My current activity contains fragments. I want to open new Activity on button click from current activity. New Activity is transparent, and because of that I have to hide fragment from prev Activity. No buttons from prev activity should be shown under new Activity's buttons. I've done that. It works. Only problem is because there is little pause between switching these two Activities. Obviusly hiding fragment of prev activity takes time. Can I make it hide fragment faster? Here is my code:
#Override
public void onArcadeButtonClicked() {
fragmentManager= getSupportFragmentManager();
FragmentTransaction transaction = fragmentManager.beginTransaction();
transaction.hide(fragments[MAINMENU]);
transaction.commit();
Intent i= new Intent(this,ArcadeMapActivity.class);
startActivity(i);
}
When i remove first four lines and only call new Intent there is no pause, new Activity is shown immediately, but fragment from old Activity stays visible under new Activity. Any idea how to solve this problem?
Related
So I have Activity A with Fragment A.1, and I also have Activity B with Fragment B.1.
What I want to ask is, how do I move directly from Fragment A.1 to Fragment B.1?
I know to move from Fragment A.1 to Activity B, is by:
Intent i = new Intent (getActivity (), MainActivity.class);
startActivity (i);
getActivity ().finish();
But how to move straight to Fragment B.1?
Each Activity A and Activity B has a different <FrameLayout> for Fragment replacement
UPDATE 1.0
I've tried my own way and also the way #cewaphi answered with code like this,
In Activity A:
Intent i = new Intent(TransactionDone.this, MainActivity.class);
i.putExtra("immediatelyTransactionToFragment", true);
startActivity(i);
finishAffinity();
In Activity B:
boolean shouldTransitionToFragment = getIntent().getBooleanExtra("immediatelyTransationToFragment", true);
if (shouldTransitionToFragment) {
Fragment fragment = new Wallet();
FragmentTransaction transaction = getSupportFragmentManager().beginTransaction();
transaction.replace(R.id.mainFrameLayout, fragment);
transaction.commit();
Log.d("DEBUGGING REDIRECT", "Go to Fragment B.1");
}
The log "Go to Fragment B.1" was created but the transaction doesn't work
When using a single activity and e.g. using the navigation component is not an option.
Consider the following:
In your fragment A.1 when starting the activity store a Boolean
i.putExtra("immediatelyTransationToFragment", true);
In activity B
shouldTransitionToFragment = getIntent().getBooleanExtra("immediatelyTransationToFragment");
// after activity was created
if (shouldTransitionToFragment) {
// Execute the transition action as you would when pressing the button
}
Update 2020/09/07
You are trying to transition to a Fragment from your Activity like this:
FragmentTransaction transaction = getSupportFragmentManager().beginTransaction();
transaction.replace(R.id.mainFrameLayout, fragment);
transaction.commit();
The documentation states that you should first add the fragment to the activity:
ExampleFragment fragment = new ExampleFragment();
fragmentTransaction.add(R.id.fragment_container, fragment);
fragmentTransaction.commit();
Apparently your transition works when you click your button. Are you doing it the same?
But I assume at that time the activity has already been created.
Try once to add your fragment instead of replace. I don't know how your container is initialised but adding might be the operation you want, I refer to this good answer for clarification.
Also consider to perform to call this transaction after your activity was created.
I'm trying to go back to main page fragment when user click to 'Done' button. It can be like swifts' "dismiss()" function. However, I dont know what am I using like that function in android.
My code run like; open activity from fragment and this fragment load detail fragment.
First of all, the first fragments' adapter open the second fragments' activity :
Intent intent = new Intent(view.getContext(), DetailActivity.class);
intent.putExtra(Consts.EXTRA_OFFER_DETAIL, binding.getController());
view.getContext().startActivity(intent);
After that, activity open fragment automatically
FragmentTransaction transaction = getSupportFragmentManager().beginTransaction();
transaction.replace(R.id.container_fragment, new DetailFragment(), null);
transaction.commit();
And I want to close last fragment when user click alert dialogs' done button
builder.setNegativeButton("Done", new DialogInterface.OnClickListener() {
#Override
public void onClick(DialogInterface dialogInterface, int i) {
getActivity().getFragmentManager().popBackStack(); //That is what I tried but doesnt work
}
});
I'm not quite sure about your activity and fragment workflow but to close the whole activity you can just call
finish();
to dismiss the whole activity.
