Why do I need a delay before showing AlertDialog? - android

Under some conditions, when my app starts, it displays an AlertDialog. However, the alert never gets displayed. I discovered that if I add a delay, it works (i.e. gets displayed).
More specifically: on app startup, it executes the main activity onCreate() which under a certain condition starts a 2nd activity. In the 2nd activity, through a separate thread, it makes a check for some web server status. If the Android device doesn't have Internet connectivity, HttpURLConnection returns an error instantly and my enclosing function executes a callback to the 2nd activity. My code then uses post() to attempt to display an alert to the user (using post allows displaying the alert on the UI thread, which is required).
Apparently it tries to display the alert before any of the either activity's UI has been created. If I use postDelayed() in the 2nd activity, the problem still persists. However, if I use the following block of code in the main activity, the alert shows properly:
new Handler().postDelayed (new Runnable ()
{
#Override public void run()
{
Intent intent = new Intent (app, MyClass.class);
app.startActivityForResult (intent, requestCode);
}
}, 3000);
My solution is a hack that happens to work at the moment. I don't mind having a little delay on start-up for this particular situation but I don't want a delay that's longer than necessary or one that may sometimes fail.
What is the proper solution?

Ok, here's a workaround. First, I'll speculate that the problem is that the attempt to display the alert is happening before the looper for the UI thread has been started. Just a speculation.
To work around the problem I added a recursive post which gets called from onResume(), like this:
private boolean paused = true;
#Override public void onResume ()
{
super.onResume();
paused = false;
checkForAlert();
}
#Override public void onPause ()
{
super.onPause();
paused = true;
}
And here's the function that does the post:
private AlertInfo alertInfo = null;
private void checkForAlert()
{
if (alertInfo != null)
{
...code to build alert goes here...
alertInfo = null;
}
if (!paused)
contentView.postDelayed (new Runnable()
{
#Override public void run() { checkForAlert(); }
}, 200);
}
AlertInfo is a simple class where the thread needing the alert can put the relevant info, e.g. title, message.
So, how does this work? checkForAlert() gets called during onResume() and will continue to get called every 200ms until "paused" is false, which happens in onPause(). It's guaranteed to be recurring whenever the activity is displayed. The alert will get built and displayed if alertInfo is not null. In the secondary thread, I simply create an AlertInfo instance and then within 200ms the alert gets displayed. 200ms is short enough that most people won't notice the delay. It could be shorter but then battery use goes up.
Why did I start checkForAlert() in onResume instead of onCreate()? Simply because there's no need for it to run unless the activity is currently "on top". This also helps with battery life.

Related

Why is Fragment.onResume() not displaying my GUI until after onResume finishes completely?

I am writing an Android application that interfaces with the Motorola EMDK, and I am running into an issue with timing/threading. I have an activity that adds a fragment to perform a very specific function using the EMDK, displays a screen that tells the user what is happening and then is cleaned up by the activity after about 15 seconds.
I am noticing a 1-2 second delay between when the EMDK action occurs, in this case the device cradle is being unlocked, and when the GUI is displayed that says "The cradle is now unlocked."
I have done some research about how Android handles drawing to the screen for fragments, and everything I can find says that onResume is called "when the fragment becomes visible." This does not match my experience, however. According to how I understand the code below should work, the screen should be drawn and then the EMDKManager.getEMDKManager() method is called, which constructs a pointer to the EMDK service and creates a new thread to perform the unlock:
#Override
public void onResume() {
super.onResume();
EMDKManager.getEMDKManager(getActivity().getApplicationContext(), this);
}
It looks more like the screen is drawn to only once onResume() completes in entirety, ie EMDKManager.getEMDKManager() finishes its call as well.
As the fragment is the EMDKListener object that is required for the second parameter for the method, I am struggling finding a way to thread this correctly. I need the GUI to be drawn first or at the same time that the cradle unlock occurs.
Are there any other methods that can be overridden or interfaced with to get the equivalent to an onViewDrawn() event for the fragment?
Thank you very much.
All the lifecycle method onCreate(), onResume() onStop() etc. are called by the main thread, which is also responsible for drawing the UI.
By preforming a long operation in those method, you block the UI thread from handling touch input as well as drawing the app
you can start your long operation on another thread by doing so:
new Thread(new Runnable() {
#Override
public void run() {
// do long operations here
}
}.start();
note that if that operation wants to update the UI components it MUST be done on the UI thread, you can do so by passing a runnable to the activity
activity.runOnUiThread(new Runnable() {
public void run() {
// do UI updating but, do not block it here
}
});
(or you can create an handler if it's a Service or you want to delay those runnables)
Although I have huge concerns about memory use/leaks, I did this in order to get the timing right:
private EMDKManager.EMDKListener getThis() {
return this;
}
private Runnable initEMDK = new Runnable() {
#Override
public void run() {
EMDKManager.getEMDKManager(getActivity().getApplicationContext(), getThis());
}
};
#Override
public void onResume() {
super.onResume();
Log.v(LOGTAG, "Starting");
new Thread(initEMDK).start();
}
I feel like there is a standard way of doing the getThis() method. If you know it, I would love to know.
Thank you.

