Develop Reference

Draw circle on arc

I have the following code
float angle = (-1) * 360 * progress / max;
canvas.drawArc(rectF, startAngle, angle, false, foregroundPaint);
double dotX = Math.cos(startAngle+angle) * rectF.centerX() + rectF.width()/2.0;
double dotY = Math.sin(startAngle+angle) * rectF.centerY() + rectF.height()/2.0;
canvas.drawCircle((float)dotX, (float)dotY,strokeWidth*1.5f, dotPaint);
This is intended to draw an arc and a red circle at the end of the orc. however my circle is not on the arc depending on the "progress" value, ie the angle.
For example on 40 it is on arc, on 47 it is outside ..etc
What is it I am doing wrong here?

if I understanding your question true, just use a library for creating arc layout and then at the end of it add your circle.
arc layout:
https://android-arsenal.com/details/1/4823

Multiple colors for single path Android

Good day.I am creating a siri like wave for android and i encounter an big issue.I need the wave to be in 4 colors.Lets assume i only have one single line which is drawing on the screen accordingly to the voice decibels.Anyway i am able to do it but no way i am able to give 4 different colors for same path.Assume it is 1 single path which moves from screen start to screen end,i need that line to have 4 different colors,mainly i had to divide the path into 4 parts and draw the color for each parts,but neither google,nor any other source give me anything (not even found anything similar to what i want).
Meanwhile i am posting the code where actually i am drawing the lines.
for (int l = 0; l < mWaveCount; ++l) {
float midH = height / 2.0f;
float midW = width / 2.0f;
float maxAmplitude = midH / 2f - 4.0f;
float progress = 1.0f - l * 1.0f / mWaveCount;
float normalAmplitude = (1.5f * progress - 0.5f) * mAmplitude;
float multiplier = (float) Math.min(1.0, (progress / 3.0f * 2.0f) + (1.0f / 3.0f));
if (l != 0) {
mSecondaryPaint.setAlpha((int) (multiplier * 255));
}
mPath.reset();
for (int x = 0; x < width + mDensity; x += mDensity) {
float scaling = 1f - (float) Math.pow(1 / midW * (x - midW), 2);
float y = scaling * maxAmplitude * normalAmplitude * (float) Math.sin(
180 * x * mFrequency / (width * Math.PI) + mPhase) + midH;
// canvas.drawPoint(x, y, l == 0 ? mPrimaryPaint : mSecondaryPaint);
//
// canvas.drawLine(x, y, x, 2*midH - y, mSecondaryPaint);
if (x == 0) {
mPath.moveTo(x, y);
} else {
mPath.lineTo(x, y);
// final float x2 = (x + mLastX) / 2;
// final float y2 = (y + mLastY) / 2;
// mPath.quadTo(x2, y2, x, y);
}
mLastX = x;
mLastY = y;
}
if (l == 0) {
canvas.drawPath(mPath, mPrimaryPaint);
} else {
canvas.drawPath(mPath, mSecondaryPaint);
}
}
I tried to change color on if (l == 0) {
canvas.drawPath(mPath, mPrimaryPaint);
} but if i change it here,no result at all,either the line is separate and not moving at all,but it should,either the color is not applied,propably because i am doing it in loop as i had to and everytime the last color is picked to draw.Anyway can you help me out?Even an small reference is gold for me because really there is nothing at all in the internet.

Anyway even though Matt Horst answer fully correct,i found the simplest and easiest solution...i never thought it would be so easy.Anyway if in world there is someone who need to make an path divided into multiple colors,here is what you can do
int[] rainbow = getRainbowColors();
Shader shader = new LinearGradient(0, 0, 0, width, rainbow,
null, Shader.TileMode.REPEAT);
Matrix matrix = new Matrix();
matrix.setRotate(90);
shader.setLocalMatrix(matrix);
mPrimaryPaint.setShader(shader);
Where getRainbowColors() is an array of colors you wish your line to have and width is the length of the path so the Shader knows how to draw the colors in right way to fit the length of path.Anyway .....easy isnt it?and pretty purged me a lot to get into this simple point.Nowhere in internet you could find only if you are looking for something completelly different,than you might come across this.

