Generate random number without repetition

Generate random number without repetition - android

bt.setOnClickListener(new OnClickListener(){
#Override
public void onClick(View p1)
{
try{
List<Integer> dataList = new ArrayList<Integer>();
int start = 5;
int end = 15;
for (int i = start; i <= end; i++){
dataList.add(i);
}
Collections.shuffle(dataList);
int[] num = new int[dataList.size()];
for (int i = 0; i < dataList.size(); i++) {
num[i] = dataList.get(i);
}
for (int i = 0; i < num.length; i++) {
t.setText(num[i]);
}
}catch (Exception e) {
e.printStackTrace();
}
}});
I want to show my random number on text view but it shown nothing or crash without catch Exception
What should I do?
What and where is my error?

You should be able to use the diamond operator <>. You can only display one String at a time, so first make a String (and you don't need to copy to an array first). Something like,
try {
List<Integer> dataList = new ArrayList<>(); // <-- <Integer> if you can't.
int start = 5;
int end = 15;
for (int i = start; i <= end; i++) {
dataList.add(i);
}
Collections.shuffle(dataList);
t.setText(dataList.toString());
} catch (Exception e) {
e.printStackTrace();
}

Related

Filter number from Array of string and get the index of last two greater number in android

I have a ArrayList that has value like [Value,Sum3,121,data8input,in:21::7,7.00,9.01] and I want to extract only number as the output should be like this [3,121,8,21,7,7.00,9.01] and then have to rearrange ascending and then get the index of last two number as result will be [21,121].
My tried code below,
for (int i = 0; i < arrayString.size(); i++) {
Pattern p = Pattern.compile("-?\\d+(,\\d+)*?\\.?\\d+?");
List<String> numbers = new ArrayList<String>();
Matcher m = p.matcher(arrayString.get(i).getvalue);
numbers.addAll(m);
for (int j = 0; j < numbers.size(); j++) {
Log.d("REMEMBERFILTER", allCollection.get(i).getTextValue());
}
}
}

do something like this, though it is not exactly memory efficient as I am using another list.
ArrayList<String> tempList = new ArrayList<>();
for (int i = 0; i < yourArrayList.size(); i++) {
tempList.add(yourArrayList.get(i).replaceAll("[^0-9]", ""));
}
//Arrange in ascending order
Collections.sort(tempList);
//Also try to remove those indexes which has only letters with
tempList.removeAll(Arrays.asList("", null));
for (int i = 0; i < tempList.size(); i++) {
Log.d("+++++++++", "" + tempList.get(i));
}
//You can get the last two or any element by get method of list by //list.size()-1 and list.size()-2 so on

This is a way to do it, finalArray has the 2 numbers you want:
String[] str = new String[] {"Value", "Sum3", "121", "data8input", "in:21::7", "7.00,9.01"};
StringBuilder longStringBuilder = new StringBuilder();
for (String s : str) {
longStringBuilder.append(s).append(" ");
}
String longString = longStringBuilder.toString();
String onlyNumbers = " " + longString.replaceAll("[^0-9.]", " ") + " ";
onlyNumbers = onlyNumbers.replaceAll(" \\. ", "").trim();
while (onlyNumbers.indexOf(" ") > 0) {
onlyNumbers = onlyNumbers.replaceAll(" ", " ");
}
String[] array = onlyNumbers.split(" ");
Double[] doubleArray = new Double[array.length];
for (int i = 0; i < array.length; i++) {
try {
doubleArray[i] = Double.parseDouble(array[i]);
} catch (NumberFormatException e) {
e.printStackTrace();
doubleArray[i] = 0.0;
}
}
Arrays.sort(doubleArray);
int numbersCount = doubleArray.length;
Double[] finalArray;
if (numbersCount >= 2) {
finalArray = new Double[]{doubleArray[numbersCount - 2], doubleArray[numbersCount - 1]};
} else if (numbersCount == 1) {
finalArray = new Double[]{ doubleArray[0]};
} else {
finalArray = new Double[]{};
}
for (Double number : finalArray) {
System.out.println(number);
}

