I currently have a decode bitmap method to optimize the size of the image file, however the input file won’t be a bitmap and will decode to bitmap afterward. So my problem is, how can I resize it if my input is a bitmap already? Thanks.
private Bitmap compressFile(File f) {
int REQUIRED_SIZE = 80;
try {
// decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(new FileInputStream(f), null, o);
// Find the correct scale value. It should be the power of 2.
int width_tmp = o.outWidth;// , height_tmp = o.outHeight;
int scale = 1;
while (REQUIRED_SIZE > 0) {
if (width_tmp <= REQUIRED_SIZE)
break;
width_tmp /= 2;
// height_tmp /= 2;
scale++;
}
// decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
} catch (FileNotFoundException e) {
}
return null;
}
What I would like to change to is compressFile (Bitmap f)
You may use this too
Bitmap b = BitmapFactory.decodeByteArray(imageAsBytes, 0, imageAsBytes.length)
profileImage.setImageBitmap(Bitmap.createScaledBitmap(b, 120, 120, false));
or are you asking for:
bitmap.compress(Bitmap.CompressFormat.PNG, quality, outStream);
check this link for more info
Related
I'm using this method:
public Bitmap decodeUri(Uri selectedImage) throws FileNotFoundException {
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(getContentResolver().openInputStream(selectedImage), null, o);
final int REQUIRED_SIZE = 800;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE || height_tmp / 2 < REQUIRED_SIZE) {
break;
}
width_tmp /= 2;
height_tmp /= 2;
scale *= 2;
}
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
return BitmapFactory.decodeStream(getContentResolver().openInputStream(selectedImage), null, o2);
}
To decode an URI from mi camera and then send to my webserver via an HttpURLConnection object in POST headers. But my instead get my original image:
I get an cropped imagen:
I don't know why. Perhaps my decodeURI method is wrong? Anybody know other best method to send my image compressed to my webserver?
I used right now the next way insteaf of my decodeUri method:
mybitMap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), selectedImageUri);
and I have the same problem. And when I tried to open the image in my webserver with Photoshop, I see an advertisement wich says "This document may be damaged (the file may be truncated or incomplete). Do you want continue?" And , after continue, I see a black space in the bottom of the image...
Anybody knows why? My code:
Bitmap mybitMap = null;
try {
mybitMap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), selectedImageUri);
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
ByteArrayOutputStream baos = new ByteArrayOutputStream();
imagen.compress(Bitmap.CompressFormat.JPEG, 100, baos);
And I send this in POST Headers:
Base64.encodeToString(baos.toByteArray(), Base64.DEFAULT);
I am trying to parse images ...large images from url!
// Decodes image and scales it to reduce memory consumption
private Bitmap decodeFile(File f) {
try {
// Decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
FileInputStream stream1 = new FileInputStream(f);
BitmapFactory.decodeStream(stream1, null, o);
stream1.close();
// Find the correct scale value. It should be the power of 2.
// Recommended Size 512
final int REQUIRED_SIZE = 70;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE
|| height_tmp / 2 < REQUIRED_SIZE)
break;
width_tmp /= 2;
height_tmp /= 2;
scale *= 2;
}
// Decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
FileInputStream stream2 = new FileInputStream(f);
Bitmap bitmap = BitmapFactory.decodeStream(stream2, null, o2);
stream2.close();
return bitmap;
} catch (FileNotFoundException e) {
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
when I parse small size images it works but when I use it in large one it crashes and bitmap is null and gives me this error
ReadStreamToBuffer : Qmage Stream read error!! required length 12 bytes, but red 0 bytes
isQmage : input SkStreamRewindable length is less than Qmage minimum size : 0
Try with this library
Picasso
Volley
Android-Universal-Image-Loader
How do I get the path name to the drawables in my resource folder? I am trying to get the image in my resource folder and pass it to the function to decode it.
the path "android.resource://com.myapp.example/"+ R.drawable.image" didnt works.
