how to send a HTTP SEARCH request in HttpURLConnection on Android? - android

I want to know if it is possible to send SEARCH request (practically) through java.net.HttpURLConnection to HTTP-based URL.
I have read so many articles describing that how to send GET, POST, DELETE requests but I still haven't found any sample code which successfully performs SEARCH request.
here is sample code.
public static String HTTPSearch(String urlAddress, String... searchDataPair) {
HttpParams myParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(myParams, 10000);
HttpConnectionParams.setSoTimeout(myParams, 30000);
DefaultHttpClient hc = new DefaultHttpClient(myParams);
ResponseHandler<String> res = new BasicResponseHandler();
HttpSearch searchMethod = new HttpSearch (urlAddress);
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(
putDataPair.length / 2);
for (int i = 0; i < putDataPair.length; i += 2) {
nameValuePairs.add(new BasicNameValuePair(searchDataPair[i],
searchDataPair[i + 1]));
}
String response = "";
try {
searchMethod .setEntity(new UrlEncodedFormEntity(nameValuePairs));
response = hc.execute(searchMethod , res);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return response;
}
in this code, HttpSearch is error.
please help me about HttpSearch.

First, i dont know whether my approach is best or not.
Im using restful codeigniter webservice. What i did to implement search is by using POST. I simply POST the search keyword and then my webservice will perform SQL Query to search that String (keyword) im my database.

According to the docs, the setRequestMethod() does not allow for the SEARCH method (which makes sense, since from what I can tell SEARCH is MS only. However, you can always try to use setRequestMethod() and see what happens.

Related

Recieving HTML file as responce instead of JSON Object through get request

I am developing an android app where user logs on to his/her account. After logging in I will receive XSRF token and Laravel Session Id to recognise the specific user. I have to send these tokens for every request I send to the API's to get the appropriate information. But when I am sending the required details as shown in the image, I am getting HTMl file as response instead of getting JSON Object. I was seriously stuck at this problem. Correct Solution may take forward the whole app.
class RegisterConnection extends AsyncTask<String,String,JSONObject> {
protected JSONObject doInBackground(String... arg0) {
JSONObject output = new JSONObject();
DefaultHttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 5000); //Timeout Limit
HttpResponse response = null;
try {
HttpGet get = new HttpGet(statsURL);
get.setHeader("Accept", "application/json");
CookieStore store = new BasicCookieStore();
BasicClientCookie cookie1 = new BasicClientCookie("XSRF-TOKEN", XSRF);
BasicClientCookie cookie2 = new BasicClientCookie("laravel_session", laravel);
store.addCookie(cookie1);
store.addCookie(cookie2);
client.setCookieStore(store);
response = client.execute(get);
if(response!=null){
InputStream in = response.getEntity().getContent();
String resultstring = Utilities.convertStreamToString(in);
Log.i("Result1", resultstring);
output = new JSONObject(resultstring);
Log.i("Result2", output.toString());
}
} catch(Exception e) {
e.printStackTrace();
try {
output.put("sai","error");
Log.i("MainActivity", output.toString());
} catch (JSONException e1) {
e1.printStackTrace();
}
return output;
}
return output;
}
These are the server requirements
http://imgur.com/OY9Q673
This is the Output received
http://imgur.com/IB5AEcT
As far as I can tell, there is nothing wrong with your Android client code.
You are getting HTML from the server so the main reason could be that your Laravel server is rendering the views and sending you back html instead of JSON. Instead of rendering the views on the server, you should send JSON response on your Laravel server side.
Add Jsoup dependency in your gradle file
implementation 'org.jsoup:jsoup:1.11.2'
Document document = Jsoup.parse("http://imgur.com/IB5AEcT");
Elements el = doc.select("button");
Log.i("..........",""+el.attr("data-invite-details"));
Jsoup tutorial
http://jsoup.org/apidocs/org/jsoup/Jsoup.html

