Firebase limitToLast (Query) not parsing the response - android

I am doing a query to get an array from Firebase and everything works fine. The query is the following:
FirebaseDatabase.getInstance().getReference()
.child("results").child("mood")
.child(Preferences.getUserId(this))
.addListenerForSingleValueEvent(new ValueEventListener() {
...
And I noticed the child() chain always returns a DatabaseReference object. However, I wanted to use limitToLast() to get only the last element of this array. I didn't really understand why but it returns a Query instead of a DatabaseReference, but both have the addListenerForSingleValueEvent() method since DbRef extends Query.
FirebaseDatabase.getInstance().getReference()
.child("results").child("mood")
.child(Preferences.getUserId(this))
.limitToLast(1)
.addListenerForSingleValueEvent(new ValueEventListener() {
The problem is that it's not parsing my response as it was with DbRef, and then I get an exception:
com.google.firebase.database.DatabaseException: Expected a List while deserializing, but got a class java.util.HashMap
I looked into the HashMap and it's just a Map of my Object attributes as Strings but not parsed.
Why do Query and DatabaseReference have a different response/deserialization method?
Any help is greatly appreciated.
EDIT: As per requested, that it the code to get the data. It's the same for both cases.
#Override
public void onDataChange(DataSnapshot snapshot) {
GenericTypeIndicator<List<Mood>> t = new GenericTypeIndicator<List<Mood>>() {};
moodList = snapshot.getValue(t);
...do stuff with moodList
Whereas moodList is a List<Mood>

You didn't post the code for your Mood class or a sample of the JSON that is stored at location "mood". I'm assuming that you have defined Mood as a POJO that satisfies the Firebase requirements for getters/setters and default constructor. Also that the value stored at "mood" is a valid array of Mood elements.
When you modify your query with limitToLast(1), Firebase returns a map containing the last Mood in the array. Perhaps you were expecting it to return a List<Mood> with length of one. I don't find the Firebase documentation clear on this point. Perhaps Firebaser Frank can provide more details.
To see more clearly what is returned with limitToLast(1), you can modify your code like this:
public void onDataChange(DataSnapshot snapshot) {
Map<String,Object> map = (Map<String,Object>) snapshot.getValue();
Log.i(TAG, "onDataChange: map=" + map);
}
The output will look like this, where N is the index for the last value in your array:
onDataChange: map={N={<the fields of your Mood POJO here>}}

Related

Returning zero nodes in realtime startAt query

Im trying to make pagination with Realtime db. I am making query first time with limit 15 and second time based on last item uid i am making second query where suppose to startAt() with that uid. After first query I am receiving as it suppose to 15 items. Next time it suppose to send me back 9 items. But it sends me zero
The code of response
DatabaseReference mReference = realtimeReference.child("OnlineUsers/" + neededGender);
Query query;
if (uid.equals("")){
query = mReference.orderByChild("rating").limitToLast(TOTAL_ITEMS_TO_LOAD);
}else {
//Pagination query with last uid to start
query = mReference.orderByChild("rating").startAt(uid).limitToLast(TOTAL_ITEMS_TO_LOAD);
}
query.addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(#NonNull DataSnapshot dataSnapshot) {
final List<OnlineUser> userList = new ArrayList<>();
for (DataSnapshot postSnapshot : dataSnapshot.getChildren()) {
OnlineUser user = postSnapshot.getValue(OnlineUser.class);
userList.add(new OnlineUser(user.getUid(), user.getName(), user.getImage(), user.getGender(), user.getCountry(), user.getRating()));
}
EventBus.getDefault().post(new ListEvent(userList));
}
Database structure
When paginating, you always need to pass the value of the property that you order on. In addition, if there are multiple nodes with the same value for that property, you should pass the key of of the first item to return.
So in your case that'd be:
mReference.orderByChild("rating").startAt(rating, key).limitToLast(TOTAL_ITEMS_TO_LOAD);
This assumes that you have the rating of the node in rating and its key in key.

