Develop Reference

Edit/Modify Uri referenced file using FileOutputStream Android

I am using ActivityResultLauncher to fetch uri of a file. Now I want to modify that file using fileoutputStream but can't, since fileoutputstream need path string. Here is a code that I am using to get File Uri:
ActivityResultLauncher<Intent> someActivityResultLauncher = registerForActivityResult(
new ActivityResultContracts.StartActivityForResult(),
new ActivityResultCallback<ActivityResult>() {
#Override
public void onActivityResult(ActivityResult result) {
if (result.getResultCode() == Activity.RESULT_OK) {
// There are no request codes
Intent data = result.getData();
Uri uri = data.getData();//this gets me URI
}
}
});
public void openFileChooser()
{
Intent data = new Intent(Intent.ACTION_GET_CONTENT);
data.addCategory(Intent.CATEGORY_OPENABLE);
data.setType("*/*");
data = Intent.createChooser(data, "Choose a file");
Intent intent = Intent.createChooser(data, "Choose a file");
someActivityResultLauncher.launch(intent);
}
The code works perfect for picking and reading file. But I am not able to use below mentioned function to write same file using:
static void writeToFile(String path,String data,Context context) {
try {
FileOutputStream output = null;
output = new FileOutputStream(path, false);
output.write(data.getBytes());
output.close();
Toast.makeText(getApplicationContext(),"SAVED",Toast.LENGTH_LONG).show();
}
catch (IOException e) {
Toast.makeText(getApplicationContext(),"File write failed: " + e.toString(),Toast.LENGTH_LONG).show();
}
}
I have tried uri.getPath() but it is returning /document/msf:21. That is some complicated uri string and can't be used as file path. I have also been trying to use realPath functions mentioned in stackflow and other forums but do not find it working (they may work but they are depending upon API levels that making them not reliable). So, what actually want to ask:
1- Is there any other way to pick file to get actual path?
2- If there is no way to pick path, how can I write to File using direct Uri? and not using getpath or path string.
3- Is there a way to use fileoutstream with Uri in this scenario where Uri is only available?
Thanks

OutputStream os = getContentResolver().openOutputStream(data.getData());

You need to pass it through input stream amd buffer reader with output stream.
Try this on start intent
Intent intent = new Intent(Intent.ACTION_CREATE_DOCUMENT);
intent.addCategory(Intent.CATEGORY_OPENABLE);
intent.setType("application/pdf");
intent.putExtra(Intent.EXTRA_TITLE, "JWI.pdf");
startActivityForResult(intent, CREATE_FILE);
Try this on activity result
try {
uri = _data.getData();
muri = uri.toString();
t.edit().putString("Uri", muri).commit();
final int takeFlags = Intent.FLAG_GRANT_READ_URI_PERMISSION |
Intent.FLAG_GRANT_WRITE_URI_PERMISSION;
getContentResolver().takePersistableUriPermission(uri, takeFlags);
DocumentFile doc = DocumentFile.fromSingleUri(this, uri);
boolean doo = doc.exists();
if (!doo) {
DocumentFile f = doc.createFile("pdf/plain", "JAMZ.pdf");}
ContentResolver cr = getContentResolver(); OutputStream output =
cr.openOutputStream(uri);
java.io.InputStream asset = getAssets().open("JWI.pdf");
final byte[] buffer = new byte[1024];
int size;
while ((size = asset.read(buffer)) != -1) {
output.write(buffer, 0, size);
}
asset.close();
output.close();
} catch (Exception e) {}}}

How to save a picture in a specific folder just for my app (correctly)?