It seems to me like you could set up one paint for each section, each with a different color. Then set up one path for each section too. Then as you draw across the screen, wherever the changeover point is between sections, start drawing with the new path. And make sure first to use moveTo() on the new path so it starts off where the old one left off.

For my solution, I tried changing the color of the linePaint in the onDraw Call. But it was drawing a single color.
So i used two different paints for two different colors and draw path on the canvas.
And it worked. Hope it helps someone out there.

How to draw watchface 'ticks' on a square watch?

I currently have this snippet generating the ticks around the outside of and android wear watchface
float innerMainTickRadius = mCenterX - 35;
for(int tickIndex = 0; tickIndex < 12; tickIndex++) {
float tickRot = (float) (tickIndex * Math.PI * 2 / 12);
float innerX = (float) Math.sin(tickRot) * innerMainTickRadius;
float innerY = (float) -Math.cos(tickRot) * innerMainTickRadius;
float outerX = (float) Math.sin(tickRot) * mCenterX;
float outerY = (float) -Math.cos(tickRot) * mCenterX;
canvas.drawLine(mCenterX + innerX, mCenterY + innerY, mCenterX + outerX, mCenterY + outerY, mTickPaint);
}
Which generates the ticks well on a round watchface but on a square it turns out like this:
but I'd like them to not be circular, but instead fit the shape a bit more suitably, e.g:
Is there a standard way to do this? I'm guessing I can't use trig again...

Of course you use geometry and trig. For example any line you put on the clock face you want to point to the center so one part will be the given (x,y) and the other will be arctan2(cy-y,cx-x) giving you the angle from the point you have towards the center (cx,cy) then simply draw the line in the direction of the center of a given length r, by drawing the line from x,y to cos(angle) * r, sin(angle) * r.
However, given your sample image you might want to draw the line from x,y to x+r,y then rotate the canvas by angle so that you can draw those numbers tweaked like that. Be sure to do canvas.save() before tweaking the canvas' matrix and canvas.restore() after the tweak.
This leaves the math of whatever shape you want to draw your ticks from and the positions thereto. You can do this within a Path. So define the path for a rounded rectangle and then use the PathMeasure class to get the getPosTan() and then ignore the tangent and just use the position it gives you to find your position around a rounded rectangle. That or simply calculate those positions as the positions through either a line segment or a bezier section depending on the decided shape.
For example:
static final int TICKS = 12;
static final float TICKLENGTH = 20;
In the draw routine,
float left = cx - 50;
float top = cy - 50;
float right = cx + 50;
float bottom = cy + 50;
float ry = 20;
float rx = 20;
float width = right-left;
float height = bottom-top;
Path path = new Path();
path.moveTo(right, top + ry);
path.rQuadTo(0, -ry, -rx, -ry);
path.rLineTo(-(width - (2 * rx)), 0);
path.rQuadTo(-rx, 0, -rx, ry);
path.rLineTo(0, (height - (2 * ry)));
path.rQuadTo(0, ry, rx, ry);
path.rLineTo((width - (2 * rx)), 0);
path.rQuadTo(rx, 0, rx, -ry);
path.rLineTo(0, -(height - (2 * ry)));
path.close();
PathMeasure pathMeasure = new PathMeasure();
pathMeasure.setPath(path,true);
float length = pathMeasure.getLength();
float[] pos = new float[2];
float r = TICKLENGTH;
for (int i = 0; i < TICKS; i++) {
pathMeasure.getPosTan(i * (length/TICKS),pos,null);
double angle = Math.atan2(cy - pos[1], cx - pos[0]); //yes, y then x.
double cos = Math.cos(angle);
double sin = Math.sin(angle);
canvas.drawLine(pos[0], pos[1], (float)(pos[0] + cos * r), (float)(pos[1] + sin * r), paint);
}
Admittedly it looks like:
So it would take a lot more work to get it looking like your image. But, it's totally doable. The path measure trick thing will work for any shape. I avoided using path.addRoundRect because of the Lollipop+ restriction. You can see my answer to that question here. And the other answers which are plenty fine to how to draw a rounded rectangle-esque shape. You can, if you would like to write an envelope function simply scale your current picture to the envelope of the rectangle according to the factor t, as it goes around the clock.