use eratosthenes sieve to find prime

hello i want my app find prime between two number with sieve algorithm i am use this code but its not working well what can i do for improve this code to my goal please help me
public int[] GetPrimes() {
int[] primesData = new int[maxValue+1];
int[] results = new int[maxValue];
int i;
int result_count = 0;
for (i=MIN_VALUE; i<=maxValue; i++) {
primesData[i] = PRIME_UNKNOWN;
}
for (i=MIN_VALUE; i<=maxValue; i++) {
if (primesData[i] == PRIME_UNKNOWN) {
primesData[i] = PRIME_YES;
results[result_count++] = i;
int j;
for (j=i; j<=maxValue; j = j + i) {
primesData[j] = PRIME_NO;
}
}
}
int[] retval = new int[result_count];
for (i=0; i<result_count; i++) {
retval[i] = results[i];
}
tvresult.setText(retval.toString());
return retval;
}
}

The algorithm is correct. Likely you are launching it with wrong values as input.
Ensure to have MIN_VALUE set to value 2 and prepopulate retval with 1 i.e.:
int[] retval = new int[result_count+1];
retval[0] = 1;
for (i=0; i<result_count; i++) {
retval[i+1] = results[i];
For the printing issue:
tvresult.setText(Arrays.toString(retval));
Because retval.toString() just returns the object reference not the content. This is true for any Java array. Instead use Arrays.toString().

Randomizing images in image views

i wanted to make an application in which i have to randomaly generate images but in order....
like :- APPLE.... i want to generate it as A_PP_E....
but i also want them uniqualy every time
final int[] imageViews = {
R.id.imageView2, R.id.imageView10, R.id.imageView3,
R.id.imageView4, R.id.imageView5, R.id.imageView6, R.id.imageView8 };
int[] photos={R.drawable.aa, R.drawable.pp
,R.drawable.ee,
R.drawable.pp_blue,R.drawable.ll};
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// for randomizing the view
Random rng = new Random();
List<Integer> generated = new ArrayList<Integer>();
for (int i = 0; i < 5; i++)
{
while(true)
{
Integer next = rng.nextInt(5) ;
if (!generated.contains(next))
{
generated.add(next);
ImageView iv = (ImageView)findViewById(imageViews[i]);
iv.setImageResource(photos[next]);
break;
}
}
}

Step 1): put the images in the array in correct order as follows:
int[] photos={R.drawable.aa, R.drawable.pp, R.drawable.pp_blue, R.drawable.ll, R.drawable.ee}; // correct order APPLE
Step 2): Update your code as below:
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Random rng = new Random();
List<Integer> generated = new ArrayList<Integer>();
// select `n` places which will be "BLANK"
int n = 2; // example `n=2`
for (int i = 0; i < n; i++)
{
while(true)
{
Integer next = rng.nextInt(5) ;
if (!generated.contains(next))
{
generated.add(next);
break;
}
}
}
// now `generated` has `n` random positions
// set these `n` positions as "BLANK" rest as "FILLED"
for (int i = 0; i < 5; i++)
{
ImageView iv = (ImageView)findViewById(imageViews[i]);
if(generated.contains(i)) {
// this was a random selected position
// set it blank or empty
iv.setImageBitmap(null);
}
else {
// set this image as the correct alphabet
iv.setImageResource(photos[i]);
}
}
}

i m doing this for getting blank images in another image view array....and its giving correct output
int n = 2; // example `n=2`
for (int i = 0; i < n; i++)
{
while(true)
{
Integer next = rng.nextInt(5) ;
Log.i("test","value:-"+next);
if (!generated.contains(next))
{
generated.add(next);
break;
}
}
}
for (int i1 = 0; i1 < 2; i1++)
{
ImageView ne = (ImageView)findViewById(nextimages[i1]);
ne.setImageResource(photos[generated.get(i1)]);Log.i("test","value:-"+photos[generated.get(i1)]);
}

Check all the view's background in an if statement in Android?