The problem is that my app saves the picture twice; one in the camera folder and the other in the folder I specified. but when I tested the app on another device, that didn't happen!
//lunch the camera and make a file to save the image in and pass it with the camera intent
public void lunchCamera() {
Intent takePictureIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
// Ensure that there's a camera activity to handle the intent
if (takePictureIntent.resolveActivity(getPackageManager()) != null) {
// Create the File where the photo should go
File photoFile = null;
try {
photoFile = createImageFile();
} catch (IOException ex) {
// Error occurred while creating the File
ex.printStackTrace();
}
// Continue only if the File was successfully created
if (photoFile != null) {
Uri photoURI = FileProvider.getUriForFile(this,
"com.ziad.sayit",
photoFile);
takePictureIntent.putExtra(MediaStore.EXTRA_OUTPUT, photoURI);
startActivityForResult(takePictureIntent, REQUEST_IMAGE_CAPTURE);
}
}
}
private File createImageFile() throws IOException {
// Create an image file name
String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
String imageFileName = "SayIt_" + timeStamp + "_";
File storageDir = getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES);
File imageFile = File.createTempFile(
imageFileName, /* prefix */
".jpg", /* suffix */
storageDir /* directory */
);
// Save a file: path for use with ACTION_VIEW intents
mCurrentPhotoPath = imageFile.getAbsolutePath();
return imageFile;
}
So, I want a solution for this, and I also want to save the picture in a folder for my app inside the Pictures Directory.. thanks

There is no solution for it, other than to not use ACTION_IMAGE_CAPTURE.
ACTION_IMAGE_CAPTURE delegates picture-taking to an arbitrary third-party camera app. There are dozens, if not hundreds, of these pre-installed on devices. There are hundreds more available for download from the Play Store and elsewhere. What they do in response to that Intent action is up to them. Ideally, they would only store the image in the location specified by EXTRA_OUTPUT. However, there is no requirement that they behave that way. Some camera apps will store the image twice, once in its normal location and once in the EXTRA_OUTPUT. Some will ignore EXTRA_OUTPUT entirely.
If this concerns you, do not use ACTION_IMAGE_CAPTURE. Use a library — CameraX, Fotoappart, CameraKit-Android, etc. — to take the photos within your own app.

Call below method from OnActivityResult.
private void saveImage(Bitmap image, String fileName) {
File direct = new File(Environment.getExternalStorageDirectory() + "/DirName");
if (!direct.exists()) {
File directory = new File("/sdcard/DirName/");
directory.mkdirs();
}
File file = new File(new File("/sdcard/DirName/"), fileName);
if (file.exists()) {
file.delete();
}
try {
FileOutputStream out = new FileOutputStream(file);
image.compress(Bitmap.CompressFormat.JPEG, 100, out);
out.flush();
out.close();
} catch (Exception e) {
e.printStackTrace();
}
}

How to get the file name of a file which is transferred via wifi direct in android?

I have seen an example about this question.But when I have a try on it , it just occur an error in this code File f = new File(Uri.parse(uri.toString())); and just say that Constructor File(Uri) is undefined . I have stucked in this error for many days. I don't know what's wrong with it because other people can work. The following is the suggested code
public class WiFiDirectBundle extends Serializable {
private String fileName;
private String mimeType;
private Long fileSize;
private byte[] fileContent;
public WiFiDirectBundle() {}
// adds a file to the bundle, given its URI
public void setFile(Uri uri) {
File f = new File(Uri.parse(uri.toString()));
fileName = f.getName();
mimeType = MimeTypeMap.getFileExtensionFromUrl(f.getAbsolutePath());
fileSize = f.length();
FileInputStream fin = new FileInputStream(f);
fileContent = new byte[(int) f.length()];
fin.read(fileContent);
}
// restores the file of the bundle, given its directory (change to whatever
// fits you better)
public String restoreFile(String baseDir) {
File f = new File(baseDir + "/" + fileName);
try {
FileOutputStream fos = new FileOutputStream(f);
if (fileContent != null) {
fos.write(fileContent);
}
fos.close();
return f.getAbsolutePath();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
public String getFileName() {
return fileName;
}
public String getMimeType() {
return mimeType;
}
public Long getFileSize() {
return fileSize;
}
}
And this is original qusetion:
How to find file name of a file which is transferred via wifi direct mode in android?
Also I am a beginner in Wifi Direct ,I can successfully link two device and transfer file ,but I want to linked more device and transfer file Sequentially can anyone give me some advices about learning it or some examples about how to do it.Thanks!

