How to convert file URI to file path? - android

I getting an URI when try to pick a file :
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
intent.setType("file/*");
startActivityForResult(intent,FILE_MANAGER_REQUEST_CODE);
In ActivityOnResult
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
Log.d("FilePick", "request code = " + requestCode + ", resultCode = " + resultCode);
Log.d("FilePick", "Intent = " + data != null ? data.getData().getPath() : null);
super.onActivityResult(requestCode, resultCode, data);
}
When i pick a file data.getData().getPath() returns
/external/file/15499
How i convert it to real file path?
Note: I read this topics :
Get filename and path from URI from mediastore
Get real path from URI, Android KitKat new storage access framework
But i think it's accessible onl;y for media content. Not for files.

There is no "real file path". A Uri is not a File.
Please use ContentResolver and methods like openInputStream() to consume the content.

Related

Editing Image using Image Uri

I have a image uri and I want to edit that image and obtain the new Image uri. After some searching I found this piece of code and tries to apply.
Intent editIntent = new Intent(Intent.ACTION_EDIT);
editIntent.setDataAndType(uri, "image/*");
editIntent.setFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
startActivityForResult(Intent.createChooser(editIntent, null), 222);
When I try to receive in callbacks I get null in data.
#Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
System.out.println("REQUEST_CODE: " + requestCode + " " + resultCode + " " + data.getData());
}
So how to get the new image uri or is there any other way to do this?
ACTION_EDIT is not designed for use with startActivityForResult(), as there is no result. See the documentation, particularly the "Output: nothing" portion.
What the other app does with the Uri is up to the other app. It might save changes to the original content identified by the Uri that you gave it, or it might not. If it elects to save changes to some new content, there is no means for you to find out where those changes were saved.

Select pdf from storage dont working in android Oreo [duplicate]

I am trying to fetch a file this way:
final Intent chooseFileIntent = new Intent(Intent.ACTION_GET_CONTENT);
String[] mimetypes = {"application/pdf"};
chooseFileIntent.setType("*/*");
chooseFileIntent.addCategory(Intent.CATEGORY_OPENABLE);
if (chooseFileIntent.resolveActivity(activity
.getApplicationContext().getPackageManager()) != null) {
chooseFileIntent.putExtra(Intent.EXTRA_MIME_TYPES, mimetypes);
activity.startActivityForResult(chooseFileIntent, Uploader.PDF);
}
Then in onActivityResult :
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
}
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath(), the file name I'm expecting is my_file.pdf, but instead I'm getting this :
/document/acc=1;doc=28
So what to do? Thanks for your help.
I am trying to fetch a file
Not with that code. That code is asking the user to pick a piece of content. This may or may not be a file.
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath()
That was never correct, though it tended to work on older versions of Android.
So what to do?
Well, that depends.
If you wish to only accept files, integrate a file chooser library instead of using ACTION_GET_CONTENT. (UPDATE 2019-04-06: since Android Q is banning most filesystem access, this solution is no longer practical)
If you are willing to allow the user to pick a piece of content using ACTION_GET_CONTENT, please understand that it does not have to be a file and it does not have to have something that resembles a filename. The closest that you will get:
If getScheme() of the Uri returns file, your original algorithm will work
If getScheme() of the Uri returns content, use DocumentFile.fromSingleUri() to create a DocumentFile, then call getName() on that DocumentFile — this should return a "display name" which should be recognizable to the user
To get the real name and to avoid getting a name that looks like "image: 4431" or even just a number, you can write code as recommended by CommonsWare.
The following is an example of a code that selects a single pdf file, prints its name and path to the log, and then sends the file by email using its uri.
private static final int FILEPICKER_RESULT_CODE = 1;
private static final int SEND_EMAIL_RESULT_CODE = 2;
private Uri fileUri;
private void chooseFile() {
Intent fileChooser = new Intent(Intent.ACTION_GET_CONTENT);
fileChooser.setType("application/pdf");
startActivityForResult(Intent.createChooser(fileChooser, "Choose one pdf file"), FILEPICKER_RESULT_CODE);
}
#Override
protected void onActivityResult(int requestCode, int resultCode, #Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == FILEPICKER_RESULT_CODE) {
if (resultCode == RESULT_OK) {
fileUri = data != null ? data.getData() : null;
if (fileUri != null) {
DocumentFile d = DocumentFile.fromSingleUri(this, fileUri);
if (d != null) {
Log.d("TAG", "file name: " + d.getName());
Log.d("TAG", "file path: " + d.getUri().getPath());
sendEmail(fileUri);
}
}
}
}
}
private void sendEmail(Uri path) {
String email = "example#gmail.com";
Intent intent = new Intent(android.content.Intent.ACTION_SEND);
intent.setType("application/octet-stream");
intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "PDF file");
String[] to = { email };
intent.putExtra(Intent.EXTRA_EMAIL, to);
intent.putExtra(Intent.EXTRA_TEXT, "This is the pdf file...");
intent.putExtra(Intent.EXTRA_STREAM, path);
startActivityForResult(Intent.createChooser(intent, "Send mail..."), SEND_EMAIL_RESULT_CODE);
}
hope it helps.

