How to get offline message of group chat from Openfire - android

Is any way in xmpp that i get offline message of MultiUserChat, when my user login and join room.
I want implement group chat like WhatsApp, Is any other way to implement this please suggest
Thanks in advance

At least in ejjaberd when you enter the chat group, you have to enter your last timestamp, given that timestamp you will receive the messages from that moment.
Save the timestamp from your last message, and when you enter to your room, like the following:
MultiUserChat muc = new MultiUserChat(mConnection, room_name);
Log.d(TAG, "JOINING => " + room_name);
DiscussionHistory history = new DiscussionHistory();
if (mLastMessageDate == null)
history.setMaxStanzas(300);
else
history.setSince(mLastMessageDate); //timestamp from your last message
muc.join(mNickName, null, history,
SmackConfiguration.getDefaultPacketReplyTimeout());
Hope it helps

First declare a MultiUserChat this way
private static MultiUserChat muc = null;
then in your oncreate method instantiate it this way
muc = new MultiUserChat(CONNECTION, room);
try {
muc.join(USERJID);
} catch (SmackException.NoResponseException e) {
e.printStackTrace();
} catch (XMPPException.XMPPErrorException e) {
e.printStackTrace();
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
and call this method in the beginning of your app
void setMessageListner() {
muc.addMessageListener(new PacketListener() {
#Override
public void processPacket(Packet packet) throws SmackException.NotConnectedException {
Message msg = (Message)packet;
msg.setSubject(msg,getBody);
Logger.i("Received message : "+msg.getBody()+" From "+msg.getSubject());
});
}
this way whenever the user get into a GroupChat he will get the last Messages of the group

Related

Invitation Listener not working smack 4.2

I can create group chat room successfully XMPP(smack). I have added
invitation listener, but never called. Does anyone know how to do it?
Using:
XMPP
Smack 4.2
Openfire server
Send Invitation code:
muc.invite(userId +"#" +XMPP.getInstance().HOST + "/Smack", "Meet me in this excellent room");
Invitation listener code:
MultiUserChatManager manager = MultiUserChatManager.getInstanceFor(connection);
manager.addInvitationListener(new InvitationListener() {
#Override
public void invitationReceived(XMPPConnection xmppConnection, MultiUserChat muc, String inviter, String reason, String password, Message message) {
try {
muc.join(nickname);
} catch (SmackException.NoResponseException e) {
e.printStackTrace();
} catch (XMPPException.XMPPErrorException e) {
e.printStackTrace();
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
}
});
Probably you have an issue about RESOURCE.
When you send an invitation to a certain JID, you might omit resource part or the message will be sent only to specified resource.
JID it's composed in following way:
user#serverdomain/resource
With this invitation, you are inviting only user using "Smack" as Resource.
Resource it's configurated in AbstractXMPPConnection object or in login phase
XMPPTCPConnectionConfiguration.builder()
.setServiceName(serverName)
.setHost(server)
.setPort(port)
.setResource( RESOURCE_IDENTIFIER)
.build();
connection = new XMPPTCPConnection(config);
connection.login(username, password, RESOURCE_IDENTIFIER);
So, probably, you declared as your resource identificator (just an arbitrary String) not "Smack" but "Spark" o something else or left default one.
Just omit Resource part (or fix with correct one, but I suggest to omit)
muc.invite(userId +"#" +XMPP.getInstance().HOST, "Meet me in this excellent room");
Of course, userId must exist and HOST it's the valid one

