Clearer Format Firebase Android retrieved data - android

When I retrieve my data it contains brackets { and unique id such as - JSDHGJDGJJSKA ... I want to make it cleaner and get rid of the brackets for e.g. my output is:
{-JfFQQRYnhiKeuN5ERGX={msg=Monday},-JfFQAhQQWIFAUuV1nD4={msg=this is test}}
I want to get rid of the brackets and the word msg and retrieve just one of the message at random.
I want my output to be if I pick up a random message:
Monday
if I pick up another at random
this is test
Any ideas on how to achieve this will be greatly appreciated.

This will retrieve a random message from the object you've shown in your question.
function getRandomMessage(data) {
if( !data ) { return null; }
var keys = Object.keys(data);
var randomKey = keys[ Math.floor(Math.random()*keys.length) ];
return data[randomKey];
}
Keep in mind that this assumes you have a small number of records. If you start getting into the thousands, you'll need a more robust solution than just grabbing the entire data set.

When I used this I was able to retrieve my data for eg. I save as Book -> title: "The book of death"
here is the code to retrieve the title:Retrieve data-
String title = (String) snapshot.child("title").getValue();
It worked after I used and I didnt used push since push creates its unique ID and its complex for my level to deal with it so I used:Saving data-
Map<String, Object> title= new HashMap<String, Object>();
title.put("title", "This is a working message");
f.child("Book").updateChildren(title);
and everything worked out. I hope it helps everyone who has having these issues. With update children you can use auto increment for your id.

are you getting data in string ? and If you are using string then it is easy , you can use the method of replace eg: yourString.replace("a","b")

Related

Avoiding same chat when using Firestore

I'm making now a chat app by using the Firestore database and im thinking how to avoid the same chat to be created twice.
For example, if person A sends message to person B, I had like the message to enter the same chat collection as if person B send the message to person A.
I have found the following suggestion here
It recommends to compare the users UID which I know and construct some chatID based on the combination of those string.
private String setOneToOneChat(String uid1, String uid2)
{
if(uid1 <uid2){
return uid1+uid2;
}
else{
return uid2+uid1;
}
}
comparing the length of both UID doesn't work since all (or at least all I have seen are from the same length).
However, first I didn't really understand how to use math operator such as < on a string, second im not sure if it really catches all cases.
If there are any suggestions to implement such thing I would like to hear.
Thank you
The ordering should be based on the actual content of the strings, not just on their length.
So in Java/Android:
if(uid1.compareTo(uid2) > 0){
return uid1+uid2;
}
else{
return uid2+uid1;
}

Document references must have an even number of segments error on a collection reference

I'm getting the rather simple error:
Document references must have an even number of segments.
I'm aware of what it is telling me and how to fix it, however it is giving me this error on a collection reference.
CollectionReference collectionReference = getFirebaseInstance()
.collection(Constants.USERS)
.document(userId)
.collection(Constants.CONTACTS);
In my database the path is (COLLECTION) < DOCUMENTS > (COLLECTION) < DOCUMENTS > I'm trying to get all contacts for a user at users/{id}/contacts but it just throws this error, any ideas?
getFirebaseInstance is a method I've created to always get the current
FirebaseFirestore.getInstance();
Your userId variable probably has a slash in it. Document ids can't have slashes, since they are interepreted as dividers between collections and documents when forming the "path" to a document.
It's also possible that the string may be empty, which is invalid.
I found the same problem, this is what solved my problem :
I tried to set a document using the :
setDoc()
without providing the document id.
So I used :
addDoc()
so firebase itself provide an id for document.
The lecon is that :
using set you must provide an ID, using add you do not have provide the ID firebase do it for you.
Thanks !
Because neither the above nor other similar posts helped me..
I got this error when calling set data and then immediately after .getDocument(...) (i.e. reading data). When I called my read data method in the completion handler of the setData method then the error message disappeared.
i'm not sure that's your case ,But, if you have a function like this, that brings data by "Id" from your firebase , just add a slash "/" after your collection's name
getDetailProduct(id: string): Observable<Interface_name> {
const productsDocuments = this.angularFirestore.doc<Interface_name>(
'collection_name/' + id //here after your collection name add "/"
);
return productsDocuments.snapshotChanges().pipe(
map((changes) => {
const data = changes.payload.data() as Interface_name;
const id = changes.payload.id;
return { id, ...data };
})
);
}