The angle is a function of the position now. I'm not immediately seeing the trick for getting a closed form in this case. But in the most general case, you could end up just storing the position of each tickmark, then you're just drawing the line that goes through that point and the center. so the angle at second i is just
theta(i)=arctan(y_pos(i) / x_pos(i))
assuming the center has coordinates (0,0). In this case, you only need to store the positions for 8 consecutive ticks because the face is periodic every 90 degrees and symmetric about the diagonals as well.

How to check the touch points of the circles as in the image in Libgdx?

I am facing problem in getting the touch point of the circle for the game i was developing
I tried to solve this by getting the points as below
public Actor hit(float x, float y, boolean touchable){
if(!this.isVisible() || this.getTouchable() == Touchable.disabled)
return null;
// Get center-point of bounding circle, also known as the center of the Rect
float centerX = _texture.getRegionWidth() / 2;
float centerY = _texture.getRegionHeight() / 2;
// Calculate radius of circle
float radius = (float) (Math.sqrt(centerX * centerX + centerY * centerY))-5f;
// And distance of point from the center of the circle
float distance = (float) Math.sqrt(((centerX - x) * (centerX - x))
+ ((centerY - y) * (centerY - y)));
// If the distance is less than the circle radius, it's a hit
if(distance <= radius) return this;
// Otherwise, it isn't
return null;}
I am getting hit positions inside circle but also the points around it near black spots, i only need the touch points near circle.
Would some body suggest the approach for achieving this.

Im guessing that you are comparing local rect coordinates (ie centerX, centerY) with screen coordinates x,y parameters that you are feeding to the function.
So you probably want to subtract the rect's x,y position from the parameters x,y so your parameters are in local coordinates.
So:
float lLocalX = x-rectX (assuming this is the rects x position on the screen)
float lLocalY = y-rectY (assuming this is the rects y position on the screen)
now you can compare them!
float distance = (float) Math.sqrt(((centerX - lLocalX ) * (centerX - lLocalX ))
+ ((centerY - lLocalY ) * (centerY - lLocalY )));

You can have a Circle object in your Actor: http://libgdx.badlogicgames.com/nightlies/docs/api/com/badlogic/gdx/math/Circle.html
Then check if the circle contains that point using the circle.contains(float x, float y) function.
Basically it'll look something like this:
public Actor hit(float x, float y, boolean touchable){
if(!this.isVisible() || this.getTouchable() == Touchable.disabled)
return null;
if (circle.contains(x,y)) return this;
return null;
}
Of course the downside is that if this is a dynamic object and it moves around a lot, then you'd have to constantly update the circles position. Hope this helps :)

Draw a dot always at a fixed point on screen, even when the Canvas is zoomed in or out? - Android