I have many buttons(81) from the left and right part of my layout. All in all, I have 162 buttons. I put those buttons to Button[] and I handle it properly.
private int[] right_lung = { R.id.btn_right_106, R.id.btn_right_113,
R.id.btn_right_114, R.id.btn_right_115, R.id.btn_right_116, R.id.btn_right_121,
R.id.btn_right_122, R.id.btn_right_123, R.id.btn_right_124, R.id.btn_right_125,
R.id.btn_right_129, R.id.btn_right_130, R.id.btn_right_131, R.id.btn_right_132,
R.id.btn_right_133, R.id.btn_right_134, R.id.btn_right_137, R.id.btn_right_138,
R.id.btn_right_139, R.id.btn_right_140, R.id.btn_right_141, R.id.btn_right_142,
R.id.btn_right_143, R.id.btn_right_145, R.id.btn_right_146, R.id.btn_right_147,
R.id.btn_right_148, R.id.btn_right_149, R.id.btn_right_150, R.id.btn_right_151,
R.id.btn_right_152, R.id.btn_right_153, R.id.btn_right_154, R.id.btn_right_155,
R.id.btn_right_156, R.id.btn_right_157, R.id.btn_right_158, R.id.btn_right_159,
R.id.btn_right_160, R.id.btn_right_161, R.id.btn_right_162, R.id.btn_right_163,
R.id.btn_right_164, R.id.btn_right_165, R.id.btn_right_166, R.id.btn_right_167,
R.id.btn_right_168, R.id.btn_right_169, R.id.btn_right_170, R.id.btn_right_171,
R.id.btn_right_172, R.id.btn_right_173, R.id.btn_right_174, R.id.btn_right_175,
R.id.btn_right_176, R.id.btn_right_177, R.id.btn_right_178, R.id.btn_right_179,
R.id.btn_right_180, R.id.btn_right_181, R.id.btn_right_182, R.id.btn_right_183,
R.id.btn_right_184, R.id.btn_right_185, R.id.btn_right_186, R.id.btn_right_187,
R.id.btn_right_188, R.id.btn_right_189, R.id.btn_right_190, R.id.btn_right_191,
R.id.btn_right_192, R.id.btn_right_194, R.id.btn_right_195, R.id.btn_right_196,
R.id.btn_right_197, R.id.btn_right_198, R.id.btn_right_199, R.id.btn_right_200,
R.id.btn_right_205, R.id.btn_right_206, R.id.btn_right_207 };
private Button[] btn_right = new Button[right_lung.length];
private int[] left_lung = { R.id.btn_left_7, R.id.btn_left_13, R.id.btn_left_14,
R.id.btn_left_15, R.id.btn_left_16, R.id.btn_left_20, R.id.btn_left_21,
R.id.btn_left_22, R.id.btn_left_23, R.id.btn_left_24, R.id.btn_left_27,
R.id.btn_left_28, R.id.btn_left_29, R.id.btn_left_30, R.id.btn_left_31,
R.id.btn_left_32, R.id.btn_left_34, R.id.btn_left_35, R.id.btn_left_36,
R.id.btn_left_37, R.id.btn_left_38, R.id.btn_left_39, R.id.btn_left_40,
R.id.btn_left_41, R.id.btn_left_42, R.id.btn_left_43, R.id.btn_left_44,
R.id.btn_left_45, R.id.btn_left_46, R.id.btn_left_47, R.id.btn_left_48,
R.id.btn_left_49, R.id.btn_left_50, R.id.btn_left_51, R.id.btn_left_52,
R.id.btn_left_53, R.id.btn_left_54, R.id.btn_left_55, R.id.btn_left_56,
R.id.btn_left_57, R.id.btn_left_58, R.id.btn_left_59, R.id.btn_left_60,
R.id.btn_left_61, R.id.btn_left_62, R.id.btn_left_63, R.id.btn_left_64,
R.id.btn_left_65, R.id.btn_left_66, R.id.btn_left_67, R.id.btn_left_68,
R.id.btn_left_69, R.id.btn_left_70, R.id.btn_left_71, R.id.btn_left_72,
R.id.btn_left_73, R.id.btn_left_74, R.id.btn_left_75, R.id.btn_left_76,
R.id.btn_left_77, R.id.btn_left_78, R.id.btn_left_79, R.id.btn_left_80,
R.id.btn_left_81, R.id.btn_left_82, R.id.btn_left_83, R.id.btn_left_84,
R.id.btn_left_85, R.id.btn_left_86, R.id.btn_left_87, R.id.btn_left_88,
R.id.btn_left_89, R.id.btn_left_90, R.id.btn_left_91, R.id.btn_left_92,
R.id.btn_left_93, R.id.btn_left_94, R.id.btn_left_95, R.id.btn_left_98,
R.id.btn_left_99, R.id.btn_left_100, };
private Button[] btn_left = new Button[left_lung.length];
Whenever I click on the button, just like in mine sweeper game, many buttons are randomly opened. And when it is opened, I am changing its background into R.drawable.affected. The goal of the game is to open all the buttons in left and right. My question is this, how can I check if all of the buttons are set in R.drawable.affected? Because after that, I will execute a method that will congratulate the user. Thanks in advance.
EDIT:
for (int i = 0; i < btn_right.length; i++) {
final int a = i;
int counter_total_affected = 0;
btn_right[i].setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
if (counter == 1) {
right_lung.add(a);
btn_right[a].setBackgroundResource(R.drawable.affected);
counter_total_affected++;
} else if (counter == 2) {
for (int i = 0; i < 2; i++) {
int n = i;
right_lung.add(a + n);
}
try {
for (int i = 0; i < 2; i++) {
int n = i;
btn_right[a + n].setBackgroundResource(R.drawable.affected);
counter_total_affected++;
}
} catch (Exception e) {
e.printStackTrace();
}
} else if (counter == 3) {
right_lung.add(a);
btn_right[a].setBackgroundResource(R.drawable.affected);
counter_total_affected++;
} else if (counter == 4) {
for (int i = 0; i < 25; i++) {
int n = i;
right_lung.add(a + n);
}
try {
for (int i = 0; i < 25; i++) {
int n = i;
btn_right[a + n].setBackgroundResource(R.drawable.affected);
counter_total_affected++;
}
} catch (Exception e) {
e.printStackTrace();
}
} else if (counter == ...) {
//statements...
} else if (counter_total_affected == (btn_left.length + btn_right.length)) {
//CONGRATULATORY METHOD
}
counter++;
}
}