Android Smack MUC 400 Bad Request sending group Chat Message

Hey i am developing Chat Application using XMPP Smack Library. Recently i am working on Group Chat While sending Group message some message will be drop so receiver wouldn't receives message from the sender side. it will gives me 400 bad request.
it is working sometimes. and sometimes not work
here i found this kind of message in 400 bad request.
<?xml version="1.0" encoding="UTF-8"?>
<message to="156#abc.com/Android" id="nXlV6-1144" type="error" from="24#confrence.abc.com/156#abc.com.com">
<received xmlns="urn:xmpp:receipts" id="nXlV6-1142" />
<error code="400" type="modify">
<bad-request xmlns="urn:ietf:params:xml:ns:xmpp-stanzas" />
</error>
</message>
if successfully send message it will give this kind of message.
<?xml version="1.0" encoding="UTF-8"?>
<message to="156#abc.com/Android" id="nXlV6-1411" type="groupchat" from="24#conference.abc.com/156#abc.com">
<body>eyu4u4</body>
<chatDetail xmlns="jabber:x:oob">
<UID>156</UID>
<time>04:20 PM</time>
<user_icon>24_group_icon.jpg</user_icon>
<SentTime>1474368652960</SentTime>
<USERName>vasudev89</USERName>
<user_name>cryan</user_name>
<message>eyu4u4</message>
<type>group</type>
<phone_number>24</phone_number>
</chatDetail>
<request xmlns="urn:xmpp:receipts" />
</message>
how i can send message persistently? Any idea?
Thank You in Advance.
here is my code sending muc message:
public boolean sendGroupMessage(Message message, String strGroupID) {
DeliveryReceiptRequest.addTo(message);
try {
Log.i(TAG, "sendGroupMessage");
//Log.i("JOIN MUC","To join group chat: " + groupChat.getClassId());
// Get the MultiUserChatManager
MultiUserChatManager manager = MultiUserChatManager.getInstanceFor(AbstractXMPPConnection);
// Create a MultiUserChat using an XMPPConnection for a room
MultiUserChat muc = manager.getMultiUserChat(strGroupID + AppWSConstants.XMPP_JID_GROUP_CHAT_SUFFIX);
muc.sendMessage(message);
return true;
} catch (NotConnectedException e) {
e.printStackTrace();
}
return false;
}
#LearnPainLess, follow these steps to solve group chat issue
-when creating groups, save the jid of group in the database, like "somegroup#conference.{domain}.com"
-create background task for creating xmpp connection (this way it will always be connected)
-after logging in to xmpp, get the group names from the database and connect to them
also, in openfire, Group Chat > Group Chat Settings > Edit Icon > Default Room Settings > Check "Make Room Persistant"
also, in other settings > Never kick idle users
I have an XmppBase class where i put all my xmpp code
All listeners in seperate folder
Connection is stored in static variable and i retrive it using
Utils.getConnection()
// this function m calling from background service and everywhere if not connectect to xmpp
public static XMPPConnection CreateXmppConnection() {
if (Utils.getConnection() == null) {
try {
Boolean isConnected = new XmppAsync(mUsername, mPassword,context).execute().get();
if (isConnected && Utils.getConnection() != null) {
RegisterConnListeners(Utils.getConnection());
updateMyProfileImg();
// connect to all groups
DBAdapter adapter = new DBAdapter(context);
adapter.openForRead();
List<UserDetail> groups = new ArrayList<>();
adapter.addAllGroups(groups);
adapter.addPastChatGroups(groups);
adapter.close();
for(UserDetail g : groups)
{
CreateXmppMUCSession(g.getGroupTemp());
}
return Utils.getConnection();
}
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
}
return null;
} else
return Utils.getConnection();
}
// get muc chat manager
public static MultiUserChatManager getMucManager() {
if(mucManager != null)
return mucManager;
if (Utils.getConnection() != null) {
return MultiUserChatManager.getInstanceFor(Utils.getConnection());
} else {
if (CreateXmppConnection() != null)
return MultiUserChatManager.getInstanceFor(Utils.getConnection());
else {
Log.v("error", "Some Error Occured");
Toast.makeText(context, "Cant Connect to Xmpp", Toast.LENGTH_SHORT).show();