android work thread and ui thread

onCreate(Bundle savedInstanceState){
// show dialog A if something is not correct
new Thread(){
public void run(){
if(something is wrong) {
runOnUIThread(new Runnable(){
public void run(){
showDialog(A);
}
});
}
}
}.start();
// show dialog B
showDialog(B);
}
I want to know
which dialog will be shown first, and is the order indeterminate? why?
if the order is indeterminate, how can i reproduce the case that A is shown before B?
Thanks!
Which dialog will be shown first is not defined and you should not rely on one occurring before the other as above. The thread scheduler is not identically deterministic in all situations.
You need to lock on a mutex (or any other locking device) to make sure one is shown before the other.
Your question about which dialog will show first is indeterminate. There are cases where the order will flip flop. But generally B would be shown first since 9/10 it will get to place it's event on the UI thread before your thread could detect there was a problem.
I'd suggest using AsyncTask to perform whatever mechanisms are needed to startup, then in the onPostExecute() allow your program to resume starting up so it can showDialog(B) for whatever it needs. That way if dialog A is showing you can stop the startup process there and not show b.
public class MyAsyncStartup extends AsyncTask<Integer,Integer,MyResult> {
MyActivity activity;
public MyResult handleBackground() {
if( somethingWentWrong ) return null;
}
public onPostExecute( MyResult result ) {
if( result == null ) {
showDialog(B);
} else {
activity.resumeStartupAndShowA();
}
}
}
I don't think it is possible that A is shown before B... this is because runOnUIThread adds the event TO THE END of the event queue. The code in that event (showing dialog A) is not going to get executed until after the onCreate() finishes (which means that dialog B gets shown first).
What cannot be guaranteed is the order between showing dialog B and calling runOnUIThread, but that doesn't matter. Here is a fragment from the official docs:
[runOnUIThread] Runs the specified action on the UI thread. If the current thread is the UI thread, then the action is executed immediately. If the current thread is not the UI thread, the action is posted to the event queue of the UI thread.
N/A
You can't show B until you know whether or not A will be shown. So you have to wait for the worker thread no matter what. Would it be possible to put showDialog(B) in your other thread like this?
onCreate(Bundle savedInstanceState){
// show dialog A if something is not correct
new Thread(){
public void run(){
runOnUiThread(new Runnable(){
public void run(){
if(something is wrong) {
showDialog(A);
}
showDialog(B);
}
});
}
}
}.start();
}

update UI from and event

I have a service which sends continously values to an activity through some custom event listeners.
Here everything works fine. Certain values are displayed in my activity as expected, but some others make the application to crash. This is because some of the incoming data is calculated inside a normal thread (that I cannot have access for changing it), and I know I have to use a handler here, but as far as I tried the app still crashing.
more graphically I would like to do the following
onValuesChanged(float val) {
myTextView.setText( Float.toString(val) )
}
where val is calculated in a normal thread, but of course it makes crash the app when doing the setText.
Any suggestions?
Use AsyncTask instead of Thread and in the onPostExecute() you can update the UI.
or use Activity.runOnUiThread(new Runnable() {
void run() {
// do something interesting.
}
});
hey u can send a custom broadcast from your service like this
Intent mintent = new Intent();
mintent.setAction("com.action");
mintent.putExtra("name", "value");
sendBroadcast(mintent);
and register a receiver in your activity which will get the value from incoming intent and then call the handler like this to update the UI ..plese parse the int to string at receiving
myTextView.post(new Runnable() {
public void run() {
myTextView.setText( Float.toString(val) )
}
});
Every time you send a broadcast to your activity and it will update the ui ..
However the above mentioned way is also right but if you have to stay with service then go for this way else above......