use
File f = new File(uri.getPath());
instead of
File f = new File(Uri.parse(uri.toString()));
to get file path from Uri

you can open inputstream of a file from its uri using content resolver
ContentResolver cr=getContentResolver();
InputStream in=cr.OpenInputStream(file_uri);
you can use this input stream to read from the file

open files which stored in database using default android program

i want to open files in database using default android program...but i have a trouble in opening it...
i store the files path in my database (as string), because it is better to store the files path instead of the files it self...(from what i read)
but when i want to open it in android using the default android program, it goes nothing...just blank...
i don't know which part i wrong, because the log cat didn't show anything...
here is my code...
String fileId = ((TextView)view.findViewById(R.id.fileid)).getText().toString();
String fileName = ((TextView)view.findViewById(R.id.TextView01)).getText().toString();
String filePath = ((TextView)view.findViewById(R.id.filepath)).getText().toString();
//starting activity intent
Intent intent= new Intent();
intent.setAction(Intent.ACTION_VIEW);
File file = new File("http://10.0.2.2/" + filePath);
MimeTypeMap mime = MimeTypeMap.getSingleton();
String ext = file.getName().substring(file.getName().indexOf(".")+1).toLowerCase();
String type = mime.getMimeTypeFromExtension(ext);
intent.setDataAndType(Uri.fromFile(file), type);
try
{
startActivity(intent);
}
catch (ActivityNotFoundException e)
{
Toast.makeText(FileChooser.this, "No Application available to View this file", Toast.LENGTH_SHORT).show();
}
the filePath is android/untitled.jpg
actually i'm really new in developing android...i hope anyone can help me solve my problem...

i got it...
finally i finished it with my own...
if one of you guys confuse about the same thing with me...hope this will help...
public void clearCache()
{
fileCache.clear();
}
private File getFileFromUrl(String url)
{
File f = fileCache.getFile(url);
try
{
URL docUrl = new URL(url);
HttpURLConnection conn = (HttpURLConnection)docUrl.openConnection();
conn.setConnectTimeout(30000);
conn.setReadTimeout(30000);
conn.setInstanceFollowRedirects(true);
InputStream is=conn.getInputStream();
OutputStream os = new FileOutputStream(f);
Utils.CopyStream(is, os);
os.close();
return f;
}
catch (Exception ex)
{
ex.printStackTrace();
return null;
}
}
public String GetExtention(String name)
{
name = name.replaceAll("%20", " ");
MimeTypeMap mime = MimeTypeMap.getSingleton();
String type = name;
String filenameArray[] = type.split("\\.");
type = filenameArray[filenameArray.length-1];
String ext = mime.getMimeTypeFromExtension(type.toLowerCase());
return ext;
}
while the file cache is class you make...
for more help this can help you...

Save bitmap to location

I am working on a function to download an image from a web server, display it on the screen, and if the user wishes to keep the image, save it on the SD card in a certain folder. Is there an easy way to take a bitmap and just save it to the SD card in a folder of my choice?
My issue is that I can download the image, display it on screen as a Bitmap. The only way I have been able to find to save an image to a particular folder is to use FileOutputStream, but that requires a byte array. I am not sure how to convert (if this is even the right way) from Bitmap to byte array, so I can use a FileOutputStream to write the data.
The other option I have is to use MediaStore :
MediaStore.Images.Media.insertImage(getContentResolver(), bm,
barcodeNumber + ".jpg Card Image", barcodeNumber + ".jpg Card Image");
Which works fine to save to SD card, but does not allow you to customize the folder.

try (FileOutputStream out = new FileOutputStream(filename)) {
bmp.compress(Bitmap.CompressFormat.PNG, 100, out); // bmp is your Bitmap instance
// PNG is a lossless format, the compression factor (100) is ignored
} catch (IOException e) {
e.printStackTrace();
}

