I have two date fields (no, not the pickers) as fromDate and toDate. When I click on my Submit button, in the onResume(), I have validations in place for both date fields. When I enter an invalid value (not from syntax, locale, etc. point of view) for toDate and click Submit, I correctly see the toast. Then, I enter the correct the value and click Submit. The toast still appears ! In other words, the corrected date value is not being received.
I guess, I am missing the activity life-cycle w.r.t. toasts. (Each Toast is immediately followed by a return.) Can you please suggest what should be the correct flow to handle this error followed by correction ?
public class MainActivity extends Activity {
private Locale l ;
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// Set locale;
l = getResources().getConfiguration().locale;
}
#Override
protected void onResume() {
super.onResume();
addButtonListener();
}
private void addButtonListener() {
Button submitButton = (Button) findViewById(R.id.buttonSubmit);
submitButton.setOnClickListener(new OnClickListener() {
EditText fromDateText = (EditText) findViewById(R.id.fromDate);
EditText toDateText = (EditText) findViewById(R.id.toDate);
#Override
public void onClick(View v) {
String s;
if (fromDateText.getText().toString().isEmpty()) {
Toast.makeText(getApplicationContext(), R.string.err_fromDate_1, Toast.LENGTH_SHORT).show();
return;
}
if (toDateText.getText().toString().isEmpty()) {
Toast.makeText(getApplicationContext(), R.string.err_toDate_1, Toast.LENGTH_SHORT).show();
return;
}
}
});
}
}
Edited to add source code.
Make fromDateText and toDateText class variables and init them in onCreate.
Related
can i know pls why the input variable why it's giving me error always, thank you so much.
This is my code below:
public class MainActivity extends AppCompatActivity {
public TextView textView;
public EditText editText;
public Button btn;
public int input;
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
textView=findViewById(R.id.textView);
editText = findViewById(R.id.editText);
btn = findViewById(R.id.btn);
` input= Integer.parseInt(editText.getText().toString());`
btn.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
textView.setText(input );
}
});
}
}
The error is happening as the String cant be cast to an integer. This could be because your editText is empty or that you have characters that are not integers in there (E.g. Letters). Therefor you should use try and catch to catch the error.
Currently you are trying to parse the input string from editText in onCreate() as soon as the view is created. This will try to parse the default text associated with the editText. I think what you want is to parse the input at the time of clicking button. In that case move the input parsing code inside onClick(). Also it is better to catch NumberFormatException when calling parseInt() if you cannot guarantee that the text entered in the EditText is always an integer.
#Override
public void onClick(View v) {
android.util.Log.i("MyActivity", "onClick: edit text = " + editText.getText());
input= Integer.parseInt(editText.getText().toString());
textView.setText(input );
}
If the user clicks the "go" button, the application should check if the EditText's value is "Settings" or not? How can I do this?
Something like this:
Button buttn1;
EditText Text1;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
buttn1 = (Button)findViewById(R.id.Button111);
Text1 = (EditText)findViewById(R.id.Text111);
buttn1.setOnClickListener(new View.OnClickListener(){
#Override
public void onClick(View v) {
if (Text1 == "Settings") {
//CODE
}else {
//CODE
}
}
});
}
You can get the content of an EditText field like this: Text1.getText().toString() and you can check String equality using .equals().
So combined, this would be Text1.getText().toString().equals("Settings")
Try This:
if (Text1.getText().toString().equals("Settings")) {
//CODE
}else {
//CODE
}
Can any one tell me? how can i use the same button for two Action?
Like em using one button in my activity that calculate some values and after calculating the when i again press same button then reset the all fields. Like in this Application
http://www.craziness.com/games/play-love-tester/ when i test the love by pressing the button
then i again press the same button then all fields reset.
what should i use in my activity for the above problem?
You can create a global variable which indicates the state of the program and then change this value when needed. In the OnClickListener of your Button you create an if statement which checks this variable and does the needed things for the associated value.
