I'm trying to open my app from Chrome but it doesn't work for me..
Here's the official (very limited) documentation:
Android Intents with Chrome
I've found a bunch of similar questions but none of the solutions seem to work for me - also, the answers are a bit fragmented so I'm looking for the complete answer with example. I'd be happy to post my full solution as soon as we found it :)
Launching an Android Application from the Browser
Open Android app from URL using intent-filter not working
Here's what I got now:
AndroidManifest.xml:
<activity android:name=".ActMain" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http" />
<data android:scheme="https" />
<data android:scheme="sharedr" />
<data android:host="pocketr.rejh.nl" />
<data android:pathPattern="/.*" />
</intent-filter>
</activity>
Javascript (it builds the intent link when user clicks on an element):
var url = "http://icerrr.rejh.nl/"
var title = "Example"
var intenturl = "intent://sharedr/#Intent;"
+ "package=com.rejh.sharedr;"
+ "S.action=share;"
+ "S.type=url;"
+ "S.title="+ app.helpers.encodeURIComponent(title) +";"
+ "S.url="+ app.helpers.encodeURIComponent(url) +";"
+ "end";
alert(intenturl); // for debugging
try {
window.location.href=intenturl;
} catch(e) { alert(JSON.stringify(e)); }
I get the following 'link' from this function:
intent://sharedr/#Intent;package=com.rejh.sharedr;S.action=share;S.type=url;S.title=Example;S.url=http%3A%2F%2Ficerrr.rejh.nl%2F;end
Human-readable:
intent://sharedr/#Intent;
package=com.rejh.sharedr;
S.action=share;
S.type=url;
S.title=Example;
S.url=http%3A%2F%2Ficerrr.rejh.nl%2F;
end
So this works as in: it opens the Play Store and shows "Item not found" and a Refresh button. So it opens an activity but not the right one..
The website I'm trying to fire this from is http://pocketr.rejh.nl
Help?
The full answer
As pointed out by Mattia below (and I just figured this out myself but found the answer waiting for me... :P)
First of all: I forgot to include the 'scheme=sharedr' in my intent link:
intent://sharedr/#Intent;
package=com.rejh.sharedr;
S.action=share;
S.type=url;
S.title=Example;
S.url=http%3A%2F%2Ficerrr.rejh.nl%2F;
end
Should be (notice the 2nd line):
intent://sharedr/#Intent;
scheme=sharedr;
package=com.rejh.sharedr;
S.action=share;
S.type=url;
S.title=Example;
S.url=http%3A%2F%2Ficerrr.rejh.nl%2F;
end
Then, in the android manifest:
<activity android:name=".ActMain" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="sharedr" android:host="sharedr" android:path="/"/>
</intent-filter>
</activity>
Where 'android:scheme="sharedr"' is the 'scheme=sharedr' part and 'android:host="sharedr"' corresponds to 'intent://sharedr/'
Thanks!
You specify sharedr as host but the host configured in your AndroidManifest.xml is pocketr.rejh.nl. Also you didn't specify the scheme.
The URL fixed is this:
intent://pocketr.rejh.nl/#Intent;scheme=sharedr;package=com.rejh.sharedr;S.action=share;S.type=url;S.title=Example;S.url=http%3A%2F%2Ficerrr.rejh.nl%2F;end
Human-readable:
intent://pocketr.rejh.nl/#Intent;
scheme=sharedr;
package=com.rejh.sharedr;
S.action=share;
S.type=url;
S.title=Example;
S.url=http%3A%2F%2Ficerrr.rejh.nl%2F;
end
Related
I have researched through most of the custom URL scheme Q&A and I have not found my possible answer.
I want my app to be launched by clicking a certain URL in the browser (any on the mobile device) , the thing is that my given URL cannot be modified as it serves IOS app as well and it looks like this:
"myapp://http://www.name.com/path/path2/"
I'm not sure how to handle "myapp://http://" and construct a proper intent filter , and everything i tried does not work.
Any help will be appreciated , and if I missed a relevant answer please except my apology.
