Develop Reference

Multiple colors for single path Android

Good day.I am creating a siri like wave for android and i encounter an big issue.I need the wave to be in 4 colors.Lets assume i only have one single line which is drawing on the screen accordingly to the voice decibels.Anyway i am able to do it but no way i am able to give 4 different colors for same path.Assume it is 1 single path which moves from screen start to screen end,i need that line to have 4 different colors,mainly i had to divide the path into 4 parts and draw the color for each parts,but neither google,nor any other source give me anything (not even found anything similar to what i want).
Meanwhile i am posting the code where actually i am drawing the lines.
for (int l = 0; l < mWaveCount; ++l) {
float midH = height / 2.0f;
float midW = width / 2.0f;
float maxAmplitude = midH / 2f - 4.0f;
float progress = 1.0f - l * 1.0f / mWaveCount;
float normalAmplitude = (1.5f * progress - 0.5f) * mAmplitude;
float multiplier = (float) Math.min(1.0, (progress / 3.0f * 2.0f) + (1.0f / 3.0f));
if (l != 0) {
mSecondaryPaint.setAlpha((int) (multiplier * 255));
}
mPath.reset();
for (int x = 0; x < width + mDensity; x += mDensity) {
float scaling = 1f - (float) Math.pow(1 / midW * (x - midW), 2);
float y = scaling * maxAmplitude * normalAmplitude * (float) Math.sin(
180 * x * mFrequency / (width * Math.PI) + mPhase) + midH;
// canvas.drawPoint(x, y, l == 0 ? mPrimaryPaint : mSecondaryPaint);
//
// canvas.drawLine(x, y, x, 2*midH - y, mSecondaryPaint);
if (x == 0) {
mPath.moveTo(x, y);
} else {
mPath.lineTo(x, y);
// final float x2 = (x + mLastX) / 2;
// final float y2 = (y + mLastY) / 2;
// mPath.quadTo(x2, y2, x, y);
}
mLastX = x;
mLastY = y;
}
if (l == 0) {
canvas.drawPath(mPath, mPrimaryPaint);
} else {
canvas.drawPath(mPath, mSecondaryPaint);
}
}
I tried to change color on if (l == 0) {
canvas.drawPath(mPath, mPrimaryPaint);
} but if i change it here,no result at all,either the line is separate and not moving at all,but it should,either the color is not applied,propably because i am doing it in loop as i had to and everytime the last color is picked to draw.Anyway can you help me out?Even an small reference is gold for me because really there is nothing at all in the internet.

Anyway even though Matt Horst answer fully correct,i found the simplest and easiest solution...i never thought it would be so easy.Anyway if in world there is someone who need to make an path divided into multiple colors,here is what you can do
int[] rainbow = getRainbowColors();
Shader shader = new LinearGradient(0, 0, 0, width, rainbow,
null, Shader.TileMode.REPEAT);
Matrix matrix = new Matrix();
matrix.setRotate(90);
shader.setLocalMatrix(matrix);
mPrimaryPaint.setShader(shader);
Where getRainbowColors() is an array of colors you wish your line to have and width is the length of the path so the Shader knows how to draw the colors in right way to fit the length of path.Anyway .....easy isnt it?and pretty purged me a lot to get into this simple point.Nowhere in internet you could find only if you are looking for something completelly different,than you might come across this.

It seems to me like you could set up one paint for each section, each with a different color. Then set up one path for each section too. Then as you draw across the screen, wherever the changeover point is between sections, start drawing with the new path. And make sure first to use moveTo() on the new path so it starts off where the old one left off.

For my solution, I tried changing the color of the linePaint in the onDraw Call. But it was drawing a single color.
So i used two different paints for two different colors and draw path on the canvas.
And it worked. Hope it helps someone out there.

How to draw watchface 'ticks' on a square watch?

