Develop Reference

Android Animation not work when i call visibility

The animation does not work after I set visibility to Invisible, I tried clear animation but not work. I have a button when I click the button it opens a linear layout with animation when I press back button I set the linear layout visibility to invisible again I click the button linear layout appear but no animation please help me.
l1 = (LinearLayout) findViewById(R.id.lnrlgn);
l2 = (LinearLayout) findViewById(R.id.lnrlgn1);
l2.setVisibility(View.INVISIBLE);
Animation uptodown = AnimationUtils.loadAnimation(this,R.anim.uptodown);
viewcrrd.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
l2.setAnimation(downtoup);
l2.clearanimation(); // is it right ?
l2.setVisibility(View.VISIBLE);
}
});
public void onBackPressed() {
// super.onBackPressed();
if (back_pressed + TIME_DELAY > System.currentTimeMillis()) {
// super.onBackPressed();
Exitdlg alert = new Exitdlg();
alert.showDialog(LoginActivity.this, "Are You Sure ");
l2.clearAnimation();
} else {
l2.clearAnimation();
l2.setVisibility(View.INVISIBLE);
}
back_pressed = System.currentTimeMillis();
}

Use startAnimation instead of setAnimation
viewcrrd.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
l2.setVisibility(View.VISIBLE);
l2.clearanimation();
l2.startAnimation(downtoup);
}
});

How to handle touch event on a ImageView

I have three Images. When I first touch, first Image is shown, when I second touch, second Image is shown, and then when I third touch, third Image is shown. After all, when I fourth touch, I want to show first Image return and so on.
Can someone point me to show how handling or touching on a ImageView of android?

The below should do what you need:
public class MainActivity extends Activity {
ImageView image;
int i=1;
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
image = (ImageView) findViewById(R.id.imageViewName);
setButtonOnClickListeners();
}
}
image.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
if (i==1){
image.setImageResource(R.drawable.image1);
i++;
}
else if(i==2){
image.setImageResource(R.drawable.image2);
i++;
}
else if(i==3){
image.setImageResource(R.drawable.image3);
i++;
}
else if(i==4){
image.setImageResource(R.drawable.image4);
i=1;
}
}
});
I've not tested but the idea is correct. When you click the image it will change the drawable depending on the value of i. When you get image 1 i will equal 1. Onclick will increment i until i==4 which it will reset to 1 as you requested.
A while loop might be tidier but this was the quickest soultion I thought of.

how to handle click on an ImageView
You can simply set a View.OnClickListener for your ImageView:
imageView.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
// do stuff
}
});

How can I make previous item's button visible when click on current item's button in recyclerview?

What I want is when I click the "x" button of the second item, it will remove the second item and then make the "+" of the first item visible. Here is what I try but not work, the "+" button is not showed.
holder.ivDelete.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
View view = recyclerView.getChildAt(position - 1);
holder.ivAdd = (ImageView) view.findViewById(R.id.img_add_items);
holder.ivAdd.setVisibility(View.VISIBLE);
list.remove(position);
notifyDataSetChanged();
}
});

Try this code,
holder.ivDelete.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
View view = recyclerView.getChildItemId(position - 1);
holder.ivAdd = (ImageView) view.findViewById(R.id.img_add_items);
holder.ivAdd.setVisibility(View.VISIBLE);
list.remove(position);
notifyDataSetChanged();
}
});
I hope that will help you for solving your problem.

How can I optimize the performance of opening an Android fragment?

I have created an 800 xml layout and a Fragment class, but opening a fragment with a button click takes too long.
Can anyone help me optimize the following code sample?
View lesson655 = (View) getActivity().findViewById(R.id.txtlesson655);
lesson655.setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
int i;
pager.setCurrentItem(0);
for (i = 1; i <= 655; i++) {
pager.setCurrentItem(pager.getCurrentItem() + 1);
}
}
});

If you don't need to go step by step through every Item you can do it this way:
View lesson655 = (View) getActivity().findViewById(R.id.txtlesson655);
lesson655.setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
pager.setCurrentItem(655);
}
});

first click change to new image and second click change to old image, android

this application requires:
first click will change image1 to image2
second click will change back to old image (image2 to image1)
image1 = (ImageView)findViewById(R.id.imageView1);
image1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
image1.setImageResource(R.drawable.a3_01);
image1.setTag(70);
}
});
this image will set a new tag for the server knows that the picture have been change.
*the code i used is only for the first click and it works. ive just have no idea to make a second click event. can anyone gives me idea of it? much appreciate. thanks.

You could use a boolean to act as a switch for you to flop back and forth with an if statement.
boolean showingFirst = true;
image1 = (ImageView)findViewById(R.id.imageView1);
image1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
if(showingFirst == true){
image1.setImageResource(R.drawable.a3_02);
showingFirst = false;
}else{
image1.setImageResource(R.drawable.a3_01);
image1.setTag(70);
showingFirst = true;
}
}
});

Put both images into an ImageSwitcher and use the Button clicks to call its showNext() method.

You can use if case in it like
public void onClick(View v) {
if (i == 0) {
Toast.makeText(getApplicationContext(), "First Click", 1000).show();
i++;
} else if (i == 1) {
Toast.makeText(getApplicationContext(), "Second Click", 1000).show();
i = 0;
}
}