I have got Socket Timeout Exception but My data submitted on server too

I have got an prob with http post request i have set time out and on socket time out exception my data submitted on server successfully how i can restrict data to submitted on server my code is following
try{HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(
AppSettings.SERVICE_URL.POST_NEW_REGISTRATION);
HttpConnectionParams.setConnectionTimeout(
httpClient.getParams(), 5000);
HttpConnectionParams.setSoTimeout(httpClient.getParams(), 5000);
JSONObject jsonObject = new JSONObject();
jsonObject.put("agent_id", SharedPrefrence.getUserID());
httpPost.setEntity(new StringEntity(jsonObject.toString(),
"UTF-8"));
// Set up the header types needed to properly transfer JSON
httpPost.setHeader("Content-Type", "application/json");
httpPost.setHeader("Accept-Encoding", "application/json");
// Execute POST
//int getConnectionTimeout (HttpParams params);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity responseEntity = httpResponse.getEntity();
if (responseEntity != null) {
response = EntityUtils.toString(responseEntity);
} else {
response = "{'success':'FALSE'}";
}
} catch (ClientProtocolException e) {
response = "{'success':'FALSE'}";
progressDialog.cancel();
} catch (IOException e) {
response = "{'success':'FALSE','message':'Connection Time Out'}";
Log.d("Ex", e.toString());
Log.e("Ex", e.toString());
progressDialog.cancel();
} catch (JSONException e) {
response = "{'success':'FALSE','message':'JSON Parse Error'}";
progressDialog.cancel();
e.printStackTrace();
} catch (Exception e) {
response = "{'success':'FALSE'}";
progressDialog.cancel();
e.printStackTrace();
}
I think you are saying that you are getting a socket timeout exception even though the data is successfully received by the server?
If so, I think you may want to look at the value you are setting for the socket timeout - this appears to be 500ms in your code, which is quite short. It is quite possible that everything on the server side is working fine, but that the response is simply not getting to the client within 500ms.
A typical default is in the 6-10 seconds range, but it is really solution dependent so you may want to experiment. This blog post suggests some defaults for different scenarios and may be a useful reference:
http://dev.bizo.com/2013/04/sensible-defaults-for-apache-httpclient.html
probably your API call takes more than 500 ms, increase it and try again.

RESTful web Service for Android Application

I have an application and I need to get some data from my database(MySQL and it stays on web, not local). I think a simple RestFul webservice will be the best option for me to access this database and get the data. However, I m not able to create the webservice. I did some researches but I got confused. All I need is just accessing the database and get a few data from the table. Please give me some help to create the neccessary webservice. I don't want it to be a complex webservice. Thank to you all
this is php page of web-service. in this userid is taken from android java file that requesting that data. and after that selecting data from mySql it will simply echo all data and that will be given to java file as response.
seluser_profile.php
<?php
//$con=mysql_connect("localhost","root","");
//mysql_select_db("android_db",$con);
$con=mysql_connect("localhost","root","");
mysql_select_db("android_db",$con);
$uname=$_POST['userid'];
$q="select * from user_details where username='$uname'";
$rec=mysql_query($q);
if(mysql_num_rows($rec)==1)
{
$arr=mysql_fetch_array($rec);
echo $arr[0]+" "+$arr[2]+" "+$arr[3];
}
else
{
echo "false";
}
?>
Java code for requesting to web service.
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.0.2/webservice/seluser_profile.php");
try {
// Add your data
//Toast.makeText(getApplicationContext(), "Hello", Toast.LENGTH_LONG).show();
List<NameValuePair> namevpair = new ArrayList<NameValuePair>(2);
namevpair.add(new BasicNameValuePair("userid",valueIWantToSend));//in this first argument is name of post variable which we will use in php web service as name of post varible $_POST['fname'];
httppost.setEntity(new UrlEncodedFormEntity(namevpair));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
str = inputStreamToString(response.getEntity().getContent()).toString();
//Toast.makeText(getApplicationContext(), "your answer="+str, Toast.LENGTH_LONG).show();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
use this java code in doInBackground method of Asynctask class. otherwise it will give you network handler exception.
private StringBuilder inputStreamToString(InputStream is) {
String line = "";
StringBuilder total = new StringBuilder();
// Wrap a BufferedReader around the InputStream
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
// Read response until the end
try {
while ((line = rd.readLine()) != null) {
total.append(line);
}
} catch (IOException e) {
e.printStackTrace();
}
// Return full string
return total;
}
and also add this function for string building from inputstream.
Here is a link, You may seen this while surfing, I know this is not an answer , but I cannot comment bcz I dnt have enough Rep.
http://www.androidhive.info/2014/01/how-to-create-rest-api-for-android-app-using-php-slim-and-mysql-day-12-2/
I used this in one of my project, customization was very easy..and a great tutorial.