return null;
}
}
}
// create muc session and m passing group name - call when you open chat page
public static void CreateXmppMUCSession(String gName)
{
RegisterGroupChatListeners(gName);
}
// connect to muc if not already connected
public static void RegisterGroupChatListeners(String groupName)
{
try {
mStateManager = getChatStateManager();
multiUserChat = getMUC(groupName);
// if(multiUserChat != null) {
multiUserChat.addMessageListener(new MyMUCMessageListener());
try {
if (!multiUserChat.isJoined()) {
DiscussionHistory discussionHistory = new DiscussionHistory();
discussionHistory.setMaxStanzas(0);
multiUserChat.join(new MyPrefrence(context).getUsername().split("#")[0], "123",
discussionHistory, SmackConfiguration.getDefaultPacketReplyTimeout());
}
} catch (SmackException.NoResponseException e) {
e.printStackTrace();
} catch (XMPPException.XMPPErrorException e) {
e.printStackTrace();
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
// }
}
catch (Exception ex)
{
//
}
}
// get muc
public static MultiUserChat getMUC(String groupName)
{
// Log.v("nick",multiUserChat.getNickname() + " , g = " + groupName);
// if(multiUserChat != null && multiUserChat.getRoom().contains(groupName))
// {
// return multiUserChat;
// }
if (Utils.getConnection() != null) {
MultiUserChatManager chatManager = getMucManager();
if (chatManager != null) {
return chatManager.getMultiUserChat(groupName);
} else {
Toast.makeText(context, "Cannot create Chat", Toast.LENGTH_SHORT).show();
return null;
}
} else {
if (CreateXmppConnection() != null) {
MultiUserChatManager chatManager = getMucManager();
if (chatManager != null) {
return chatManager.getMultiUserChat(groupName);
} else {
Toast.makeText(context, "Cannot create Chat", Toast.LENGTH_SHORT).show();
return null;
}
}
else {
Toast.makeText(context, "Cannot create Chat", Toast.LENGTH_SHORT).show();
return null;
}
}
}
and whenever i want to send message i just call this
public static Boolean sendMUCChatMsg(Message msg)
{
if(multiUserChat != null)
try {
multiUserChat.sendMessage(msg);
return true;
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
return false;
}
Sorry if it looks clumpsy, if I missed any function there let me know, but this is working code which i am using
try this,
I modified your last function
static MultiUserChat multiUserChat;
// call this function when you open the chat window
private void CreateGroupConnection(String strGroupID ) {
// Get the MultiUserChatManager
MultiUserChatManager manager = MultiUserChatManager.getInstanceFor(AbstractXMPPConnection);
// Create a MultiUserChat using an XMPPConnection for a room
MultiUserChat multiUserChat = manager.getMultiUserChat(strGroupID + AppWSConstants.XMPP_JID_GROUP_CHAT_SUFFIX);
return multiUserChat;
}
// whenever sending message from chat call this
publilc static void sendMucMessage(Message message){
if(multiUserChat != null)
multiUserChat.sendMessage(message);
}
I am working on "seen and delivered" in MUC and facing with this issue when replying back with the same packet id, still testing but I think in your case you should move your xmpp connection to background service and after connecting to xmpp on device launch up, connect to all the muc in your database. This way you will always be connected to groups.
cause : according to me, when the other user is not connected to the muc and you send a message or when you reply to the group with the same packet id.
Note: I am using multiuserchat.sendmessage to send group message and chat.sendmessage to send message to single user
SMACK 4.1
** update **
I fixed it by creating new packet instead of modifying the one i am receiving
here is the packet
Message msgg = new Message();
msgg.setBody(message.getPacketID());
msgg.setSubject(MessageModel.CHAT_STATUS_SEEN + "");
XmppBase.sendMUCChatMsg(msgg);
in your case, try with simple packet first. if all works well, then add extension one by one and see where you get the error, Thanks