OrderByChild() is not sorting my firebase data

I am new in firebase, I want to sort data, by timestamp and my database is below, here key is timestamp
My code for retrieving data is below
FirebaseDatabase database = FirebaseDatabase.getInstance();
DatabaseReference myRef = database.getReference("MainDoor");
Query dataOrderedByKey = myRef.orderByChild("{pushId}/key");
dataOrderedByKey.addValueEventListener(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot dataSnapshot) {
Map<String, MyListData> value = ((HashMap<String, MyListData>) dataSnapshot.getValue());
Here i am getting value is not by order of key
I am getting data like below which is not in sort order
Data in a Map is by definition not sorted. So when you call dataSnapshot.getValue(), all information about the order of the items in the DataSnapshot is list.
To maintain the order, use a data structure that supports that, such as a list, and extract the individual items in the correct order by looping over DataSnapshot.getChildren().
So something like:
dataOrderedByKey.addValueEventListener(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot snapshot: dataSnapshot.getChildren()) {
System.out.println(snapshot.getKey());
MyListData value = snapshot.getValue()
}
}
...
Also you can get data from firebase in sorted order . Refer my answer at Sort Firebase data in ascending/Descending Order
You want to sort by date, right? Try it
FirebaseDatabase database = FirebaseDatabase.getInstance();
DatabaseReference myRef = database.getReference("MainDoor");
myRef.orderByChild('date').addChildEventListener(new ChildEventListener() {
// implement the ChildEventListener methods as documented above
});
Because of the way JavaScript objects work, the ordering of data in the JavaScript object returned by val() is not guaranteed to match the ordering on the server nor the ordering of child_added events. That is where forEach() comes in handy. It guarantees the children of a DataSnapshot will be iterated in their query order.
// Assume we have the following data in the Database:
{
"users": {
"ada": {
"first": "Ada",
"last": "Lovelace"
},
"alan": {
"first": "Alan",
"last": "Turing"
}
}
}
// Loop through users in order with the forEach() method. The callback
// provided to forEach() will be called synchronously with a DataSnapshot
// for each child:
var query = firebase.database().ref("users").orderByKey();
query.once("value")
.then(function(snapshot) {
snapshot.forEach(function(childSnapshot) {
// key will be "ada" the first time and "alan" the second time
var key = childSnapshot.key;
// childData will be the actual contents of the child
var childData = childSnapshot.val();
});
});

Firebase Cloud Firestore Query whereEqualTo for reference

I am trying to create a query which only selects documents whose reference is equal to a given reference, using Java for Android development. A document which it would match contains the reference for the path "/users/someUser". I am creating the reference like so:
DocumentReference ref = mDatabase.document("users/someUser");
I have also tried:
DocumentReference ref = mDatabase.document("/users/someUser");
Then the query:
Query query = mDatabase.collection("myCollection").whereEqualTo("refField", ref).limit(10);
However, when I run the query and check the task.isSuccessful() in the onComplete method, it's not passing, i.e. it didn't work, whereas when I remove the .whereEqualTo(), it passes and the task's result isn't empty. How can I properly use .whereEqualTo() to check for all documents containing a specific reference?
An example of a document that should match my query would be:
/myCollection/GDpojS5koac2C7YlIqxS which contains the field:
refField: /users/someUser (value of type reference)
And an example of a document that should not match my query would be:
/myCollection/J5ZcVAMYU1nI5XZmh6Bv which contains the field:
refField: /users/wrongUser (value of type reference)
I think you need to add a get() method to run the query and add an onCompletionListener.
Something like this should work:
mDatabase.collection("myCollection")
.whereEqualTo("refField", ref)
.limit(10)
.get()
.addOnCompleteListener({task ->
if(task.isSuccessful){
val result = task.result
})
The above example is in kotlin, but i guess in java it is something similar
You need not to worry about the documents, if you create a query based on your fields then all the documents will be returned in the "QuerySnapshot" object,
for eg,
CollectionReference collectionReference = db.collection(FIRESTORE_USERS);
DocumentReference documentReference = collectionReference.document(userID);
CollectionReference notificationCollection = documentReference.collection(FIRESTORE_NOTIFICATIONS);
notificationCollection.whereEqualTo(USER_TYPE, userType)
.whereGreaterThanOrEqualTo(SEND_AT, calendar.getTime())
.get().addOnSuccessListener(new OnSuccessListener<QuerySnapshot>() {
#Override
public void onSuccess(QuerySnapshot documentSnapshots) {
List<DocumentSnapshot> snapshotsList = documentSnapshots.getDocuments();
ArrayList<NotificationCollections> notificationCollectionsArrayList = new ArrayList<>();
for (DocumentSnapshot snapshot : snapshotsList) {
// each document having that particular field based on query
}
}});
in the above example I am fetching all those documents which match a particular user id and also having time greater than or equal to supplied time (time will not be used in your case)
I hope this helps...
Happy coding :)