HttpServletRequest get no parameters from my httppost

I have just a curiosity question. I have an HttpPost request in Android that looks something like this:
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(getString(R.string.url));
//This code does not work
HttpParams params = new BasicHttpParams();
params.setParameter("type", "20");
post.setParams(params);
try {
HttpResponse response = client.execute(post);
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
On my server side, I have a servlet that listens for requests and parses the parameters:
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
Enumeration en = request.getParameterNames();
while (en.hasMoreElements()){
System.out.println(en.nextElement());
}
}
When I execute this code, the servlet does not see any parameters at all. But if I replace the whole "parameter" chunk with this code:
//This code works
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(5);
nameValuePairs.add(new BasicNameValuePair("type", "20"));
try {
post.setEntity(new UrlEncodedFormEntity(nameValuePairs));
} catch (UnsupportedEncodingException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
My servlet can parse parameters. It's not a problem, I'm just going to use the entity but my question is, why can't my servlet getthe parameters from the first code chunk? What's wrong with setParams? Why can the servlet see parameters if I make them an entity?
In HTML when we have something like "http://host/path?user=uname&passwd=pass", we call the part (user=uname&passwd=pass) after the question mark "form data".The "form data" can be attached to the end of the URL after a question mark (as above), for GET requests, or sent to the server on a separate line, for POST requests.The "form data" are split to parameters. The parameters are separated by & when we use GET.
In our case the HttpPost and HttpGet classes extend the AbstractHttpMessage which implements the setParams method. This method is same for GET and POST but does the job only for GET! In the case of GET the parameters are put in the URL. In the case of POST you need to set the entity for the parameters to be on a "separate line".
On the server side when using servlets the getParameters is clever enough to find the parameters for GET and POST.
Thats why on the server side we do not need to change the code for getting the parameters!
Hope I helped!

How to send POST request in JSON using HTTPClient in Android?