Firebase overwrites existing records instead of appending them

I am a bit new to Firebase and so have been playing around with to help myself get more acquainted with it. So while I was playing around with realtime databases, I was trying to append data to the JSON tree. The code is as below
mSaudi.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View view) {
count++;
mHistory = mChildRef.child(Integer.toString(count));
current = riyadh;
mChildRef.setValue(riyadh);
mHistory.push().setValue("riyadh");
}
});
The tree which I require is something like this:
value:
1: some text
2: some other text
But what's a actually happening is this:
value:
1: some text
and on updation
value:
2:some text
the previous entry gets erased
I have tried changing the references in various ways but to no avail. Any help in this regard would be appreciated.
If you would like to save both values, you have to save them using a variable such as a Hashmap. If you save a string and then try save another one under the same branch, it will delete everything previously saved. So try the following
HashMap<String, String> map = new HashMap<>();
map.put("1","String");
map.put("2","String");
mHistory.push().setValue(map);
This will save both the strings without deleting one.
If you would only like to add one String
mHistory.push().child("1").setValue("Your first String");
The biggest problem with this though is that everytime you use push() you generate a random key, so you would have to save the key as a string and use it as a reference in your child.
When you set a value on Firebase, it is going to replace everything in, and under the reference.
Let's say that you have a house value, with 2 childs: Color and Size.
If you want to edit only the color value, before the setValue(), you will have to change the reference you are pushing to.
If your reference was getReference().child("houses") and you push something there, it's going to replace everything there and below it. The way to do it is create a new reference (or update the previews one) like this: getReference().child("houses").child(houseKey).child("color") and push your String there.
In your example, you will need to add the field you want to change as a child before the push() method.
The other way was already told by #Janwilx72 and is getting the whole object, updating the value locally and pushing the entire object again.
You can try this
mChildRef.child("2").setValue("some text");
It should be appending new item instead of overwriting them

How to write and update data to google spreadsheet android (api v4)

I have followed the Android Quickstart provided by google Google Sheets API Android Quickstart and was able to retrieve data from the google spreadsheet but I am not able to understand how to write and update single or multiple data.
I read this code from StackOverflow, I think It's good but I can't understand how to set (valueRange) object here
this.mService.spreadsheets().values().update(spreadsheetId, range, valueRange)
.setValueInputOption("RAW")
.execute();
In case you still need the answer, or for anyone else who does:
I faced the same issue too, and from the docs, I was able to work this out.
Here's a method in which i write the data to the sheet
private void writeDataToApi() throws IOException {
String spreadsheetId = "the_spreadsheet_id_like_the_google_example";
String range = "YourSheetName!A1:B1"; //Read the docs on how these ranges work.
//Currently, this is the range of a single row which would return
//as [[objA, objB]] if major dimension is set as ROW.(default).
// would be [[objA],[objB]] if its set to COLUMN. Read the doc for more info.
//for the values that you want to input, create a list of object lists
List<List<Object>> values = new ArrayList<>();
//Where each value represents the list of objects that is to be written to a range
//I simply want to edit a single row, so I use a single list of objects
List<Object> data1 = new ArrayList<>();
data1.add("objA");
data1.add("objB");
//There are obviously more dynamic ways to do these, but you get the picture
values.add(data1);
//Create the valuerange object and set its fields
ValueRange valueRange = new ValueRange();
valueRange.setMajorDimension("ROWS");
valueRange.setRange(range);
valueRange.setValues(values);
//then gloriously execute this copy-pasted code ;)
this.mService.spreadsheets().values()
.update(spreadsheetId, range, valueRange)
.setValueInputOption("RAW")
.execute();
//Try calling this method before executing the readDataFromApi method,
//and you'll see the immediate change
}
I hope this helped.
And for more info, pls see the docs
EDIT: Also remember to change scope from SheetsScopes.SPREADSHEETS_READONLY to SheetsScopes.SPREADSHEETS

how to retrieve data from firebase in reverse order [duplicate]

I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?
Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console
Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase
To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.
There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);
I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p
You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}
In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.
Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}
I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}
There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});
To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster
I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}
myarray.reverse(); or this.myitems = items.map(item => item).reverse();
I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});
Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.
You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.
just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},
For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.
PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.

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