Increment the counter each time you change background of button and compare its value with length of button array. if both are same that means, all button backgrounds are set.
Try this :
for (int i = 0; i < btn_right.length; i++) {
final int b = i;
btn_right[i].setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
if btn_right[i].getDrawable().getConstantState().equals
(getResources().getDrawable(R.drawable.affected).getConstantState()))
{
if(counter == btn_right.length){
//Congratulate user...
}
}else{
btn_right[b].setBackgroundResource(R.drawable.affected);
counter++;
}
}
}

U can set Tag:
for (int i = 0; i < btn_right.length; i++) {
final int b = i;
btn_right[i].setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
if (counter == 1) {
right_affected.add(b);
btn_right[b].setBackgroundResource(R.drawable.affected);
btn_right[b].setTag('1');
} else {
//some stuff here...
}
}
}
after congratulate the user set its Tag to 0.
EDIT:
ArrayList<Integer> arrayofId =new ArrayList<Integer>();
#Override
public void onClick(View v) {
if (counter == 1) {
right_affected.add(b);
btn_right[b].setBackgroundResource(R.drawable.affected);
arrayofId.add(b);//need to convert int to Integer.
} else {
//some stuff here...
}
}
To congratulate:
for(int i=0;i<arrayofId.size();i++)
{
// you can get here id of effected buttons
}

receive a string message from user input in android and parse to an int so can be stored in an array and compared with another array of integers

