how to draw erase strokes programmatically using Samsung Pen SDK - android

I am using the pen SDK 4.0.7
I want to erase strokes programatically, pretty much the same thing a user will do with his finger or pen when the eraser is enabled.
I know that this code is used to draw pen strokes programatically:
SpenObjectStroke strokeObj = new SpenObjectStroke(penName, points, pressures, timestamps);
strokeObj.setPenSize(size);
strokeObj.setColor(color);
mSpenPageDoc.appendObject(strokeObj);
mSpenSurfaceView.update();
So my question is: how do I draw an Eraser stroke? (that cleans all the pen stokes it overlaps)

The solution I implemented was to use the MagicPen which has the capability of erasing a stroke when the intensity is set to the max value.
String penName = SpenPenManager.SPEN_MAGIC_PEN;
float penSize = eraserSettingView.getInfo().size;
int penColor = -16777216; // gotten from the max transparent color value of the Magic pen
SpenObjectStroke strokeObj = new SpenObjectStroke(penName, points, pressures, timestamps);
strokeObj.setPenSize(size);
strokeObj.setColor(color);
mSpenPageDoc.appendObject(strokeObj);
mSpenSurfaceView.update();

Related

Android - how to properly draw an arrow with Path?

I'm trying to draw an arrow but I get a really strange result.
This is how it looks like and the problem is pretty clear - the overlapping part.
int radius = 100; //Radius of blue circle to the right
Path leftArrow = new Path();
Paint leftArrowPaint = new Paint(Paint.ANTI_ALIAS_FLAG);
leftArrowPaint.setStyle(Paint.Style.STROKE);
leftArrowPaint.setColor(ContextCompat.getColor(getContext(), R.color.buttonText));
leftArrowPaint.setAlpha(80);
leftArrowPaint.setStrokeWidth(8);
Within onDraw method:
//Start point
leftArrow.moveTo(touchX-(radius+5), (int)touchY);
//Line to left
leftArrow.lineTo(touchX-(radius+60), (int)touchY);
//Line up
leftArrow.lineTo(touchX-(radius+30), (int)touchY-30);
//Move back to the middle
leftArrow.moveTo(touchX-(radius+60), (int)touchY);
//Line down
leftArrow.lineTo(touchX-(radius+30), (int)touchY+30);
canvas.drawPath(leftArrow, leftArrowPaint);
leftArrow.reset();
Ok, I know it's too late for you, but I'm gonna answer anyway in case someone comes across the same problem.
You need to specify the Paint's Join property.
https://developer.android.com/reference/android/graphics/Paint.Join.html
leftArrowPaint.setStrokeJoin(Paint.Join.BEVEL);
You can also use Paint.Join.ROUND, depending on what looks better for you.

LibGDX. Android. Black background on transparent DecalSprites

In my App I use several DecalSprites as a part of my scene. They all have transparency (PNG-textures). When I have them overlapping, some of those show black background instead of transparency. Those DecalSprites have different Z-coordinates. So they should look like one behind another.
Please note also the line on the border of a texture. This is also something that I'm struggling to remove.
Update 1: I use PerspectiveCamera in the scene. But all the decals are positioned to face the camera as in 2d mode. So this "black" background appears only in certain cases e.g. when camera goes right (and all those decals appear in the left of the scene). Also I use the CameraGroupStrategy
Solved! The reason was that CameraGroupStrategy when ordering Decals (from farthest to closest to camera) takes the "combined" vector distance between camera and the Decal. When my camera panned to left or to right the distance to the Z-farthest Decal became LESS than the Z-closer Decal. This produced the artifact. Fix:
GroupStrategy strategy = new CameraGroupStrategy(cam , new ZStrategyComparator());
And the Comparator:
private class ZStrategyComparator implements Comparator<Decal> {
#Override
public int compare (Decal o1, Decal o2) {
float dist1 = cam.position.dst(0, 0, o1.getPosition().z);
float dist2 = cam.position.dst(0, 0, o2.getPosition().z);
return (int)Math.signum(dist2 - dist1);
}
}
Thanks to all guys who tried to help. Especially Xoppa. He sent me into the right direction in libGDX IRC.

