Always open a new/fresh tab/window using Android browser intent - android

It's a simple request from a simple man.
I am running some OAuth challenge stuff in my code and I want the user to always see a fresh new page on the browser.
I have seen a whole bunch of threads; but none of them really answer this question.
Here's how I am creating an Android browser intent (using c#/Xamarin):
static void GoToAndroidBrowserWithLoginUri(Activity activity, Uri uri)
{
Intent oauthIntent = new Intent(Intent.ActionView, uri);
activity.StartActivity(oauthIntent);
}

with intent flags you can do this:
oauthIntent.setFlags(Intent.FLAG_ACTIVITY_NO_HISTORY);
update: what happens if you add this category to the intent:
oauthIntent.addCategory("android.intent.category.LAUNCHER");
if that doesn't work, lets create a separate task for these activities. Add these flags only:
oauthIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TASK); //clear whats already in your task list
oauthIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);//create a new task to contain the activity

Related

Different types of Android Intents

I have recently started a new Android project and I'm working off the previous developer's code. I'm relatively new to Android and I've come across something that I'm unsure of.
What is the difference between this:
Intent intent = new Intent("com.example.project.MENU");
and this:
Intent intent = new Intent(this, DisplayMenu.class);
I understand what the 2nd code snippet does, I just can't get my head around as to what the first one is doing? Is it referencing the file in the package? Thanks
The first one is an implicit intent, while the second is an explicit intent.
The first one fired an Intent for the action com.example.project.MENU. If you look inside you project AndroidManifest.xml you can see some <intent-filter> balise. This baslise register activity, service or broadcast receiver to different actions.
This mecanism can be used to allow third party app to launch some of your activities.
You can see more on this tutorial http://www.vogella.com/tutorials/AndroidIntent/article.html#intenttypes
Basically an Intent carries some information that are used by the system in order to determine which component should be called for executing the action.
These information are:
Component name: the name of the component that should be launched. (If present the Intent is Explicit)
Action: it specifies the generic action that should be executed (es. ACTION_VIEW, ACTION_SEND). It determines how the rest of the intent is strucutred.
Data: represents the URI that refers to the object that should be associated with the action. For example with the action ACTION_EDIT, the Data should contain the URI of the document that you want modify.
Category: Additional infromation (for example if you want that your app is shown in the launcher you can use CATEGORY_LAUNCHER)
Extras: keys-values pairs that carries additional information
Flags: it is like a metadata that specify how the intent should be managed by the system.
The Intent class provides a lot of different constructors.
The first one you asked for is public Intent (String action)
So, this sets the Action, and lets null all other fields.
The second one public Intent (Context packageContext, Class<?> cls) creates an intent for a specific component by its Component name. All other fields are null. This is a Explicit Intent, since you declare exactly which component should receive it.
The first one is used when you need to call Intent from System
such as Open Camera, Gallery, or Share something to other Application
for example
// this one call Camera to Capture Image
Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
// this one call gallery to let you select image
Intent intent = new Intent(Intent.ACTION_PICK, MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
and That MediaStore.something here is just a Path to the system
for example
MediaStore.ACTION_IMAGE_CAPTURE = "android.media.action.IMAGE_CAPTURE"
Intent.ACTION_PICK = "android.intent.action.PICK"
The first type of intent is mostly used if you want to open another application from your application while the second type of intent is used to open another activity in your application.

