In my string.xml I have a text which contains 2 paragraphs "\n\n". When I try to split it by String.split("\n\n")
or String.split("\\n\\n") it does not work. Knows anywhone the reason?
and here it is the sample data:
it displays well on the screen
val content = resources.getString(R.string.test).split("\n \n ")
strings.xml
<string name="test">first
\n
\n
second</string>
You should add gaps after \n. Use my pattern for spliting and it'll work.
Your text appears to actually have literal \n values in it. In that case, you may try splitting on \\n (which becomes \\\\n in Java syntax):
String yourText = "Part one \\n Part two";
String[] parts = yourText.split("\\\\n");
System.out.println(Arrays.toString(parts));
This prints:
[Part one , Part two]
I'm doing Firebase RemoteConfig integration. In one of the scenarios, I need to break a text line, so I tried to use new line character (\n).
But this is not working, it is neither displaying as an extra character nor creating another line.
My solution is replace \n manually (assuming that in Firebase Console you put property for TITLE as "Title\nNewLine"):
FirebaseRemoteConfig.getInstance().getString(TITLE).replace("\\n", "\n")
Try using an uncommon character like two pipes || and then replacing every occurance of those with a newline after you do getString() in the code.
You can insert encoded text(with Base64) to Firebase panel.
After, decode the String from your Java class and use it.
Like
byte[] data = Base64.decode(base64, Base64.DEFAULT);
String text = new String(data, "UTF-8");
The trick (which actually works for all HTML tags supported on your target platform) is to wrap the String in a JSON Object on RemoteConfig, like so:
{
"text":"Your text with linebreaks...<br><br>...as well as <b>bold</b> and <i>italic</i> text.
}
On the target platform you then need to parse the JSON and convert it back to a simple string. On Android this looks like this:
// extract value from JSON
val text = JSONObject(remoteConfig.getString("remoteConfig_key")).getString("text")
// create Spanned and use it
view.text = HtmlCompat.fromHtml(text)
So what worked for me is to use "||" (or some other character combination you are confident will not be in the string) as the new line character. Then replace "||" with "\n". This string will then display properly for me.
For some reason sending "\n" in the string doesn't get recognized as expected but adding it manually on the receiving side seems to work.
To make the suggestion mentioned above, you can try this code(that can be generalized to "n" number of elements). Simply replace the sample text with yours with the same format and add the amount of elements
String text="#Elemento1#Elemento2#Elemento3#";
int cantElementos=3;
arrayElementosFinales= new String[cantElementos];
int posicionNum0=0;
int posicionNum1;
int posicionNum2;
for(int i=0;i<cantElementos;i++){
posicionNum1=text.indexOf("#",posicionNum0);
posicionNum2=text.indexOf("#", posicionNum1+1);
char [] m = new char[posicionNum2-posicionNum1-1];
text.getChars(posicionNum1+1, posicionNum2,m,0);
arrayElementosFinales[i]=String.valueOf(m);
posicionNum0=posicionNum2;
}
Use Cdata in the remote config in combination with "br" tag and HTML.fromHtml() .. for eg.
<![CDATA[ line 1<br/>line 2]]>
I have a .txt file which contains above 1000 words
sample city names below
Razvilka
Moscow
Firozpur Jhirka
Kathmandu
Kiev
Pokhara
Merida
Delhi
Reshetnikovo
Ciudad Bolivar
Marfino
Zhukovskiy
Reutov
Kurovskoye
etc
I would like to have these words in this format below
"Razvilka","Moscow","etc","etc"
enclosed with double quotation and with a comma in the end.I am using Notepad++.Could you mention how to do it and which software should I use it?
If you're using Notepad++, make a Search and Replace replacing
\b(\w+)\b
with
"$1",
It'll find all words and replace with them self, surrounded by quotes. You'll have to manually remove the last , if that's unwanted.
Regards
I wonder if this question is about programming, but You tagged android, regex and android studio, so I guess it is. If yes, You can simply split a string in that way:
String[] splitted = yourString.split("\\s+");
In that case, You are splitting the strings by whitespaces (this regex is also for more than one whitespace), like Your string seems to be. If You have more than one delimiter, You can do it by using the OR operator |
String[]splitted = yourString.split("-|\\.");
In that example, You are splitting the String by - and . (minus and point). The delimiter is the sign where the String is splitted by.