Since there is no fragement in the backstack, popBackStack() won't do anything.
If you only wnat to dismiss the fragement, you should use:
super.onBackPressed();
I am developing an android in which when I pressed device back button I go to previous fragment. What I want to achieve is that when I pressed device back button I don't want to go to previous fragment. How can I achieve that?.
You must be doing calling addtobackstack("name") while adding or replacing the fragment.Remove this function before calling next fragment you wont go back to previous fragment for further desc
Do not add that fragment to backstack of the new fragment you're calling. Look at the below example I've used to explain you how this works.
To make that fragment come again, just add that fragment to backstack which you want to come on back pressed,
Eg:
btnSignIn.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
Fragment fragment = new LoginFragment();
//replacing the fragment
if (fragment != null) {
FragmentTransaction ft = ((FragmentActivity)getContext()).getSupportFragmentManager().beginTransaction();
ft.replace(R.id.content_frame, fragment);
ft.addToBackStack("SignupFragment");
ft.commit();
}
}
});
In the above case, I m opening a LoginFragment when signIn button is pressed, right now am in SignupFragment. So if I call addToBackStack(TAG), TAG = "SignupFragment", then when back button is pressed in LoginFragment, we come to SignUpFragment.
Happy Coding!
I have an app in which I swap two fragments. The fragments are in a LinearLayout. Below the linearlayout I have icons (ImageViews) that when clicked hides or shows the appropriate fragment. When the app first loads, everything is fine. After I exit my app and use another app then return to my app the fragments dont hide/show when I click the icons (ImageView). WHy is this happening? Does it have something to do with the activity life cycles?
xml_layout:
<LinearLayout
android:id="#+id/Linearlayout"
android:layout_width="match_parent"
android:layout_height="wrap_content"
>
</LinearLayout>
onCreate()
{
ft = this.getSupportFragmentManager()
.beginTransaction();
frag1= new Frag1();
frag2= new Frag2();
ft.add(R.id.linearlayout,frag1);
ft.add(R.id.linearlayout, frag2);
ft.hide(frag1).show(frag2);
ft.commit();
icon1.setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
ftt = MainActivity.this.getSupportFragmentManager()
.beginTransaction();
ftt.hide(frag2).show(frag1);
ftt.commit();
}
});
}
I think your problem is in this line:
ft.hide(frag2).show(frag2);
You want to hide frag1 and show frag2:
ft.hide(frag1).show(frag2);
Yes, the answer relates to the activity cycle. You need to override onCreateView and put your onClickListener inside of that. The onCreate is only getting called when the activity is first created. OnCreateView is called immediately after that, but it is also called when your activity is brought back to the front after you return from another activity.
I have this design problem. I have an activity which hosts two fragment and any given point of time only one activity is visible.
Activity A hosts Fragment B and Fragment C
Host Activity A implements FragmentCommunicator interface and implement respond(int code) method using this method communicator both Fragment B and C can talk to host Activity.
Now here is the problem.
In onClick of Host activity I check certain condition and based on that I take decision which fragment to show.
public void onClick(View v) {
switch (v.getId()) {
case R.id.some_button
if(authNotedone)
showFragmentA();
else{
EDIT: //setting some properties before showing Fragment B
showFragmentB();
}
}
}
So far it works fine. If condition is true FragmentA will be visible with login form. After successful login I would like to show fragment B again. How can I achieve this.
What I have tried?
1) After successful login Fragment A send message to Host activity using Fragmentcommunicator's respond(code) method but it was ugly design as I have to either call performClick() or call showFragmentA() in respond method if code is success.
There could be multiple such conditions in my program How I can handle these neatly?
Use a interface as a call back to the activity. Once you get the message in the activity there is no need to click the button just replace the existing fragment in the container.
Implement the interface in the activity
FragmentB newFragment = new FragmentB();
Bundle args = new Bundle();
args.putInt("key", "message");
newFragment.setArguments(args);
FragmentTransaction transaction = getFragmentManager().beginTransaction();
transaction.replace(R.id.fragment_container, newFragment);
// replace with fragmentb. no need to perform click again.
// based on the message you decide which fragment you want to replace with
transaction.commit();
You can find an example #
http://developer.android.com/training/basics/fragments/communicating.html
Do you want to navigate between fragments? If so, why don't you implement navigation tabs, have a look at this link.