This is what I tried so far :
<activity
android:name="com.myapp.test.SplashScreen"
android:exported="true"
android:label="#string/app_name"
android:screenOrientation="portrait"
android:theme="#android:style/Theme.Black.NoTitleBar.Fullscreen" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<!-- Test for URL scheme -->
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="www.name.com"
android:path="/path/path2/"
android:scheme="http" />
<data
android:host="www.name.com"
android:path="/path/path2/"
android:scheme="https" />
<data android:scheme="myapp" />
</intent-filter>
<!-- End Test for URL scheme -->
</activity>
Note: I have tried with/without the exported:true
As CommonsWare said the given URI upon I needed to create a Scheme is not a valid URI thus the scheme didn't not work and the application didn't launch. After this explanation the server side guys were convinced to change the URI to myapp://... and it worked like magic :).
The Activity looks like this now :
<activity
android:name="com.myapp.test.SplashScreen"
android:exported="true"
android:label="#string/app_name"
android:screenOrientation="portrait"
android:theme="#android:style/Theme.Black.NoTitleBar.Fullscreen" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<!-- Test for URL scheme -->
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="myapp" />
</intent-filter>
<!-- End Test for URL scheme -->
</activity>
That's a misuse of the URI scheme and is invalid. The HTTP URL you want to pass is a piece of data and should thus be sent in the query string.
myapp://somehost/action?url=http%3A%2F%2Fwww.name.com%2Fpath%2Fpath2%2F
you need use a hyperlink to start the app . for example ,you set scheme="yourpackagename" ,you need to set a hyperlink like this: yourpackagename://host ,and you should vist the hyperlink on you moble browser .If you do not have host lable,just remove it.
<!-- Test for URL scheme -->
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:host="host" android:scheme="yourpackagename" />
</intent-filter>
<!-- End Test for URL scheme -->
If your activity has more than one scheme, you should use 2 or more to specify it
I want from the android browser be able to launch my application if it's installed, or launch my website in the other case.
So in order to make it work, I put :
<activity android:name=".MMLogin" android:label="MeetMe" android:theme="#android:style/Theme.NoTitleBar" android:screenOrientation="portrait">
<intent-filter>
<data android:scheme="http" android:host="meet-me.com" android:path="/signin" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.BROWSABLE"/>
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</activity>
in the Manifest, and I created a dummy link to test; and it's not working.
I've tried with and without: BROWSABLE and DEFAULT
I've tried with meetme://datas and change the scheme; nothing worked.
I used threads on stackoverflow like :
Launch custom android application from android browser
What am I doing wrong, or is there a special thing to do to make it work ?
My application suppports from API 7.
Cheers
I used :
Intent Filter to Launch My Activity when custom URI is clicked, I think what was missing is this block :
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<action android:name="android.intent.action.EDIT" />
<action android:name="android.intent.action.PICK" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="application/myapp" />
</intent-filter>
There are many answers in stackoverflow showing how to lauch app from a web browser ,but I am not sure what went wrong with my code, that never seems to be doing the intended.
I am trying to launch my app by a URL from any other app like web browser,initially
my manifest file looks like this
<activity android:name=".Main">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<data android:scheme="http" android:host="ebay.com" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
And When I typed http://ebay.com in the browser that never started my app.Obviously,how does the browser know about my app?,then i tried the other way around and added another Activity called MyActivity and altered the manifest file as
<activity android:name=".Main">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".MyActivity">
<intent-filter>
<data android:scheme="http" android:host="ebay.com" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
</activity>
and tried in my Main Activity
startActivity(new Intent(Intent.ACTION_VIEW,Uri.parse("http://mycityway.com")));
Thus producing the intended result.I can also start another application Activity using this method.
But most of the answers here says that the later is possible.What is the mistake i am doing,I couldn't launch my app from browser.Please guide me.
And When I typed http://ebay.com in the browser that never started my
app.
It gets started when a matching link is clicked not when you type the url in the browser.
Try it by sending yourself an email containing http://ebay.com and click the link in the email application.
I need the browser to start my app whenever I enter the "myapp://blah.com/a?b=1&c=2" in the browser. I have searched a lot on this topic, but non of the answers really helped me. Could you please help to understand what I'm missing?