How to get file path from "/document/(some_number)" uri [duplicate]

I am trying to fetch a file this way:
final Intent chooseFileIntent = new Intent(Intent.ACTION_GET_CONTENT);
String[] mimetypes = {"application/pdf"};
chooseFileIntent.setType("*/*");
chooseFileIntent.addCategory(Intent.CATEGORY_OPENABLE);
if (chooseFileIntent.resolveActivity(activity
.getApplicationContext().getPackageManager()) != null) {
chooseFileIntent.putExtra(Intent.EXTRA_MIME_TYPES, mimetypes);
activity.startActivityForResult(chooseFileIntent, Uploader.PDF);
}
Then in onActivityResult :
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
}
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath(), the file name I'm expecting is my_file.pdf, but instead I'm getting this :
/document/acc=1;doc=28
So what to do? Thanks for your help.
I am trying to fetch a file
Not with that code. That code is asking the user to pick a piece of content. This may or may not be a file.
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath()
That was never correct, though it tended to work on older versions of Android.
So what to do?
Well, that depends.
If you wish to only accept files, integrate a file chooser library instead of using ACTION_GET_CONTENT. (UPDATE 2019-04-06: since Android Q is banning most filesystem access, this solution is no longer practical)
If you are willing to allow the user to pick a piece of content using ACTION_GET_CONTENT, please understand that it does not have to be a file and it does not have to have something that resembles a filename. The closest that you will get:
If getScheme() of the Uri returns file, your original algorithm will work
If getScheme() of the Uri returns content, use DocumentFile.fromSingleUri() to create a DocumentFile, then call getName() on that DocumentFile — this should return a "display name" which should be recognizable to the user
To get the real name and to avoid getting a name that looks like "image: 4431" or even just a number, you can write code as recommended by CommonsWare.
The following is an example of a code that selects a single pdf file, prints its name and path to the log, and then sends the file by email using its uri.
private static final int FILEPICKER_RESULT_CODE = 1;
private static final int SEND_EMAIL_RESULT_CODE = 2;
private Uri fileUri;
private void chooseFile() {
Intent fileChooser = new Intent(Intent.ACTION_GET_CONTENT);
fileChooser.setType("application/pdf");
startActivityForResult(Intent.createChooser(fileChooser, "Choose one pdf file"), FILEPICKER_RESULT_CODE);
}
#Override
protected void onActivityResult(int requestCode, int resultCode, #Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == FILEPICKER_RESULT_CODE) {
if (resultCode == RESULT_OK) {
fileUri = data != null ? data.getData() : null;
if (fileUri != null) {
DocumentFile d = DocumentFile.fromSingleUri(this, fileUri);
if (d != null) {
Log.d("TAG", "file name: " + d.getName());
Log.d("TAG", "file path: " + d.getUri().getPath());
sendEmail(fileUri);
}
}
}
}
}
private void sendEmail(Uri path) {
String email = "example#gmail.com";
Intent intent = new Intent(android.content.Intent.ACTION_SEND);
intent.setType("application/octet-stream");
intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "PDF file");
String[] to = { email };
intent.putExtra(Intent.EXTRA_EMAIL, to);
intent.putExtra(Intent.EXTRA_TEXT, "This is the pdf file...");
intent.putExtra(Intent.EXTRA_STREAM, path);
startActivityForResult(Intent.createChooser(intent, "Send mail..."), SEND_EMAIL_RESULT_CODE);
}
hope it helps.