Bitmap bitmap;
File image = new File("android.resource://com.myapp.example/"+ R.drawable.image);
bitmap.decodeFile(image);
public Bitmap decodeFile(File f) {
try {
// decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(new FileInputStream(f), null, o);
// Find the correct scale value. It should be the power of 2.
final int REQUIRED_SIZE = 70;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE
|| height_tmp / 2 < REQUIRED_SIZE)
break;
width_tmp /= 2;
height_tmp /= 2;
scale++;
}
// decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
} catch (FileNotFoundException e) {
}
return null;
}
BitmapFactory has function to decode resources:
Bitmap BitmapFactory.decodeResource (Resources res, int id, BitmapFactory.Options opts)
Example:
bitmap.decodeFile(R.drawable.image);
public Bitmap decodeFile(int resId) {
try {
// decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeResource(getContext().getResources(), resId, o);
// Find the correct scale value. It should be the power of 2.
final int REQUIRED_SIZE = 70;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE
|| height_tmp / 2 < REQUIRED_SIZE)
break;
width_tmp /= 2;
height_tmp /= 2;
scale++;
}
// decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
return BitmapFactory.decodeResource(getContext().getResources(), resId, o2);
} catch (Exception e) {
}
return null;
}
No, you cant get the path because the resource folder is compiled into the apk, but you can grab the resource like this:
Resources rsrc= getResources();
Drawable drawable= rsrc.getDrawable(R.drawable.datImage);
Bitmap bm = BitmapFactory.decodeResource(rsrc,drawable, opts);
I'm trying to display image full screen but seems that the image loses quality. I get the image from an URL, I download it and when I'm displaying the images, it looks pretty bad. The images that I'm getting are in high resolution so I do not know what can the problem be?
Here is my Layout where i'm displaying the image:
<?xml version="1.0" encoding="utf-8"?>
<ImageView xmlns:android="http://schemas.android.com/apk/res/android"
android:id="#+id/full_screen_banner"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:contentDescription="#string/app_name" />
and here is the java code:
imageViews.put(imageView, url);
Bitmap bitmap = memoryCache.get(url);
if (bitmap != null)
imageView.setImageBitmap(bitmap);
If you are using image loader just go to imageloader class then
Check these lines
private Bitmap decodeFile(File f) {
try {
// decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(new FileInputStream(f), null, o);
// Find the correct scale value. It should be the power of 2.
final int REQUIRED_SIZE = 100;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE
|| height_tmp / 2 < REQUIRED_SIZE)
break;
width_tmp /= 2;
height_tmp /= 2;
scale *= 2;
}
// decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
} catch (FileNotFoundException e) {
}
return null;
}
Ok so i download a image and send the input stream to this method witch has to decode it once to find the image size then calculate a scale value then create a mini version of the bitmap from the stream.... but i get errors in logcat that the bitmapFactory is returning null, anyone have a idea what could be wrong ?
public static Bitmap getSampleBitmapFromStream(InputStream is,
int reqWidth, int reqHeight) {
BitmapFactory.Options options = new BitmapFactory.Options();
options.inJustDecodeBounds = true;
BitmapFactory.decodeStream(new FlushedInputStream(is), null, options);
// Find the correct scale value. It should be the power of 2.
int width_tmp = options.outWidth, height_tmp = options.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 2 < reqWidth || height_tmp / 2 < reqHeight)
break;
width_tmp /= 2;
height_tmp /= 2;
scale *= 2;
}
// decode with inSampleSize
options.inJustDecodeBounds = false;
options.inSampleSize = scale;
return BitmapFactory.decodeStream(new FlushedInputStream(is), null, options);
}
the reason is: the stream you used twice
options.inJustDecodeBounds = true;
BitmapFactory.decodeStream(new FlushedInputStream(is), null, options);
and again:
options.inJustDecodeBounds = false;
options.inSampleSize = scale;
return BitmapFactory.decodeStream(new FlushedInputStream(is), null, options);
so if you want avoid this, you need close the stream and reopen the stream again.
What about supplying the InputStream directly?
return BitmapFactory.decodeStream(is, null, options);