<activity android:name=".MyAppMain"
android:label="#string/app_name"
android:configChanges="keyboardHidden|orientation"
android:screenOrientation="portrait">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="myapp" />
</intent-filter>
</activity>
After installation from Eclipse (Run As Android application) my app can work ok on its own, but when I type in "myapp://blah.com/a?b=1&c=2", the browser is simply googling for this string. Could you point out what else I'm missing? Do I need after installation to somehow register in the system that I want to handle "myapp://" urls?
I have done this using the
<activity android:name=".ReceiveInviteActivity">
<intent-filter >
<category android:name="android.intent.category.BROWSABLE" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<data
android:scheme="appname"
android:host="project.example.com"
/>
</intent-filter>
</activity>
And activity
if (Intent.ACTION_VIEW.equals(action)) {
final List<String> segments = intent.getData().getPathSegments();
Log.d("LISTARRAY",segments.toString());
String idString = segments.get(0);
Log.d("LISTITEM",segments.get(0).getClass().toString());
String friendId = idString.substring((idString.indexOf("="))+1);
Log.d("friendId!",friendId);
I hope this will help you.
Check out this answer for why it isn't working: Android custom URI scheme incorrectly encoded when type in browser
Basically, the default Android browser only accepts certain URI schemes, so your custom one won't work when typed directly into the URL bar.
Im trying to create my own url scheme so my android app can get called via an URL but for now I dont have a success.
Im trying to have this url to work : cedemo://com.cedemo.scan?X=toto
Here is part of my manifest file :
<activity android:name=".Gallery1" android:label="#string/app_name" android:launchMode="singleTask" android:screenOrientation="portrait">
<intent-filter>
<action android:name="android.intent.action.GALLERY" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="cedemo" android:host="com.cedemo.scan" />
</intent-filter>
</activity>
Does anyone can help telling me what is wrong ?
Also, if someone find what is wrong, can someone tell me how I read the "X" variable from inside the android code from my app ?
Update:
Update: I did the modification of the action (as advised in one of the answers) and it's worked fine. The thing is that I still cannot get the url variable value. Here is the code I tried.
final Intent intent = getIntent();
final String myScheme=intent.getScheme();
final Bundle myBundle=intent.getExtras();
final boolean inContestKey;
if (myBundle != null) {
inContestKey=myBundle.containsKey("inContest");
}
final Uri myURI=intent.getData();
final String value;
if (myURI != null) {
value = myURI.getQueryParameter("inContest");
}
But I receiving null from all the functions… what else can i do?
May be I should explain better the context of my software:
My software is started
My software launch then the browser
the user click a link in the browser and the browser go to the url scheme, back to the software with a variable "X" (for example)
the software should read the variable "X"
But in my case : myScheme, myBundle, myURI are set to null.
Any ideas ?
Update:
I found the answer is that you have to be in the main activity to do that.
I think the problem is with the Action you defined.
There is a "android.intent.action.VIEW" which is what I think you want.
<activity android:name=".Gallery1" android:label="#string/app_name" android:launchMode="singleTask" android:screenOrientation="portrait">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="cedemo" android:host="com.cedemo.scan" />
</intent-filter>
</activity>
Try that and I bet will resolve correctly. I only made this assumption because you included the browsable category which is usually used by the Browser, which does not know of any of your custom actions. If you do want the GALLERY action as you have implied then just create 2 filters
<activity android:name=".Gallery1" android:label="#string/app_name" android:launchMode="singleTask" android:screenOrientation="portrait">
<intent-filter>
<action android:name="android.intent.action.GALLERY" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="cedemo" android:host="com.cedemo.scan" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="cedemo" android:host="com.cedemo.scan" />
</intent-filter>
</activity>
So within the contents of your activity you can do something like:
// Value should be "toto" as in your example
String value = getData().getQueryParameter("X");
What finally fixed things for me was changing the order of the XML elements. Specifically, swapping the data and action rows so data is before action made it start working.
<intent-filter>
<data android:scheme="myappname" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.BROWSABLE" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
And for completeness, my link in the html is "myappname://noop".
One more thing, i would like to throw light. Initially it was not working for me because i was using Main/Launcher tags before View/Default/Browsable/data.
Once i changed the order it started working fine.
i.e Initially not working code
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="myapp" />
</intent-filter>
correct code order
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="myapp" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
and way to test for android is very simple.
Make any html file insert
test to launch myapp <br /><br />
just open this html file and click on test to .... :-)