How to gracefully fall back to website when Deep Link can't be handled by app

The situation:
You have an extensive mobile website, m.somewhere.com
On Google Play you have an Android App that duplicates the key features of m.somewhere.com, but not all of them.
Your Client/Employer/Investor has asked you to implement deep-linking for those urls that can be handled by the app.
TL;DR - how do you implement this?
My Approach So Far:
First instinct: match only certain urls and launch for them. Problem: paucity of expression in the AndroidManifest intent-filter prevents this (e.g. http://weiyang.wordpress.ncsu.edu/2013/04/11/a-limitation-in-intent-filter-of-android-application/).
As a subset of the problem, suppose the server at m.somewhere.com knows that any url that ends in a number goes to a certain page on the site, and the marketing guys are constantly futzing with the seo, so e.g.
I want to launch the app for:
http://m.somewhere.com/find/abc-12345
https://m.somewhere.com/shop/xyz-45678928492
But not for
http://m.somewhere.com/find/abc-12345-xyz
https://m.somewhere.com/about-us
no combination of path, pathPrefix, or pathPattern will handle this.
Best practice on stackoverflow (Match URIs with <data> like http://example.com/something in AndroidManifest) seems to be to catch everything, and then handle the situation when you get to onCreate() and realize you shouldn't have handled this particular url:
Android Manifest:
...
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http"
android:host="m.somewhere.com"
android:pathPattern=".*"/>
</intent-filter>
...
Activity onCreate():
Intent i = getIntent()
String action = i.getAction();
Uri uri = i.getData();
if (Intent.ACTION_VIEW.equals(action) && cantHandleUrl(uri)) {
// TODO - fallback to browser.
}
I have programmed something similar to the above that is working, but it leads to a very bad end-user experience:
While browsing m.somewhere.com, there is a hiccup on every url click
while the app is launched and then falls back.
There is a nasty habit for a Chooser screen to popup for each and every link click on m.somewhere.com, asking the user which they would like to use (and the Android App is listed along with the browsers, but clicking on the Android App just launches the chooser screen again). If I'm not careful I get in an infinite relaunch loop for my app (if the user selects "Always"), and even if I am careful, it appears to the user that their "Always" selection is being ignored.
What can be done?
(EDIT: Displaying the site in a WebView in the app for unhandled pages is NOT an option).
Late answer, but for future readers: if you're supporting a minimum of API level 15 then there's a more direct (less hacky) way of falling back to a browser for URLs you realize you don't want to handle, without resorting to disabling/re-enabling URL catching components.
nbarraille's answer is creative and possibly your only option if you need to support APIs lower than 15, but if you don't then you can make use of Intent.makeMainSelectorActivity() to directly launch the user's default browser, allowing you to bypass Android's ResolverActivity app selection dialog.
Don't do this
So instead of re-broadcasting the URL Intent the typical way like this:
// The URL your Activity intercepted
String data = "example.com/someurl"
Intent webIntent = new Intent(Intent.ACTION_VIEW, data);
webIntent.addCategory(Intent.CATEGORY_BROWSABLE);
startActivity(webIntent);
Do this
You would broadcast this Intent instead:
Intent defaultBrowser = Intent.makeMainSelectorActivity(Intent.ACTION_MAIN, Intent.CATEGORY_APP_BROWSER);
defaultBrowser.setData(data);
startActivity(defaultBrowser);
This will tell Android to load the browser app and data URL. This should bypass the chooser dialog even if they have more than one browser app installed. And without the chooser dialog you don't have to worry about the app falling into an infinite loop of intercepting/re-broadcasting the same Intent.
Caveat
You have to be okay with opening the URL (the one you didn't want to handle) in the user's browser. If you wanted to give other non-browser apps a chance to open the link as well, this solution wouldn't work since there is no chooser dialog.
Pitfalls
As far as I can tell, the only quirk from using this solution is that when the user clicks one of your deep links, they'll get to choose to open in your app or their browser, etc. When they choose your app and your internal app logic realizes it's a URL it doesn't want to intercept, the user gets shown the browser right away. So they choose your app but get shown the browser instead.
NOTE: when I say "broadcast" in this answer, I mean the general term, not the actual Android system feature.
There is a somewhat hacky way of doing this:
In the manifest, create an intent-filter for m.somewhere.com, to open a specific deeplink handler activity.
In that Activity, figure out if your app supports that URL or not.
If it does, just open whatever activity
