This question already has answers here:
Simple parse JSON from URL on Android and display in listview
(6 answers)
parse simple json string in android
(4 answers)
Closed 7 years ago.
i have a url that inide of this url is json code .
i need this content to decode. for example if my url is : http://url.com
i have this json in it:
{ "employee":{"mesg":"username is exsist!","id":0,"name":0,"username":0,"email":0,"status":500} }
i need from url.com this data to put in a variable and decode this.
for decoding i dont have problem . just i need to get data from url , like file_get_contents in php .
, thanks
NOTICE:
i use HttpClient for this solution . but it is deprecated . is another way for this?
You can use IOUtils.toString(url) from Apache Commons library.
Related
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How can I fix 'android.os.NetworkOnMainThreadException'?
(66 answers)
The AsyncTask API is deprecated in Android 11. What are the alternatives?
(19 answers)
Closed 9 months ago.
I am trying to convert a URL to Base64 in Kotlin. I am using Apache Commons IO to accomplish this by first converting the URL to a ByteArray:
val imageBytes = IOUtils.toByteArray(URL(url))
This line creates a android.os.NetworkOnMainThreadException error when I run my app. How do I resolve this? I don't want to change the ThreadPolicy to bypass the error. Below the above line of code, I also have the following:
val imageBase64 = Base64.encode(imageBytes, Base64.URL_SAFE and Base64.NO_WRAP)
val item = ItemCard(
imageBase64,
label,
total
)
list += item
The entire code block is in a loop. So I would also need something where I can get the result in a timely manner where it doesn't interfere with the actual Base64 encoding.
This question already has answers here:
Java URL encoding of query string parameters
(11 answers)
Closed 5 years ago.
I am using URL in one format. but when I enter it in Google and when pressed enter it is converting to another format.
below is my original URL
'https://translation.googleapis.com/language/translate/v2?q=hai basha.how are you&target=te&key={YOUR_API_KEY}'
below is my encoded url
'https://translation.googleapis.com/language/translate/v2?q=hai%20basha.how%20are%20you&target=te&key={YOUR_API_KEY}'
how can I implement this in my code. Actually it is a GET method.
you can use String.replace method to change characters to their respective special character notation. and make a call through get or post or what ever you want.
This question already has answers here:
How do I parse JSON in Android? [duplicate]
(3 answers)
Closed 5 years ago.
I am new to android development. I am stuck try to show dropdown's data into android . Data will come from server as a json format. I am using volley library for HTTP requests. Here is my volley response
{"blood_group_map":[{"value":"1","text":"O+"},{"value":"2","text":"O-"},{"value":"3","text":"A+"},{"value":"4","text":"A-"},{"value":"5","text":"B+"},{"value":"6","text":"B-"},{"value":"7","text":"AB+"},{"value":"8","text":"AB-"}]}
In this response I want draw blood_group_map key in Spinner option list like this HTML. Here value key is used for value and text key is used for display text.
<option value="1">O+</option>
Update:
I parsed this JSON but I want to send spiner value property to server and display text property. How can I send value to server not text ?
For Example if I select O+ blood group then I send spinner value 1 to server.
Use GSON parser to parse data to from json.
Basic working of GSON is: you build an object with structure same as your json.
All you have to do is pass it to spinner. An example of GSON parser here: GSON parser example
Spinner example: Spinner example
This question already has answers here:
How do I parse JSON in Android? [duplicate]
(3 answers)
Closed 8 years ago.
How can I parse this json in an android project?
{"code":200,"lang":"en-ru","**text**":["Лучше поздно, чем никогда"]}
I need only a part of "**text**":["Лучше поздно, чем никогда"]
JSONObject jObj = new JSONObject("{"code":200,"lang":"en-ru","text":"Лучше поздно, чем никогда"}");
String text = jObj.optString("text");
Check those links to understand the concept of JSON serialization/de-serialization
http://www.javacodegeeks.com/2013/10/android-json-tutorial-create-and-parse-json-data.html
http://www.vogella.com/tutorials/AndroidJSON/article.html
And here are the 2 most famous library for handling JSON:
GSON
https://sites.google.com/site/gson/gson-user-guide
&
Jackson
http://wiki.fasterxml.com/JacksonInFiveMinutes
This question already has answers here:
Parsing JSON file in android
(4 answers)
Closed 7 months ago.
I need to call this URL: https://login.skype.com/json/validator?new_username=name.surname
I obtain a json file format. I need only to take the element associated to tag "status". For the above link is "status":406, so I need the value 406. What is the most simple way for implementing a parser that get only this element?
Simplest way to do it for this particular situation is
JSONObject obj=new JSONObject(myJSONString);
String status=obj.getString("status");
You'll have to handle the JSONException incase the tag "status" isn't found.
Have you got this response as a string yet? That is your first step but as you are asking for a parser I assume youve done this. If so the rest is easy:
String jsonString = parsedString; //The downloaded JSON String
JSONObject firstObj = new JSONObject(parsedString);
String status = firstObj.getString("status");