I have following data in my db row:
Espresso: 7,00
Double Espresso: 8,00
Ristretto: 7,00
Espresso Machiato: 8,00
Espresso Con Panna: 8,00
I write it on Word, then copy & paste to MySQL editor. When I save it, my IOS and Android apps cannot show the prices aligned because of the tab characters.
What is the best way to do that?
The best way- those 2 things are different data and are in different columns in your database, I would expect (if not, you need to fix your schema). So put the 2 strings in separate TextViews, and align the text view in xml.
First you can split the data from tab character and use formatting like below in java. I believe in objective-c it should be similar.
String ehe = String.format("%-20s : \t %4dTL \n","ehemehe",23);
String ehe2 = String.format("%-20s : \t %4dTL \n","ehemeheadawd",44);
System.out.println(ehe);
System.out.println(ehe2);
Output it produces is
ehemehe : 23TL
ehemeheadawd : 44TL
replace the "/t" chars with "" before you display the text. by using
String.replace("/t","");
Use a fixed-width font if you have precalculated the number of spaces.
I am trying to add a line break in the TextView.
I tried suggested \n but that does nothing. Here is how I set my texts.
TextView txtSubTitle = (TextView)findViewById(r.id.txtSubTitle);
txtSubTitle.setText(Html.fromHtml(getResources().getString(R.string.sample_string)));
This is my String: <string name="sample_string">some test line 1 \n some test line 2</string>
It should show like so:
some test line 1
some test line 2
But it shows like so: some test line 1 some test line 2.
Am I missing something?
\n works for me, like this:
<TextView android:text="First line\nNext line"
ok figured it out:
<string name="sample_string"><![CDATA[some test line 1 <br />some test line 2]]></string>
so wrap in CDATA is necessary and breaks added inside as html tags
Android version 1.6 does not recognize \r\n.
Instead, use: System.getProperty("line.separator")
String s = "Line 1"
+ System.getProperty("line.separator")
+ "Line 2"
+ System.getProperty("line.separator");
Linebreaks (\n) only work if you put your string resource value in quotes like this:
<string name="sample_string">"some test line 1 \n some test line 2"</string>
It won't do linebreaks if you put it without quotes like this:
<string name="sample_string">some test line 1 \n some test line 2</string>
yes, it's that easy.
Tried all the above, did some research of my own resulting in the following solution for rendering linefeed escape chars:
string = string.replace("\\\n", System.getProperty("line.separator"));
Using the replace method you need to filter escaped linefeeds (e.g. '\\n')
Only then each instance of line feed '\n' escape chars gets rendered into the actual linefeed
For this example I used a Google Apps Scripting noSQL database (ScriptDb) with JSON formatted data.
Cheers :D
There are two ways around this.
If you use your string as a raw string, you need to use the newline
character. If you use it as html, e.g. by parsing it with Html.fromString,
the second variant is better.
1) Newline character \n
<string name="sample">This\nis a sample</string>
2) Html newline tag <br> or <br />
<string name="sample">This<br>is a sample</string>
This worked for me
android:text="First \n Second"
This worked for me, maybe someone will find out this helpful:
TextView textField = (TextView) findViewById(R.id.textview1);
textField.setText("First line of text" + System.getProperty("line.separator") + "Linija 2");
If you're using XML to declare your TextView use android:singleLine = "false" or in Java, use txtSubTitle.setSingleLine(false);
Used Android Studio 0.8.9. The only way worked for me is using \n.
Neither wrapping with CDATA nor <br> or <br /> worked.
I use the following:
YOUR_TEXTVIEW.setText("Got some text \n another line");
very easy : use "\n"
String aString1 = "abcd";
String aString2 = "1234";
mSomeTextView.setText(aString1 + "\n" + aString2);
\n corresponds to ASCII char 0xA, which is 'LF' or line feed
\r corresponds to ASCII char 0xD, which is 'CR' or carriage return
this dates back from the very first typewriters, where you could choose to do only a line feed (and type just a line lower), or a line feed + carriage return (which also moves to the beginning of a line)
on Android / java the \n corresponds to a carriage return + line feed, as you would otherwise just 'overwrite' the same line
As I know in the previous version of android studio uses separate lines " \n " code. But new one (4.1.2) uses "<br/" to separate lines. For example -
Old one:
<string name="string_name">Sample text 1 \n Sample text 2 </string>
New one:
<string name="string_name">Sample text 1 <br/> Sample text 2 </string>
Also you can add "<br/>" instead of \n.