You should use the Bitmap.compress() method to save a Bitmap as a file. It will compress (if the format used allows it) your picture and push it into an OutputStream.
Here is an example of a Bitmap instance obtained through getImageBitmap(myurl) that can be compressed as a JPEG with a compression rate of 85% :
// Assume block needs to be inside a Try/Catch block.
String path = Environment.getExternalStorageDirectory().toString();
OutputStream fOut = null;
Integer counter = 0;
File file = new File(path, "FitnessGirl"+counter+".jpg"); // the File to save , append increasing numeric counter to prevent files from getting overwritten.
fOut = new FileOutputStream(file);
Bitmap pictureBitmap = getImageBitmap(myurl); // obtaining the Bitmap
pictureBitmap.compress(Bitmap.CompressFormat.JPEG, 85, fOut); // saving the Bitmap to a file compressed as a JPEG with 85% compression rate
fOut.flush(); // Not really required
fOut.close(); // do not forget to close the stream
MediaStore.Images.Media.insertImage(getContentResolver(),file.getAbsolutePath(),file.getName(),file.getName());

outStream = new FileOutputStream(file);
will throw exception without permission in AndroidManifest.xml (at least in os2.2):
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>

Inside onActivityResult:
String filename = "pippo.png";
File sd = Environment.getExternalStorageDirectory();
File dest = new File(sd, filename);
Bitmap bitmap = (Bitmap)data.getExtras().get("data");
try {
FileOutputStream out = new FileOutputStream(dest);
bitmap.compress(Bitmap.CompressFormat.PNG, 90, out);
out.flush();
out.close();
} catch (Exception e) {
e.printStackTrace();
}

Some formats, like PNG which is lossless, will ignore the quality setting.

Here is the sample code for saving bitmap to file :
public static File savebitmap(Bitmap bmp) throws IOException {
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
bmp.compress(Bitmap.CompressFormat.JPEG, 60, bytes);
File f = new File(Environment.getExternalStorageDirectory()
+ File.separator + "testimage.jpg");
f.createNewFile();
FileOutputStream fo = new FileOutputStream(f);
fo.write(bytes.toByteArray());
fo.close();
return f;
}
Now call this function to save the bitmap to internal memory.
File newfile = savebitmap(bitmap);
I hope it will help you.
Happy codeing life.

I know this question is old, but now we can achieve the same result without WRITE_EXTERNAL_STORAGE permission. Instead of we can use File provider.
private fun storeBitmap(bitmap: Bitmap, file: File){
requireContext().getUriForFile(file)?.run {
requireContext().contentResolver.openOutputStream(this)?.run {
bitmap.compress(Bitmap.CompressFormat.JPEG, 100, this)
close()
}
}
}
How to retrieve file from provider ?
fun Context.getUriForFile(file: File): Uri? {
return FileProvider.getUriForFile(
this,
"$packageName.fileprovider",
file
)
}
Also do not forget register your provider in Android manifest
<provider
android:name="androidx.core.content.FileProvider"
android:authorities="${applicationId}.fileprovider"
android:exported="false"
android:grantUriPermissions="true">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="#xml/file_paths"/>
</provider>

Why not call the Bitmap.compress method with 100 (which sounds like it is lossless)?

Bitmap bbicon;
bbicon=BitmapFactory.decodeResource(getResources(),R.drawable.bannerd10);
//ByteArrayOutputStream baosicon = new ByteArrayOutputStream();
//bbicon.compress(Bitmap.CompressFormat.PNG,0, baosicon);
//bicon=baosicon.toByteArray();
String extStorageDirectory = Environment.getExternalStorageDirectory().toString();
OutputStream outStream = null;
File file = new File(extStorageDirectory, "er.PNG");
try {
outStream = new FileOutputStream(file);
bbicon.compress(Bitmap.CompressFormat.PNG, 100, outStream);
outStream.flush();
outStream.close();
} catch(Exception e) {
}