Example:
public class MainActivity extends Activity {
private int state = 0;
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button button = (Button) findViewById(R.id.button);
button.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
if (state == 0) {
// State 1
}
else if (state == 1) {
// State 2
}
else {
// Default state
}
}
});
// Rest of your code including state changing part
}
}
You can do it by changing the button text.
If you do not want that someone sees the text change. Test (example "click" and the other state "click " (1 blank at the end) or another solution.
....
Button bt = (Button) findViewById(R.id.button);
bt.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// todo: check for expected instance (Button)
Button btc = (Button)v;
String bText = btc.getText().toString();
if (bText == "open") {
btc.setText("close");
}
else if (bText == "close") {
btc.setText("open");
}
}
[...]
You can do so by using a toggle button.
In your xml file add a toggle button
<ToggleButton
android:id="#+id/tbtn"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text=""
android:textOff="Reset"
android:textOn="Calculation"
android:background="#drawable/icon"/>
Java file
public class Reviews extends Activity implements OnClickListener {
private ToggleButton tbtn;
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
tbtn = (ToggleButton) findViewById(R.id.tbtn);
tbtn.setOnClickListener(this);
public void onClick(View view) {
if (tbtn.isChecked()) {
//calculate the result
}
else {
//Reset your global calculation variable;
}
}
}
}
Can anyone please tell why the if statement never gets executed even though I enter ran in the edit text field and press ok? When the user enters ran and presses the button ok, I want another button to become visible which enables him to stop the current activity. Basically I want to know why the if is skipped.
public class Reciever extends Activity{
protected static final String TAG = null;
private Button ok,stp;
private TextView tv;
private EditText ev;
private String s1,s2,s3,s4;
#Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
s1="nar";
setContentView(R.layout.stop);
tv=(TextView) findViewById(R.id.textView1);
tv.setText(s1);
ev=(EditText) findViewById(R.id.editText1);
ok=(Button) findViewById(R.id.ok_button);
ok.setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
s2="ran";
tv.setText(ev.getText().toString());
s3=ev.getText().toString();
if(s3==s2)//not going inside this loop
{
stp=(Button) findViewById(R.id.stopb);
stp.setVisibility(View.VISIBLE);
stp.setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
// TODO Auto-generated method stub
finish();
}
});
}
}
});
}
}
if(s3==s2)//no
just replace the above line with below
if(s3.equalsIgnoreCase(s2))//no
Use .equals instead of == to compare the value of two strings.
if (s2.equals(s3))
Using == tests for reference equality. Two strings can contain the same characters but have different references.
You can't compare text with ==, you need to use equals.
if(s3.equals(s2))
I'm trying to create a simple username/password login screen. I have the layout done, and right now, I'm trying to set it so when the username (EditText) == "crete", then it should do something. Here is my code...:
public class Login extends Activity {
public static EditText username, password;
public Button loginbutton;
boolean accessgranted;
public String dbu, dbp, user1;
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
username = (EditText) this.findViewById(R.id.username);
password = (EditText) this.findViewById(R.id.password);
loginbutton = (Button) this.findViewById(R.id.loginbutton);
user1 = "crete";
loginbutton.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
try{
dbu = (username.getText()).toString();
}
finally{
if (dbu == user1){
username.setText("SUCCESS");
}
}
}
});
}
}
this, sadly, doesn't work. It correctly converts it to a string (i think) because when I tested this code out :
loginbutton.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
try{
dbu = (username.getText()).toString();
}
finally{
username.setText("done" + dbu);
}
}
}
});
It correctly enters what you entered into the EditText, plus the word "done".
There seems to be a problem with creating if-then statements??
You test for String equality with the method .equals("String").
With == you are testing if the references to the objects are equal.
Try using equalsIgnoreCase(String) instead of the == comparator.
Like this: dbu.equalsIgnoreCase(user1)
dub and user1 are two separate String objects. You're comparing them like this: dbu == user1. This will always return false. Instead, replace it with dbu.equals(user1).