Develop Reference

JSON request does not give anything

I have a bug in the code, but I can not find it. I have to read the message and the code from the JSON request below.
try {
Log.d("qwertz", json);
progressDialog.dismiss();
JSONObject jsonObject = new JSONObject(json);
JSONArray jsonArray = jsonObject.getJSONArray("server_response");
JSONObject JO = jsonArray.getJSONObject(0);
String code = JO.getString("code");
String message = JO.getString("message");
if (code.equals("win"))
{
showDialog("Du hast etwas gewonnen", message,code);
}
else if (code.equals("false"))
{
showDialog("Du hast leider nichts gewonnen", message,code);
}
} catch (JSONException e) {
e.printStackTrace();
}
That is a JSON example
{
"server_response": {
"code": "win",
"message": "Du hast einen PzKpfw S35 739(f) gewonnen"
}
}

I advice you not to process json directly by yourself, instead you can use many libraries that will do the job for you. To mention you can use jackson or gson.
If you still want to correct your code you can try this:
JSONObject response = jsonObject.getJsonObject("server_response");
String code = response.getString("code");

Parse JSON Android convert jsonObject

I have a problem with JSON
I get a json since https://proxyepn-test.epnbn.net/wsapi/epn
But when I want to display a single data eg "name".
The console displays:
Log
org.json.JSONException: No value for Name
org.json.JSONException: Value status at 0 of the type java.lang.String can not be converted to JSONObject
Can you help me ?
Thanks.
here is my code :
String test2 = test.execute(restURL).get().toString();
Log.i("result",test2);
JSONObject obj = new JSONObject(test2);
String data = obj.getString("data");
Log.i("testjson",data);
String pageName = obj.getJSONObject("data").getString("Name");
Log.i("testjsondata",pageName);
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}

Try below:
JSONObject obj = new JSONObject(test2);
JSONObject data = obj.getJSONObject("data");
Iterator<String> iterator = data.keys();
while(iterator.hasNext()){
String key = iterator.next();
String Name = data.getString(key);
}

JSONObject obj = new JSONObject(test2);
JSONObject data=obj.getJSONobject("data");
JSONObject ob1=obj.getJSONobject("1");
String pageName = ob1.getString("Name");

You have to parse your next level of JSONObject (labeled as "1","2","3".. from response).
It seems like issue in Json response structure you shared. why cann't it be array inside "data"?
Then you can easily read data as JSONArray with those objects as ("1","2","3"..) array item.
Else
Android JSON parsing of multiple JSONObjects inside JSONObject

How to get this JSON format value in android?

How can I create a JSON with this format in Android?
I want to send this JSON in my SOAP Web Service Parameter
"{'\obj\':{\"MeterSrNo\":\"5\"},'\SPName\':'XXMFU_GETMobilityDetail'}"
SPName is my second parameter.

Use JSONObject
try {
JSONObject jsonObject = new JSONObject();
JSONObject obj = new JSONObject();
obj.put("MeterSrNo", "5");
jsonObject.put("obj", obj);
jsonObject.put("SPName", "XXMFU_GETMobilityDetail");
} catch (JSONException e) {
}

Json String created in Wrong Format

I have to send request body in Http request in below format:
{
"flag":false,
"Ids":["xyz","abc"]
}
I was trying like:
LinkedHashMap<String, Object> requestParamsMap = new LinkedHashMap<String, Object>();
requestParamsMap.put("flag",false);
ArrayList<String> IdList = new ArrayList<>();
IdList.add("xyz");
IdList.add("abc");
requestParamsMap.put("Ids", IdList.toString());
And then I was converting requestParamsMap to json string. But I am not getting request body in desired format.
I want to create a generalized method which can return me data in this type of format, so that I can use it throughout application.
Any help would be appreciated.. !!!

Do something like this:
JSONObject object=new JSONObject();
try {
object.put("flag","xyz");
JSONArray array=new JSONArray();
array.put("xyz");
array.put("abc");
object.put("Ids",array);
//added a log to see the output
Log.e("output",object.toString());
} catch (JSONException e) {
e.printStackTrace();
}
object.toString() should contain exactly the json you want in string format. You can use a loop to populate the contents of the jsonArray or JSONObject depending on the number of items you have

Its not that though at all, output you want is JSONArray inside JSONObject and JSONObject inside another JSONObject. So, you can create them seperately and then can put in together. as below.
CODE
try {
JSONObject parent = new JSONObject();
JSONObject jsonObject = new JSONObject();
JSONArray jsonArray = new JSONArray();
jsonArray.put("lv1");
jsonArray.put("lv2");
jsonObject.put("mk1", "mv1");
jsonObject.put("mk2", jsonArray);
parent.put("root", jsonObject);
Log.d("output", parent.toString(2));
} catch (JSONException e) {
e.printStackTrace();
}
OUTPUT
{
"root": {
"mk1": "mv1",
"mk2": [
"lv1",
"lv2"
]
}
}

JSON on Android - serialization

is there any simple example for Android of using JSON in a serialization?
Thanks

We use the gson library for that. Serialization is as simple as calling
new Gson().toJson(obj)
And for deserialization,
new Gson().fromJson(jsonStr, MyClass.class);

If you want to avoid using another library in your Android project just to (de)serialize JSON, you cau use following code as I do.
To serialize
JSONObject json = new JSONObject();
json.put("key", "value");
// ...
// "serialize"
Bundle bundle = new Bundle();
bundle.putString("json", json.toString());
and to deserialize
Bundle bundle = getBundleFromIntentOrWhaterver();
JSONObject json = null;
try {
json = new JSONObject(bundle.getString("json"));
String key = json.getString("key");
} catch (JSONException e) {
e.printStackTrace();
}

There is a simple library to (de)serialize JSON,compatible with android own json library.
// deserialize a java bean to json object
JSONObject studentJson = JsonDeer.toJson(student);
// serialize a java bean from json object
Student student1 = JsonDeer.fromJson(studentJson,Student.class);
library address

protected void onPostExecute(String results) {
if (results!=null) {
try {
Tec tec_m=new Tec();
tec_m=new Gson().fromJson(results, Technician.class);
((AndroidActivity)activity).setData(tec_m);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}