I currently have this snippet generating the ticks around the outside of and android wear watchface
float innerMainTickRadius = mCenterX - 35;
for(int tickIndex = 0; tickIndex < 12; tickIndex++) {
float tickRot = (float) (tickIndex * Math.PI * 2 / 12);
float innerX = (float) Math.sin(tickRot) * innerMainTickRadius;
float innerY = (float) -Math.cos(tickRot) * innerMainTickRadius;
float outerX = (float) Math.sin(tickRot) * mCenterX;
float outerY = (float) -Math.cos(tickRot) * mCenterX;
canvas.drawLine(mCenterX + innerX, mCenterY + innerY, mCenterX + outerX, mCenterY + outerY, mTickPaint);
}
Which generates the ticks well on a round watchface but on a square it turns out like this:
but I'd like them to not be circular, but instead fit the shape a bit more suitably, e.g:
Is there a standard way to do this? I'm guessing I can't use trig again...

Of course you use geometry and trig. For example any line you put on the clock face you want to point to the center so one part will be the given (x,y) and the other will be arctan2(cy-y,cx-x) giving you the angle from the point you have towards the center (cx,cy) then simply draw the line in the direction of the center of a given length r, by drawing the line from x,y to cos(angle) * r, sin(angle) * r.
However, given your sample image you might want to draw the line from x,y to x+r,y then rotate the canvas by angle so that you can draw those numbers tweaked like that. Be sure to do canvas.save() before tweaking the canvas' matrix and canvas.restore() after the tweak.
This leaves the math of whatever shape you want to draw your ticks from and the positions thereto. You can do this within a Path. So define the path for a rounded rectangle and then use the PathMeasure class to get the getPosTan() and then ignore the tangent and just use the position it gives you to find your position around a rounded rectangle. That or simply calculate those positions as the positions through either a line segment or a bezier section depending on the decided shape.
For example:
static final int TICKS = 12;
static final float TICKLENGTH = 20;
In the draw routine,
float left = cx - 50;
float top = cy - 50;
float right = cx + 50;
float bottom = cy + 50;
float ry = 20;
float rx = 20;
float width = right-left;
float height = bottom-top;
Path path = new Path();
path.moveTo(right, top + ry);
path.rQuadTo(0, -ry, -rx, -ry);
path.rLineTo(-(width - (2 * rx)), 0);
path.rQuadTo(-rx, 0, -rx, ry);
path.rLineTo(0, (height - (2 * ry)));
path.rQuadTo(0, ry, rx, ry);
path.rLineTo((width - (2 * rx)), 0);
path.rQuadTo(rx, 0, rx, -ry);
path.rLineTo(0, -(height - (2 * ry)));
path.close();
PathMeasure pathMeasure = new PathMeasure();
pathMeasure.setPath(path,true);
float length = pathMeasure.getLength();
float[] pos = new float[2];
float r = TICKLENGTH;
for (int i = 0; i < TICKS; i++) {
pathMeasure.getPosTan(i * (length/TICKS),pos,null);
double angle = Math.atan2(cy - pos[1], cx - pos[0]); //yes, y then x.
double cos = Math.cos(angle);
double sin = Math.sin(angle);
canvas.drawLine(pos[0], pos[1], (float)(pos[0] + cos * r), (float)(pos[1] + sin * r), paint);
}
Admittedly it looks like:
So it would take a lot more work to get it looking like your image. But, it's totally doable. The path measure trick thing will work for any shape. I avoided using path.addRoundRect because of the Lollipop+ restriction. You can see my answer to that question here. And the other answers which are plenty fine to how to draw a rounded rectangle-esque shape. You can, if you would like to write an envelope function simply scale your current picture to the envelope of the rectangle according to the factor t, as it goes around the clock.

The angle is a function of the position now. I'm not immediately seeing the trick for getting a closed form in this case. But in the most general case, you could end up just storing the position of each tickmark, then you're just drawing the line that goes through that point and the center. so the angle at second i is just
theta(i)=arctan(y_pos(i) / x_pos(i))
assuming the center has coordinates (0,0). In this case, you only need to store the positions for 8 consecutive ticks because the face is periodic every 90 degrees and symmetric about the diagonals as well.