I now draw a dot on the canvas, which may be zoomed in or out.
As far as I know, the drawing function, canvas.drawCircle() takes in the coordinates in canvas coordinate system. Furthermore, the co-ordinates remain unchanged when the canvas is zoomed.
E.g. previously you draw a dot at (50, 50) in the canvas coordinate system, and then you zoom in the canvas, the dot's coordinates in the canvas still remain (50, 50). But obviously, the dot has been moved w.r.t. the screen.
When the canvas is zoomed, the dot should be kept at the same position on the screen. *i.e. After the dot moves w.r.t. to the screen, I want to move it back to its original position w.r.t. the screen.*
My onDraw() function is as follows:
#Override
public void onDraw(Canvas canvas) {
super.onDraw(canvas);
canvasWidth = canvas.getWidth();
canvasHeight = canvas.getHeight();
canvas.save();
canvas.translate(mPosX, mPosY);
canvas.scale(mScaleFactor, mScaleFactor);
mImage.draw(canvas); // draw the map as the background
Paint PointStyle = new Paint();
PointStyle.setColor(Color.BLUE);
PointStyle.setStyle(Paint.Style.FILL_AND_STROKE);
PointStyle.setStrokeWidth(2);
canvas.drawCircle(Constant.INITIAL_X, Constant.INITIAL_Y, 3, PointStyle);
canvas.restore();
}
I tried the following method to move the dot back on screen after the scaling.
private class ScaleListener extends ScaleGestureDetector.SimpleOnScaleGestureListener {
#Override
public boolean onScale(ScaleGestureDetector detector) {
mScaleFactor *= detector.getScaleFactor(); // accumulate the scale factors
// Don't let the object get too small or too large.
mScaleFactor = Math.max(1f, Math.min(mScaleFactor, 10.0f)); // 1 ~ 10
float pinToCornerOnScreenXDistance = 0;
float pinToCornerOnScreenYDistance = 0;
float canvasToScreenDiffRatioX = 0;
float canvasToScreenDiffRatioY = 0;
float pinOnCanvasX = 0;
float pinOnCanvasY = 0;
// pin's location on the screen --> S:(336, 578)
pinToCornerOnScreenXDistance = 336 - canvasLeftTopCornerOnScreenX;
pinToCornerOnScreenYDistance = 578 - canvasLeftTopCornerOnScreenY;
Log.d("Screen Diff", "X: " + pinToCornerOnScreenXDistance + " Y: " + pinToCornerOnScreenYDistance);
canvasToScreenDiffRatioX = canvasWidth * mScaleFactor / 720; // screen of HTC One X --> 720*1280
canvasToScreenDiffRatioY = canvasHeight * mScaleFactor / 1280;
Log.d("Ratio", canvasToScreenDiffRatioX + " " + canvasToScreenDiffRatioY);
pinOnCanvasX = 0 + pinToCornerOnScreenXDistance * canvasToScreenDiffRatioX; // canvas left top corner is the origin (0, 0)
pinOnCanvasY = 0 + pinToCornerOnScreenYDistance * canvasToScreenDiffRatioY;
Log.d("Pin on Canvas", "X: " + pinOnCanvasX + " Y: " + pinOnCanvasY);
Constant.setInitialX(pinOnCanvasX);
Constant.setInitialY(pinOnCanvasY);
historyXSeries.set(0, Constant.INITIAL_X);
historyYSeries.set(0, Constant.INITIAL_Y);
invalidate();
return true;
}
}
The idea is based on the fact that I notice when I zoom in or out the canvas, its left top corner never moves. That is, the canvas' let top corner is the zooming center.
Then I successfully keep updating the zooming center's co-ordinates when the canvas is moved. So in this way, no matter I move the canvas or zoom it, I always have the zooming center's coordinates in my canvasLeftTopCornerOnScreenX and canvasLeftTopCornerOnScreenY.
Then I try to utilize the distance between the never-moved-during-scaling zooming center and the desired position where I hope to place my dot, (336, 578) here. I calculate it as pinToCornerOnScreenDistance.
As its name suggests, it is the on-screen distance. I have to scale it into canvas distance so that I can draw the dot, since the drawing function is based on the canvas coordinate system instead of the screen coordinate system. Currently, the code is device-specific, i.e. it is only for HTC One X, which has a 1280*720 screen, for now. So I do the scaling as follows:
canvasToScreenDiffRatioX = canvasWidth * mScaleFactor / 720;
canvasToScreenDiffRatioY = canvasHeight * mScaleFactor / 1280;
Then, finally I calculate the new on-canvas coordinates of on-screen point (336, 578) and then draw the dot there.
But the result is not correct. When I zoom the canvas, the dot I draw fails to remain at (336, 578) on screen.
Can anybody tell me where goes wrong?
Or propose another way of doing this?
Any comment or Answer will be greatly appreciated!

Is your app using full-screen? Otherwise, it is not 1280 for the height. But I don't think that is your problem.
Based on my understanding, I will change the code to
pinOnCanvasX = 336 / mScaleFactor;
pinOnCanvasY = 578 / mScaleFactor;
which I assume when mScaleFactor == 1, the pin that on Canvas are the same on screen

Try this one,
I think this can be useful for your issue,
pinOnCanvasX = (336 * mScaleFactor) + trans_x;
pinOnCanvasY = (578 * mScaleFactor) + trans_y;
here, trans_x and trans_y is translation of canvas on x and y axis. here in your case should be mPosX, mPosY but not sure what these points means for.
The way I would like to share you is scale and translate your starting
point of the circle as much as canvas does. That means if your canvas
scale and translate with some value then apply the same for
your starting point too.
hope this will solve your problem.