Develop Reference

Spanned text in Number picker

I have a problem with to show meter m2 in android. I can use SpannedBuilderString for setText in TextView and it work.
The problem is I want to show m2 in Number Picker like 50 m2 100 m2 but Number Picker only show String and I can't. Please help me fix that. Tks everyone.

Using Unicode Character makes it very easy :
First create an array with your values(this will go to the number picker)
String mValues[] = { "100 " + "\u33A1", "200 " + "\u33A1" };
Now use this method to create number picker with custom values:
private void setNubmerPicker(NumberPicker nubmerPicker,String [] numbers ){
nubmerPicker.setMaxValue(numbers.length-1);
nubmerPicker.setMinValue(0);
nubmerPicker.setWrapSelectorWheel(true);
nubmerPicker.setDisplayedValues(numbers);
}
And for the final step call this method:
setNubmerPicker(yourNumberPicker,mValues);

Apply this custom Formatter to your NumberPicker:
NumberPicker.Formatter formatter = new NumberPicker.Formatter(){
#Override
public String format(int i) {
return String.valueOf(i) + " " + Character.toString((char) 0x33A1);
}
};
numberPicker.setFormatter(formatter);

how to remove special character from string except + in android?

I am fetching number from contact book and sending it to server. i get number like this (+91)942 80-60 135 but i want result like this +9428060135.+ must be first character of string number.

Given your example you want to replace the prefix with a single + character. You also want to remove other non-numeric characters from the number string. Here's how you can do that:
String number = "(+91)942 80-60 135";
number = "+" + number.replaceAll("\\(\\+\\d+\\)|[^\\d]", "");
The regex matches any prefix (left paren followed by a + followed by one or more digits, followed by a right paren) or any non digit character, and removes them. This is concatenated to a leading + as required. This code will also handle + characters within the number string, e.g. +9428060135+++ and +(+91)9428060135+++.
If you simply wanted to remove any character that is not a digit nor a +, the code would be:
String number = "(+91)942 80-60 135";
number = number.replaceAll("[^\\d+]", "");
but be aware that this will retain the digits in the prefix, which is not the same as your example.

You can use String.replace(oldChar, newChar). Use the code below
String phone = "(+91)942 80-60 135"; // fetched string
String trimmedPhone = phone.replace("(","").replace(")","").replace("-","").trim();
I hope it will work for you.

check this. Pass your string to this function or use as per code goes
String inputString = "(+91)942 80-60 135";
public void removeSpecialCharacter(String inputString) {
String replaced = inputString.replaceAll("[(\\-)]", "");
String finalString = replaced.replaceAll(" ", "");
Log.e("String Output", " " + replaced + " " + second);
}

String to display number currency in Android

I have a string
String retail = c.getString(c.getColumnIndex("retail"));
The date is being passed as "99999", I need it to print out as "999.99", how can I do this?

If you always have to add the "." 2 character before the end, this should work:
retail = retail.substring(0, retail.length()-2) + "." + retail.substring(retail.length()-2,retail.length());
This will add a dot two character before the end of the String, as you need.

How to replace character at particular index in android?

I am working on android. I have a string containing huge data. In that string I want to replace a particular character to another character. I got the index of the character which I want to replace. But I am unable to replace that character.
How can I do that?
String str = "data1data2mdata2test1test2test3dd"
int ind = str.indexOf("m");
System.out.println("the index of m" + ind);
Now in the above string I want to replace the character "m"(after data2) to "#".
Now how can I replace the m to #. Please help me in this reagard.

You can use substring:
String newStr = str.substring(0, ind) + '#' + str.substring(ind + 1);

Try this:
str = str.replaceFirst("m", "#");
It will replace the first m to #

String str1 = "data1data2mdata2test1test2test3dd"
String str = str1.replace("m", "#");
System.out.println(str);

So you are getting 10 as system out,
so this way you can replace it like,
Str.replace('m', '#')--->when you want all occurrences of it to replace it,
Or if you want only first occurrence to be replaced by # then you can do following trick,
StringBuffer buff=new StringBuffer();
buff.append(Str.substring(0,ind)).append("#").append(Str.substring(ind+1));
i hope it would help

Convert String to Double excluding part of the string

How to convert double to a string value that I get from the spinner, for example: "10 (ton)."
In summary:
How to convert string to double and delete the part (ton)?
I need only the value 10

Another option is using Java's substring method in the String class.
The signature is:
substring(int beginIndex, int endIndex)
Where endIndex equals to the index of the last character you want to include + 1.
In the case of your example, it will look like this:
String myString = "10 (ton)";
Double dbl = Double.parseDouble(myString.substring(0, 2));
Here is the link to the method:
Java substring

You must parse this String. Here is some example. Also use search.

Check these methods Double.parseDouble() and Double.toString() use these functions for converting double to string or vice-versa.

first you have to get rid of "(ton)" which can be achieved by using a String method for example
String inputString = "10 (ton)";
String str = inputString.split(" ")[0];
After that just parse the double Value
Double dbl = Double.parseDouble(str);
BTW: Not sure whether you want to go from double to string or vice-versa

i have a similar problem.
for correct formatting EditText text content to double value i use this code:
try {
String eAm = etAmount.getText().toString();
DecimalFormat dF = new DecimalFormat("0.00");
Number num = dF.parse(eAm);
mPayContext.amount = num.doubleValue();
} catch (Exception e) {
mPayContext.amount = 0.0d;
}
this is independet from current phone locale and return correct double value.
hope it's help;