I would also like to save a picture. But my problem(?) is that I want to save it from a bitmap that ive drawed.
I made it like this:
#Override
public boolean onOptionsItemSelected(MenuItem item) {
switch (item.getItemId()) {
case R.id.save_sign:
myView.save();
break;
}
return false;
}
public void save() {
String filename;
Date date = new Date(0);
SimpleDateFormat sdf = new SimpleDateFormat ("yyyyMMddHHmmss");
filename = sdf.format(date);
try{
String path = Environment.getExternalStorageDirectory().toString();
OutputStream fOut = null;
File file = new File(path, "/DCIM/Signatures/"+filename+".jpg");
fOut = new FileOutputStream(file);
mBitmap.compress(Bitmap.CompressFormat.JPEG, 85, fOut);
fOut.flush();
fOut.close();
MediaStore.Images.Media.insertImage(getContentResolver()
,file.getAbsolutePath(),file.getName(),file.getName());
}catch (Exception e) {
e.printStackTrace();
}
}

The way I found to send PNG and transparency.
String file_path = Environment.getExternalStorageDirectory().getAbsolutePath() +
"/CustomDir";
File dir = new File(file_path);
if(!dir.exists())
dir.mkdirs();
String format = new SimpleDateFormat("yyyyMMddHHmmss",
java.util.Locale.getDefault()).format(new Date());
File file = new File(dir, format + ".png");
FileOutputStream fOut;
try {
fOut = new FileOutputStream(file);
yourbitmap.compress(Bitmap.CompressFormat.PNG, 85, fOut);
fOut.flush();
fOut.close();
} catch (Exception e) {
e.printStackTrace();
}
Uri uri = Uri.fromFile(file);
Intent intent = new Intent(android.content.Intent.ACTION_SEND);
intent.setType("image/*");
intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "");
intent.putExtra(android.content.Intent.EXTRA_TEXT, "");
intent.putExtra(Intent.EXTRA_STREAM, uri);
startActivity(Intent.createChooser(intent,"Sharing something")));

Save Bitmap to your Gallery Without Compress.
private File saveBitMap(Context context, Bitmap Final_bitmap) {
File pictureFileDir = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES), "Your Folder Name");
if (!pictureFileDir.exists()) {
boolean isDirectoryCreated = pictureFileDir.mkdirs();
if (!isDirectoryCreated)
Log.i("TAG", "Can't create directory to save the image");
return null;
}
String filename = pictureFileDir.getPath() + File.separator + System.currentTimeMillis() + ".jpg";
File pictureFile = new File(filename);
try {
pictureFile.createNewFile();
FileOutputStream oStream = new FileOutputStream(pictureFile);
Final_bitmap.compress(Bitmap.CompressFormat.PNG, 100, oStream);
oStream.flush();
oStream.close();
Toast.makeText(Full_Screen_Activity.this, "Save Image Successfully..", Toast.LENGTH_SHORT).show();
} catch (IOException e) {
e.printStackTrace();
Log.i("TAG", "There was an issue saving the image.");
}
scanGallery(context, pictureFile.getAbsolutePath());
return pictureFile;
}
private void scanGallery(Context cntx, String path) {
try {
MediaScannerConnection.scanFile(cntx, new String[]{path}, null, new MediaScannerConnection.OnScanCompletedListener() {
public void onScanCompleted(String path, Uri uri) {
Toast.makeText(Full_Screen_Activity.this, "Save Image Successfully..", Toast.LENGTH_SHORT).show();
}
});
} catch (Exception e) {
e.printStackTrace();
Log.i("TAG", "There was an issue scanning gallery.");
}
}

You want to save Bitmap to Directory of your Choice. I have made a library ImageWorker that enables the user to load, save and convert bitmaps/drawables/base64 images.
Min SDK - 14
Pre-requisite
Saving files would require WRITE_EXTERNAL_STORAGE permission.
Retrieving files would require READ_EXTERNAL_STORAGE permission.
Saving Bitmap/Drawable/Base64
ImageWorker.to(context).
directory("ImageWorker").
subDirectory("SubDirectory").
setFileName("Image").
withExtension(Extension.PNG).
save(sourceBitmap,85)
Loading Bitmap
val bitmap: Bitmap? = ImageWorker.from(context).
directory("ImageWorker").
subDirectory("SubDirectory").
setFileName("Image").
withExtension(Extension.PNG).
load()
Implementation
Add Dependencies
In Project Level Gradle
allprojects {
repositories {
...
maven { url 'https://jitpack.io' }
}
}
In Application Level Gradle
dependencies {
implementation 'com.github.ihimanshurawat:ImageWorker:0.51'
}
You can read more on https://github.com/ihimanshurawat/ImageWorker/blob/master/README.md

