I am working on an APP using Xamarin MonoTouch, this App requires custom licence key as provided by us. To identify each and every installation we have to store some kind of device information to control misuse of App.
After trying various ways, now the problems are:
Device Id or Android id : gets changed every time a device is factory reset or format.
Settings.System.GetString(this.ContentResolver, Settings.Secure.AndroidId);
IMEI Number: No SIM Tabs dont have. Double SIM phones have no fix slot wise imei and sends randomly chose one.
var telephonyManager = (TelephonyManager)GetSystemService(TelephonyService);
string imei = telephonyManager.DeviceId;
WIFI Mac Address: Good way but some sets like HTC and Chinese ones throwing exception while retrieving mac address, but works some time. SO not getting fix id everytime app starts.
WifiManager wm = (WifiManager)GetSystemService(WifiService);
string macid = wm.ConnectionInfo.MacAddress;
So everytime any of the above ID fails, user needs to re register app again and again. Do we have any fool proof way of doing this?
Ok, as per comment by Matt, since there is not fool-proof method of getting unique id from an android device. So I have made a provision of validating installations against WIFI Mac ID and Android ID both. If any one of these found matched then installation is genuine or spoofed.
Related
I have the need to detect a common factor between two apps, one written in Xamarin and one written in Java (Android Studio), running on a users phone.
In the good old days the IMEI did the job nicely. However now I am having to use the Device ID, which is fine for the current purpose, but not perfect.
Anyway, using the following statement in Xamarin gives one result, while using the statement that follows this in Android, gives a different result, both on the same phone.
Why would this be, why is the Device ID not reported as the same value, and is there a way to identify the DeviceID via both platforms that result in the same output ?
Thanks
Xamarin code - Result is "a70c996e74002942"
var Device_ID = Android.Provider.Settings.Secure.GetString(ContentResolver, Android.Provider.Settings.Secure.AndroidId);
Android Studio code - Result is "702669b2e9a6f7d1"
String Device_ID = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
From the docs
unique to each combination of app-signing key, user, and device
For privacy reasons, two different apps on the same device will have different ids
I'm making a pair of website-based apps for both Android and iOS interfaces, and I'm struggling with a part of it. Perhaps you guys could help me out!
I'm using Android Studio and Xcode, and launching the website through WebKit and WK WebView respectively. It's super simple, just an app which calls a website into it directly. No external navigation, nothing but a full-page website. And this part is working great!
But I do have one problem! I don't want my users to get consistently logged out if they close the app, or after a few hours of not using it. I'd like it to stay logged in for them, or to automatically log-in when they use it.
The maker of the website has given me a way to do this through the URL.
Basically, my URL currently is set up like "https://URL.com/x/y/z" and it goes to the website, and that is great, but I need to set it up to be "https://url.com/x/y/z/[insert user's IMEI or UDID here]". That unique ID from their Android device will keep them logged in. I've tested it using my own device with my own IMEI and it works great, but obviously using one specific identifier for everyone will not work. I just need it to call the specific user's IMEI or UDID into the URL, to complete it.
How should I go about this?
I am assuming that you are talking about an Android app that visualizes a website in an activity. On Android, you can retrieve the device's IMEI OR MEID string by calling:
android.telephony.TelephonyManager.getDeviceId().
But be warned, this requires that you add a permission to your manifest:
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
You should inform your users why you are requesting this permission.
For iOS/Xcode, you can get the device UUID via UIDevice:
// Swift 4
let uuid = UIDevice.current.identifierForVendor!.uuidString
If you are targeting iOS 11 or newer, Apple introduced Device Check to get a device specific token. I personally haven't used it, but it sounds like it's use case is similar to what you're looking for.
Update:
From your comment, here is how'd you include it in the url string.
let urlString = "url.com/x/y/z/" + uuid
I'm currently planning on creating an app. Unfortunately the need for usercreation is there. I know users don't like goind through a registration process with opt in by email activation link click.
