I am working on an application where i have to create a link of my application and copy that link to text buffer and paste that link in my device in any text editor. Now when i tap on that link my application should open and show appropriate data. I don't know how to implement this i searched on internet I did not find any solution which can explain this feature implementation. give me the best way to implement this.
I have tried this but can not understand
Launch your application when a link taped
You have to use other app to start it. You should register intent-filter with other action and category in your app. The most common action should be ACTION_VIEW combine with category BROWSABLE, then you can use a url in brower or sms to open you app. The intent-filter should be like:
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="openmyapp"
android:scheme="http" />
</intent-filter>
Related
My objective is to open my android application when user clicks link e.g I have shared specific item link (http://example.com/api_shirts.php?utmsource=shirt98) then if user have already installed my application then open it else where open it on browser.
I have searched a lot and get this but it's not working for me
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http"
android:host="www.example.com" />
<data android:scheme="https"
android:host="www.example.com"/>
</intent-filter>
I'm not sure if you may need to set a pathPrefix on this case. Also, the OS may open other prefered app that the user has set up as default app for that schema.
If I remember correcly you have to associate your app with your website so the OS can open the app directly bypassing the user's choice:
https://developer.android.com/studio/write/app-link-indexing.html#associatesite
Also, check https://developer.android.com/training/app-links/verify-site-associations.html to read about "deep links" vs "app links". You need app links for what you are trying to do.
I want to write a NFC tag that opens a specific note in Google Keep when touched.
I have an URL in the form of https://keep.google.com/u/0/#LIST/<id> that does the desired action of opening the note in the installed Google Keep app on my phone when I read it with a QR-reader or click on it as a link.
When I write this URL to the tag an touch the tag afterwards, it opens in the browser. Is the NFC handler skipping other apps and opening it directly in a browser? When I clear the app-defaults for the browser, it shows a selection menu for the installed browsers after tapping the tag. Does anyone have an idea what I am doing wrong?
Links on NFC tags are not launched as intents with the typical VIEW action. Consequently, other apps may not pick those links up correctly and you will instead experience the web browser to be opened. Only apps that specifically register for the intent action NDEF_DISCOVERED will be able to receive links from NFC tags. It seems that Google Keep currently does not do this, so there's not much you can do without creating your own wrapper app that handles these URLs and passes them on to Google Keep.
You should enable deeplinks in your activity. Also you should indicate your activity NFC tag discoverable as follows. You can learn anything about deep linking via this link
<activity
android:name="ExampleActivity"
android:label="Example">
<intent-filter android:autoVerify="true">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="example.com"
android:scheme="http" />
<data android:scheme="https" />
</intent-filter>
<intent-filter>
<action android:name="android.nfc.action.NDEF_DISCOVERED" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="text/plain" />
</intent-filter>
</activity>
I am looking for a solution so far, i.e When user clicks on a link from his mail box My Application should open if My Application is already installed in his device without asking user to choose options with Just Once and Always .For example, clicking a URI in an email from a bank might result in a dialog asking the user whether to use the browser, or the bank's own app, to open the link, But in my case my application should open directly without asking to choose any option.
I have implemented my application as follows:
My manifest file as AndroidManifest.xml
<activity android:name=".WelcomeActivity"
android:label="#string/app_name">
<intent-filter>
<action android:name="android.intent.action.VIEW"></action>
<category android:name="android.intent.category.DEFAULT"></category>
<category android:name="android.intent.category.BROWSABLE"></category>
<data android:host="www.example.com"
android:scheme="http"
android:pathPrefix="/blog"></data>
</intent-filter>
</activity>
My example url is http://www.example.com/blog
I would like to open my application if user clicks on above link.
Please help me with sample code with steps.
This feature is only available on Android devices running at least Marshmallow (6+) and is referenced as App Link throughout the Android documentation.
To fully implement this feature, it requires you to own the corresponding url and add a configuration file at this address: https://www.example.com/.well-known/assetlinks.json. The file content is described in the documentation (contains the package name and its signature).
Then, modify your intent-filter as follow to enable the auto-verify feature:
<intent-filter android:autoVerify="true">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="https" android:host="www.example.com" android:pathPrefix="/blog" />
</intent-filter>
You should definitely read the documentation about this feature. It contains a lot of usefuls tips to test your implementation.
When I click a link in something like Gmail, how can I have my web browser show up as an option to open said link? And what code would I implement to go about it? Even just a link to the correct documentation would be incredibly helpful.
Thanks!
You are probably missing to declare this <intent-filter> in your Manifest
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http"/>
</intent-filter>
For your app to be on the list of apps, you need an <intent-filter> that support web browsing. You can look at this link as a reference and determine what you need to add.
Hi
Is it possible to invoke an Android App from a Web Page that i am displaying on the phone browser to the user. I know that this is possible from an another Android App using Intents. But i am not sure if this is possible from a WebPage.
Thanks in advance.
Intent filters with the BROWSABLE category will let you launch an application using a URI scheme. Inside your <activity>, add:
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<data android:scheme="myprotocol" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
and set up the action and categories how you want, and change the scheme to something relevant to your application.
Then inside your webpage, you can link to your application with
test link
Simply define a intent filter for a particular URI within your Activity:
http://developer.android.com/guide/topics/manifest/data-element.html
That way, that activity will be called when a corresponding link is clicked. By using a custom scheme you'll make sure that your app is the only one responding.
It's the same way the android market responds to market links.