Make sure the directory is created before you call bitmap.compress:
new File(FileName.substring(0,FileName.lastIndexOf("/"))).mkdirs();

Create a video thumbnail for a video. It may return null if the video is corrupted or the format is not supported.
private void makeVideoPreview() {
Bitmap thumbnail = ThumbnailUtils.createVideoThumbnail(videoAbsolutePath, MediaStore.Images.Thumbnails.MINI_KIND);
saveImage(thumbnail);
}
To Save your bitmap in sdcard use the following code
Store Image
private void storeImage(Bitmap image) {
File pictureFile = getOutputMediaFile();
if (pictureFile == null) {
Log.d(TAG,
"Error creating media file, check storage permissions: ");// e.getMessage());
return;
}
try {
FileOutputStream fos = new FileOutputStream(pictureFile);
image.compress(Bitmap.CompressFormat.PNG, 90, fos);
fos.close();
} catch (FileNotFoundException e) {
Log.d(TAG, "File not found: " + e.getMessage());
} catch (IOException e) {
Log.d(TAG, "Error accessing file: " + e.getMessage());
}
}
To Get the Path for Image Storage
/** Create a File for saving an image or video */
private File getOutputMediaFile(){
// To be safe, you should check that the SDCard is mounted
// using Environment.getExternalStorageState() before doing this.
File mediaStorageDir = new File(Environment.getExternalStorageDirectory()
+ "/Android/data/"
+ getApplicationContext().getPackageName()
+ "/Files");
// This location works best if you want the created images to be shared
// between applications and persist after your app has been uninstalled.
// Create the storage directory if it does not exist
if (! mediaStorageDir.exists()){
if (! mediaStorageDir.mkdirs()){
return null;
}
}
// Create a media file name
String timeStamp = new SimpleDateFormat("ddMMyyyy_HHmm").format(new Date());
File mediaFile;
String mImageName="MI_"+ timeStamp +".jpg";
mediaFile = new File(mediaStorageDir.getPath() + File.separator + mImageName);
return mediaFile;
}

Some new devices don't save bitmap So I explained a little more..
make sure you have added below Permission
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
and create a xml file under xml folder name provider_paths.xml
<?xml version="1.0" encoding="utf-8"?>
<paths>
<external-path
name="external_files"
path="." />
</paths>
and in AndroidManifest under
<provider
android:name="android.support.v4.content.FileProvider"
android:authorities="${applicationId}.provider"
android:exported="false"
android:grantUriPermissions="true">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="#xml/provider_paths"/>
</provider>
then simply call saveBitmapFile(passYourBitmapHere)
public static void saveBitmapFile(Bitmap bitmap) throws IOException {
File mediaFile = getOutputMediaFile();
FileOutputStream fileOutputStream = new FileOutputStream(mediaFile);
bitmap.compress(Bitmap.CompressFormat.JPEG, getQualityNumber(bitmap), fileOutputStream);
fileOutputStream.flush();
fileOutputStream.close();
}
where
File getOutputMediaFile() {
File mediaStorageDir = new File(
Environment.getExternalStorageDirectory(),
"easyTouchPro");
if (mediaStorageDir.isDirectory()) {
// Create a media file name
String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss")
.format(Calendar.getInstance().getTime());
String mCurrentPath = mediaStorageDir.getPath() + File.separator
+ "IMG_" + timeStamp + ".jpg";
File mediaFile = new File(mCurrentPath);
return mediaFile;
} else { /// error handling for PIE devices..
mediaStorageDir.delete();
mediaStorageDir.mkdirs();
galleryAddPic(mediaStorageDir);
return (getOutputMediaFile());
}
}
and other methods
public static int getQualityNumber(Bitmap bitmap) {
int size = bitmap.getByteCount();
int percentage = 0;
if (size > 500000 && size <= 800000) {
percentage = 15;
} else if (size > 800000 && size <= 1000000) {
percentage = 20;
} else if (size > 1000000 && size <= 1500000) {
percentage = 25;
} else if (size > 1500000 && size <= 2500000) {
percentage = 27;
} else if (size > 2500000 && size <= 3500000) {
percentage = 30;
} else if (size > 3500000 && size <= 4000000) {
percentage = 40;
} else if (size > 4000000 && size <= 5000000) {
percentage = 50;
} else if (size > 5000000) {
percentage = 75;
}
return percentage;
}
and
void galleryAddPic(File f) {
Intent mediaScanIntent = new Intent(
"android.intent.action.MEDIA_SCANNER_SCAN_FILE");
Uri contentUri = Uri.fromFile(f);
mediaScanIntent.setData(contentUri);
this.sendBroadcast(mediaScanIntent);
}

