImageButtons

I have created a bunch of ImageButtons programmatically while in a for loop. They have worked fine as the data displayed in a HorizontalScrollView. Now I need each one to go dim or bright when clicked. First click will setAlpha(45); second click will setAlpha(255);.
I don't think I fully understand how the Views and onClickListener works yet. It seems the onClick function examples I find take a View. How would that function know which button is clicked? Perhaps there is an easier way to do what I want?
Here are the ImageButtons.
TableRow tr0 = new TableRow(this);
tr0.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT));
for(int but=0; but<ClueList.size(); but++){
ImageButton clueBut = new ImageButton(this);
clueBut.setBackgroundResource(0);
clueBut.setImageBitmap(ClueList.get(but).btmp);
//clueBut.setOnClickListener(this);
tr0.addView(clueBut);
}
Is there something I need to do to make the buttons identifiable? And how would that pass in through into the onClick function to be used?
-: Added Information :-
I am starting to wonder if the problem isn't with the buttons, but with the way I built the screen. More information added.
The Game activity is the main game, which uses the PuzzleView for the upper part of the screen holding the game grid. The lower part is where the ImageButtons are and I built them in place in the Game class.
public class Game extends Activity{
//various variables and stuff
private PuzzleView puzzleView; // The PuzzleView is from another .java file
// public class PuzzleView extends View
#Override
protected void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
LinearLayout mainPanel = new LinearLayout(this);
mainPanel.setOrientation(LinearLayout.VERTICLE);
puzzleView = new PuzzleView(this);
mainPanel.addView(puzzleView);
HorizontalScrollView bottom = new HorizontalScrollView(this);
mainPanel.addView(bottom);
TableLayout clues = new TableLayout(this);
bottom.addView(clues);
TableRow tr0 = new TableRow(this);
for(int but=0; but<ClueList.size(); but++){
ImageButton clueBut = new ImageButton(this);
clueBut.setImageBitmap(ClueList.get(but).btmp);
tr0.addView(clueBut);
}
When I try to add the ClickListener(this) I get errors about this not being able to be a Game. I have similar problems in the onClick(View v) function referencing the View. Are these problems because I am building the buttons in the Game Activity instead of a View class?
Thanks
When you set up an OnClickListener and implement the onClick(View v) callback, it's the Dalvik VM the one that will call that method each time the View is clicked, and it will pass the View instance as a parameter. Thus, the code you write inside that method will be applied only to the View that received the click and not to any other View. Add something like this to your loop:
clueBut.setOnClickListener(new OnClickListener() {
public void onClick (View v) {
if (v.getAlpha() == 1f)
v.setAlpha(0.2f);
else
v.setAlpha(1f);
}
});
In the onClick event:
public void onClick(View currentView)
{
Button currentButton = (Button)CurrentView;
//Do whatever you need with that button here.
}
To identify each view uniquely use the property
View. setId(int)
In your case the code would look something like this
for(int but=0; but<ClueList.size(); but++){
ImageButton clueBut = new ImageButton(this);
clueBut.setBackgroundResource(0);
clueBut.setImageBitmap(ClueList.get(but).btmp);
clueBut.setId(but);
//clueBut.setOnClickListener(this);
tr0.addView(clueBut);
}
Inside the onclick listener match the id of the view using findViewByID()

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