Android Firestore query get the id of the document that contains the value in the search

Firestore database image
Hello, I just tried to use Firestore. I had some problem when getting document id.
The question is, I want to get a document id (red box) which has value (blue box) in it.
I use the following query:
collection("mychannel").whereEqualTo("74wRU4xHrcV9oWAXEkKeRNp41c53")
But did not give results.
Thanks!
As in the official documentation:
Although Cloud Firestore can store arrays, it does not support querying array members or updating single array elements.
So there is no way in which you can use the following query:
collection("mychannel").whereEqualTo("74wRU4xHrcV9oWAXEkKeRNp41c53")
If you only want to get the entire userId array you need to iterate over a Map like this:
collection("mychannel").document("1fReXb8pgQvJzFdzpkSy").get().addOnCompleteListener(new OnCompleteListener<DocumentSnapshot>() {
#Override
public void onComplete(#NonNull Task<DocumentSnapshot> task) {
if (task.isSuccessful()) {
DocumentSnapshot document = task.getResult();
if (document.exists()) {
Map<String, Object> map = document.getData();
for (Map.Entry<String, Object> entry : map.entrySet()) {
if (entry.getKey().equals("userId")) {
Log.d("TAG", entry.getValue().toString());
}
}
}
}
}
});
But note, even if userId object is stored in the database as an array, entry.getValue() returns an ArrayList, not an array.
So the output will be:
[74wRU4xHrcV9oWAXEkKeRNp41c53]
A better approach will be if you consider this alternative database structure, where each user id is the key in a map and all values are true:
userId: {
"74wRU4xHrcV9oWAXEkKeRNp41c53": true,
"AdwF...": true,
"YsHs...": true
}
This question is answered here: Firestore: Query by item in array of document
In summary, don't use arrays to store data in Firestore as the query you are trying to do is not available yet (remember it is still in beta). You should use a Map instead.

How to query highest values if children have dynamic keys in Firebase? [duplicate]

My Firebase Database is like this
When the coding below was run:
String loc=(snapshot.child("loc").getvalue()).tostring();
The output I get has different sequence with the database:
Why is that so?
Firebase data is stored as JSON and is inherently unordered.
If you want to access the data in a specific order, you should specify an orderBy clause for your query and access the data using the snapshot's getChildren() method.
Say you want to log the items by ascending key:
DatabaseReference rootRef = FirebaseDatabase.getInstance().getRef();
Query locations = rootRef.orderByKey();
locations.addListenerForSingleValueEvent(new ValueEventListener() {
public void onDataChange(DataSnapshot snapshot) {
for (DataSnapshot locSnapshot: snapshot.getChildren()) {
System.out.println(locSnapshot.getKey() + ": " + locSnapshot.getValue(String.class));
}
}
public void onCancelled(DatabaseError databaseError) {
Log.w(TAG, "loadPost:onCancelled", databaseError.toException());
// ...
}
});
This sample comes (modified) from the Firebase documentation on reading lists of data.
Frank beat me to my edit, check out his correct solution using orderBy....
You need to use forEach rather than the child method (or child.foreach)
Here is a snippet from the doc:
Because of the way JavaScript Objects work, the ordering of data in
the JavaScript Object returned by val() is not guaranteed to match the
ordering on the server nor the ordering of child_added events. That is
where forEach() comes in handy. It guarantees the children of a
DataSnapshot will be iterated in their query-order.
Source: https://firebase.google.com/docs/reference/js/firebase.database.DataSnapshot#forEach

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