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Any suggestions to deserialize this json with Gson? [closed]

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Any suggestions to deserialize this json with Gson ?
{
"0": {
"id": 1,
"name": "pepe"
},
"1": {
"id": 2,
"name": "pipo"
},
"2": {
"id": 3,
"name": "pato"
}
...
n objects
}

Convert the Json string to Hashmap like below using Google's Gson, then you can interate through the hashmap
String jsonString = "Your JSON string";
HashMap<String, JsonObject> map = new Gson().fromJson(jsonString, new TypeToken<HashMap<String, JsonObject>>(){}.getType());

How to parse this Json with no object name [duplicate]

This question already has answers here:
How do I parse JSON in Android? [duplicate]
(3 answers)
Closed 5 years ago.
{
"quote": "To understand the heart and mind of a person, look not at
what he has already achieved, but at what he aspires to.",
"author": "Kahlil Gibran (1883-1931)"
}
How to parse this with no any object name

There are different methods to parse json object
Simple way
JSONObject myJson = new JSONObject(yourJsonString);
String quote = myJson. getString("quote");
String author = myJson. getString("author");
Another and recomented way is parse json using Gson
For this you can refer below links
How to parse json parsing Using GSON in android
https://www.journaldev.com/2321/gson-example-tutorial-parse-json

How to do it ?
If you meet {} in your code , you can use JSONObject to parse it .
If you meet [] in your code , you can use JSONArray to parse it .
And if you meet [] in your code , you can use for loop to get value in it .
And you should use try catch in your code .
Try this .
try {
JSONObject jsonObject = new JSONObject(response);
String author = jsonObject.getString("author");
String quote = jsonObject.getString("quote");
} catch (JSONException e) {
e.printStackTrace();
}

This is absolutely normal json.
JSONObject json = new JSONObject(your_json);
String quote = json.getString("quote");
String author = json.getString("author");

How to parse data by array in android? [closed]

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I am developing an android application were I want to parse data through an array to URL API.
Taking an example, there are 5 TextBox and I enter some information in it. Then all the values entered in textView should parse in an array format to That API URL.
Please help!!

This is what i did, note that this is just an example.
final Map<String,String> postParam = new HashMap<String, String>();
for(int i = 0; i < 5; i++)
postParam.put("child_id[" + i + "]", i+"");
You will get :
child_id[0] with value 0
child_id[1] with value i
And goes on.
UPDATE
In your case, you might want to do something like :
postParam.put("child_id[" + i + "]", myEditText.getText.toString());
for each of your edittext.
Feel free to comment if you dont understand my answer or if i miss-understood you.

I hope i am understanding you correctly, you want to put 5 TextBox's entered text into one Array and then send this Array to API.
Try this:
ArrayList<String> textViewTexts = new ArrayList<String>();
// Put all EditText's text to array
// Do this for each EditText
textViewTexts.add(someEditText.getText());
You can then use textViewTexts.toString() and send this to API.
EDIT:
you can parse textViewTexts like this:
for (int i = 0; i < textViewTexts.size(); i++) {
String text = textViewTexts.get(i);
// Do something with text..
}
EDIT2:
you can parse textViewTexts like this:
JSONArray jArray=new JSONArray();
for (int i = 0; i < textViewTexts.size(); i++) {
String text = textViewTexts.get(i);
jArray.put(text);
}
// Send JSONArray to API
jArray.toString();

If you want to send that array to server via an api, then you should send data in JSONArray like this
JSONArray jArray=new JSONArray();
jArray.put(yourTextViewText1);
jArray.put(yourTextViewText2);
jArray.put(yourTextViewText3);
jArray.put(yourTextViewText4);
jArray.put(yourTextViewText5);
and you can send that to server like that
params.put("key",jArray.toString());
Moreover, It is easy for you web developer to parse this JSONArray.

android json object can not be convert to jsonarray? [closed]