If it doesn't, send a non-resolved ACTION_VIEW intent to be opened by your browser. The problem here, is that your app will also catch this intent, and this will create an infinite loop if your app is selected as the default handler for that URL. The solution is to use PackageManager.setComponentEnabledSetting() to disable your deeplink handler Activity before you send that intent, and re-enable it after.
Some example code:
public class DeepLinkHandlerActivity extends Activity {
#Override
protected void onCreate(Bundle savedInstanceState) {
Uri uri = intent.getData();
Intent intent = makeInternallySupportedIntent(uri);
if (intent == null) {
final PackageManager pm = getPackageManager();
final ComponentName component = new ComponentName(context, DeepLinkHandlerActivity.class);
pm.setComponentEnabledSetting(component, PackageManager.COMPONENT_ENABLED_STATE_DISABLED, PackageManager.DONT_KILL_APP);
Intent webIntent = new Intent(Intent.ACTION_VIEW);
webIntent.setData(uri);
context.startActivity(webIntent);
AsyncTask<Void, Void, Void> task = new AsyncTask<Void, Void, Void>() {
#Override
protected Void doInBackground(Void[] params) {
SystemClock.sleep(2000);
pm.setComponentEnabledSetting(component, PackageManager.COMPONENT_ENABLED_STATE_ENABLED, PackageManager.DONT_KILL_APP);
return null;
}
};
task.execute();
} else {
startActivity(intent);
}
finish();
}
}
Hope that helps.
Note: It looks like you need to delay the re-enabling by a couple of seconds for this to work.
Note 2: For a better experience, using a Transparent theme for your activity will make it look like your app didn't even open.
Note 3: If for some reason your app crashes or gets killed before the component re-registers, you're loosing deep link support forever (or until next update/reinstall), so I would also do the component re-enabling in App.onCreate() just in case.
URX provides a free tool (urxlinks.js) that automatically redirects mobile web users into an app if the app is installed. The documentation is available here: http://developers.urx.com/deeplinks/urx-links.html#using-urx-links-js
If two apps are using same scheme then the chooser screen will be popped as android wont know which app the link is intended for. Using custom scheme for your app might solve this issue. But still you can't be sure no one else will use that scheme.
It sounds like you're trying to treat your mobile app and mobile website as extensions of the same experience. That's good practice, generally speaking, but at this point the two are simply not at parity. At least until they reach parity I would not recommend automatically pushing the end user into your mobile app because users who are deliberately using the mobile site in order to find the content your app is missing will find this incredibly frustrating.
Instead, it might make sense to use a smart banner to encourage users on the mobile website pages that do have an in-app equivalent to open the app instead. Those banners would be your deeplinks. You could create them yourself or integrate a tool like Branch ( https://branch.io/universal-app-banner/ ) that handles deep linking and smart banners both.
That last part of your question has to do with where to place the deep links. One advantage to using smart banners instead of redirects is that you can embed them into the appropriate templates on your CMS instead of needing to rely on url detection.
Good luck!
This was my solution to your second problem. PackageManager.queryIntentActivities() will give you the list of apps/activities that would appear in the chooser. Iterate through the list (which should at least include the browser) and find an activity whose package name doesn't match the current app, and set the intent class name to it, then launch an Activity with that intent and call finish();
public Intent getNotMeIntent(Uri uri) {
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
PackageManager manager = context.getPackageManager();
List<ResolveInfo> infos = manager.queryIntentActivities(intent, 0);
for (int i = 0; i < infos.size(); i++) {
ResolveInfo info = infos.get(i);
// Find a handler for this url that isn't us
if (!info.activityInfo.packageName.equals(context.getPackageName())) {
intent.setComponent(null);
intent.setClassName(info.activityInfo.packageName, info.activityInfo.name);
return intent;
}
}
// They have no browser
return null;
}
The Transparent theme (mentioned above) should be a good solution for the first problem.
In destination activity in onCreate set this code for Kotlin:
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
handleIntent(intent)
}
‌private fun handleIntent(intent: Intent?) {
val appLinkAction: String? = intent?.action
val appLinkData: Uri? = intent?.data
showDeepLinkData(appLinkAction, appLinkData)
}
private fun showDeepLinkData(appLinkAction: String?, appLinkData: Uri?) {
if (Intent.ACTION_VIEW == appLinkAction && appLinkData != null) {
val promotionCode = appLinkData.getQueryParameter("exampleQueryString")
Log.e("TAG", "Uri is: $appLinkData")
}
}

