How to write code to hide current sencha touch app? - android

There is one case that I need to click one button that does the same thing like the 'home' button, just to hide the app, not exit the app.
Could you tell me how to write method to simulate the 'home' button in android and ios?
thanks.

I read somewhere and it seems like it is not possible for now.

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Flutter Android - How to disable the Android back Button for the whole App?

I want to block the Back button in the Android Bottom Bar for the whole Application. User should never be able to go back with this Button inside the App.
I already know WillPopScope() to block this on certain Screens. It doesnt work if I wrap WillPopScope around the MaterialApp.
Anyone know how to do this?

React native handle Home button press in android?

Can I add some handle after user press Home button in android ?
Such as show modal ask user need to exit app or cancel.
I see this link Detect home button press in android can helpful.
But I do not know how to apply that code to MainActivity.java of android in react-native.
onUserLeaveHint is work after app close but I need modal work before app close.
Thank for any help.
I was able to solve it myself. I open sourced my solution here - https://www.npmjs.com/package/react-native-home-pressed Let me know what you think

Is it possible to create an app that when installed the user can easily turn Bluetooth/NFC ON and OFF by double clicking the Home button?

I'm looking to create a shortcut to Bluetooth or NFC on Android+IOS,
preferably by "Double clicking the Home button." Is this possible?
If not possible are there other shortcuts? Like maybe double tapping the
mobile screen?
Thanks for reading.
On iOS, as of 10 june 2015, it is not possible on non-jailbroken devices, as there is no public API that would expose the button actions to developer.
It's not possible to override a click on the Home button on Android. If you want to double tap the screen for it, that's certainly possible. Just implement onTouchEvent in your application. You could also set up gestures or simply have a button.
Check http://developer.android.com/guide/components/services.html
other than that, how it works is up to how you code it

Opening up the options list and adding 2 buttons, one to a little alert with about us and a exit

I'm building an mobile application with JQuery Mobile and I found a very big bug..
If I press the back button on the phone it's just like clicking on the back arrow on the browser. I would like to click on the button surrounded by red on this picture:
I want it to when I click it shows the 2 options which are "About" and "Exit". I saw some stuff online about the exit button but couldnt get any to work and I also tried to find something on the jquerymobile docs but no success..
Thanks for your attention!
To listen to those events you will have to use PhoneGap if you are building non native app.

Android Jelly Bean More Option Button

I use Galaxy Nexus and it hasn't any button. But others have some special buttons. For example home,menu,back and search. I am developing an android app and for example I want to use menu button. How can I do this ? How can I add one or more keys on bottom line ?
For example Whatsapp using this. I start whatsapp and I see 4 button, back, home, apps and consecutive three-point. If I click this three-point button , new tab opened and there are few options here.
I want to use this logic how can I do this ?
Note: I don't know how can I pronounced these buttons name.
Please, check this from the documentation in order to get Menu into your app
http://developer.android.com/guide/topics/ui/menus.html
It's quite simple, just override few methods...
you're developing a web application?
if you're, you can using jquery mobile which already provides the keys/buttons for you. otherwise you have to create the button on the app. CMIIW

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