It's HTML escaped code for <br/>
And then you can add text to TexView:
articleTextView.setText(Html.fromHtml(textForTextView));
Try to double-check your localizations.
Possible, you trying to edit one file (localization), but actually program using another, just like in my case. The default system language is russian, while I trying to edit english localization.
In my case, working solution is to use "\n" as line separator:
<string name="string_one">line one.
\nline two;
\nline three.</string>
You could also use the String-Editor of Android Studio, it automatically generates line brakes and stuff like that...
As Html.fromHtml deprecated I simply I used this code to get String2 in next line.
textView.setText(fromHtml("String1 <br/> String2"));
.
#SuppressWarnings("deprecation")
public static Spanned fromHtml(String html){
Spanned result;
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {
result = Html.fromHtml(html,Html.FROM_HTML_MODE_LEGACY);
} else {
result = Html.fromHtml(html);
}
return result;
}
The most easy way to do it is to go to values/strings (in your resource folder)
Declare a string there:
<string name="example_string">Line 1\Line2\Line n</string>
And in your specific xml file just call the string like
<TextView
android:id="#+id/textView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="#string/example_string" />
I found another method:
Is necessary to add the "android:maxWidth="40dp"" attribute.
Of course, it may not work perfectly, but it gives a line break.
\n was not working for me. I was able to fix the issue by changing the xml to text and building the textview text property like below.
android:text="Line 1
Line 2
Line 3
DoubleSpace"
Hopefully This helps those who have said that \n did not work for them.
I'm reading my text from a file, so I took a slightly different approach, since adding \n to the file resulted in \n appearing in the text.
final TextView textView = (TextView) findViewById(R.id.warm_up_view);
StringBuilder sb = new StringBuilder();
Scanner scanner = new Scanner(getResources().openRawResource(R.raw.warm_up_file));
while (scanner.hasNextLine()) {
sb.append(scanner.nextLine());
sb.append("\n");
}
textView.setText(sb.toString());
In my case, I solved this problem by adding the following:
android:inputType="textMultiLine"
Maybe you are able to put the lf into the text, but it doesn't display? Make sure you have enough height for the control. For example:
Correct:
android:layout_height="wrap_content"
May be wrong:
android:layout_height="10dp"
I feel like a more complete answer is needed to describe how this works more thoroughly.
Firstly, if you need advanced formatting, check the manual on how to use HTML in string resources.
Then you can use <br/>, etc. However, this requires setting the text using code.
If it's just plain text, there are many ways to escape a newline character (LF) in static string resources.
Enclosing the string in double quotes
The cleanest way is to enclose the string in double quotes.
This will make it so whitespace is interpreted exactly as it appears, not collapsed.
Then you can simply use newline normally in this method (don't use indentation).
<string name="str1">"Line 1.
Line 2.
Line 3."</string>
Note that some characters require special escaping in this mode (such as \").
The escape sequences below also work in quoted mode.
When using a single-line in XML to represent multi-line strings
The most elegant way to escape the newline in XML is with its code point (10 or 0xA in hex) by using its XML/HTML entity
or
. This is the XML way to escape any character.
However, this seems to work only in quoted mode.
Another method is to simply use \n, though it negatively affects legibility, in my opinion (since it's not a special escape sequence in XML, Android Studio doesn't highlight it).
<string name="str1">"Line 1.
Line 2.
Line 3."</string>
<string name="str1">"Line 1.\nLine 2.\nLine 3."</string>
<string name="str1">Line 1.\nLine 2.\nLine 3.</string>
Do not include a newline or any whitespace after any of these escape sequences, since that will be interpreted as extra space.
I would recommend querying the line.separator property, and using that whenever you want to add a line break.
Here is some sample code:
TextView calloutContent = new TextView(getApplicationContext());
calloutContent.setTextColor(Color.BLACK);
calloutContent.setSingleLine(false);
calloutContent.setLines(2);
calloutContent.setText(" line 1" + System.getProperty ("line.separator")+" line2" );