onActivityResult's intent.getPath() doesn't give me the correct filename

I am trying to fetch a file this way:
final Intent chooseFileIntent = new Intent(Intent.ACTION_GET_CONTENT);
String[] mimetypes = {"application/pdf"};
chooseFileIntent.setType("*/*");
chooseFileIntent.addCategory(Intent.CATEGORY_OPENABLE);
if (chooseFileIntent.resolveActivity(activity
.getApplicationContext().getPackageManager()) != null) {
chooseFileIntent.putExtra(Intent.EXTRA_MIME_TYPES, mimetypes);
activity.startActivityForResult(chooseFileIntent, Uploader.PDF);
}
Then in onActivityResult :
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
}
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath(), the file name I'm expecting is my_file.pdf, but instead I'm getting this :
/document/acc=1;doc=28
So what to do? Thanks for your help.
I am trying to fetch a file
Not with that code. That code is asking the user to pick a piece of content. This may or may not be a file.
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath()
That was never correct, though it tended to work on older versions of Android.
So what to do?
Well, that depends.
If you wish to only accept files, integrate a file chooser library instead of using ACTION_GET_CONTENT. (UPDATE 2019-04-06: since Android Q is banning most filesystem access, this solution is no longer practical)
If you are willing to allow the user to pick a piece of content using ACTION_GET_CONTENT, please understand that it does not have to be a file and it does not have to have something that resembles a filename. The closest that you will get:
If getScheme() of the Uri returns file, your original algorithm will work
If getScheme() of the Uri returns content, use DocumentFile.fromSingleUri() to create a DocumentFile, then call getName() on that DocumentFile — this should return a "display name" which should be recognizable to the user
To get the real name and to avoid getting a name that looks like "image: 4431" or even just a number, you can write code as recommended by CommonsWare.
The following is an example of a code that selects a single pdf file, prints its name and path to the log, and then sends the file by email using its uri.
private static final int FILEPICKER_RESULT_CODE = 1;
private static final int SEND_EMAIL_RESULT_CODE = 2;
private Uri fileUri;
private void chooseFile() {
Intent fileChooser = new Intent(Intent.ACTION_GET_CONTENT);
fileChooser.setType("application/pdf");
startActivityForResult(Intent.createChooser(fileChooser, "Choose one pdf file"), FILEPICKER_RESULT_CODE);
}
#Override
protected void onActivityResult(int requestCode, int resultCode, #Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == FILEPICKER_RESULT_CODE) {
if (resultCode == RESULT_OK) {
fileUri = data != null ? data.getData() : null;
if (fileUri != null) {
DocumentFile d = DocumentFile.fromSingleUri(this, fileUri);
if (d != null) {
Log.d("TAG", "file name: " + d.getName());
Log.d("TAG", "file path: " + d.getUri().getPath());
sendEmail(fileUri);
}
}
}
}
}
private void sendEmail(Uri path) {
String email = "example#gmail.com";
Intent intent = new Intent(android.content.Intent.ACTION_SEND);
intent.setType("application/octet-stream");
intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "PDF file");
String[] to = { email };
intent.putExtra(Intent.EXTRA_EMAIL, to);
intent.putExtra(Intent.EXTRA_TEXT, "This is the pdf file...");
intent.putExtra(Intent.EXTRA_STREAM, path);
startActivityForResult(Intent.createChooser(intent, "Send mail..."), SEND_EMAIL_RESULT_CODE);
}
hope it helps.

Android - open txt file from Intent Chooser

by click on some button - an intent for selecting txt file is created:
Intent intent = new Intent()
.setType("text/plain")
.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select a TXT file"), 123);
And it works OK - I select txt file from root folder on phone internal memory --- /storage/emulated/0/kote.txt
But when I try to read data from it, I get FileNotFoundException:
#Override
public void onActivityResult(int requestCode, int resultCode, Intent intent) {
super.onActivityResult(requestCode, resultCode, intent);
if(requestCode==123 && resultCode==RESULT_OK) {
Uri selectedfile_uri = intent.getData();
Log.e("TAG7", "selectedfile_uri --- " + selectedfile_uri );
File myFile_test1 = new File(selectedfile_uri.getPath());
Log.e("TAG7", myFile_test1.getPath() + " .exists() "+myFile_test1.exists());
File myFile_test2 = new File(selectedfile_uri.getEncodedPath());
Log.e("TAG7", myFile_test2.getPath() + " .exists() "+myFile_test2.exists());
function_read_txt_file(myFile_test1); //returns FileNotFoundException
function_read_txt_file(myFile_test2); //returns FileNotFoundException
}
}
logcat:
E/TAG7: selectedfile_uri --- content://com.android.externalstorage.documents/document/primary%3Akote.txt
E/TAG7: /document/primary:kote.txt .exists() false
E/TAG7: /document/primary%3Akote.txt .exists() false
E/TAG7: FileNotFoundException
What I'm missing here? cheers
Uri may not have the directly accessible path to your file. You should open the file by opening the InputStream from the Uri
Uri selectedfile_uri = intent.getData();
InputStream inputStream = getContentResolver().openInputStream()

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