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I am getting Exception that json object cannot be converted to json array..,when I am showing values from server, here is my code. Please help me.
if(respons!=null){
try{
JSONObject jsonObj=new JSONObject(respons);
JSONArray post=jsonObj.getJSONArray("List of image URLs");
for(int i =0;i<post.length();i++){
String values = post.getString(i);
_issueList.add(values);
}
}
Here is my json exception at this output
{
"message": [
"http:\/\/app.lionforge.com\/comics\/adminpanel\/upload\/1389346961Quincredible_1-
2.png",
"http:\/\/app.lionforge.com\/comics\/adminpanel\/upload\/1389346977Quincredible_1-
3.png",
"http:\/\/app.lionforge.com\/comics\/adminpanel\/upload\/1389346996Quincredible_1-
4.png",
"http:\/\/app.lionforge.com\/comics\/adminpanel\/upload\/1389347016Quincredible_1-
5.png",
"http:\/\/app.lionforge.com\/comics\/adminpanel\/upload\/1389347039Quincredible_1-
6.png",
"http:\/\/app.lionforge.com\/comics\/adminpanel\/upload\/1389347052Quincredible_1-
7.png",
"http:\/\/app.lionforge.com\/comics\/adminpanel\/upload\/1389347062Quincr32.png"
]
}
This data is coming from server. I don't know why this error is occurring, my images are not showing and moving.
Please help me. Thank you.

if(respons!=null){
try{
JSONObject jsonObj=new JSONObject(respons);
JSONArray post=jsonObj.getJSONArray("message");
for(int i =0;i<post.length();i++){
String values = post.getString(i);
_issueList.add(values);
}

change to:
if(respons!=null){
try{
JSONObject jsonObj=new JSONObject(respons);
JSONArray post=jsonObj.getJSONArray("message");
for(int i =0;i<post.length();i++){
String values = post.getString(i);
_issueList.add(values);
}
}
key for your json array is message not List of image URLs

Change your below line in which you need to get the arraylist of message where you have written wrong key. Other code is fine.
JSONArray post=jsonObj.getJSONArray("List of image URLs");
Change it to
JSONArray post=jsonObj.getJSONArray("message");
As you are getting only the JSONArray in your response there is not need of JSONObject in your code.
You can parse your array as below which will directly give you an array :
try{
JSONArray post=new JSONArray(respons);
for(int i =0;i<post.length();i++){
String values = post.getString(i);
_issueList.add(values);
}

convert string array into integer array android [closed]

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I created a url string array.
String urls[]={"http://www.kllhjj.png","http://yui.kl.png"};
this url are not exactly correct. But in my code them are correct. Then I try to convert them into integer array just like following way.
int a[] = new int[urls.length];
for(int i=0; i<a.length; i++) {
try {
a[i] = Integer.parseInt(urls[i]);
}
catch(Exception e) { }
}
But here always show the a integer values as 0. why is it?
help me

Because Integer.parseInt(urls[i]); is throwing NumberFormatException and you are swallowing the Exception . The below code will not work in your case, but at least you will get to know the error:
try{
a[i]=Integer.parseInt(urls[i]);
}catch(Exception e){
e.printStackTrace();
throw new RunTimeException(e);
}
All the elements of a primitive int array are defaulted to 0. Hence you get the 0s .
You cannot parse string like "http://yui.kl.png" etc to int as they are not in numeric format . Read the documentation:
Throws:
NumberFormatException - if the string does not contain a parsable integer.

You are getting the NumberFormatException Exception hence not changing any values in a[] and because the default values of integer is 0 you are having 0 for every element in a[]

Urls are text string and you parsing text to int:
a[i]=Integer.parseInt(urls[i]);
which through an exception absorbed by:
catch(Exception e)
and default value for int is zero so u always getting it.

ParseInt is a function that search for integer in some string. it's like atoi if you're familiar with c language.
When you have a string that contains only letters it will return 0.
When you have a string that begins with letter and ends with number it also will return 0.
It will convert a string to integer if the string will contains a number characters like "0123".
I don't know what you're trying to do, but if you want that number will represent a url.
I think you can create an enum for the urls.