Calculating the total area of a Region

I would like to be able to know the total area covered by a region (e.g. a double integral over this said area).
I cannot find any method for that, and I wonder will I have to go pixel-by-pixel.
Thanks in advance!
You should be able to use a RegionIterator and sum the areas of the rectangles returned.
Reasoning: The Andriod docs imply that when boolean ops are done on regions, the result region is a new set of non-overlapping rectangles with the desired union. In other words, A - B, where A and B are rectangles, may produce 0, 1, 2, 3, or 4 rectangles as a result.
I have not tested, but the source at the Android xRef site shows that a validated region consists of rectangles with no overlaps.
It seems, i have the same problem like your problem.
I'm not sure, if it is a "real" solution. But i post my code. The values looks ok.
private void calculateArea(Region region) {
RegionIterator regionIterator = new RegionIterator(region);
int size = 0; // amount of Rects
float area = 0; // units of area
Rect tmpRect= new Rect();
while (regionIterator.next(tmpRect)) {
size++;
area += tmpRect.width() * tmpRect.height();
}
log.d("Rect amount=" + size);
log.d("Area Size / units of area=" + area);
}
}
My Problem is: I want to get the area size of some drawn pathes. To recognize touches on the pathes i added a Region too.

Faster Paint on Flex Mobile

I am trying to build an app that tracks touchpoints and draws circles at those points using Flash Builder. The following works perfectly, but after a while, it begins to lag and the touch will be well ahead of the drawn circles. Is there a way of drawing the circles that does not produce lag as more and more of them are added?
In declarations, I have:
<fx:Component className="Circle">
<s:Ellipse>
<s:stroke>
<s:SolidColorStroke alpha="0"/>
</s:stroke>
</s:Ellipse>
</fx:Component>
And this is the drawing function:
var c:Circle = new Circle();
c.x = somex;
c.y = somey;
c.fill = new SolidColor(somecolorint);
c.height = somesize;
c.width = somesize;
c.alpha = 1;
addElement(c);
c = null;
Try taking a look at doing a fullscreen Bitmap created with a BitmapData class. As the touch points are moved, update the bitmap data at the coordinates where the touch occured. Modifying and blitting a screen-sized bitmap is extremely fast and will probably work great for what you're trying to do.
Another performance trade off often done is to make a series of lines instead of continuous circles. You create a new line segment only when a certain distance has been traveled, this lets you limit the number of nodes in the segment thereby keeping performance high.

How can I tell if a closed path contains a given point?