Drawing stripes in a flag math formula

I have a rectangle with known size and position. (flag)
I have to fill this rectangle with 4 other rectangles. (stripes)
Each stripe must have 1/4 of the total width of the flag and his position is near the previous.
I have to draw this stripes with a random angle that goes from 0° to 90°.
0° = Vertical stripes (stripe width = flag width / 4)
90° = Horizontal stripes (stripe width = flag height / 4)
How can I calculate the width of each stripe for other angles?
int stripes = 4;
RectF rect = new RectF(0, 0, 100f, 75f);
float angle = new Random.nextInt(90);
float stripeSize;
if (angle == 0) {
stripeSize = rect.width() / stripes;
} else if (angle == 90) {
stripeSize = rect.height() / stripes;
} else {
stripeSize = ?
}
canvas.save();
canvas.rotate(angle, rect.centerX(), rect.centerY());
float offset = 0;
for (int i = 0; i < stripes; i++) {
if (angle == 0) {
reusableRect.set(offset, rect.top, offset + stripeSize, rect.bottom);
} else if (angle == 90) {
reusableRect.set(rect.left, offset, rect.right, offset + stripeSize);
} else {
reusableRect.set(?, ?, ?, ?);
}
canvas.drawRect(reusableRect, paint);
offset += stripeSize;
}
canvas.restore();

Let's pretend you have one stripe. Depending on the angle, the stripe width is going to be a value between the shorter dimension (the height in your case) and the longer dimension (the width in your case). The formula for the stripe width calculation should look something like this:
height + ((width - height) * ?)
where ? varies between 0 and 1 based on the angle of rotation. To me that sounds like the sine function might be a good candidate: sine(0) = 0 and sine(90) = 1. You can use Math.sin(), but be aware that the argument it takes is in radians, not degrees, so you need to use Math.toRadians() on your angle first. Then just divide by the number of stripes:
double radians = Math.toRadians(angle);
float stripeTotal = height + ((width - height) * Math.sin(radians));
float stripeWidth = stripeTotal / 4; // or however many stripes you have
If it's not perfect, you can adjust the formula. One last point, since these values only need to be calculated once, I would do that separately every time the angle changes (if it ever changes), not inside of onDraw().

Getting the overlapping area of two circles

I'm in a tremendous bind with a last minute request on a consulting project I'm working on.
Essentially here is what I am trying to accomplish:
I have a surfaceview that draws a series of randomly sized circles. Each circle can have a radius from 50-100.
The x,y values are randomly generated along with a random radius
Each circle is created as an object representing that circle (x, y coord's and radius) and it is added to a list.
Once they are all created they are drawn.
The problem is I want to make sure none of these circles overlap.
I'm struggling a bit. This seems like it's shouldn't be all that difficult but it is for me unfortunately.
Here's my code so far (I know it's not close...be kind):
x = 100 + (int) (Math.random() * (mCanvasWidth - 200));
y = 100 + (int) (Math.random() * (mCanvasHeight - 200));
radius = 50 + (int) (Math.random() * 99);
color[0] = (float) (Math.random() * 360);
color[1] = 1;
color[2] = 1;
String radVal = String.valueOf(radius);
circle circ = new circle(x, y, radius, Color.HSVToColor(128, color), radVal);
boolean addit = true;
for (dot d : Dots) {
int leftSide = d.get_x() - radius;
int rightSide = d.get_x() + radius;
int xBoundary = x + radius;
int yBoundary = y + radius;
int exist_xLeft = d.get_x() - d.get_radius();
int exist_xRight = d.get_x() + d.get_radius();
int exist_yTop = d.get_y() - d.get_radius();
int exist_yBottom = d.get_y() + d.get_radius();
if ((xBoundary > exist_xLeft) && (xBoundary < exist_xRight))
{
if (yBoundary > (exist_yTop) && (yBoundary < exist_yBottom)) {
addit = false;
break;
}
}
}
if (addit)
circles.add(mdot);
if (circles.size() >= 5)
running = false;
Then it iterates the circles list and draws them to the canvas.
Any suggestions on where I'm failing in the collision detection?