Custom Action Intent Opens my App in the same context as the app that I clicked From

I have searched a lot on this.
But, I have my code working to open my app using a custom intent URL. This URL is usually delivered via email.
When I click on the link, it opens my app fine and everything seems to be working; however, it opens in the context of the email application.
For example, if I click on the link from Gmail, when I open multitasking, I have to click on Gmail to return back to the app that just opened.
I would think it should open my app and I can continue using Gmail while my other app is running.
Any thoughts on this?
Make your URL look like this:
intent:#Intent;launchFlags=0x10000000;component=com.mycompany.myapp/com.mycompany.myapp.MyActivity;end
This URL contains the launchFlag for Intent.FLAG_ACTIVIY_NEW_TASK, so this will launch your app in a separate task (outside of the email client or browser or whatever).
EDIT: Add additional details based on OP's comment
You say that you are using a URL like this: http://com.my.app/5058749
In that case you must have used an Intent filter to get Android to open your app by specifying an <intent-filter> on a certain <activity> in your manifest. There are several things you can do to deal with the problem of the launched Activity ending up in the same task as the Activity that launched it:
1) If the Activity is always intended to be the root (starting, first) Activity of a task, you can put the following code in onCreate() after the call to super.onCreate():
if (!isTaskRoot()) {
// Activity was launched into another task. Restart it in its own task
Intent intent = new Intent(this, this.class);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
finish();
return;
}
2) You can set the launch mode of this Activity to singleTask in the manifest by adding
android:launchMode="singleTask"
to the <activity> definition. This will cause the Activity to be launched in its own task but this launch mode has other consequences that are more subtle and so you need to be careful about using it. In general I don't like to suggest this because it tends to create more problems than it solves.
3) You can determine if your app was launched from the browser or email client by examining the Intent used to start it in onCreate() (The Intent will have the data set to the URL when launched via the browser or email client). You can then decide if you want to restart it in its own task by using the code I've supplied in option 1 above.
Add Intent.FLAG_ACTIVITY_NEW_TASK and Intent.FLAG_ACTIVITY_CLEAR_TOP flags(intent.SetFlags() to your intent. Your actitivty will be opened in a new task and this activity will be the root of your new stack.
This is the default behavior with android, but to override it, you need to pass
Intent.FLAG_ACTIVITY_NEW_TASK
Intent.FLAG_ACTIVITY_CLEAR_TOP
with your intent.

Open my application from another in android

My boss asked me to prove that my application behaves properly when summoned by another application (dunno why he asked that).
So I have two apps here, one launches a second one. How I launch the specific app I want? Using Intent launch seemly any generic app that reaches a certain goal, not the app I really want.
Give this a try.
Intent secondIntent = new Intent();
secondIntent.setAction(Intent.ACTION_MAIN);
secondIntent.setClassName("com.example", "com.example.YourSecondApp");
startActivity(secondIntent);
I should point out that com.example should be the package of your second application (the one you want to call) and com.example.YourSecondapp is the class name where you have your onCreate() method.
Intent secondApp = new Intent("com.test.SecondApp");
startActivity(secondApp);
Check out for more examples
http://developer.android.com/resources/faq/commontasks.html#opennewscreen
Create one Intent using the following code
Explicit Intent
When you know the particular component(activity/service) to be loaded
Intent intent = new Intent();
intent.setClass("className/package name");
start<Activity/Service>(intent);
Imlicit Intent
When we do not have the idea which class to load and we know the Action to be perform by the launched application we can go with this intent.
Action needs to set, and the Android run time fallows the intent Resolution technique and list out(one or more components) the components to perform the action. from the list out components (if more than one), user will get the chance to launch his chosen application

Open an url in android browser, avoid multiple tabs

My project is mostly a web application. Now I have an android app with a home screen widget and would like to open a web page in the built-in browser on some user actions. That is easy. In MyAppWidgetProvider.onUpdate I create a new intent:
Intent intent = new Intent("android.intent.action.VIEW",
Uri.parse("http://my.example.com/"));
PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, intent, 0);
views.setOnClickPendingIntent(R.id.text, pendingIntent);
Unfortunately, a new browser window/tab is opened every time the user clicks the widget. My page contains some fancy AJAX/javascript running in the background and regularly sending http requests. So I end up having 8 tabs containing the same page and continuously sending 8-fold amount of http requests.
Is there any way, e.g. different action or additional parameters to avoid opening new tabs?
As a workaround I am now thinking about creating a new activity containing a WebView, but would like to avoid this complexity.
Yes, this is possible.
Use http://developer.android.com/reference/android/provider/Browser.html#EXTRA_APPLICATION_ID to ensure that the same browser tab is reused for your application. For example:
Context context = widget.getContext();
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
intent.putExtra(Browser.EXTRA_APPLICATION_ID, context.getPackageName());
To the best of my knowledge there is no way to specify if a new tab is opened or not using the Intent. I even did some looking and could not find anyway to check which tabs were open.
Another thing you may be able to try is keeping track of if the user has recently been sent to the browser activity from your application, and check if the browser is still open, but once again I can see this going wrong in numerous ways.
Your activity idea would probably be one of the best bets in this situation, though I can understand why you would want to avoid that.

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