In Android, I have a Path object which I happen to know defines a closed path, and I need to figure out if a given point is contained within the path. What I was hoping for was something along the lines of
path.contains(int x, int y)
but that doesn't seem to exist.
The specific reason I'm looking for this is because I have a collection of shapes on screen defined as paths, and I want to figure out which one the user clicked on. If there is a better way to be approaching this such as using different UI elements rather than doing it "the hard way" myself, I'm open to suggestions.
I'm open to writing an algorithm myself if I have to, but that means different research I guess.
Here is what I did and it seems to work:
RectF rectF = new RectF();
path.computeBounds(rectF, true);
region = new Region();
region.setPath(path, new Region((int) rectF.left, (int) rectF.top, (int) rectF.right, (int) rectF.bottom));
Now you can use the region.contains(x,y) method.
Point point = new Point();
mapView.getProjection().toPixels(geoPoint, point);
if (region.contains(point.x, point.y)) {
// Within the path.
}
** Update on 6/7/2010 **
The region.setPath method will cause my app to crash (no warning message) if the rectF is too large. Here is my solution:
// Get the screen rect. If this intersects with the path's rect
// then lets display this zone. The rectF will become the
// intersection of the two rects. This will decrease the size therefor no more crashes.
Rect drawableRect = new Rect();
mapView.getDrawingRect(drawableRect);
if (rectF.intersects(drawableRect.left, drawableRect.top, drawableRect.right, drawableRect.bottom)) {
// ... Display Zone.
}
The android.graphics.Path class doesn't have such a method. The Canvas class does have a clipping region that can be set to a path, there is no way to test it against a point. You might try Canvas.quickReject, testing against a single point rectangle (or a 1x1 Rect). I don't know if that would really check against the path or just the enclosing rectangle, though.
The Region class clearly only keeps track of the containing rectangle.
You might consider drawing each of your regions into an 8-bit alpha layer Bitmap with each Path filled in it's own 'color' value (make sure anti-aliasing is turned off in your Paint). This creates kind of a mask for each path filled with an index to the path that filled it. Then you could just use the pixel value as an index into your list of paths.
Bitmap lookup = Bitmap.createBitmap(width, height, Bitmap.Config.ALPHA_8);
//do this so that regions outside any path have a default
//path index of 255
lookup.eraseColor(0xFF000000);
Canvas canvas = new Canvas(lookup);
Paint paint = new Paint();
//these are defaults, you only need them if reusing a Paint
paint.setAntiAlias(false);
paint.setStyle(Paint.Style.FILL);
for(int i=0;i<paths.size();i++)
{
paint.setColor(i<<24); // use only alpha value for color 0xXX000000
canvas.drawPath(paths.get(i), paint);
}
Then look up points,
int pathIndex = lookup.getPixel(x, y);
pathIndex >>>= 24;
Be sure to check for 255 (no path) if there are unfilled points.
WebKit's SkiaUtils has a C++ work-around for Randy Findley's bug:
bool SkPathContainsPoint(SkPath* originalPath, const FloatPoint& point, SkPath::FillType ft)
{
SkRegion rgn;
SkRegion clip;
SkPath::FillType originalFillType = originalPath->getFillType();
const SkPath* path = originalPath;
SkPath scaledPath;
int scale = 1;
SkRect bounds = originalPath->getBounds();
// We can immediately return false if the point is outside the bounding rect
if (!bounds.contains(SkFloatToScalar(point.x()), SkFloatToScalar(point.y())))
return false;
originalPath->setFillType(ft);
// Skia has trouble with coordinates close to the max signed 16-bit values
// If we have those, we need to scale.
//
// TODO: remove this code once Skia is patched to work properly with large
// values
const SkScalar kMaxCoordinate = SkIntToScalar(1<<15);
SkScalar biggestCoord = std::max(std::max(std::max(bounds.fRight, bounds.fBottom), -bounds.fLeft), -bounds.fTop);
if (biggestCoord > kMaxCoordinate) {
scale = SkScalarCeil(SkScalarDiv(biggestCoord, kMaxCoordinate));
SkMatrix m;
m.setScale(SkScalarInvert(SkIntToScalar(scale)), SkScalarInvert(SkIntToScalar(scale)));
originalPath->transform(m, &scaledPath);
path = &scaledPath;
}
int x = static_cast<int>(floorf(point.x() / scale));
int y = static_cast<int>(floorf(point.y() / scale));
clip.setRect(x, y, x + 1, y + 1);
bool contains = rgn.setPath(*path, clip);
originalPath->setFillType(originalFillType);
return contains;
}
I know I'm a bit late to the party, but I would solve this problem by thinking about it like determining whether or not a point is in a polygon.
http://en.wikipedia.org/wiki/Point_in_polygon
The math computes more slowly when you're looking at Bezier splines instead of line segments, but drawing a ray from the point still works.
For completeness, I want to make a couple notes here:
As of API 19, there is an intersection operation for Paths. You could create a very small square path around your test point, intersect it with the Path, and see if the result is empty or not.
You can convert Paths to Regions and do a contains() operation. However Regions work in integer coordinates, and I think they use transformed (pixel) coordinates, so you'll have to work with that. I also suspect that the conversion process is computationally intensive.
The edge-crossing algorithm that Hans posted is good and quick, but you have to be very careful for certain corner cases such as when the ray passes directly through a vertex, or intersects a horizontal edge, or when round-off error is a problem, which it always is.
The winding number method is pretty much fool proof, but involves a lot of trig and is computationally expensive.
This paper by Dan Sunday gives a hybrid algorithm that's as accurate as the winding number but as computationally simple as the ray-casting algorithm. It blew me away how elegant it was.
See https://stackoverflow.com/a/33974251/338479 for my code which will do point-in-path calculation for a path consisting of line segments, arcs, and circles.

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