Task not finishing and forbidding TextView to be updated

I am now working on an android app in which I need to display a text after some processing is done.
I'm using a Thread to run a process in the back while my progress dialog is being displayed to the user. The Thread works properly and I've followed it step by step and, apparently, it also ends fine; however, the method in which I call it does not seem to come to an end (at least, during a normal cycle) because the text I am setting afterward does display immediately, I have to wait and do some other action (like in order for it to display
Below is the piece of code I'm having trouble with:
private OnClickListener saldoDisp = new OnClickListener(){
public void onClick(View v){
int x = s2.getSelectedItemPosition();
branchSel = arrSucsId[x];
mainProc();
saldoAdminTex.setText(strSaldo); //The late one
}
};
public void mainProc(){
chekP = new Thread (null,doProc,"Background");
chekP.start();
mProgress =ProgressDialog.show(SivetaAsaldo.this, "","Obteniendo saldo...",true, false);
}
private Runnable doProc = new Runnable(){
public void run(){
if(getSaldoAdmin(levelSel,branchSel))
{
mProgress.dismis();
Log.i(TAG,"Task completed properly");
}else
handler.post(tosti);
}
};
So I do get the "Task completed properly" but seems like it still waits for something else, any clues guys?
Thanks for taking a bit of your time to check it out =).
saldoAdminTex.setText(strSaldo); //The late one
is going to get called immediately. It doesn't wait until after the Thread started in mainProc ends. You also cannot dismiss the Progress Dialog in your runnable. You can only do UI related things on the main UI thread.
It would help you to read the article on Painless Threading on the Android Dev site.
About your ProgressDialog, please see this answer about how to use a AsyncTask with a ProgressDialog.
Looking at your code, this:
saldoAdminTex.setText(strSaldo);
would potentially be executed before your thread finishes as the thread will be running in parallel to that line.
An alternative way would be to do this:
public void mainProc(){
mProgress =ProgressDialog.show(SivetaAsaldo.this, "","Obteniendo saldo...",true,false);
handler.post(new Runable(){
public void run(){
if(getSaldoAdmin(levelSel,branchSel))
{
mProgress.dismis();
saldoAdminTex.setText(strSaldo);
Log.i(TAG,"Task completed properly");
}else
handler.post(tosti);
}
});
}

Android: Stopping method to be called twice if already running

I am trying to prevent my application calling the same method twice in the event of a double-click, or if the user presses different buttons quickly, almost at the same time.
I have clickable Views, acting as buttons, that call the same method but passing different parameters. This is the call:
startTheSearch(context, getState(), what, where);
Inside this method I'm creating a new Thread, because it queries a web server for the result:
new Thread(new Runnable() {
public void run() {
progDiag = ProgressDialog.show(ctx, null, "Searching", true);
getServerXML(context, what, where, searchIsCustom, mOffset);
handler.sendEmptyMessage(0);
}
}).start();
The problem is that upon two quick clicks, the method is fired twice, two threads are created, and consequently two new activities are created. That makes my app crash.
When the methods are done, and we have the result from the server, we call the handler:
private Handler handler = new Handler() {
#Override
public void handleMessage(Message msg) {
super.handleMessage(msg);
try {
Intent i = new Intent(Golf.this, Result.class);
Bundle b = new Bundle();
b.putString("what", mWhat);
b.putString("where", mWhere);
b.putInt("offset", mOffset);
b.putBoolean("searchIsCustom", searchIsCustom);
i.putExtras(b);
startActivityForResult(i, Activity.RESULT_OK);
progDiag.dismiss();
} catch (Exception e) {
Alerts.generalDialogAlert("Error", "settings", ctx);
}
}
};
I tried to have a global boolean variable called "blocked" initially set to false, creating a condition like:
if(!blocked){
blocked = true;
new Thread(new Runnable() {
public void run() {
But this only seems to work on slower phones like the G1, I tried on Nexus and before it set blocked = true, the second request has was granted. So is there any way I can block the method being called if it's already running, or if the thread has started so it wont create a new one?
In the book Hello Android the author Ed Burnette gives a very nice solution for this problem.
To leave your app snappy and responsive you should create a second thread to do the web request.
Instead of creating a new thread for every request you can use a SingleThreadExecutor. If you start a second thread you can check if you are waiting for the result of another thread and block until this thread is ready, or cancel the old thread and start a new one if you think that the user now wants to do some other thing.
You can find the source code from the book on this page. Look for the Translate folder inside the source. It is a nice example on how to react to user commands and how to prevent too many web requests because of a user touching a lot on the gui.
Instead of using the "blocked" Boolean, you might investigate using a mutex. They're designed for this kind of problem.
I tried on Nexus and before it set
blocked = true, the second request has
was granted
That is impossible. Android UIs are single-threaded. There is no way that two onClick() methods of OnClickListeners will be called at the same time.

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