How can I do that my application appears in the “share” list of another application? For example, I want to choose a pdf file and send it to my application.
I can’t find the solution, any idea?
Thanks
You can add an intent filter in your AndroidManifest.xml
for example for a pdf you can indicate the mimeType application/pdf.
<activity name="package.name.MyActivity">
<intent-filter>
<action android:name="android.intent.action.VIEW"/>
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:mimeType="application/pdf" />
</intent-filter>
</activity>
Look at the documentation at http://developer.android.com/guide/components/intents-filters.html#Receiving
Related
I'm creating a messaging app with Air for Android. I would like to enable other apps to share text to my app via the share menu option.
How do I get my app listed in there?
(This is the menu I would like to get listed in:)
Add an appropriate intent filter in your Activity tag in manifest file.
<intent-filter>
<action android:name="android.intent.action.SEND" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="text/plain" />
</intent-filter>
Your Activity will show up, when Android searches for such Share Intent handlers.
To an Activity that will handle any shared content, add an Intent Filter to your Manifest. For example:
<intent-filter>
<action android:name="android.intent.action.SEND" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="text/plain" />
<data android:mimeType="image/*" />
</intent-filter>
I want my service to be accessible as one of the default options of the Share page when the user long-touches the web-link (standard android feature). This is what I wrote in the manifest file :
<service android:name=".ShareLink"
android:enabled="true">
<intent-filter>
<action android:name="android.intent.action.SEND" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="text/plain" />
</intent-filter>
</service>
But it is still not being displayed. What am I doing wrong? P.S. When I do the same thing with the Activity - it works fine.
This is not possible, You will have to write a Dummy Activity to do this.
This is because, ResolverActivity that shows the names or selects the appropriate component to launch gets the list by querying Only Activities that match intent with API PackageManager.queryIntentActivities
This should do it:
<intent-filter
android:label="Open Using My Service">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<data android:scheme="http" />
</intent-filter>
I want to launch my application from web browser in Android using Intent-Filter based on scheme, host in the DATA tag like this.
<activity android:name=".activity.LogoActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".activity.phone.MainActivityPhone" android:configChanges="orientation|keyboard"
android:launchMode="singleTask">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="my" android:host="mystore" />
</intent-filter>
</activity>
<activity android:name=".activity.tablet.MainActivityTablet" android:configChanges="orientation|keyboard"
android:launchMode="singleTask">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="my" android:host="mystore" />
</intent-filter>
</activity>
As you see, There are two Main Activities for phone and tablet, and in LogoActivity determine which Main Activity will be opened by screen size. But the problem is when user clicks my://mystore link in web browser, there are two choices to launch that MainActivtyPhone and MainActivityTablet.
What I want is there is only one proper intent-filter works for uri my://mystore .
Any help? Thanks.
On the first run of your application, use PackageManager to disable the activity you do not want to use.
Please do not invent custom schemes. Please use HTTP URLs instead:
<data android:scheme="http" android:host="yourdomain.com" android:path="/something/or/another" />
That way, you can actually put a real Web page at http://yourdomain.com/something/or/another, so if somebody gets your link but does not have your app installed, they will see your Web page, instead of getting an error.
Also, please remove android:configChanges, or handle all configuration changes.
I cannot download (from web & from e-mail) unkwown extentions such as (*.ini, *.zip, *.ddd)
unless there exists an app that can understand the extention.
For example, I couldn't download *.ini file from the browser (or email) until I downloaded 'Astro' app.
How can you by pass so that they are downloadable?
How can you register your app to understan certain extention so that it can be downloadable?
How can you by pass so that they are downloadable?
You don't.
How can you register your app to understan certain extention so that it can be downloadable?
Ideally, you don't. You do it by MIME type. File extensions are very fragile. However, either can be achieved via the use of the <data> element in your activity's <intent-filter>. You will also want the BROWSEABLE category and probably the VIEW action.
For example, here is how you would arrange to be an option for viewing PDF files:
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:mimeType="application/pdf" />
</intent-filter>
<activity
android:name=".Main"
android:label="#string/app_name">
<intent-filter>
<action
android:name="android.intent.action.MAIN" />
<category
android:name="android.intent.category.LAUNCHER" />
<category
android:name="android.intent.category.DEFAULT" />
<category
android:name="android.intent.category.BROWSABLE" />
<data
android:scheme="file" />
<data
android:pathPattern=".*\\.ini" />
<data
android:host="*" />
</intent-filter>
</activity>
Above code allowed me to download *.ini files.
Thank you for your help.
I'm trying to figure out how to launch an activity in my app from a custom URI such as myapp://myuriactivity
I've read a lot about the intent and intent filters in the android references and also read several examples, but for some reason I can't get my simple test to work. Below is my manifest file, can anyone tell me what I'm doing wrong? With the below file, if I open the browser and try to navigate to http://org.test.launchtest it just says the page doesn't exist. Shouldn't this work?
<?xml version="1.0" encoding="utf-8"?>
<activity android:name=".MyUriActivity">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http" android:host="org.test.launchtest" />
Hmm I wasn't able to do the trick with host too. Hence I ended up with using more specific scheme.
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="com.stackoverflow.example" />
</intent-filter>
Probably you may use scheme solution too?