How to create and send Bye message from client to server in jainsip android?

I have tried jainsip example in Mobicents restcomm-android-sdk.Its worked for me but i am not able create bye message from client side properly.
I created a Bye Message class like this
public class Bye {
public Request MakeRequest(SipManager sipManager) throws ParseException,
InvalidArgumentException {
AddressFactory addressFactory = sipManager.addressFactory;
SipProvider sipProvider = sipManager.sipProvider;
MessageFactory messageFactory = sipManager.messageFactory;
HeaderFactory headerFactory = sipManager.headerFactory;
// Create addresses and via header for the request
Address fromAddress = addressFactory.createAddress("sip:"
+ sipManager.getSipProfile().getSipUserName() + "#"
+ sipManager.getSipProfile().getRemoteIp());
fromAddress.setDisplayName(sipManager.getSipProfile().getSipUserName());
Address toAddress = addressFactory.createAddress("sip:"
+ sipManager.getSipProfile().getSipUserName() + "#"
+ sipManager.getSipProfile().getRemoteIp());
toAddress.setDisplayName(sipManager.getSipProfile().getSipUserName());
Address contactAddress = sipManager.createContactAddress();
ArrayList<ViaHeader> viaHeaders = sipManager.createViaHeader();
URI requestURI = addressFactory.createAddress(
"sip:" + sipManager.getSipProfile().getRemoteEndpoint())
.getURI();
// Build the request
CallIdHeader callIdHeader = sipManager.sipProvider.;
final Request request = messageFactory.createRequest(requestURI,
Request.BYE, sipProvider.getNewCallId(),
headerFactory.createCSeqHeader(1l, Request.BYE),
headerFactory.createFromHeader(fromAddress, "c3ff411e"),
headerFactory.createToHeader(toAddress, null), viaHeaders,
headerFactory.createMaxForwardsHeader(70));
// Add the contact header
request.addHeader(headerFactory.createContactHeader(contactAddress));
ExpiresHeader eh = headerFactory.createExpiresHeader(300);
request.addHeader(eh);
// Print the request
System.out.println(request.toString());
return request;
// Send the request --- triggers an IOException
// sipProvider.sendRequest(request);
// ClientTransaction transaction = sipProvider
// .getNewClientTransaction(request);
// Send the request statefully, through the client transaction.
// transaction.sendRequest();
}
}
Call it From SipManager class as
public void disconnectCall() throws NotInitializedException {
// TODO Auto-generated method stub
if (!initialized)
throw new NotInitializedException("Sip Stack not initialized");
this.sipManagerState = SipManagerState.BYE;
Bye byeRequest = new Bye();
Request r=null ;
try{
r = byeRequest.MakeRequest(this);//byeRequest.MakeRequest(SipManager.this);
final ClientTransaction transaction = this.sipProvider
.getNewClientTransaction(r);
Thread thread = new Thread() {
public void run() {
try {
transaction.sendRequest();
} catch (SipException e) {
e.printStackTrace();
}
}
};
thread.start();
} catch (TransactionUnavailableException e) {
e.printStackTrace();
}catch (InvalidArgumentException e) {
e.printStackTrace();
} catch (ParseException e) {
e.printStackTrace();
}
}
I have got 481 error code as response.I think I have missed the current callid field in the bye message.I have searched for it but not found from sipmanager class.pls help.
Nidhin,
BYE messages are always inside a SIP dialog, so you don't have to create a new message from scratch. Instead, you just need to get ahold of the dialog you want to terminate, create a request of type BYE from that and send it. JAIN will take care of the rest.
For an example, you can check the code at the Mobicents restcomm-android-sdk repo, method sendByeClient():
https://github.com/Mobicents/restcomm-android-sdk/blob/master/sipua/src/main/java/org/mobicents/restcomm/android/sipua/impl/SipManager.java#L931
Please also keep in mind that the JAIN SIP example has been obsoleted by Messenger example that uses the Restcomm Android Client SDK which offers a simpler API. Here's its code for your reference:
https://github.com/Mobicents/restcomm-android-sdk/tree/master/Examples/restcomm-messenger

Missing Offline messages asmack (Android)

I have offline messages option enabled in the openfire server.But I'm unable to get offline messages
User A is online ,User B is online ,in this case I'm able to get messages.
Now User B Turned off his WiFi(Note : User A waited till the user B Session completely killed in the server )
now User A send a message to User B
in this case I'm able to see the message in the openfire offline table.
Now User B Comes online again server is sending the message to user B as the server come to know that User B is online
(Message disappeared from offline messages table ).
But User B is not going to receive that message.
connection.login(userName, userPwd, UiUtility.getMyPhoneNO());
PacketFilter filter = new PacketTypeFilter(org.jivesoftware.smack.packet.Message.class);
packetListener =new PacketListener() {
public void processPacket(Packet packet) {
Message message = (Message) packet;
if (message.getBody() != null) {
String fromName = StringUtils.parseBareAddress(message
.getFrom());
Log.i("XMPPClient", "Got text [" + message.getBody()
+ "] from [" + fromName + "]");
}
}
};
connection.addPacketListener(packetListener, filter);
Again after successful login im able to chat normally.But I wonder why those offline messages are missing ? .My PacketListener unable to catch those offline messages .Please Help me
Asmack is depreceated. Use Smack. An Open Source XMPP Client Library written in Java for JVMs and Android. Add the following lines to your gradle file:
compile 'org.igniterealtime.smack:smack-android:4.1.3'
compile 'org.igniterealtime.smack:smack-tcp:4.1.3'
compile 'org.igniterealtime.smack:smack-extensions:4.1.3'
The problem is easy to be solved.
Before making connection with the XMPP server just register providers using ProviderManager class provided by ASmack library.
If this can't solve ur problem visit ur local server and search for offline messages, and select the option ALWAYS STORE setting the storage limit to be 1000 kb. It is 100 kb by default.
Hope this works.
After lot struggle, I have resolved the issue. In your openfire admin page, go to "client settings" and reduce the idle time from 360sec (by default) to 1 sec(may be). Only then when you disconnected from Internet, it can detect that you are offline and preserve rest of the messages as OFFLINE.
#Override
public void onNetworkConnectionChanged(boolean isConnected) {
if(isConnected){
new Thread() {
public void run() {
try {
XMPPTCPConnectionConfiguration.Builder builder = XMPPTCPConnectionConfiguration.builder();
builder.setSecurityMode(ConnectionConfiguration.SecurityMode.disabled);
builder.setUsernameAndPassword("phone", "admin");
builder.setSendPresence(true);
builder.setServiceName(<Service name>);
builder.setHost(<Host name>);
builder.setResource("Test");
builder.setDebuggerEnabled(true);
Presence presence = new Presence(Presence.Type.available);
presence.setStatus("Available");
connection = new XMPPTCPConnection(builder.build());
connection.connect();
connection.login();
Presence presence123 = new Presence(Presence.Type.available);
presence123.setStatus("Available");
try {
connection.sendStanza(presence123);
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
StanzaFilter filter = new AndFilter(new StanzaTypeFilter(Message.class));
PacketListener myListener = new PacketListener()
{
public void processPacket(Stanza stanza)
{
retrieveMessage(stanza,userType);
}
};
connection.addPacketListener(myListener, filter);
try {
connection.sendStanza(presence);
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
} catch (SmackException | XMPPException | IOException e) {
e.printStackTrace();
}
//return connection.isConnected();
}
}.start();
The above is working fine and able to retrieve the offline messages. The method "retrieveMessage(stanza,userType);" is used to process the incoming message and update the Adapter. Make sure to send the Presence as "Available" when you reconnect. Please let me know if there are still any issues.