I am having a problem with the above task in my android application. I am accepting user input from the EditText widget in the form of String. I accepting numbers from the user so I have to parse them to integers so they can be compared with another array of integers. I have the line:
String message = editText.getText().toString()
then to try and parse the String to an int I have the code line:
int userNumbers = Integer.parseInt(message).
However when I attempt to compare the array userArray with the array numbers I am getting the error that "Incompatible operand types String and Integer.
Can anyone see where my problem is or how I can solve it? Here's my code:
Thanks in advance.
public class MainActivity extends Activity {
public final static String EXTRA_MESSAGE = ".com.example.lotterychecker.MESSAGE";
static boolean bonus = false;
static boolean jackpot = false;
static int lottCount = 0;
Button check;
Integer [] numbers;
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
//link to the intended web site and get the lottery numbers while the app is opening
try {
Document doc = Jsoup.connect("http://www.national-lottery.co.uk/player/p/drawHistory.do").userAgent("Mozilla").get();
Elements elements = doc.getElementsByClass("drawhistory");
Element table = elements.first();
Element tbody = table.getElementsByTag("tbody").first();
Element firstLottoRow = tbody.getElementsByClass("lottorow").first();
Element dateElement = firstLottoRow.child(0);
System.out.println(dateElement.text());
Element gameElement = firstLottoRow.child(1);
System.out.println(gameElement.text());
Element noElement = firstLottoRow.child(2);
System.out.println(noElement.text());
String [] split = noElement.text().split(" - ");
// set up an array to store numbers from the latest draw on the lottery web page
Integer [] numbers = new Integer [split.length];
int i = 0;
for (String strNo : split) {
numbers [i] = Integer.valueOf(strNo);
i++;
}
for (Integer no : numbers) {
System.out.println(no);
}
Element bonusElement = firstLottoRow.child(3);
Integer bonusBall = Integer.valueOf(bonusElement.text());
System.out.println("Bonus ball: " + bonusBall);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
#Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
//called when the user clicks the send button
public void checkNumbers(View view) {
final int SIZE =6;
String [] userArray = new String[SIZE];
//create an intent to display the numbers
Intent intent = new Intent(this, DisplayNumbersActivity.class);
EditText editText = (EditText) findViewById(R.id.enter_numbers);
String message = editText.getText().toString();
intent.putExtra(EXTRA_MESSAGE, message );
startActivity(intent);
//parse string message to an int for user numbers
try{
int userNumbers = Integer.parseInt(message); //is this right?
}//try
catch (NumberFormatException e)
{
System.out.println("Not a number" + e.getMessage());
}
Toast.makeText(MainActivity.this, "Here are your numbers", Toast.LENGTH_LONG).show();
for (int count =0; count < SIZE; count ++)
{
if (check.isPressed())
{
userArray[count] = editText.getText().toString();
}
}//for
//compare the two arrays of integers
for (int loop = 0; loop < userArray.length; loop++)
{
for (int loopOther = 0; loopOther < numbers.length; loopOther++)
{
if (userArray[loop] == numbers[loopOther]) //how do I parse this?
{
lottCount++;
}else if (userArray[loop] == bonus)
{
bonus = true;
}
}//for
}//for main

You have this
Integer [] numbers; // numbers is an integer array
You have string array
String [] userArray = new String[SIZE]; // userArray is a string array
You compare like below
if (userArray[loop] == numbers[loopOther])
So you get the error Incompatible operand types String and Integer.
try
if (Integer.parseInt(userArray[loop]) == numbers[loopOther])
Enclosing the above with try catch block
String message = editText.getText().toString();
try{
int userNumbers = Integer.parseInt(message);
//is this right? yes
}
catch (NumberFormatException e)
{
e.printStacktrace();
}

Change String to Int here:
for (int loop = 0; loop < userArray.length; loop++)
{
for (int loopOther = 0; loopOther < numbers.length; loopOther++)
{
if (Integer.valueOf(userArray[loop]) == numbers[loopOther]) //how do I parse this?
{
lottCount++;
}else if (Integer.valueOf(userArray[loop]) == bonus)
{
bonus = true;
}
}//for
}//for main

Parse Like this :
for (int loop = 0; loop < userArray.length; loop++)
{
for (int loopOther = 0; loopOther < numbers.length; loopOther++)
{
if (Integer.parseInt(userArray[loop]) == numbers[loopOther])
{
lottCount++;
}else if (userArray[loop] == bonus)
{
bonus = true;
}
}
}

Develop Reference

The Android operating system is a mobile operating system that was developed by Google (GOOGL?) to be primarily used for touchscreen devices, cell phones, and tablets.

Generate random number without repetition - android

Related

Filter number from Array of string and get the index of last two greater number in android

use eratosthenes sieve to find prime

Randomizing images in image views

Check all the view's background in an if statement in Android?

receive a string message from user input in android and parse to an int so can be stored in an array and compared with another array of integers

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