You can detect if 2 circles are colliding like this:
Given:
centerpoints cx1,cy1 & cx2,cy2
and given radii r1 & r2,
Then you can determine if the 2 circles are colliding:
areColliding=((cx2-cx1)*(cx2-cx1)+(cy2-cy1)*(cy2-cy1))<((r1+r2)*(r1+r2));

Detect road lanes with android and opencv

i have problem with detection road lanes with my phone.
i wrote some code for road lanes detection, but him not working for me.
From camera get modifications from normal view to BGR colors and try use GausianBlur and Canny, but i think i not good draw lanes for detection.
Maybe some people have another idea how detection road lanes with OpenCV?
Mat mYuv = new Mat(height + height / 2, width, CvType.CV_8UC1);
Mat mRgba = new Mat(height + height / 2, width, CvType.CV_8UC1);
Mat thresholdImage = new Mat(height + height / 2, width, CvType.CV_8UC1);
mYuv.put(0, 0, data);
Imgproc.cvtColor(mYuv, mRgba, Imgproc.COLOR_YUV420p2BGR, 4);
//convert to grayscale
Imgproc.cvtColor(mRgba, thresholdImage, Imgproc.COLOR_mRGBA2RGBA, 4);
// Perform a Gaussian blur (convolving in 5x5 Gaussian) & detect edges
Imgproc.GaussianBlur(mRgba, mRgba, new Size(5,5), 2.2, 2);
Imgproc.Canny(mRgba, thresholdImage, VActivity.CANNY_MIN_TRESHOLD, VActivity.CANNY_MAX_THRESHOLD);
Mat lines = new Mat();
double rho = 1;
double theta = Math.PI/180;
int threshold = 50;
//do Hough transform to find lanes
Imgproc.HoughLinesP(thresholdImage, lines, rho, theta, threshold, VActivity.HOUGH_MIN_LINE_LENGTH, VActivity.HOUGH_MAX_LINE_GAP);
for (int x = 0; x < lines.cols() && x < 1; x++){
double[] vec = lines.get(0, x);
double x1 = vec[0],
y1 = vec[1],
x2 = vec[2],
y2 = vec[3];
Point start = new Point(x1, y1);
Point end = new Point(x2, y2);
Core.line(mRgba, start, end, new Scalar(255, 0, 0), 3);
}

This approach is fine and I've done something similar, not for road line detection but I did notice that it could be used for that purpose. Some comments:
Not sure why you do:
Imgproc.cvtColor(mRgba, thresholdImage, Imgproc.COLOR_mRGBA2RGBA, 4);
as 1. the comment say convert to greyscale, which is a single channel and 2. thresholdImage will get overwritten with the call to Canny later. You just need to dimension thresholdImage with:
thresholdImage = new Mat(mRgba.size(), CvType.CV_8UC1);
What are your parameter values to the call to Canny? I played about with mine considerably and ended up with values like: threshold1 = 441, threshold2 = 160, aperture = 3.
Likewise Imgproc.HoughLinesP: I use Imgproc.HoughLines rather than Imgproc.HoughLinesP with parameters: threshold = 80, minLen = 30, maxLen = 10.
Also have a look at:
for (int x = 0; x < lines.cols() && x < 1; x++){
&& x < 1 means you will only take the first line that the call to HoughLinesP returns. I'd suggest you remove this and use some other criteria to reduce the number of lines; for example, I was interesting in only horizontal and vertical lines so I used atan2 to calculate line angles and exclude those that deviate too much.
UPDATE
Here is how I get the angle of a line. Assuming coordinates of one point is (x1,y1) and the other (x2, y2) then to get the angle:
double lineAngle = Math.atan2(y2 - y1, x2 - x1);
this should return an angle in radians between -PI/2 and PI/2
With regard Canny parameters then I would experiment - I set up onTouch so that I could adjust the threshold values by touching certain parts of the screen to see the effects in realtime. Note that aperture is rather disappointing parameter: it seems to only like odd values 3, 5 and 7 and 3 is the best that I've found.
Something like in the onTouch method:
int w = mRgba.width();
int h = mRgba.height();
float x = event.getX();
float y = event.getY();
if ((x < w / 3) && (y < h / 2)) t1 += 20;
if ((x < w / 3) && (y >= h / 2)) t1 -= 20;
if ((x > 2 * w / 3) && (y < h / 2)) t2 += 20;
if ((x > 2 * w / 3) && (y >= h / 2)) t2 -= 20;
t1 and t2 being the threshold values passed to the Canny call.