Hey just give the name to .bmp
Do this:
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
_bitmapScaled.compress(Bitmap.CompressFormat.PNG, 40, bytes);
//you can create a new file name "test.BMP" in sdcard folder.
File f = new File(Environment.getExternalStorageDirectory()
+ File.separator + "**test.bmp**")
it'll sound that IM JUST FOOLING AROUND but try it once it'll get saved in bmp foramt..Cheers

After Android 4.4 Kitkat, and as of 2017 share of Android 4.4 and less is about 20% and decreasing, it's not possible to save to SD card using File class and getExternalStorageDirectory() method. This method returns your device internal memory and images save visible to every app. You can also save images only private to your app and to be deleted when user deletes your app with openFileOutput() method.
Starting with Android 6.0, you can format your SD card as an internal memory but only private to your device.(If you format SD car as internal memory, only your device can access or see it's contents) You can save to that SD card using other answers but if you want to use a removable SD card you should read my answer below.
You should use Storage Access Framework to get uri to folder onActivityResult method of activity to get folder selected by user, and add retreive persistiable permission to be able to access folder after user restarts the device.
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (resultCode == RESULT_OK) {
// selectDirectory() invoked
if (requestCode == REQUEST_FOLDER_ACCESS) {
if (data.getData() != null) {
Uri treeUri = data.getData();
tvSAF.setText("Dir: " + data.getData().toString());
currentFolder = treeUri.toString();
saveCurrentFolderToPrefs();
// grantUriPermission(getPackageName(), treeUri,
// Intent.FLAG_GRANT_READ_URI_PERMISSION |
// Intent.FLAG_GRANT_WRITE_URI_PERMISSION);
final int takeFlags = data.getFlags()
& (Intent.FLAG_GRANT_READ_URI_PERMISSION | Intent.FLAG_GRANT_WRITE_URI_PERMISSION);
// Check for the freshest data.
getContentResolver().takePersistableUriPermission(treeUri, takeFlags);
}
}
}
}
Now, save save folder to shared preferences not to ask user to select folder every time you want to save an image.
You should use DocumentFile class to save your image, not File or ParcelFileDescriptor, for more info you can check this thread for saving image to SD card with compress(CompressFormat.JPEG, 100, out); method and DocumentFile classes.

// |==| Create a PNG File from Bitmap :
void devImjFylFnc(String pthAndFylTtlVar, Bitmap iptBmjVar)
{
try
{
FileOutputStream fylBytWrtrVar = new FileOutputStream(pthAndFylTtlVar);
iptBmjVar.compress(Bitmap.CompressFormat.PNG, 100, fylBytWrtrVar);
fylBytWrtrVar.close();
}
catch (Exception errVar) { errVar.printStackTrace(); }
}
// |==| Get Bimap from File :
Bitmap getBmjFrmFylFnc(String pthAndFylTtlVar)
{
return BitmapFactory.decodeFile(pthAndFylTtlVar);
}