I'm trying to figure out how to POST JSON from Android by using HTTPClient. I've been trying to figure this out for a while, I have found plenty of examples online, but I cannot get any of them to work. I believe this is because of my lack of JSON/networking knowledge in general. I know there are plenty of examples out there but could someone point me to an actual tutorial? I'm looking for a step by step process with code and explanation of why you do each step, or of what that step does. It doesn't need to be a complicated, simple will suffice.
Again, I know there are a ton of examples out there, I'm just really looking for an example with an explanation of what exactly is happening and why it is doing that way.
If someone knows about a good Android book on this, then please let me know.
Thanks again for the help #terrance, here is the code I described below
public void shNameVerParams() throws Exception{
String path = //removed
HashMap params = new HashMap();
params.put(new String("Name"), "Value");
params.put(new String("Name"), "Value");
try {
HttpClient.SendHttpPost(path, params);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
In this answer I am using an example posted by Justin Grammens.
About JSON
JSON stands for JavaScript Object Notation. In JavaScript properties can be referenced both like this object1.name and like this object['name'];. The example from the article uses this bit of JSON.
The Parts
A fan object with email as a key and foo#bar.com as a value
{
fan:
{
email : 'foo#bar.com'
}
}
So the object equivalent would be fan.email; or fan['email'];. Both would have the same value
of 'foo#bar.com'.
About HttpClient Request
The following is what our author used to make a HttpClient Request. I do not claim to be an expert at all this so if anyone has a better way to word some of the terminology feel free.
public static HttpResponse makeRequest(String path, Map params) throws Exception
{
//instantiates httpclient to make request
DefaultHttpClient httpclient = new DefaultHttpClient();
//url with the post data
HttpPost httpost = new HttpPost(path);
//convert parameters into JSON object
JSONObject holder = getJsonObjectFromMap(params);
//passes the results to a string builder/entity
StringEntity se = new StringEntity(holder.toString());
//sets the post request as the resulting string
httpost.setEntity(se);
//sets a request header so the page receving the request
//will know what to do with it
httpost.setHeader("Accept", "application/json");
httpost.setHeader("Content-type", "application/json");
//Handles what is returned from the page
ResponseHandler responseHandler = new BasicResponseHandler();
return httpclient.execute(httpost, responseHandler);
}
Map
If you are not familiar with the Map data structure please take a look at the Java Map reference. In short, a map is similar to a dictionary or a hash.
private static JSONObject getJsonObjectFromMap(Map params) throws JSONException {
//all the passed parameters from the post request
//iterator used to loop through all the parameters
//passed in the post request
Iterator iter = params.entrySet().iterator();
//Stores JSON
JSONObject holder = new JSONObject();
//using the earlier example your first entry would get email
//and the inner while would get the value which would be 'foo#bar.com'
//{ fan: { email : 'foo#bar.com' } }
//While there is another entry
while (iter.hasNext())
{
//gets an entry in the params
Map.Entry pairs = (Map.Entry)iter.next();
//creates a key for Map
String key = (String)pairs.getKey();
//Create a new map
Map m = (Map)pairs.getValue();
//object for storing Json
JSONObject data = new JSONObject();
//gets the value
Iterator iter2 = m.entrySet().iterator();
while (iter2.hasNext())
{
Map.Entry pairs2 = (Map.Entry)iter2.next();
data.put((String)pairs2.getKey(), (String)pairs2.getValue());
}
//puts email and 'foo#bar.com' together in map
holder.put(key, data);
}
return holder;
}
Please feel free to comment on any questions that arise about this post or if I have not made something clear or if I have not touched on something that your still confused about... etc whatever pops in your head really.
(I will take down if Justin Grammens does not approve. But if not then thanks Justin for being cool about it.)
Update
I just happend to get a comment about how to use the code and realized that there was a mistake in the return type.
The method signature was set to return a string but in this case it wasnt returning anything. I changed the signature
to HttpResponse and will refer you to this link on Getting Response Body of HttpResponse
the path variable is the url and I updated to fix a mistake in the code.
Here is an alternative solution to #Terrance's answer. You can easly outsource the conversion. The Gson library does wonderful work converting various data structures into JSON and the other way around.
public static void execute() {
Map<String, String> comment = new HashMap<String, String>();
comment.put("subject", "Using the GSON library");
comment.put("message", "Using libraries is convenient.");
String json = new GsonBuilder().create().toJson(comment, Map.class);
makeRequest("http://192.168.0.1:3000/post/77/comments", json);
}
public static HttpResponse makeRequest(String uri, String json) {
try {
HttpPost httpPost = new HttpPost(uri);
httpPost.setEntity(new StringEntity(json));
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
return new DefaultHttpClient().execute(httpPost);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
Similar can be done by using Jackson instead of Gson. I also recommend taking a look at Retrofit which hides a lot of this boilerplate code for you. For more experienced developers I recommend trying out RxAndroid.
I recommend using this HttpURLConnectioninstead HttpGet. As HttpGet is already deprecated in Android API level 22.
HttpURLConnection httpcon;
String url = null;
String data = null;
String result = null;
try {
//Connect
httpcon = (HttpURLConnection) ((new URL (url).openConnection()));
httpcon.setDoOutput(true);
httpcon.setRequestProperty("Content-Type", "application/json");
httpcon.setRequestProperty("Accept", "application/json");
httpcon.setRequestMethod("POST");
httpcon.connect();
//Write
OutputStream os = httpcon.getOutputStream();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));
writer.write(data);
writer.close();
os.close();
//Read
BufferedReader br = new BufferedReader(new InputStreamReader(httpcon.getInputStream(),"UTF-8"));
String line = null;
StringBuilder sb = new StringBuilder();
while ((line = br.readLine()) != null) {
sb.append(line);
}
br.close();
result = sb.toString();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
Too much code for this task, checkout this library https://github.com/kodart/Httpzoid
Is uses GSON internally and provides API that works with objects. All JSON details are hidden.
Http http = HttpFactory.create(context);
http.get("http://example.com/users")
.handler(new ResponseHandler<User[]>() {
#Override
public void success(User[] users, HttpResponse response) {
}
}).execute();
There are couple of ways to establish HHTP connection and fetch data from a RESTFULL web service. The most recent one is GSON. But before you proceed to GSON you must have some idea of the most traditional way of creating an HTTP Client and perform data communication with a remote server. I have mentioned both the methods to send POST & GET requests using HTTPClient.
/**
* This method is used to process GET requests to the server.
*
* #param url
* #return String
* #throws IOException
*/
public static String connect(String url) throws IOException {
HttpGet httpget = new HttpGet(url);
HttpResponse response;
HttpParams httpParameters = new BasicHttpParams();
// Set the timeout in milliseconds until a connection is established.
// The default value is zero, that means the timeout is not used.
int timeoutConnection = 60*1000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT)
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 60*1000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
HttpClient httpclient = new DefaultHttpClient(httpParameters);
try {
response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream instream = entity.getContent();
result = convertStreamToString(instream);
//instream.close();
}
}
catch (ClientProtocolException e) {
Utilities.showDLog("connect","ClientProtocolException:-"+e);
} catch (IOException e) {
Utilities.showDLog("connect","IOException:-"+e);
}
return result;
}
/**
* This method is used to send POST requests to the server.
*
* #param URL
* #param paramenter
* #return result of server response
*/
static public String postHTPPRequest(String URL, String paramenter) {
HttpParams httpParameters = new BasicHttpParams();
// Set the timeout in milliseconds until a connection is established.
// The default value is zero, that means the timeout is not used.
int timeoutConnection = 60*1000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT)
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 60*1000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
HttpClient httpclient = new DefaultHttpClient(httpParameters);
HttpPost httppost = new HttpPost(URL);
httppost.setHeader("Content-Type", "application/json");
try {
if (paramenter != null) {
StringEntity tmp = null;
tmp = new StringEntity(paramenter, "UTF-8");
httppost.setEntity(tmp);
}
HttpResponse httpResponse = null;
httpResponse = httpclient.execute(httppost);
HttpEntity entity = httpResponse.getEntity();
if (entity != null) {
InputStream input = null;
input = entity.getContent();
String res = convertStreamToString(input);
return res;
}
}
catch (Exception e) {
System.out.print(e.toString());
}
return null;
}

Categories

Resources