How to Add and Subscribe a jabber entry to my XMPP Account?

I am able to add Entry to the Xmpp account by using this code. i can't get subscription "both", instead of this i am getting none.
roster.createEntry("abc#xyz.com", "abc", null);
How to add entry with the presence type=both, when i am subscribing entry to this account. I want to know whether xmpp publish-subscribe functionality ?
How to get Inbound presence notifications ?
How to send Outbound presence notifications ?
EDIT :
public void Addcontact() {
Roster.setDefaultSubscriptionMode(Roster.SubscriptionMode.manual);
Roster roster = m_connection.getRoster();
if(!roster.contains("pa#ace.com")) { try {
roster.createEntry("pa#ace.com", "pa", null);
} catch (XMPPException e) {
e.printStackTrace();
}
}else {
Log.i("Acc = ", "contains");
}
}
I am adding entry like this still i am getting Presence Type = none..
Here is how I add another friend in my application.
protected void doAddContactToListAsync(String address, String name,
ContactList list) throws ImException {
debug(TAG, "add contact to " + list.getName());
Presence response = new Presence.Type.subscribed);
response.setTo(address);
sendPacket(response);
Roster roster = mConnection.getRoster();
String[] groups = new String[] { list.getName() };
if (name == null) {
name = parseAddressName(address);
}
try {
roster.createEntry(address, name, groups);
// If contact exists locally, don't create another copy
Contact contact = makeContact(name, address);
if (!containsContact(contact))
notifyContactListUpdated(list,
ContactListListener.LIST_CONTACT_ADDED, contact);
else
debug(TAG, "skip adding existing contact locally " + name);
} catch (XMPPException e) {
throw new RuntimeException(e);
}
}
Just use the essential part
Presence response = new Presence.Type.subscribed);
response.setTo(address);
sendPacket(response);
Roster roster = mConnection.getRoster();
roster.createEntry(address, name, groups);
In order to listen to incoming request, register addPacketListener to your connection
mConnection.addPacketListener(new PacketListener() {
#Override
public void processPacket(Packet packet) {
Presence presence = (Presence) packet;
if (presence.getType() == Type.subscribe) {
debug(TAG, "sub request from 1" + address);
//Implement accept or reject depend on user action.
mContactListManager.getSubscriptionRequestListener()
.onSubScriptionRequest(contact);
//or you can test with send back Presence.subscribe first and send Presence.subscribed back to requester.
} else {// Handle other Presence type.
int type = parsePresence(presence);
debug(TAG, "sub request from " + type);
contact.setPresence(new Presence(type,
presence.getStatus(), null, null,
Presence.CLIENT_TYPE_DEFAULT));
}
}
}, new PacketTypeFilter(Presence.class));
mConnection.connect();
The right order:
User1 send Subscribe to user2.
User2 send Subscribe and Subsribed back to user1.
User1 send Subsribed to user2.
Another SO question you can check

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