So I thought maybe using the apple/google id as a replacement for email address would be cool since the verification step by email can be dropped. In addition when the user changes his or her mail address that's no problem since his or her id doesn't change in this case.
I'm not really into this particular topic so I have some questions, any help is highly appreciated:
Is there any numeric/alphanumeric id anyway or is the google/apple id (i.e. the "username") the email address itself?
Is this possible in Android and Apple SDK (and Cordova in addition since I use this one)?
Is this a good idea in general or am I missing something?
Thanks in advance!
You could use the below DeviceIDs solutions as primary key for your users registrations. Look:
1 - Android
1.1 - Android Phones (With SIM chip) - For Android I use the Cordova SIM plugin. It generates uniqueIDs for devices based on SIM chip informations. So, you can manipulate your data based on the plugins return;
Link: https://github.com/pbakondy/cordova-plugin-sim
1.2 - Adroid Tablets - The plugin above is fantastic, but it does not work for devices that does not have any SIM chip. In this case, I use the following code:
if(mContext == null){
mContext = this.cordova.getActivity();
if(dialog == null){
dialog = new ProgressDialog(mContext);
}
}
String tabletID = Secure.getString(mContext.getContentResolver(), Secure.ANDROID_ID);
Conclusion: If you are developing only for phones (App projected for Mobile Phone) you should use the plugin. If your App targets Tablets or devices without SIM card, than you can take a look at the other solution. The IDs generated are "Devices ID", unique for each device.
2 - iOS
For iOS, I use the following code to generate an unique ID for each device:
NSString *uniqueIdentifier = [[[UIDevice currentDevice] identifierForVendor] UUIDString];
The only problem: When user uninstalls all Apps of your iTunes vendor ID from the device and installs any of them again, the ID will be changed. Other easy ways to get Unique ID for iOS is deprecated since version 7.0 of the system.
See more here: Device Id from an iphone app
I am developing a android application for a exploratory project using client server architecture. I thought of using UDID but now its replaced by new "Advertising ID", but in my application, i need to store data about user on server with some unique ID per device.
so what should i use as alternative to UDID?
i checked open UDID but that is also outdated now.
Using "advertising ID" imposes problem of consistency when user clears/resets his advertising ID.
Request the community to help me out.
There is also identifierForVendor see more in apple docs
I don't have much idea about Android :
But Check these :
GeneratingDeviceSpecificSerialNo && HEre
In IOS :
-identifierForVendor
ID that is identical between apps from the same developer.
Erased with removal of the last app for that Team ID.
Backed up.
For more Info Here
You can register the device with the Google Cloud Messaging platform.
When you register the device correctly this gives you back a register id that´s unique for every device.
http://developer.android.com/google/gcm/client.html
UPDATE
You can also, if you haven't tried it out yet, to user the telephony manager to get the device identifier.
TelephonyManager tManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
String uuid = tManager.getDeviceId();
On iOS you can try this
NSString *UUID = [[NSUUID UUID] UUIDString];
This will give you a unique id per app.
I want to make an application which has to be very secured. So f I install an apk in a phone it should only work in that phone. When apk is shared it should not work.Can any one help me in implementing this.
One idea from my side is using an algorithm to generate password using device mac address and so the password won't work for two different devices to log in.Is there any way to get the MAC address( or something unique to device) in android from java? .Expecting alternate solutions!!
If you are distributing the app through Google play store, you can make use of the Google Play Application licensing.
You may read Identifying App Installations on Android Developer's Blog for a discussion about how to uniquely identify a device.
I implemented with IMEI number. So my apk is designed based on IMEI number.So it will check whether IMEI given matches with the device IMEI then only it will launch the new Activity, else it will exit.
TextView tx = (TextView) findViewById(R.id.tx);
String ts = Context.TELEPHONY_SERVICE;
TelephonyManager mTelephonyMgr = (TelephonyManager) getSystemService(ts);
String imei = mTelephonyMgr.getDeviceId();
if (imei.equals("<what we given inthe source>")) {
// Launch the activity
} else {
// show an alert dialog and exit
}